Writing sequelize queries for geometries in POSTGRES - sql

Question

I have the following query and want to write it as a sequelize query
`SELECT "Gigs"."id",
"gigType",
"gigCategory",
"gigTitle",
"gigDescription",
"minOrderAmount",
unit,
"unitPrice",
stock,
sold,
"expireDate",
"Gigs".userid AS "sellerId",
"growerType" AS "sellerType",
"points",
json_build_object('id', "locationId", 'lat', lat, 'lng', lng) AS location
FROM (SELECT DISTINCT ON ("gigid") "gigid", "locationId", lat, lng
FROM (SELECT "gigid",
id as "locationId",
st_x(coordinates::geometry) as lat,
st_y(coordinates::geometry) as lng
FROM "Locations"
WHERE ST_DWithin(coordinates,
ST_MakePoint(${location.lat}, ${location.lng})::geography,
${distance})
ORDER BY coordinates <-> ST_MakePoint(${location.lat}, ${location.lng})::geography
LIMIT ${limit}) AS nearGigIds) AS distinctGigIds
INNER JOIN "Gigs"
ON distinctGigIds."gigid" = "Gigs"."id"
INNER JOIN "Users" U
ON U.id = "Gigs".userid
INNER JOIN "Customers" C on U.id = C.userid
INNER JOIN "Growers" G on C.userid = G.userid
WHERE "expireDate" > ${today}::text::date
ORDER BY points DESC
OFFSET ${offset} LIMIT 10;`
I want to know how to write ORDER BY coordinates <-> ST_MakePoint(${location.lat}, ${location.lng})::geography part in the query. I referred the docs and there is a way to write functions in ORDER BY as follows.
order: [
// Will order by otherfunction(`col1`, 12, 'lalala') DESC
[sequelize.fn('otherfunction', sequelize.col('col1'), 12, 'lalala'), 'DESC'],
],
});
But I am confused about how to write the aforesaid part like this.

Answer 1

db.Table.findAll({
attributes: {
include: [
[
Sequelize.fn(
'ST_Distance',
Sequelize.fn('point', Sequelize.col('longitude'), Sequelize.col('latitude')),
Sequelize.fn('point', longitude, latitude),
),
'distanceAttribute',
],
],
},
order:[['distanceAttribute', 'DESC']]
});