I constructed a pandas dataframe of results. This data frame acts as a table. There are MultiIndexed columns and each row represents a name, ie index=['name1','name2',...] when creating the DataFrame. I would like to display this table and save it as a png (or any graphic format really). At the moment, the closest I can get is converting it to html, but I would like a png. It looks like similar questions have been asked such as How to save the Pandas dataframe/series data as a figure?
However, the marked solution converts the dataframe into a line plot (not a table) and the other solution relies on PySide which I would like to stay away simply because I cannot pip install it on linux. I would like this code to be easily portable. I really was expecting table creation to png to be easy with python. All help is appreciated.
Pandas allows you to plot tables using matplotlib (details here).
Usually this plots the table directly onto a plot (with axes and everything) which is not what you want. However, these can be removed first:
import matplotlib.pyplot as plt
import pandas as pd
from pandas.table.plotting import table # EDIT: see deprecation warnings below
ax = plt.subplot(111, frame_on=False) # no visible frame
ax.xaxis.set_visible(False) # hide the x axis
ax.yaxis.set_visible(False) # hide the y axis
table(ax, df) # where df is your data frame
plt.savefig('mytable.png')
The output might not be the prettiest but you can find additional arguments for the table() function here.
Also thanks to this post for info on how to remove axes in matplotlib.
EDIT:
Here is a (admittedly quite hacky) way of simulating multi-indexes when plotting using the method above. If you have a multi-index data frame called df that looks like:
first second
bar one 1.991802
two 0.403415
baz one -1.024986
two -0.522366
foo one 0.350297
two -0.444106
qux one -0.472536
two 0.999393
dtype: float64
First reset the indexes so they become normal columns
df = df.reset_index()
df
first second 0
0 bar one 1.991802
1 bar two 0.403415
2 baz one -1.024986
3 baz two -0.522366
4 foo one 0.350297
5 foo two -0.444106
6 qux one -0.472536
7 qux two 0.999393
Remove all duplicates from the higher order multi-index columns by setting them to an empty string (in my example I only have duplicate indexes in "first"):
df.ix[df.duplicated('first') , 'first'] = '' # see deprecation warnings below
df
first second 0
0 bar one 1.991802
1 two 0.403415
2 baz one -1.024986
3 two -0.522366
4 foo one 0.350297
5 two -0.444106
6 qux one -0.472536
7 two 0.999393
Change the column names over your "indexes" to the empty string
new_cols = df.columns.values
new_cols[:2] = '','' # since my index columns are the two left-most on the table
df.columns = new_cols
Now call the table function but set all the row labels in the table to the empty string (this makes sure the actual indexes of your plot are not displayed):
table(ax, df, rowLabels=['']*df.shape[0], loc='center')
et voila:
Your not-so-pretty but totally functional multi-indexed table.
EDIT: DEPRECATION WARNINGS
As pointed out in the comments, the import statement for table:
from pandas.tools.plotting import table
is now deprecated in newer versions of pandas in favour of:
from pandas.plotting import table
EDIT: DEPRECATION WARNINGS 2
The ix indexer has now been fully deprecated so we should use the loc indexer instead. Replace:
df.ix[df.duplicated('first') , 'first'] = ''
with
df.loc[df.duplicated('first') , 'first'] = ''
There is actually a python library called dataframe_image
Just do a
pip install dataframe_image
Do the imports
import pandas as pd
import numpy as np
import dataframe_image as dfi
df = pd.DataFrame(np.random.randn(6, 6), columns=list('ABCDEF'))
and style your table if you want by:
df_styled = df.style.background_gradient() #adding a gradient based on values in cell
and finally:
dfi.export(df_styled,"mytable.png")
The best solution to your problem is probably to first export your dataframe to HTML and then convert it using an HTML-to-image tool.
The final appearance could be tweaked via CSS.
Popular options for HTML-to-image rendering include:
WeasyPrint
wkhtmltopdf/wkhtmltoimage
Let us assume we have a dataframe named df.
