Colon functions and $ variables in c++? - bcc-bpf

I'm still a bit new to c++ and I'm having trouble understanding what this piece of code is doing:
#include <net/sock.h>
BEGIN
{
printf("%-8s %-6s %-16s %-2s %-16s %-5s\n", "TIME", "PID", "COMM",
"IP", "RADDR", "RPORT");
}
kprobe:ip4_datagram_connect,
kprobe:ip6_datagram_connect
{
$sk = (struct sock *)arg0;
$sa = (struct sockaddr *)arg1;
if (($sa->sa_family == AF_INET || $sa->sa_family == AF_INET6) &&
$sk->sk_protocol == IPPROTO_UDP) {
time("%H:%M:%S ");
if ($sa->sa_family == AF_INET) {
$s = (struct sockaddr_in *)arg1;
$port = ($s->sin_port >> 8) |
(($s->sin_port << 8) & 0xff00);
printf("%-6d %-16s 4 %-16s %-5d\n", pid, comm,
ntop(AF_INET, $s->sin_addr.s_addr), $port);
} else {
$s6 = (struct sockaddr_in6 *)arg1;
$port = ($s6->sin6_port >> 8) |
(($s6->sin6_port << 8) & 0xff00);
printf("%-6d %-16s 6 %-16s %-5d\n", pid, comm,
ntop(AF_INET6, $s6->sin6_addr.in6_u.u6_addr8),
$port);
}
}
}
I think the "BEGIN" portion of this is defining a macro, but I'm not fully sure. What I'm really confused about is the
kprobe:ip4_datagram_connect,
kprobe:ip6_datagram_connect
{
What is this doing? It seems like a function declaration, but what does the single colon mean in this context? Is this some sort initialization list but for functions? Is this setting both ip4 and ip6 to that function?
Also, do the dollar sign variable names have any sort of significance? or are they just a valid way of declaring variables?
This is the code for udpconnect.bt from bcc tools. I'm try to convert it to python.

As mentioned in the comments, this is a script for bpftrace. You probably want to look at the reference guide for this tool.
The BEGIN block is run at the start of your program (just like with awk scripts, if you are familiar with it). In this case it is used to print the header row for an array to the console output.
Then the block:
kprobe:ip4_datagram_connect,
kprobe:ip6_datagram_connect
{
... defines instructions that will be translated to an eBPF program (with an intermediary step as LLVM intermediate representation), and attached to one or several hooks in the Linux kernel. In the current case, the kprobe:... define the hooks: The program will run as a kprobe function for the functions ip4_datagram_connect and its IPv6 counterpart in the kernel. In other words, it will run each time the kernel enters those functions.
On a quick look, I think the program is supposed to print, each time a UDP flow starts, the time, PID and name of the process opening the socket, the IP address, remote address and remote port. The first if checks that the packet is (IPv4 or IPv6) and UDP, the if/else below splits the two cases IPv4/IPv6.

Related

Parallel Dynamic Programming with CUDA

It is my first attempt to implement recursion with CUDA. The goal is to extract all the combinations from a set of chars "12345" using the power of CUDA to parallelize dynamically the task. Here is my kernel:
__device__ char route[31] = { "_________________________"};
__device__ char init[6] = { "12345" };
__global__ void Recursive(int depth) {
// up to depth 6
if (depth == 5) return;
// newroute = route - idx
int x = depth * 6;
printf("%s\n", route);
int o = 0;
int newlen = 0;
for (int i = 0; i<6; ++i)
{
if (i != threadIdx.x)
{
route[i+x-o] = init[i];
newlen++;
}
else
{
o = 1;
}
}
Recursive<<<1,newlen>>>(depth + 1);
}
__global__ void RecursiveCount() {
Recursive <<<1,5>>>(0);
}
The idea is to exclude 1 item (the item corresponding to the threadIdx) in each different thread. In each recursive call, using the variable depth, it works over a different base (variable x) on the route device variable.
I expect the kernel prompts something like:
2345_____________________
1345_____________________
1245_____________________
1234_____________________
2345_345_________________
2345_245_________________
2345_234_________________
2345_345__45_____________
2345_345__35_____________
2345_345__34_____________
..
2345_245__45_____________
..
But it prompts ...
