I have table like this:
receipt
position
unit
booking time
1
1
1
08:00:00
1
2
1
08:00:05
1
3
1
08:00:11
1
4
1
08:00:18
1
5
1
08:00:21
1
6
5
08:00:25
1
1
1
08:00:30
1
2
1
08:00:33
1
3
1
08:00:37
1
4
1
08:00:40
1
5
1
08:00:49
2
1
1
08:01:55
2
2
1
08:01:58
2
3
1
08:02:04
3
1
1
08:02:20
3
2
5
08:02:24
3
1
1
08:02:30
3
2
1
08:02:35
I want to check for every receipt whether unit 5 exists or not. If unit 5 exists, I only want to select positions with a booking time after the entry with unit 5.
For the example above my result therefore should look like this:
receipt
position
unit
bookingtime
1
1
1
08:00:30
1
2
1
08:00:33
1
3
1
08:00:37
1
4
1
08:00:40
1
5
1
08:00:49
2
1
1
08:01:55
2
2
1
08:01:58
2
3
1
08:02:04
3
1
1
08:02:30
3
2
1
08:02:35
I have kind of a start, which delivers the right result if there was only one receipt:
Select * from test
where bookingtime> (case
when (select Max(bookingtime) from test where unit=5) is null
then (Select convert(time,'00:00:00'))
Else (select Max(bookingtime) from testdb where unit=5)
End)
What am I missing to let this code run through every single receipt separately so that I get the result I am looking for?
You can use a window function to get the time for unit 5:
select t.*
from (select t.*,
min(case when unit = 5 then bookingtime end) over (partition by receipt) as bookingtime_5
from t
) t
where bookingtime_5 is null or
bookingtime > bookingtime_5;
Related
I have a table that looks something like this:
id name status
2 a 1
2 a 2
2 a 3
2 a 2
2 a 1
3 b 2
3 b 1
3 b 2
3 b 1
and the resultant i want is:
id name total count count(status3) count(status2) count(status1)
2 a 5 1 2 2
3 b 4 0 2 2
please help me get this result somehow, i can just get id, name or one of them at a time, don't know how to put a clause to get this table at once.
Here's a simple solution using group by and case when.
select id
,count(*) as 'total count'
,count(case status when 3 then 1 end) as 'count(status1)'
,count(case status when 2 then 1 end) as 'count(status3)'
,count(case status when 1 then 1 end) as 'count(status2)'
from t
group by id
id
total count
count(status3)
count(status2)
count(status1)
2
5
1
2
2
3
4
0
2
2
Fiddle
Here's a way to solve it using pivot.
select *
from (select status,id, count(*) over (partition by id) as "total count" from t) tmp
pivot (count(status) for status in ([1],[2],[3])) pvt
d
total count
1
2
3
3
4
2
2
0
2
5
2
2
1
Fiddle
I have a table with Scenario,Product,AlgoKey,User Select,System Select columns, I have to select the algo key for each scenario, The first priority goes to user selected otherwise system selected.
I have Shared my Inout & output result below, could you please help me how to write query for this.
Scenario
Product
AlgoKey
User Select
SystemSelect
1
P101
1
0
1
1
P102
2
1
0
2
P101
1
0
1
2
P102
2
0
0
3
P101
1
1
1
3
P102
2
0
0
4
P101
1
0
0
4
P102
2
0
1
OutPut :
Scenario
AlgoKey
Columnselected
1
2
User
2
1
System
3
1
User
4
2
System
here is how you can do it
select scenario , AlgoKey, case when Userselect = 1 then 'User' else 'System' end Columnselected
from (
select *, ROW_NUMBER() over (partition by scenario,productkey order by userselect desc, systemselect desc) rn
from tableName
) t
where rn = 1
1.I have data as follows (just a subset - there are 20K records)
sku,id
1 1
1 2
1 2
1 2
1 3
1 4
1 1
1 2
1 3
1 4
1 4
1 4
1 5
1 6
1 6
2 1
2 1
2 2
2 3
2 3
2 3
2 4
2 4
2 5
2 5
2 6
2 7
2 1
2 2
2 3
The above values translate to
1 = 4 records
1 = 6 records
2 = 7 records
2 = 3 records
The MAX would just give me 6 for one and 7 for 2
The actual total is 1 = 10 and 2 = 10
How do I sum up to get the correct values?
You can use order by and some way of limiting rows. In standard SQL this would be:
select t.*
from t
order by id desc
fetch first 2 rows only;
However, some databases might use limit or select top or some other method.
No handling of ties here. Thousands of other questions handle this topic.
select sku, id
from (
select *, row_number() over (order by id desc) rn
from T
) t
where rn <= 2
order by rn desc;
I have 4 columns a,b,c,d.
Some of my rows have the same values for all columns, is there any option to use row_number to insert same row number for those rows and continue counting if at least one of the values is different from values in the previous row
Example:
a b c d
1 1 1 1
1 1 1 1
1 1 1 2
1 1 1 2
1 1 1 3
1 1 1 3
1 1 2 4
I need it to look like: r=row_number
r a b c d
1 1 1 1 1
1 1 1 1 1
2 1 1 1 2
2 1 1 1 2
3 1 1 1 3
3 1 1 1 3
4 1 1 2 4
P.S. How to write here something like a table?
declare #t table(a int, b int, c int, d int)
insert #t values(1,1,1,1),(1,1,1,1),(1,1,1,2),
(1,1,1,2),(1,1,1,3),(1,1,1,3),(1,1,1,4)
select dense_rank() over(order by a,b,c,d) r, a,b,c,d from #t
Result:
r a b c d
1 1 1 1 1
1 1 1 1 1
2 1 1 1 2
2 1 1 1 2
3 1 1 1 3
3 1 1 1 3
4 1 1 1 4
I've got two tables.
I'm trying to calculating the SUM quantity of tbl1
tbl1.xid is the primary, while tbl2.xid is the foreign
tbl1
xid pub quantity
1 1 10
2 1 2
3 0 1
4 1 5
tbl2
id ttype fno xid qnty
1 A 0 1 0
2 A 1 1 3
3 B 1 1 4
4 A 1 2 1
5 A 1 3 2
6 A 1 4 3
7 A 1 4 1
8 A 0 1 0
We are calculating the sum of tbl1's quantity
1) Whos tbl1.pub is 1
Thus tbl1.xid 3 is removed form the list, for it's pub is 0
Results
tbl1
xid pub quantity
1 1 10
2 1 2
4 1 5
2) AND Who's tbl1 has at least one tbl2.xid who's tbl2.ttype is 'A' and who's tbl2.fno is '0'
Thus tbl1.xid 2 & 4 are removed form the list, because none of them have at least one tbl2.xid who's fno is '0' and who's tbl2.ttype is 'A'
Results
parent_tbl1
xid pub quantity
1 1 10
The final results should be 10
SELECT SUM(quantity) AS Total
FROM tbl1
WHERE pub=1
AND EXISTS
(SELECT *
FROM tbl2
WHERE tbl2.ttype = 'A'
AND tbl2.fno = 0
AND tbl1.xid = tbl2.xid
)