We can generate one with the following code:
import string
import numpy as np
import pandas as pd
np.random.seed(0) # just to get reproducible results from `np.random`
rows, cols = 5, 10
labels = list(string.ascii_uppercase[:cols])
df = pd.DataFrame(np.random.randint(0, 100, size=(5, 10)), columns=labels)
print(df)
# A B C D E F G H I J
# 0 44 47 64 67 67 9 83 21 36 87
# 1 70 88 88 12 58 65 39 87 46 88
# 2 81 37 25 77 72 9 20 80 69 79
# 3 47 64 82 99 88 49 29 19 19 14
# 4 39 32 65 9 57 32 31 74 23 35
Using WeasyPrint
This approach uses a pip-installable package, which will allow you to do everything using the Python ecosystem.
One shortcoming of weasyprint is that it does not seem to provide a way of adapting the image size to its content.
Anyway, removing some background from an image is relatively easy in Python / PIL, and it is implemented in the trim() function below (adapted from here).
One also would need to make sure that the image will be large enough, and this can be done with CSS's #page size property.
The code follows:
import weasyprint as wsp
import PIL as pil
def trim(source_filepath, target_filepath=None, background=None):
if not target_filepath:
target_filepath = source_filepath
img = pil.Image.open(source_filepath)
if background is None:
background = img.getpixel((0, 0))
border = pil.Image.new(img.mode, img.size, background)
diff = pil.ImageChops.difference(img, border)
bbox = diff.getbbox()
img = img.crop(bbox) if bbox else img
img.save(target_filepath)
img_filepath = 'table1.png'
css = wsp.CSS(string='''
#page { size: 2048px 2048px; padding: 0px; margin: 0px; }
table, td, tr, th { border: 1px solid black; }
td, th { padding: 4px 8px; }
''')
html = wsp.HTML(string=df.to_html())
html.write_png(img_filepath, stylesheets=[css])
trim(img_filepath)
Using wkhtmltopdf/wkhtmltoimage
This approach uses an external open source tool and this needs to be installed prior to the generation of the image.
There is also a Python package, pdfkit, that serves as a front-end to it (it does not waive you from installing the core software yourself), but I will not use it.
wkhtmltoimage can be simply called using subprocess (or any other similar means of running an external program in Python).
One would also need to output to disk the HTML file.
The code follows:
import subprocess
df.to_html('table2.html')
subprocess.call(
'wkhtmltoimage -f png --width 0 table2.html table2.png', shell=True)
and its aspect could be further tweaked with CSS similarly to the other approach.
Although I am not sure if this is the result you expect, you can save your DataFrame in png by plotting the DataFrame with Seaborn Heatmap with annotations on, like this:
http://stanford.edu/~mwaskom/software/seaborn/generated/seaborn.heatmap.html#seaborn.heatmap
It works right away with a Pandas Dataframe. You can look at this example: Efficiently ploting a table in csv format using Python
You might want to change the colormap so it displays a white background only.
Hope this helps.
Edit:
Here is a snippet that does this:
import matplotlib
import seaborn as sns
def save_df_as_image(df, path):
# Set background to white
norm = matplotlib.colors.Normalize(-1,1)
colors = [[norm(-1.0), "white"],
[norm( 1.0), "white"]]
cmap = matplotlib.colors.LinearSegmentedColormap.from_list("", colors)
# Make plot
plot = sns.heatmap(df, annot=True, cmap=cmap, cbar=False)
fig = plot.get_figure()
fig.savefig(path)
The solution of #bunji works for me, but default options don't always give a good result.