·_____________
·_____________
·_____________
·_____________
·_____________
·2345
·2345
·2345
·2345
...
What I´m doing wrong?
What I´m doing wrong?
I may not articulate every problem with your code, but these items should get you a lot closer.
I recommend providing a complete example. In my view it is basically required by Stack Overflow, see item 1 here, note use of the word "must". Your example is missing any host code, including the original kernel call. It's only a few extra lines of code, why not include it? Sure, in this case, I can deduce what the call must have been, but why not just include it? Anyway, based on the output you indicated, it seems fairly evident the launch configuration of the host launch would have to be <<<1,1>>>.
This doesn't seem to be logical to me:
I expect the kernel prompts something like:
2345_____________________
The very first thing your kernel does is print out the route variable, before making any changes to it, so I would expect _____________________. However we can "fix" this by moving the printout to the end of the kernel.
You may be confused about what a __device__ variable is. It is a global variable, and there is only one copy of it. Therefore, when you modify it in your kernel code, every thread, in every kernel, is attempting to modify the same global variable, at the same time. That cannot possibly have orderly results, in any thread-parallel environment. I chose to "fix" this by making a local copy for each thread to work on.
You have an off-by-1 error, as well as an extent error in this loop:
for (int i = 0; i<6; ++i)
The off-by-1 error is due to the fact that you are iterating over 6 possible items (that is, i can reach a value of 5) but there are only 5 items in your init variable (the 6th item being a null terminator. The correct indexing starts out over 0-4 (with one of those being skipped). On subsequent iteration depths, its necessary to reduce this indexing extent by 1. Note that I've chosen to fix the first error here by increasing the length of init. There are other ways to fix, of course. My method inserts an extra _ between depths in the result.
You assume that at each iteration depth, the correct choice of items is the same, and in the same order, i.e. init. However this is not the case. At each depth, the choices of items must be selected not from the unchanging init variable, but from the choices passed from previous depth. Therefore we need a local, per-thread copy of init also.
A few other comments about CUDA Dynamic Parallelism (CDP). When passing pointers to data from one kernel scope to a child scope, local space pointers cannot be used. Therefore I allocate for the local copy of route from the heap, so it can be passed to child kernels. init can be deduced from route, so we can use an ordinary local variable for myinit.
You're going to quickly hit some dynamic parallelism (and perhaps memory) limits here if you continue this. I believe the total number of kernel launches for this is 5^5, which is 3125 (I'm doing this quickly, I may be mistaken). CDP has a pending launch limit of 2000 kernels by default. We're not hitting this here according to what I see, but you'll run into that sooner or later if you increase the depth or width of this operation. Furthermore, in-kernel allocations from the device heap are by default limited to 8KB. I don't seem to be hitting that limit, but probably I am, so my design should probably be modified to fix that.
Finally, in-kernel printf output is limited to the size of a particular buffer. If this technique is not already hitting that limit, it will soon if you increase the width or depth.
Here is a worked example, attempting to address the various items above. I'm not claiming it is defect free, but I think the output is closer to your expectations. Note that due to character limits on SO answers, I've truncated/excerpted some of the output.
