I am trying to select the max date in a table that has a Booking Date and a Written Premium value for that date. I want the newest date that has Written Premium (not equal to Zero).
In the above table I want, or expect the 4th Row in my query (7/28/2021, 330000), but I get the first row
(8/20/21, 0)
This is the query I run:
SELECT
MAX(booking_date) AS [Max Booking Date]
FROM
DW.dbo.Table1
GROUP BY
booking_year
HAVING
SUM(written_premium) <> 0
AND booking_year = '2021'
I think this is summing all the written premium, not over the rows so I am just getting the max booking date. Maybe I need a PARTITION BY function or something? I am stuck on this and would appreciate any help on how to best do this.
Thanks,
Brian
I think there are multiple options, but one could be:
SELECT TOP 1 booking_date, written_premium
FROM DW.dbo.Table1
WHERE written_premium <> 0
ORDER BY booking_date DESC
If all you want is the date then there is no need of group by and a HAVING clause.
Set your conditions in the WHERE clause:
SELECT MAX(booking_date) AS [Max Booking Date]
FROM DW.dbo.Table1
WHERE booking_year = '2021' AND written_premium <> 0;
If you want both columns:
SELECT TOP 1 booking_date AS [Max Booking Date], written_premium
FROM DW.dbo.Table1
WHERE booking_year = '2021' AND written_premium <> 0
ORDER BY booking_date DESC;
Related
I'm trying to use a nested aggregate function. I know that SQL does not support it, but I really need to do something like the below query. Basically, I want to count the number of users for each day. But I want to only count the users that haven't completed an order within a 15 days window (relative to a specific day) and that have completed any order within a 30 days window (relative to a specific day). I already know that it is not possible to solve this problem using a regular subquery (it does not allow to change subquery values for each date). The "id" and the "state" attributes are related to the orders. Also, I'm using Fivetran with Snowflake.
SELECT
db.created_at::date as Date,
count(case when
(count(case when (db.state = 'finished')
and (db.created_at::date between dateadd(day,-15,Date) and dateadd(day,-1,Date)) then db.id end)
= 0) and
(count(case when (db.state = 'finished')
and (db.created_at::date between dateadd(day,-30,Date) and dateadd(day,-16,Date)) then db.id end)
> 0) then db.user end)
FROM
data_base as db
WHERE
db.created_at::date between '2020-01-01' and dateadd(day,-1,current_date)
GROUP BY Date
In other words, I want to transform the below query in a way that the "current_date" changes for each date.
WITH completed_15_days_before AS (
select
db.user as User,
count(case when db.state = 'finished' then db.id end) as Completed
from
data_base as db
where
db.created_at::date between dateadd(day,-15,current_date) and dateadd(day,-1,current_date)
group by User
),
completed_16_days_before AS (
select
db.user as User,
count(case when db.state = 'finished' then db.id end) as Completed
from
data_base as db
where
db.created_at::date between dateadd(day,-30,current_date) and dateadd(day,-16,current_date)
group by User
)
SELECT
date(db.created_at) as Date,
count(distinct case when comp_15.completadas = 0 and comp_16.completadas > 0 then comp_15.user end) as "Total Users Churn",
count(distinct case when comp_15.completadas > 0 then comp_15.user end) as "Total Users Active",
week(Date) as Week
FROM
data_base as db
left join completadas_15_days_before as comp_15 on comp_15.user = db.user
left join completadas_16_days_before as comp_16 on comp_16.user = db.user
WHERE
db.created_at::date between '2020-01-01' and dateadd(day,-1,current_date)
GROUP BY Date
Does anyone have a clue on how to solve this puzzle? Thank you very much!
The following should give you roughly what you want - difficult to test without sample data but should be a good enough starting point for you to then amend it to give you exactly what you want.
I've commented to the code to hopefully explain what each section is doing.
