I am trying to get the frequency of unique ID values for each month of the last year. However, I don't get the outcome.. including the error message "SELECT list expression references column user_id which is neither grouped nor aggregated".
How can I get the count of unique IDs in each month and them group them by month?
What I tried:
SELECT
user_id,
EXTRACT(MONTH FROM date) as month
FROM
TABLE
WHERE
date >= '2020-09-01'
GROUP BY
month
I want something like this:
month
count of unique user_id
1
300
2
200
...
...
12
250
You would use GROUP BY and COUNT(DISTINCT):
SELECT EXTRACT(MONTH FROM date) as month, COUNT(DISTINCT user_id)
FROM TABLE
WHERE date >= '2020-09-01'
GROUP BY 1;
I would advise you to include the year in the query. In BigQuery, this is simplest using DATE_TRUNC():
SELECT DATE_TRUNC(date, MONTH) as month, COUNT(DISTINCT user_id)
FROM TABLE
WHERE date >= '2020-09-01'
GROUP BY 1;
Related
This is what my table looks like:
NOTE: Don't worry about the BMI field being empty in some rows. We assume that each row is a reading. I have omitted some columns for privacy reasons.
I want to get a count of the number of active customers per month. A customer is active if they have at least 18 readings in total (1 reading per day for 18 days in a given month). How do I write this SQL query? Assume the table name is 'cust'. I'm using SQL Server. Any help is appreciated.
Presumably a patient is a customer in your world. If so, you can use two levels of aggregation:
select yyyy, mm, count(*)
from (select year(createdat) as yyyy, month(createdat) as mm,
patient_id,
count(distinct convert(date, createdat)) as num_days
from t
group by year(createdat), month(createdat), patient_id
) ymp
where num_days >= 18
group by yyyy, mm;
You need to group by patient and the month, then group again by just the month
SELECT
mth,
COUNT(*) NumPatients
FROM (
SELECT
EOMONTH(c.createdat) mth
FROM cust c
GROUP BY EOMONTH(c.createdat), c.patient_id
HAVING COUNT(*) >= 18
-- for distinct days you could change it to:
-- HAVING COUNT(DISTINCT CAST(c.createdat AS date)) >= 18
) c
GROUP BY mth;
I have a table like this, I hope to count the number of ids by month. I used the following code but it does not work.
id date_time
1390880502018723840,2021-05-08
1390881127930372100,2021-05-08
1390881498270736386,2021-05-08
SELECT twitter.tweets.id
WHERE Month(twitter.tweets.date_time)=01 AND Year(twitter.tweets.date_time)=2021 ;
you have to use count() function and to_char to get year month part of date in one column:
SELECT count(witter.tweets.id)
WHERE to_char(twitter.tweets.date_time,'YYYY-MM')= '2021-01';
you can generalize it for all the month/year by using group by :
SELECT to_char(twitter.tweets.date_time,'YYYY-MM') , count(witter.tweets.id)
group by to_char(twitter.tweets.date_time,'YYYY-MM');
To get counts for all months since Jan 2021:
SELECT date_trunc('month', date_time), count(*)
FROM twitter.tweets
WHERE date_time >= '2021-01-01'
GROUP BY 1;
If id can be NULL (which should be disallowed for an id column), use the slightly more expensive count(id) instead.
Count of distinct IDs:
SELECT date_trunc('month', date_time), count(DISTINCT id)
FROM twitter.tweets
WHERE date_time >= '2021-01-01'
GROUP BY 1;
For only Jan 2021:
SELECT count(DISTINCT id)
FROM twitter.tweets
WHERE date_time >= '2021-01-01'
WHERE date_time < '2021-02-01';
There's a table with customerID, timestamp, activity columns and I found DAU(DailyActiveUsers) and MAU(MonthlyActiveUsers) from this table. Now I need to find DAU/MAU. The problem is I got DAU and MAU as two separate queries as they both need to be grouped by day and month respectively.
Also, DAU would be a table since it's grouped by day and would have 30 rows in the table. MAU is just a single number. How can I find DAU/MAU which is apparently a ratio?
My query for DAU
select date, count(distinct customerID) as dau
from table
where extract(month from timestamp) = 1 and extract(year from timestamp) = 2020
and activity = 'opened_the_app'
group by date
This gives me dau for all the 31 days in month of january.
Similarly i found MAU by grouping month which gives me a single value for the month of january.
How can I find the DAU/MAU ratio for january?
You can join them together:
select d.*, d.dau * 1.0 / m.mau
from (select date, count(distinct customerID) as dau
from table
where timestamp >= '2020-01-01' and
timestamp < '2020-02-01' and
activity = 'opened_the_app'
group by date
) d cross join
(select count(distinct customerID) as mau
from table
where timestamp >= '2020-01-01' and
timestamp < '2020-02-01' and
activity = 'opened_the_app'
) m
You can find it from the DAU table itself since the MAU will be the sum of DAU
select dau/sum(dau) as result from (
select date, count(distinct customerID) as dau
from table
where extract(month from timestamp) = 1 and extract(year from timestamp) = 2020
and activity = 'opened_the_app'
) dau_table
I have a table with 4 columns huge number of records. It has the following structure:
DATE_ENTERED EMP_NAME DATA ORIGINATED
01-JAN-20 A 545454 APPLE
I want to calculate no of records for every first day of every month in a year
is there any way can we fetch the data for every first day of month.