$ cat t1639.cu
#include <stdio.h>
__device__ char route[31] = { "_________________________"};
__device__ char init[7] = { "12345_" };
__global__ void Recursive(int depth, const char *oroute) {
char *nroute = (char *)malloc(31);
char myinit[7];
if (depth == 0) memcpy(myinit, init, 6);
else memcpy(myinit, oroute+(depth-1)*6, 6);
myinit[6] = 0;
if (nroute == NULL) {printf("oops\n"); return;}
memcpy(nroute, oroute, 30);
nroute[30] = 0;
// up to depth 6
if (depth == 5) return;
// newroute = route - idx
int x = depth * 6;
//printf("%s\n", nroute);
int o = 0;
int newlen = 0;
for (int i = 0; i<(6-depth); ++i)
{
if (i != threadIdx.x)
{
nroute[i+x-o] = myinit[i];
newlen++;
}
else
{
o = 1;
}
}
printf("%s\n", nroute);
Recursive<<<1,newlen>>>(depth + 1, nroute);
}
__global__ void RecursiveCount() {
Recursive <<<1,5>>>(0, route);
}
int main(){
RecursiveCount<<<1,1>>>();
cudaDeviceSynchronize();
}
$ nvcc -o t1639 t1639.cu -rdc=true -lcudadevrt -arch=sm_70
$ cuda-memcheck ./t1639
========= CUDA-MEMCHECK
2345_____________________
1345_____________________
1245_____________________
1235_____________________
1234_____________________
2345__345________________
2345__245________________
2345__235________________
2345__234________________
2345__2345_______________
2345__345___45___________
2345__345___35___________
2345__345___34___________
2345__345___345__________
2345__345___45____5______
2345__345___45____4______
2345__345___45____45_____
2345__345___45____5______
2345__345___45____5_____5
2345__345___45____4______
2345__345___45____4_____4
2345__345___45____45____5
2345__345___45____45____4
2345__345___35____5______
2345__345___35____3______
2345__345___35____35_____
2345__345___35____5______
2345__345___35____5_____5
2345__345___35____3______
2345__345___35____3_____3
2345__345___35____35____5
2345__345___35____35____3
2345__345___34____4______
2345__345___34____3______
2345__345___34____34_____
2345__345___34____4______
2345__345___34____4_____4
2345__345___34____3______
2345__345___34____3_____3
2345__345___34____34____4
2345__345___34____34____3
2345__345___345___45_____
2345__345___345___35_____
2345__345___345___34_____
2345__345___345___45____5
2345__345___345___45____4
2345__345___345___35____5
2345__345___345___35____3
2345__345___345___34____4
2345__345___345___34____3
2345__245___45___________
2345__245___25___________
2345__245___24___________
2345__245___245__________
2345__245___45____5______
2345__245___45____4______
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2345__245___45____5______
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2345__245___45____4______
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2345__245___45____45____5
2345__245___45____45____4
2345__245___25____5______
2345__245___25____2______
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2345__245___25____2______
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2345__245___25____25____5
2345__245___25____25____2
2345__245___24____4______
2345__245___24____2______
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2345__245___24____4______
2345__245___24____4_____4
2345__245___24____2______
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2345__245___24____24____4
2345__245___24____24____2
2345__245___245___45_____
2345__245___245___25_____
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2345__245___245___45____5
2345__245___245___45____4
2345__245___245___25____5
2345__245___245___25____2
2345__245___245___24____4
2345__245___245___24____2
2345__235___35___________
2345__235___25___________
2345__235___23___________
2345__235___235__________
2345__235___35____5______
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2345__235___35____3______
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2345__235___35____35____5
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2345__235___25____5______
2345__235___25____2______
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2345__235___25____5______
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2345__235___25____2______
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2345__235___25____25____5
2345__235___25____25____2
2345__235___23____3______
2345__235___23____2______
2345__235___23____23_____
2345__235___23____3______
2345__235___23____3_____3
2345__235___23____2______
2345__235___23____2_____2
2345__235___23____23____3
2345__235___23____23____2
2345__235___235___35_____
2345__235___235___25_____
2345__235___235___23_____
2345__235___235___35____5
2345__235___235___35____3
2345__235___235___25____5
2345__235___235___25____2
2345__235___235___23____3
2345__235___235___23____2
2345__234___34___________
2345__234___24___________
2345__234___23___________
2345__234___234__________
2345__234___34____4______
2345__234___34____3______
2345__234___34____34_____
2345__234___34____4______
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2345__234___34____3______
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2345__234___34____34____4
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2345__234___24____4______
2345__234___24____2______
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2345__234___24____2______
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2345__234___24____24____4
2345__234___24____24____2
2345__234___23____3______