-- set parameter for the first date you want to generate the resultset for
set start_date = TO_DATE('2020-01-01','YYYY-MM-DD');
-- calculate the number of days between the start_date and the current date
set num_days = (Select datediff(day, $start_date , current_date()+1));
--generate a list of all the dates from the start date to the current date
-- i.e. every date that needs to appear in the resultset
WITH date_list as (
select
dateadd(
day,
'-' || row_number() over (order by null),
dateadd(day, '+1', current_date())
) as date_item
from table (generator(rowcount => ($num_days)))
)
--Create a list of all the orders that are in scope
-- i.e. 30 days before the start_date up to the current date
-- amend WHERE clause to in/exclude records as appropriate
,order_list as (
SELECT created_at, rt_id
from data_base
where created_at between dateadd(day,-30,$start_date) and current_date()
and state = 'finished'
)
SELECT dl.date_item
,COUNT (DISTINCT ol30.RT_ID) AS USER_COUNT
,COUNT (ol30.RT_ID) as ORDER_COUNT
FROM date_list dl
-- get all orders between -30 and -16 days of each date in date_list
left outer join order_list ol30 on ol30.created_at between dateadd(day,-30,dl.date_item) and dateadd(day,-16,dl.date_item)
-- exclude records that have the same RT_ID as in the ol30 dataset but have a date between 0 amd -15 of the date in date_list
WHERE NOT EXISTS (SELECT ol15.RT_ID
FROM order_list ol15
WHERE ol30.RT_ID = ol15.RT_ID
AND ol15.created_at between dateadd(day,-15,dl.date_item) and dl.date_item)
GROUP BY dl.date_item
ORDER BY dl.date_item;
How do I select rows if the data exists after a specified date? For example, I want to find the revenue when the TIN wasn't in the database before 2017. And if the TIN was in the database before 2017, I don't want to pull the revenue in the previous years.
For example, this pulls all the revenue, and doesn't take into consideration whether or not there was data associated with the TIN prior.
SELECT [DateRevenueAccrued]
,[TIN]
,[Net Revenue]
FROM [CSTM].[reports].[IncomeNew]
WHERE DateRevenueAccrued > '1/1/2017'
Is this what you want?
SELECT [DateRevenueAccrued], [TIN], [Net Revenue]
FROM [CSTM].[reports].[IncomeNew] i
WHERE NOT EXISTS (SELECT 1
FROM [CSTM].[reports].[IncomeNew] i2
WHERE i2.TIN = i.TIN AND
DateRevenueAccrued < '2017-01-01'
);
I guess the below if the question is TIN
exists/not exists though this is row by row
SELECT REVENUE FROM TABLE
WHERE (DateRevenueAccrued <
'1/1/2017' AND TIN IS NULL )OR
(DateRevenueAccrued >=
'1/1/2017')
I have two tables, INVOICES and INV_PRICES. I am trying to find the Invoice table's part price from the Inv_Prices based upon the Invoice_Dt on the Invoice table; if the Invoice_Dt is between (greater than, but less than) or greater than the max EFF_DT on the Inv_Prices, then return that part's price.
I have tired variations on the following code, but no luck. I either do not get all the parts or multiple records.
SELECT DISTINCT A.INVOICE_NBR, A.INVOICE_DT, A.PART_NO,
CASE WHEN TRUNC(A.INVOICE_DT) >= TRUNC(B.EFF_DT) THEN B.DLR_NET_PRC_AM
WHEN (TRUNC(A.INVOICE_DT)||ROWNUM >= TRUNC(B.EFF_DT)||ROWNUM) AND (TRUNC(B.EFF_DT)||ROWNUM <= TRUNC(A.INVOICE_DT)||ROWNUM) THEN B.DLR_NET_PRC_AM
/*MAX(B.EFF_DT) THEN B.DLR_NET_PRC_AM*/
ELSE 0
END AS PRICE
FROM INVOICES A,
INV_PRICES B
WHERE A.PART_NO = B.PART_NO
ORDER BY A.INVOICE_NBR
Can someone assist? I have a sample of each table if needed.