I added some useful parameter to tweak the appearance of the table.
import pandas as pd
import matplotlib.pyplot as plt
from pandas.plotting import table
import numpy as np
dates = pd.date_range('20130101',periods=6)
df = pd.DataFrame(np.random.randn(6,4),index=dates,columns=list('ABCD'))
df.index = [item.strftime('%Y-%m-%d') for item in df.index] # Format date
fig, ax = plt.subplots(figsize=(12, 2)) # set size frame
ax.xaxis.set_visible(False) # hide the x axis
ax.yaxis.set_visible(False) # hide the y axis
ax.set_frame_on(False) # no visible frame, uncomment if size is ok
tabla = table(ax, df, loc='upper right', colWidths=[0.17]*len(df.columns)) # where df is your data frame
tabla.auto_set_font_size(False) # Activate set fontsize manually
tabla.set_fontsize(12) # if ++fontsize is necessary ++colWidths
tabla.scale(1.2, 1.2) # change size table
plt.savefig('table.png', transparent=True)
The result:
I had the same requirement for a project I am doing. But none of the answers came elegant to my requirement. Here is something which finally helped me, and might be useful for this case:
from bokeh.io import export_png, export_svgs
from bokeh.models import ColumnDataSource, DataTable, TableColumn
def save_df_as_image(df, path):
source = ColumnDataSource(df)
df_columns = [df.index.name]
df_columns.extend(df.columns.values)
columns_for_table=[]
for column in df_columns:
columns_for_table.append(TableColumn(field=column, title=column))
data_table = DataTable(source=source, columns=columns_for_table,height_policy="auto",width_policy="auto",index_position=None)
export_png(data_table, filename = path)
There is a Python library called df2img available at https://pypi.org/project/df2img/ (disclaimer: I'm the author). It's a wrapper/convenience function using plotly as backend.
You can find the documentation at https://df2img.dev.
import pandas as pd
import df2img
df = pd.DataFrame(
data=dict(
float_col=[1.4, float("NaN"), 250, 24.65],
str_col=("string1", "string2", float("NaN"), "string4"),
),
index=["row1", "row2", "row3", "row4"],
)
Saving a pd.DataFrame as a .png-file can be done fairly quickly. You can apply formatting, such as background colors or alternating the row colors for better readability.
fig = df2img.plot_dataframe(
df,
title=dict(
font_color="darkred",
font_family="Times New Roman",
font_size=16,
text="This is a title",
),
tbl_header=dict(
align="right",
fill_color="blue",
font_color="white",
font_size=10,
line_color="darkslategray",
),
tbl_cells=dict(
align="right",
line_color="darkslategray",
),
row_fill_color=("#ffffff", "#d7d8d6"),
fig_size=(300, 160),
)
df2img.save_dataframe(fig=fig, filename="plot.png")
If you're okay with the formatting as it appears when you call the DataFrame in your coding environment, then the absolute easiest way is to just use print screen and crop the image using basic image editing software.
Here's how it turned out for me using Jupyter Notebook, and Pinta Image Editor (Ubuntu freeware).
As jcdoming suggested, use Seaborn heatmap():
import seaborn as sns
import matplotlib.pyplot as plt
fig = plt.figure(facecolor='w', edgecolor='k')
sns.heatmap(df.head(), annot=True, cmap='viridis', cbar=False)
plt.savefig('DataFrame.png')
The easiest and fastest way to convert a Pandas dataframe into a png image using Anaconda Spyder IDE- just double-click on the dataframe in variable explorer, and the IDE table will appear, nicely packaged with automatic formatting and color scheme. Just use a snipping tool to capture the table for use in your reports, saved as a png:
This saves me lots of time, and is still elegant and professional.