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2345__234___23____23_____
2345__234___23____3______
2345__234___23____3_____3
2345__234___23____2______
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2345__234___23____23____3
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2345__234___234___34_____
2345__234___234___24_____
2345__234___234___23_____
2345__234___234___34____4
2345__234___234___34____3
2345__234___234___24____4
2345__234___234___24____2
2345__234___234___23____3
2345__234___234___23____2
2345__2345__345__________
2345__2345__245__________
2345__2345__235__________
2345__2345__234__________
2345__2345__345___45_____
2345__2345__345___35_____
2345__2345__345___34_____
2345__2345__345___45____5
2345__2345__345___45____4
2345__2345__345___35____5
2345__2345__345___35____3
2345__2345__345___34____4
2345__2345__345___34____3
2345__2345__245___45_____
2345__2345__245___25_____
2345__2345__245___24_____
2345__2345__245___45____5
2345__2345__245___45____4
2345__2345__245___25____5
2345__2345__245___25____2
2345__2345__245___24____4
2345__2345__245___24____2
2345__2345__235___35_____
2345__2345__235___25_____
2345__2345__235___23_____
2345__2345__235___35____5
2345__2345__235___35____3
2345__2345__235___25____5
2345__2345__235___25____2
2345__2345__235___23____3
2345__2345__235___23____2
2345__2345__234___34_____
2345__2345__234___24_____
2345__2345__234___23_____
2345__2345__234___34____4
2345__2345__234___34____3
2345__2345__234___24____4
2345__2345__234___24____2
2345__2345__234___23____3
2345__2345__234___23____2
1345__345________________
1345__145________________
1345__135________________
1345__134________________
1345__1345_______________
1345__345___45___________
1345__345___35___________
1345__345___34___________
1345__345___345__________
1345__345___45____5______
1345__345___45____4______
1345__345___45____45_____
1345__345___45____5______
1345__345___45____5_____5
1345__345___45____4______
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1345__345___45____45____5
1345__345___45____45____4
1345__345___35____5______
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1345__345___345___45____5
1345__345___345___45____4
1345__345___345___35____5
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1345__145___45___________
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1345__145___45____45____5
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1345__145___15____5______
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1345__145___15____1______
1345__145___15____1_____1
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1345__145___145___45____5
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1345__145___145___15____5
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1345__145___145___14____1
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1345__135___35____35____5
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1345__135___15____1______
1345__135___15____1_____1
1345__135___15____15____5
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1345__1345__345__________
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1345__1345__145___14____1
1345__1345__135___35_____
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1345__1345__135___13_____
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1345__1345__135___15____5
1345__1345__135___15____1
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1345__1345__135___13____1
1345__1345__134___34_____
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1245__245________________
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1245__245___245___25_____
1245__245___245___24_____
1245__245___245___45____5
1245__245___245___45____4
1245__245___245___25____5
1245__245___245___25____2
1245__245___245___24____4
1245__245___245___24____2
1245__145___45___________
1245__145___15___________
1245__145___14___________
1245__145___145__________
1245__145___45____5______
1245__145___45____4______
1245__145___45____45_____
1245__145___45____5______
1245__145___45____5_____5
1245__145___45____4______
...
1235__1235__235___25_____
1235__1235__235___23_____
1235__1235__235___35____5
1235__1235__235___35____3
1235__1235__235___25____5
1235__1235__235___25____2
1235__1235__235___23____3
1235__1235__235___23____2
1235__1235__135___35_____
1235__1235__135___15_____
1235__1235__135___13_____
1235__1235__135___35____5
1235__1235__135___35____3
1235__1235__135___15____5
1235__1235__135___15____1
1235__1235__135___13____3
1235__1235__135___13____1
1235__1235__125___25_____
1235__1235__125___15_____
1235__1235__125___12_____
1235__1235__125___25____5
1235__1235__125___25____2
1235__1235__125___15____5
1235__1235__125___15____1
1235__1235__125___12____2
1235__1235__125___12____1
1235__1235__123___23_____
1235__1235__123___13_____
1235__1235__123___12_____
1235__1235__123___23____3
1235__1235__123___23____2
1235__1235__123___13____3
1235__1235__123___13____1
1235__1235__123___12____2
1235__1235__123___12____1
1234__234________________
1234__134________________
1234__124________________
1234__123________________
1234__1234_______________
1234__234___34___________
1234__234___24___________
1234__234___23___________
1234__234___234__________
1234__234___34____4______
1234__234___34____3______
1234__234___34____34_____
1234__234___34____4______