In oracle you can use TRUNC function on the date as follows:
SELECT TRUNC(DATE_ENTERED), COUNT(1) AS CNT
FROM YOUR_TABLE
WHERE TRUNC(DATE_ENTERED) = TRUNC(DATE_ENTERED, 'MON')
GROUP BY TRUNC(DATE_ENTERED, 'MON')
Please note that the TRUNC(DATE_ENTERED, 'MON') returns the first day of the month for DATE_ENTERED.
Cheers!!
SELECT Year, Month, COUNT(*)
FROM
(
SELECT
YEAR(DATE_ENTERED) Year
MONTH(DATE_ENTERED) Month
DAY(DATE_ENTERED) Day
FROM your_table
WHERE DAY(DATE_ENTERED) = 1
) A
GROUP BY Year, Month
Generally WHERE DAY(DATE_ENTERED) = 1 will get you the records only for dates at the start of each month. Thus using Year and Month function you can group them by in order to get a count for each year and each month
You mean something like
SELECT COUNT(*)
FROM Table
WHERE DAY(DATE_ENTERED) = 1 AND
YEAR(DATE_ENTERED) = Some_Year
GROUP BY DATE_ENTERED
You can also use DATE_ENTERED BETWEEN 'YYYY0101' and 'YYYY1231' (replace the YYYY with the year you want to retrieve data for) instead of YEAR(DATE_ENTERED) = Some_Year, if performance is an issue.
You can use something like this:
select * from your_table
where DAY(DATE_ENTERED) = 1
and DATE_ENTERED between '2020-01-01' and '2020-12-31'
for number of count use this:
select count(*) from your_table
where DAY(DATE_ENTERED)= 1
and DATE_ENTERED between '2020-01-01' and '2020-12-31'
UPDATE
select * from your_table where Extract(day FROM DATE_ENTERED) = 1 and DATE_ENTERED between '01-JAN-20 ' and '01-DEC-20 ';
this is how the data looks like:
For the list of records
select count(*) from your_table where Extract(day FROM DATE_ENTERED) = 1 and DATE_ENTERED between '01-JAN-20 ' and '01-DEC-20 ';
UPDATE-2
select EXTRACT(month from DATE_ENTERED) as Count,
to_char(to_date(DATE_ENTERED, 'DD-MM-YYYY'), 'Month') from your_table
where Extract(day FROM DATE_ENTERED) = 1 and DATE_ENTERED between '01-JAN-20
'and '01-DEC-20 ' group by EXTRACT(month from DATE_ENTERED),
to_char(to_date(DATE_ENTERED, 'DD-MM-YYYY'), 'Month');
Here is the output:
SELECT EVENT_DT - ((EVENT_DT -DATE'1900-01-07') MOD 7) AS dates,
CLSFD_USER_ID AS user_id,
COUNT(DISTINCT CLSFD_USER_ID) AS number_of_user_ids,
COUNT(DISTINCT CLSFD_CAS_AD_ID) AS number_of_ads,
SUM(IMPRSN_CNT) AS number_of_impressions
FROM clsfd_access_views.CLSFD_CAS_AD_HST
WHERE CLSFD_SITE_ID = 3001
AND datum >= '2017-01-01'
GROUP BY 1,2
I want to have the total number of unique users during each month of the year 2017. I tried:
GROUP BY EXTRACT(MONTH FROM datum), 2
But this returns an error. What would be the most efficient code to retrieve the total number of user ids, ads, and impressions, per month.
It doesn't make sense to me to be aggregating by users, since they are what you are trying to count. Try grouping by the month and year alone:
SELECT
EXTRACT(YEAR FROM EVENT_DT) || '-' || EXTRACT(MONTH FROM EVENT_DT) AS month,
COUNT(DISTINCT CLSFD_USER_ID) AS number_of_user_ids,
COUNT(DISTINCT CLSFD_CAS_AD_ID) AS number_of_ads,
SUM(IMPRSN_CNT) AS number_of_impressions
FROM clsfd_access_views.CLSFD_CAS_AD_HST
WHERE
CLSFD_SITE_ID = 3001 AND
datum >= '2017-01-01' AND datum < '2018-01-01'
GROUP BY
EXTRACT(YEAR FROM EVENT_DT) || '-' || EXTRACT(MONTH FROM EVENT_DT);
Note that I changed your restriction on datum to also exclude any year greater than 2017.
If you want this values to be included in current query, then you should use analytical functions. For example "total number of unique users during each month" would be something like:
select count(distinct user_id) over(partition by EXTRACT(MONTH FROM datum))
Be aware that those values will be repeated for each user.