The following would need extensive customisation to format the table correctly, but the bones of it works:
import numpy as np
from PIL import Image, ImageDraw, ImageFont
import pandas as pd
df = pd.DataFrame({ 'A' : 1.,
'B' : pd.Series(1,index=list(range(4)),dtype='float32'),
'C' : np.array([3] * 4,dtype='int32'),
'D' : pd.Categorical(["test","train","test","train"]),
'E' : 'foo' })
class DrawTable():
def __init__(self,_df):
self.rows,self.cols = _df.shape
img_size = (300,200)
self.border = 50
self.bg_col = (255,255,255)
self.div_w = 1
self.div_col = (128,128,128)
self.head_w = 2
self.head_col = (0,0,0)
self.image = Image.new("RGBA", img_size,self.bg_col)
self.draw = ImageDraw.Draw(self.image)
self.draw_grid()
self.populate(_df)
self.image.show()
def draw_grid(self):
width,height = self.image.size
row_step = (height-self.border*2)/(self.rows)
col_step = (width-self.border*2)/(self.cols)
for row in range(1,self.rows+1):
self.draw.line((self.border-row_step//2,self.border+row_step*row,width-self.border,self.border+row_step*row),fill=self.div_col,width=self.div_w)
for col in range(1,self.cols+1):
self.draw.line((self.border+col_step*col,self.border-col_step//2,self.border+col_step*col,height-self.border),fill=self.div_col,width=self.div_w)
self.draw.line((self.border-row_step//2,self.border,width-self.border,self.border),fill=self.head_col,width=self.head_w)
self.draw.line((self.border,self.border-col_step//2,self.border,height-self.border),fill=self.head_col,width=self.head_w)
self.row_step = row_step
self.col_step = col_step
def populate(self,_df2):
font = ImageFont.load_default().font
for row in range(self.rows):
print(_df2.iloc[row,0])
self.draw.text((self.border-self.row_step//2,self.border+self.row_step*row),str(_df2.index[row]),font=font,fill=(0,0,128))
for col in range(self.cols):
text = str(_df2.iloc[row,col])
text_w, text_h = font.getsize(text)
x_pos = self.border+self.col_step*(col+1)-text_w
y_pos = self.border+self.row_step*row
self.draw.text((x_pos,y_pos),text,font=font,fill=(0,0,128))
for col in range(self.cols):
text = str(_df2.columns[col])
text_w, text_h = font.getsize(text)
x_pos = self.border+self.col_step*(col+1)-text_w
y_pos = self.border - self.row_step//2
self.draw.text((x_pos,y_pos),text,font=font,fill=(0,0,128))
def save(self,filename):
try:
self.image.save(filename,mode='RGBA')
print(filename," Saved.")
except:
print("Error saving:",filename)
table1 = DrawTable(df)
table1.save('C:/Users/user/Pictures/table1.png')
The output looks like this:
People who use Plotly for data visualization:
You can easily convert the dataframe to go.Table.
You can save the dataframe with columns names.
You can format the dataframe through go.Table.
You can save the dataframe as pdf, jpg, or png with different scales and high resolution.
import plotly.express as px
df = px.data.medals_long()
fig = go.Figure(data=[
go.Table(
header=dict(values=list(df.columns),align='center'),
cells=dict(values=df.values.transpose(),
fill_color = [["white","lightgrey"]*df.shape[0]],
align='center'
)
)
])
fig.write_image('image.png',scale=6)
Note: the image is downloaded in the same directory where the current python file is running.
Output:
I really like the way Jupyter notebooks format the DataFrame and this library exports it in the same format:
import dataframe_image as dfi
dfi.export(df, "df.png")
There is also a dpi argument in case you want to increase the quality of the image. I'd recommend 300 for an ok quality, 600 for exelent, 1200 for perfect and more than that is probably too much.
import dataframe_image as dfi
dfi.export(df, "df.png", dpi = 600)
Related
This is my code:
import pandas as pd
import plotly.express as px
df={'x':[1,2,3,4,5],'y1':[1,2,3,4,5],'y2':[2,3,4,5,6],'y3':[3,4,5,6,7]}
df=pd.DataFrame(df)
fig = px.area(df, x="x", y=['y1','y2','y3'])
fig.show()
As you can see my Y data are maximum 7. Why the results in the figure shows wrong values?
Why the results in the figure shows wrong values?
plotly.express.area creates a stacked area plot, where each filled area corresponds to one column of the input data: https://plotly.com/python/filled-area-plots/
For example, at x = 5, the stacked area plot reaches y = 18 = 5 + 6 + 7.