1234__234___34____4_____4
1234__234___34____3______
1234__234___34____3_____3
1234__234___34____34____4
1234__234___34____34____3
1234__234___24____4______
1234__234___24____2______
1234__234___24____24_____
1234__234___24____4______
1234__234___24____4_____4
1234__234___24____2______
1234__234___24____2_____2
1234__234___24____24____4
1234__234___24____24____2
1234__234___23____3______
1234__234___23____2______
1234__234___23____23_____
1234__234___23____3______
1234__234___23____3_____3
1234__234___23____2______
1234__234___23____2_____2
1234__234___23____23____3
1234__234___23____23____2
1234__234___234___34_____
1234__234___234___24_____
1234__234___234___23_____
1234__234___234___34____4
1234__234___234___34____3
1234__234___234___24____4
1234__234___234___24____2
1234__234___234___23____3
1234__234___234___23____2
1234__134___34___________
1234__134___14___________
1234__134___13___________
1234__134___134__________
1234__134___34____4______
1234__134___34____3______
1234__134___34____34_____
1234__134___34____4______
1234__134___34____4_____4
1234__134___34____3______
1234__134___34____3_____3
1234__134___34____34____4
1234__134___34____34____3
1234__134___14____4______
1234__134___14____1______
1234__134___14____14_____
1234__134___14____4______
1234__134___14____4_____4
1234__134___14____1______
1234__134___14____1_____1
1234__134___14____14____4
1234__134___14____14____1
1234__134___13____3______
1234__134___13____1______
1234__134___13____13_____
1234__134___13____3______
1234__134___13____3_____3
1234__134___13____1______
1234__134___13____1_____1
1234__134___13____13____3
1234__134___13____13____1
1234__134___134___34_____
1234__134___134___14_____
1234__134___134___13_____
1234__134___134___34____4
1234__134___134___34____3
1234__134___134___14____4
1234__134___134___14____1
1234__134___134___13____3
1234__134___134___13____1
1234__124___24___________
1234__124___14___________
1234__124___12___________
1234__124___124__________
1234__124___24____4______
1234__124___24____2______
1234__124___24____24_____
1234__124___24____4______
1234__124___24____4_____4
1234__124___24____2______
1234__124___24____2_____2
1234__124___24____24____4
1234__124___24____24____2
1234__124___14____4______
1234__124___14____1______
1234__124___14____14_____
1234__124___14____4______
1234__124___14____4_____4
1234__124___14____1______
1234__124___14____1_____1
1234__124___14____14____4
1234__124___14____14____1
1234__124___12____2______
1234__124___12____1______
1234__124___12____12_____
1234__124___12____2______
1234__124___12____2_____2
1234__124___12____1______
1234__124___12____1_____1
1234__124___12____12____2
1234__124___12____12____1
1234__124___124___24_____
1234__124___124___14_____
1234__124___124___12_____
1234__124___124___24____4
1234__124___124___24____2
1234__124___124___14____4
1234__124___124___14____1
1234__124___124___12____2
1234__124___124___12____1
1234__123___23___________
1234__123___13___________
1234__123___12___________
1234__123___123__________
1234__123___23____3______
1234__123___23____2______
1234__123___23____23_____
1234__123___23____3______
1234__123___23____3_____3
1234__123___23____2______
1234__123___23____2_____2
1234__123___23____23____3
1234__123___23____23____2
1234__123___13____3______
1234__123___13____1______
1234__123___13____13_____
1234__123___13____3______
1234__123___13____3_____3
1234__123___13____1______
1234__123___13____1_____1
1234__123___13____13____3
1234__123___13____13____1
1234__123___12____2______
1234__123___12____1______
1234__123___12____12_____
1234__123___12____2______
1234__123___12____2_____2
1234__123___12____1______
1234__123___12____1_____1
1234__123___12____12____2
1234__123___12____12____1
1234__123___123___23_____
1234__123___123___13_____
1234__123___123___12_____
1234__123___123___23____3
1234__123___123___23____2
1234__123___123___13____3
1234__123___123___13____1
1234__123___123___12____2
1234__123___123___12____1
1234__1234__234__________
1234__1234__134__________
1234__1234__124__________
1234__1234__123__________
1234__1234__234___34_____
1234__1234__234___24_____
1234__1234__234___23_____
1234__1234__234___34____4
1234__1234__234___34____3
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1234__1234__234___24____2
1234__1234__234___23____3
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1234__1234__134___34_____
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1234__1234__134___13_____
1234__1234__134___34____4
1234__1234__134___34____3
1234__1234__134___14____4
1234__1234__134___14____1
1234__1234__134___13____3
1234__1234__134___13____1
1234__1234__124___24_____
1234__1234__124___14_____
1234__1234__124___12_____
1234__1234__124___24____4
1234__1234__124___24____2
1234__1234__124___14____4
1234__1234__124___14____1
1234__1234__124___12____2
1234__1234__124___12____1
1234__1234__123___23_____
1234__1234__123___13_____
1234__1234__123___12_____
1234__1234__123___23____3
1234__1234__123___23____2
1234__1234__123___13____3
1234__1234__123___13____1
1234__1234__123___12____2
1234__1234__123___12____1
========= ERROR SUMMARY: 0 errors
$
The answer given by Robert Crovella is correct at the 5th point, the mistake was in the using of init in every recursive call, but I want to clarify something that can be useful for other beginners with CUDA.
