Running into some issues figuring out how to add in an extra column that will give me the percentage of the total of the aggregate of the count function. The query I have looks like this:
Select
count(*) AS num_rides,
member_casual
FROM `2020_bikeshare_data`
GROUP BY member_casual
ORDER BY num_rides DESC
And returns me this result:
num_rides
member_casual
2134988
member
1341217
casual
And what I'd like to do is add a 3rd column that lists the percent of the total each membership makes up
num_rides
member_casual
perc_tot
2134988
member
61.4%
1341217
casual
38.6
thoughts?
You window functions:
SELECT member_casual,
COUNT(*) AS num_rides,
COUNT(*) * 1.0 / SUM(COUNT(*)) OVER ()
FROM `2020_bikeshare_data`
GROUP BY member_casual
ORDER BY num_rides DESC;
No subquery is needed.
Consider below approach
select distinct member_casual,
count(num_rides) over type as num_rides,
round(count(num_rides) over type * 100.0 / count(num_rides) over(), 2) as perc_tot
from `2020_bikeshare_data`
window type as (partition by member_casual)
# order by num_rides desc
if applied to sample data in your question - output is
The simplest way is use a subquery as part of the column expression to calculate your percentage:
select
count(1) as num_rides,
member_casual,
sum(100) / (select sum(1.0) from `2020_bikeshare_data`) as perc_tot -- return as percentage
from
`2020_bikeshare_data`
group by
member_casual
Using the subquery, get the total number of rows and calculate the percentage accordingly.
Select
count(*) AS num_rides,
member_casual,
Concat(count(*) * 100 / totalRecord,' %') as perc_tot
FROM (SELECT *,COUNT(*) as totalRecord FROM `2020_bikeshare_data`)
GROUP BY member_casual
or
Select
count(*) AS num_rides,
member_casual,
Concat(count(*) * 100 / (SELECT COUNT(*) FROM `2020_bikeshare_data`) ,' %') as perc_tot
FROM `2020_bikeshare_data`
GROUP BY member_casual
In addition to the other answers, you can also break this down into simple SQL (without window functions) by organizing with CTEs.
with
data as (select * from `2020_bikeshare_data`),
total as (select count(*) as ride_count from data),
by_type as (select member_casual, count(*) as ride_count from data group by 1)
select
member_casual,
by_type.ride_count as num_rides,
by_type.ride_count / total.ride_count as perc_tot
from by_type
cross join total
In my opinion, this is much easier to see the perc_tot calculation.
Related
I'm not much used to SQL, but on my own I've been able to run this code:
SELECT
event_name,
COUNT(event_name) AS count,
COUNT(event_name) / SUM(COUNT(event_name)) OVER () * 100 AS event_percent
FROM `table_1`
WHERE
event_name IN ('session_start', 'view_item', 'select_item', 'add_to_cart', 'remove_from_cart', 'begin_checkout', 'purchase' )
GROUP BY
event_name
ORDER BY
count DESC
enter image description here
What I'd like to achive is the percentatge of each COUNT divided by the MAX COUNT. Example: purchase / session_start (22 / 1258)
If anyone can help.. I've tried some things but none worked
I guess a CTE would work
WITH prep AS (
SELECT
event_name,
COUNT(event_name) AS cnt,
COUNT(event_name) / SUM(COUNT(event_name)) OVER () * 100 AS event_percent
FROM `table_1`
WHERE
event_name IN ('session_start', 'view_item', 'select_item', 'add_to_cart', 'remove_from_cart', 'begin_checkout', 'purchase' )
GROUP BY
event_name
ORDER BY
count DESC
)
SELECT
*,
cnt / max(cnt) over()
FROM
prep
I have a SQL query in BigQuery:
SELECT
creator.country,
(SUM(length) / 60) AS total_minutes,
COUNT(DISTINCT creator.id) AS total_users,
(SUM(length) / 60 / COUNT(DISTINCT creator.id)) AS minutes_per_user
FROM
...
You may have noticed that the last column is equivalent to total_minutes / total_users.
I tried this, but it doesn't work:
SELECT
creator.country,
(SUM(length) / 60) AS total_minutes,
COUNT(DISTINCT creator.id) AS total_users,
(total_minutes / total_users) AS minutes_per_user
FROM
...
Is there any way to make this simpler?