To show each column's data series as-is, without stacking (i.e., starting from the y-coordinate of zero):
fig = px.line(df, x='x', y=['y1', 'y2', 'y3'])
Short answer:
Just add the following to your setup to obtain the desired behavior of px.area:
fig.update_traces(stackgroup = None, fill = 'tozeroy')
The details:
px.area produces a stacked area chart through the trace attribute stackgroup which by default is set to 'one'. To obtain what you're requesting here, you can update this attribute to None with:
fig.update_traces(stackgroup = None)
Plot 1 - Unstacked traces
As you can see, this will display the values in the way you're requesting, but that won't help you that much since the area fill colors are missing. By default, the fill attribute for the traces are set to tonexty. Other options are:
['none', 'tozeroy', 'tozerox', 'tonexty', 'tonextx', 'toself', 'tonext']
And if you set fill to tozeroy with fig.update_traces(fill = 'tozeroy') you'll get what you're looking for:
Plot 2 - Almost there, but what's up with the colors?
This is going to look a bit strange for your particular dataset since the resulting areas will cover each other all the way and because the area colors are opaque. But you can see by the colors of the legend that the color setup is still the same as in your plot. You can verify this by using the following dataset:
df={'x':[1,2,3,4,5],'y1':[1,2,3,4,5],'y2':[2,3,4,5,2],'y3':[3,4,5,6,1]}
Plot 3 - Bingo!
Complete code:
import pandas as pd
import plotly.express as px
# df={'x':[1,2,3,4,5],'y1':[1,2,3,4,5],'y2':[2,3,4,5,6],'y3':[3,4,5,6,7]}
df={'x':[1,2,3,4,5],'y1':[1,2,3,4,5],'y2':[2,3,4,5,2],'y3':[3,4,5,6,1]}
df=pd.DataFrame(df)
fig = px.area(df, x="x", y=['y1','y2','y3'])
#fig.update_traces(stackgroup = None)
#fig.update_traces(fill = 'tozeroy')
fig.update_traces(stackgroup = None, fill = 'tozeroy')
fig.show()
The plot below shows the correlation for one column. The problem is that the numbers are not readable, because there are many columns in it.
How is it possible to show only 5 or 6 most important columns and not all of them with very low importance?
plt.figure(figsize=(20,3))
sns.heatmap(df.corr()[['price']].sort_values('price', ascending=False).iloc[1:].T, annot=True,
cmap='Spectral_r', vmax=0.9, vmin=-0.31)
You can limit the cells shown via .iloc[1:7]. If you also want to show the highest negative values, you could create a second plot with .iloc[-6:]. To have both together, you could use numpy's slicing function and write .iloc[np.r_[1:4, -3:0]].
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
df = pd.DataFrame(np.random.rand(7, 27), columns=['price'] + [*'abcdefghijklmnopqrstuvwxyz'])
plt.figure(figsize=(20, 3))
sns.heatmap(df.corr()[['price']].sort_values('price', ascending=False).iloc[1:7].T,
annot=True, annot_kws={'rotation':90, 'size': 20},
cmap='Spectral_r', vmax=0.9, vmin=-0.31)
plt.show()
annot can also be a list of labels. Using this, you can define a string matrix that you use to display the desired numbers and set the others to an empty string.
import matplotlib.pyplot as plt
import numpy as np; np.random.seed(0)
import seaborn as sns; sns.set_theme()
import pandas as pd
from string import ascii_letters
# generate random data
rs = np.random.RandomState(33)
df = pd.DataFrame(data=rs.normal(size=(100, 26)),
columns=list(ascii_letters[26:]))
importance_index = 5 # until which idx to hide values
data = df.corr()[['A']].sort_values('A', ascending=False).iloc[1:].T
labels = data.astype(str) # make a str-copy
labels.iloc[0,:importance_index] = ' ' # mask columns that you want to hide
sns.heatmap(data, annot=labels, cmap='Spectral_r', vmax=0.9, vmin=-0.31, fmt='', annot_kws={'rotation':90})
plt.show()
The output on some random data:
This works but it has its limits, particulary with setting fmt='' (can't use it to conveniently format decimals anymore, need to do it manually now). I would also question whether your approach is even the best one to take here. I think consistency in plots is quite important. I would rather evaluate if we can't rotate the heatmap labels (I've included it above) or leave them out completely since it is technically redundant due to the color-coding. Alternatively, you could only plot the cells with the "important" values.