I used this variable because when I tried to launch a child kernel passing a local variable I always got the exception: Error: a pointer to local memory cannot be passed to a launch as an argument.
As I´m C# expert developer I´m not used to using pointers (Ref does the low-level-work for that) so I thought there was no way to do it in CUDA/c programming.
As Robert shows in its code it is possible copying the pointer with memalloc for using it as a referable argument.
Here is a kernel simplified as an example of deep recursion.
__device__ char init[6] = { "12345" };
__global__ void Recursive(int depth, const char* route) {
// up to depth 6
if (depth == 5) return;
//declaration for a referable argument (point 6)
char* newroute = (char*)malloc(6);
memcpy(newroute, route, 5);
int o = 0;
int newlen = 0;
for (int i = 0; i < (6 - depth); ++i)
{
if (i != threadIdx.x)
{
newroute[i - o] = route[i];
newlen++;
}
else
{
o = 1;
}
}
printf("%s\n", newroute);
Recursive <<<1, newlen>>>(depth + 1, newroute);
}
__global__ void RecursiveCount() {
Recursive <<<1, 5>>>(0, init);
}
I don't add the main call because I´m using ManagedCUDA for C# but as Robert says it can be figured-out how the call RecursiveCount is.
About ending arrays of char with /0 ... sorry but I don't know exactly what is the benefit; this code works fine without them.

Checksum calculation issue for ICMPv6 using Asio Boost

I have used the ICMP example provided in the ASIO documentation to create a simple ping utility. However, the example covers IPv4 only and I have a hard time to make it work with IPv6.
Upgrading the ICMP header class to support IPv6 requires a minor change - the only difference between ICMP and ICMPv6 header is the different enumeration of ICMP types. However, I have a problem computing the checksum that needs to be incorporated in the ICMPv6 header.
For IPv4 the checksum is based on the ICMP header and payload. However, for IPv6 the checksum should include the IPv6 pseudo-header before the ICMPv6 header and payload. The ICMPv6 checksum function needs to know the source and destination address that will be in the IPv6 header. However, we have no control over what goes into the IPv6 header. How can this be done in Asio-Boost?
For reference please find below the function for IPv4 checksum calculation.
void compute_checksum(icmp_header& header, Iterator body_begin, Iterator body_end)
{
unsigned int sum = (header.type() << 8) + header.code()
+ header.identifier() + header.sequence_number();
Iterator body_iter = body_begin;
while (body_iter != body_end)
{
sum += (static_cast<unsigned char>(*body_iter++) << 8);
if (body_iter != body_end)
sum += static_cast<unsigned char>(*body_iter++);
}
sum = (sum >> 16) + (sum & 0xFFFF);
sum += (sum >> 16);
header.checksum(static_cast<unsigned short>(~sum));
}
[EDIT]
What are the consequences if the checksum is not calculated correctly? Will the target host send echo reply if the echo request has invalid checksum?
If the checksum is incorrect, a typical IPv6 implementation will drop the packet. So, it is a serious issue.