Not really. That is, you cannot re-use column aliases in expressions in the same SELECT. If you really want, you can use a subquery or CTE:
SELECT c.*,
total_minutes / total_users
FROM (SELECT creator.country,
(SUM(length) / 60) AS total_minutes,
COUNT(DISTINCT creator.id) AS total_users
FROM
) c;
Another option is to move all business logic of metrics calculation into UDF (temp or permanent depends on usage needs) ...
create temp function custom_stats(arr any type) as ((
select as struct
sum(length) / 60 as total_minutes,
count(distinct id) as total_users,
sum(length) / 60 / count(distinct id) as minutes_per_user
from unnest(arr)
));
... and thus keep query itself simple and least verbose - as in below example
select creator.country,
custom_stats(array_agg(struct(length, creator.id))).*
from `project.dataset.table`
group by country
The following SQL statement:
SELECT FTR, COUNT(FTR)
FROM football_data
WHERE Matchday >= '2019-01-18'
GROUP BY FTR
Returns the following result:
Now I'm trying to get a percentage for each of those COUNT(FTR)'s.
So the sum of those 3 numbers is 153. Now I would like to get the percentage of them
You can use window functions, if I understand correctly:
SELECT FTR, COUNT(*),
COUNT(*) * 1.0 / SUM(COUNT(*)) OVER () as ratio
FROM football_data
WHERE Matchday >= '2019-01-18'
GROUP BY FTR;
This query would be too heavy, needs to be refactored. How can I do that?
Please help
SELECT
contract_type, SUM(fte), ROUND(SUM(fte * 100 / t.s ), 0) AS "% of total"
FROM
design_studio_testing.empfinal_tableau
CROSS JOIN
(SELECT SUM(fte) AS s
FROM design_studio_testing.empfinal_tableau) t
GROUP BY
contract_type;
Output should be like this:
Use window functions:
SELECT contract_type,
SUM(fte),
ROUND(SUM(fte) * 100.0 / SUM(SUM(fte)) OVER (), 0) AS "% of total"
FROM design_studio_testing.empfinal_tableau
GROUP BY contract_type;
That said, your original version should not be that much slower than this, unless perhaps empfinal_tableau is a view.
If it is a table, you could further speed this with an index on empfinal_tableau(contract_type, fte).
There is no need to sum over the expression:
fte * 100 / t.s
which may slow the process.
Get SUM(fte) and then multiply and divide:
SELECT g.contract_type, g.sum_fte,
ROUND(100.0 * g.sum_fte / t.s, 0) AS [% of total]
FROM (
SELECT
contract_type,
SUM(fte) AS sum_fte
FROM design_studio_testing.empfinal_tableau
GROUP BY contract_type
) AS g CROSS JOIN (SELECT SUM(fte) AS s FROM design_studio_testing.empfinal_tableau) t
Edit for Oracle:
SELECT g.contract_type, g.sum_fte,
ROUND(100.0 * g.sum_fte / t.s, 0) AS "% of total"
FROM (
SELECT
contract_type,
SUM(fte) AS sum_fte
FROM empfinal_tableau
GROUP BY contract_type
) g CROSS JOIN (SELECT SUM(fte) AS s FROM empfinal_tableau) t
For school, I have to answer the following question, using a window function.
For each year, for each month, for each product category, indicate the percentage of that month's turnover that was from the annual turnover of that category.
I tried to use the window function but it didnt work. Because i dont know how to use the over (partition by) function
select
catcode,
year(besteldatum) as jaar,
month(besteldatum) as maand,
sum(regelomzet) as omzet,
sum(regelomzet) / (
select sum(regelomzet)
from ##joinall t2
where t2.catcode = t1.catcode
and year(t2.besteldatum) = year(t1.besteldatum)
) * 100 as perc
from ##joinall t1
group by catcode, year(besteldatum), month(besteldatum)
order by catcode, year(besteldatum), month(besteldatum)
With the window functions there's a thing to realize about them.
They get processed after the GROUP BY.
Hence, it's possible to sum over a sum.
And the PARTITION BY in an OVER is kinda similar to GROUP BY.
SELECT
catcode,
year(besteldatum) as jaar,
month(besteldatum) as maand,
sum(regelomzet) as omzet,
cast(
(sum(regelomzet) /
SUM(sum(regelomzet)) OVER (PARTITION BY catcode, year(besteldatum))) * 100
as decimal(5,2)) as perc
FROM bestellingen t
GROUP BY catcode, year(besteldatum), month(besteldatum)
ORDER BY 1, 2, 3;