As shown in the figure,
How can I plot a line that have different colors based on a specific value of x ?
The simplest solution here may be to slice your data at the corresponding index of x_lim found by np.where :
from matplotlib import pyplot as plt
import numpy as np
x = np.linspace(0,2*np.pi,100)
y = np.cos(x)*np.exp(-x/2)
# specify your x limitation
x_lim = np.pi
# find the first corresponding idx where the condition x>=x_lim hold
x_lim_idx = np.where(x>=x_lim)[0][0]
# plot sliced data
plt.plot(x[:x_lim_idx],y[:x_lim_idx],'r')
plt.plot(x[x_lim_idx:],y[x_lim_idx:],'b')
which gives for x_lim = np.pi :
And if the remaining gap between the lines bothers you, for small x discretization for instance, you can still close it by making the two slices overlap.
I have a Series that I would like to plot as a bar chart: pd.Series([-4,2, 3,3, 4,5,9,20]).value_counts()
Since I have many bars I only want to display some (equidistant) ticks.
However, unless I actively work against it, pyplot will print the wrong labels. E.g. if I leave out set_xticklabels in the code below I get
where every element from the index is taken and just displayed with the specified distance.
This code does what I want:
import numpy as np
import pandas as pd
import matplotlib
import matplotlib.pyplot as plt
s = pd.Series([-4,2, 3,3, 4,5,9,20]).value_counts().sort_index()
mi,ma = min(s.index), max(s.index)
s = s.reindex(range(mi,ma+1,1), fill_value=0)
distance = 10
a = s.plot(kind='bar')
condition = lambda t: int(t[1].get_text()) % 10 == 0
ticks_,labels_=zip(*filter(condition, zip(a.get_xticks(), a.get_xticklabels())))
a.set_xticks(ticks_)
a.set_xticklabels(labels_)
plt.show()
But I still feel like I'm being unnecessarily clever here. Am I missing a function? Is this the best way of doing that?
Consider not using a pandas bar plot in case you intend to plot numeric values; that is because pandas bar plots are categorical in nature.
If instead using a matplotlib bar plot, which is numeric in nature, there is no need to tinker with any ticks at all.
s = pd.Series([-4,2, 3,3, 4,5,9,20]).value_counts().sort_index()
plt.bar(s.index, s)
I think you overcomplicated it. You can simply use the following. You just need to find the relationship between the ticks and the ticklabels.
a = s.plot(kind='bar')
xticks = np.arange(0, max(s)*10+1, 10)
plt.xticks(xticks + abs(mi), xticks)
I'm trying to do simple plotting using the built-in pandas.DataFrame.plot function (I want to avoid the full-blown pyplt figure/axes object setup approach). However, I get strange results when I don't specify the x-axes range parameter (xlim). You would think that plot would pick defaults based on the max and min of the data.
(I'm using inline plotting in a Jupyter notebook with Python 2.7)
Setup code
import numpy as np
import pandas as pd
%matplotlib inline
n = 366
x = 10.0*np.random.randn(n)
time_series = pd.date_range("2016-01-01", "2016-12-31")
df = pd.DataFrame(data=x, index=time_series, columns=['X'])
df['y'] = 100 + 2.5*x + 5.0*np.random.randn(n)
df.describe()
Here is what the data looks like:
Desired code:
df.plot('X', 'y', style='.')
Here is what I get from above code:
Here is what I expect to get:
df.plot('X', 'y', xlim=(-35, 35), style='.')
Each time I run the code I get an equally-odd choice of default axis range.