Doesn't it work to put the condition in the JOIN conditions? You can calculate the period when a price is valid using LEAD():
SELECT i.INVOICE_NBR, i.INVOICE_DT, i.PART_NO,
COALESCE(ip.DLR_NET_PRC_AM, 0) as price
FROM INVOICES i LEFT JOIN
(SELECT ip.*, LEAD(eff_dt) OVER (PARTITION BY PART_NO ORDER BY eff_dt) as next_eff_dt
FROM INV_PRICES ip
) ip
ON i.PART_NO = ip.PART_NO AND
i.invoice_dt >= ip.eff_dt AND
(i.invoice_dt < ip.next_eff_dt or ip.next_eff_dt is null)
ORDER BY i.INVOICE_NBR
I am trying to find patients that have more than 1 appointment on the same day. I want to then display all the appointments the patient may have. Do I need to use a subquery to do this? Here is what I have so far:
Select
Appt.ID-PatNm as Patient,
ApptNum,
Sched_ApptType.Prov.Mnemonic as Type,
Appt.Provider-Name as Provider,
Appt.Dt,
Appt.Tm,
Appt.Department-Mnemonic As Dept,
Appt.SchedulerInits,
Case $EXTRACT(Appt.InternalStatus,1)
when 'P' then 'Pending'
when 'A' then 'Arrived'
when 'R' then 'Rescheduled'
End as Status
From Sched.Appointment Appt
JOIN Sched_ApptType.Prov ON
Appt.Department = Sched_ApptType.Prov.Department
and
Appt.Provider = Sched_ApptType.Prov.Provider
and
Appt.Type = Sched_ApptType.Prov.ApptType
Where (Appt.Dt) > DATEADD('DD',-120,CURRENT_DATE)
AND Appt.InternalStatus IN ('P','R','A')
AND Appt.Department-Mnemonic= 'EYE'
Group By
Appt.ID-PatNm,
Appt.Dt
You get the patients having more than one appointment in a day by grouping by patient and day:
select distinct a.id_patnm
from sched.appointment a
group by a.id_patnm, a.dt
having count(*) > 1
So yes, you need a subquery:
Where (Appt.Dt) > DATEADD('DD',-120,CURRENT_DATE)
AND Appt.InternalStatus IN ('P','R','A')
AND Appt.Department_Mnemonic= 'EYE'
AND Appt.ID_PatNm IN
(
select a.id_patnm
from sched.appointment a
group by a.id_patnm, a.dt
having count(*) > 1
)
(BTW: I used id_patnm instead of id-patnm here, for I don't know any DBMS that would allow the hyphen. When using a hyphen in a column name you have to use quotes on the name, e.g. "id-patnm".)
I suppose you could add a column for Appointment_id which would then allow you to get the desired result.
I have a table which has account information for each individual working day. Each record shows the balance on the account for that particular day. I need to create a field that has a running count on how many days it has been since the balance on that particular account was zero.
For example: I have an account which is number 00000001. It was opened a week ago. The database has created a record for the account for last Tuesday, Wednesday, Thursday, Friday and Monday. The account did not have a balance until Friday and the balance was the same for Monday. I want the field to show '2' as a result. Further to this if the balance drops to '0' today, I need the count to reset on the next record and start again if the account has a balance the following day. There are several accounts in this table so I need this to work for each one individually.
Below is as far as I have got:
SELECT
pos.EffDate,
cus.CNA1,
pos.ACNO,
pos.CCY,
pos.LDBL,
pos.LDBLUSD,
MIN(pos3.effdate) AS 'First Post Date',
pos3.Balcount
FROM[dbo].[Account] AS pos
JOIN [dbo].[Customer] AS cus ON ((pos.CNUM=cus.CUST_NO) AND (cus.effdate=pos.effdate))
LEFT JOIN (SELECT pos2.effdate, pos2.ACNO, SUM(CASE pos2.LDBL WHEN 0 THEN 0 ELSE 1 END) AS 'Balcount' FROM [dbo].[Account] AS pos2 GROUP BY pos2.ACNO, pos2.Effdate HAVING pos2.effdate BETWEEN pos2.effdate AND MIN(pos2.effdate)) pos3 ON pos3.ACNO = pos.ACNO
WHERE pos.effdate >='1 Dec 2015' AND pos.Effdate <'30 Dec 2015'
AND pos.srcsys = 'MP_UK'
AND pos.LDBL <= 0
AND pos.CNUM <> '000020'
AND pos.intbear <> 'N'
AND pos.blockdeb IS null
GROUP BY pos.EffDate,cus.CNA1,pos.ACNO,pos.CCY,pos.LDBL,pos.LDBLUSD, pos3.Balcount
ORDER BY 1,2,3
If you need me to clarify anything please let me know. All help is greatly appreciated.
Thanks,
Ben
Basically, you want to group the data, based on the number of time the account is zero before a given row. Then, within each group, you want to enumerate the records.
In SQL Server 2012+, you can do these things with window functions. I am not sure exactly what your sample query has to do with the question, but here is the basic idea:
select a.*, row_number() over (partition by cust_no, grp order by eff_date) as seqnum
from (select a.*,
sum(case when balance = 0 then 1 else 0 end) over
(partition by cust_no order by eff_date) as grp
from Account a
) a;
In earlier versions of SQL Server, you can do something very similar using apply.