If you insist on crafting the packet yourself, you'll have to do it
completely. This incldues finding the source IP address, to put it in
the pseudo-header before computing the checksum. Here is how I do it
in C, by calling connect() for my intended destination address
(even when I use UDP, so it should work for ICMP):
/* Get the source IP addresse chosen by the system (for verbose display, and
* for checksumming) */
if (connect(sd, destination->ai_addr, destination->ai_addrlen) < 0) {
fprintf(stderr, "Cannot connect the socket: %s\n", strerror(errno));
abort();
}
source = malloc(sizeof(struct addrinfo));
source->ai_addr = malloc(sizeof(struct sockaddr_storage));
source_len = sizeof(struct sockaddr_storage);
if (getsockname(sd, source->ai_addr, &source_len) < 0) {
fprintf(stderr, "Cannot getsockname: %s\n", strerror(errno));
abort();
}
then, later:
sockaddr6 = (struct sockaddr_in6 *) source->ai_addr;
op6.ip.ip6_src = sockaddr6->sin6_addr;
and:
op6.udp.check =
checksum6(op6.ip, op6.udp, (u_int8_t *) & message, messagesize);

How to make a pass that can read LLVM IR and parse it

I had read this page , http://llvm.org/docs/WritingAnLLVMPass.html
And i can do the example of the Hello.so completely.
Now i just want to make a .so file that can be called by opt and read my IR file name as input argument. And after i commit it , it will output the name of the file.
I had tried several methods before , but i still don't know how to do it....
I hope i can do it like this.
opt -load ../Debug+Asserts/lib/xxxx.so -flag < llvm.ll > /dev/null
when i press ENTER , it will output the name of the file -> "llvm.ll"
Can anyone help me write this simple program , i am going to optimize the llvm IR as my semester project , and now i stuck here ... help me , thanks ~
Can you tell me the code in detail , this doesn't work for me
using namespace llvm;
namespace {
struct Hello : public ModulePass {
static char ID;
Hello() : ModulePass(ID) {}
virtual bool runOnModule(Module &M) {
dbgs() << M.getModuleIdentifier() << "\n";
return false;
}
};
}
char Hello::ID = 0;
static RegisterPass<Hello> X("hello", "Hello World Pass", false, false);
~
Your question could really be simplified to "how can I access the name of the current .ll file from within an LLVM pass". You don't need to "parse LLVM IR" or anything like that - when an LLVM pass is being ran it is already way past the parsing phase.
In any case, I'm not aware of any surefire way to get the filename from an LLVM module, but you can encode that information when you prepare the .ll file. For example, set the module id to be the filename via ; ModuleID = 'llvm.ll', then retrieve it by writing a module pass and invoking getModuleIdentifier to get the string. Then you could just print it out, e.g.
bool runOnModule(Module& M) {
dbgs() << M.getModuleIdentifier() << "\n";
return false;
}
Alternatively, use metadata.

Linux splice() returning EINVAL ("Invalid argument")

I'm trying to experiment with using splice (man 2 splice) to copy data from a UDP socket directly to a file. Unfortunately the first call to splice() returns EINVAL.
The man page states:
EINVAL Target file system doesn't support splicing; target file is opened in
append mode; neither of the descriptors refers to a pipe; or offset
given for nonseekable device.
However, I believe none of those conditions apply. I'm using Fedora 15 (kernel 2.6.40-4) so I believe splice() is supported on all filesystems. The target file should be irrelevant in the first call to splice, but for completeness I'm opening it via open(path, O_CREAT | O_WRONLY | O_TRUNC, S_IRUSR | S_IWUSR). Both calls use a pipe and neither call uses an offset besides NULL.
Here's my sample code:
int sz = splice(sock_fd, 0, mPipeFds[1], 0, 8192, SPLICE_F_MORE);
if (-1 == sz)
{
int err = errno;
LOG4CXX_ERROR(spLogger, "splice from: " << strerror(err));
return 0;
}
sz = splice(mPipeFds[0], 0, file_fd, 0, sz, SPLICE_F_MORE);
if (-1 == sz)
{
int err = errno;
LOG4CXX_ERROR(spLogger, "splice to: " << strerror(err));
}
return 0;
sock_fd is initialized by the following psuedocode:
int sock_fd = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
setsockopt(sock_fd, SOL_SOCKET, SO_REUSEADDR, &one, sizeof(one));
fcntl(sock_fd, F_SETFL, flags | O_NONBLOCK);
bind(sock_fd, ...);
Possibly related is that this code snippet is running inside a libevent loop. libevent is using epoll() to determine if the UDP socket is hot.
Found my answer. tl;dr - UDP isn't supported on the inbound side.
After enough Googling I stumbled upon a forum discussion and some test code which prints out a table of in/out fd types and their support:
$ ./a.out
in\out pipe reg chr unix tcp udp
pipe yes yes yes yes yes yes
reg yes no no no no no
chr yes no no no no no
unix no no no no no no
tcp yes no no no no no
udp no no no no no no
Yeah, it is definitely not supported for reading from a UDP socket, even in the latest kernels. References to the kernel source follow.
splice invokes do_splice in the kernel, which calls do_splice_to, which calls the splice_read member in the file_operations structure for the file.
For sockets, that structure is defined as socket_file_ops in net/socket.c, which initializes the splice_read field to sock_splice_read.
That function, in turn, contains this line of code:
if (unlikely(!sock->ops->splice_read))
return -EINVAL;
The ops field of the socket is a struct proto_ops. For an IPv4 UDP socket, it is initialized to inet_dgram_ops in net/ipv4/af_inet.c. Finally, that structure does not explicitly initialize the splice_read field of struct proto_ops; i.e., it initializes it to zero.
So sock_splice_read returns -EINVAL, and that propagates up.

How do I get user input without using scanf in a console app?

I'm trying to allow users to simply hit Enter without typing anything, and use this to mean accepting a default value. scanf isn't doing what I want and the app still 'blocks': the next line of code doesn't run.
The only way is to actually type something THEN press Enter.
I tried using NSFileHandle and fileHandleWithStandardInput; however, it seems that the user is now forced to hit Ctrl-D to indicate EOF.
Someone suggested using fgets, but I cannot work out what to pass as 3rd parameter (of FILE* type). Tried stdin but it doesn't 'block'.
How do I accept input from a user, using Objective-C, and at the same time allow the user to simply hit Enter without being forced to type anything? How do I read a single line, even if that line is blank?
Assuming the code doesn't block and the next line runs immediately (as you seemed to indicate early in the question and in a comment), you have a common problem when mixing non-line-based and line-based input.
What happens is you have a newline left in the buffer, and fgets sees that, reads it, and returns, instead of doing what you really want: ignoring it, and then reading a line.
The solution is to simply do the ignoring part yourself, and then call fgets:
#include <stdio.h>
#include <string.h>
FILE* ignoreline(FILE* stream) {
for (int c; (c = fgetc(stream)) != EOF;) {
if (c == '\n') break;
}
return stream;
}
void example_use() {
char buf[1000];
ignoreline(stdin);
fgets(buf, sizeof buf, stdin);
// or, since it returns the stream, can be more compact:
fgets(buf, sizeof buf, ignoreline(stdin));
}
int main() { // error handling omitted
int n;
printf("Enter a number: ");
scanf("%d", &n);
char buf[1000];
printf("Enter a line: ");
ignoreline(stdin); // comment this line and compare the difference
fgets(buf, sizeof buf, stdin);
*strchr(buf, '\n') = '\0';
printf("You entered '%s'.\n", buf);
return 0;
}
Note that it is also common and encouraged to "pair" the ignoreline with the scanf (or other non-line-based input) to turn that into line-based input. You may want to modify it, in that case, so you can tell the difference between input of "42 abc" and "42" (in the "Enter a number" case). Some people just use fgets everywhere, then parse that line with sscanf, and while that works, it's not necessary.
I use getch(); in library conio.h
simply the program waits for any key to be pressed
If you're using Windows, you can use the ReadConsoleInput function (see MSDN for more on this) :
INPUT_RECORD keyin;
DWORD r;
while (ReadConsoleInput(GetStdHandle(STD_INPUT_HANDLE),&keyin,1,&r)) {
if (keyin.EventType!=KEY_EVENT) continue;
if (keyin.Event.KeyEvent.wVirtualKeyCode==VK_SPACE) break; ///use these VK codes to get any key's input
if (keyin.Event.KeyEvent.wVirtualKeyCode==VK_F1)
{
printf("You pressed F1\n");
}
if (keyin.Event.KeyEvent.wVirtualKeyCode==VK_F2)
{
printf("You pressed F2\n",);
}
}//end while loop
You don't need to hit enter after each key then.This works like a dream for me...
use getchar() to take input without using scanf function...