Oracle SQL Developer question from newbie - sql

Sorry could not think of more descriptive title. I have data that looks like:
MEMBERID
TICKETID
STATUS
A
123
Y
A
012
N
A
456
Y
B
XYZ
N
B
ABC
N
C
DEF
Y
C
789
Y
I want to separate the above into three tables:
(1) Members that ONLY have tickets with Status=Y
(2) Members that have mixed status tickets (so at least one ticket with status=Y and at least one ticket with status=N)
(3) Members that ONLY have tickets with Status=N
In Excel I would just do a pivot table that results in something like:
MEMBERID
"Y"
"N"
A
2
1
B
0
2
C
2
0
...then add a 4th column with a formula that allows me to separate member IDs by "Only Y", "Only N", and "Y/N". I'm new to SQL though, and can't seem to get "pivot" to run correctly, or maybe there's a "where" clause that could resolve this without using pivot? Help!

You could pivot but it's probably simpler to just do the aggregation yourself:
select memberid,
count(case when status = 'Y' then ticketid end) as y,
count(case when status = 'N' then ticketid end) as n
from your_table
group by memberid
order by memberid;
To get the fourth column you can either repeat the counts within another case expression:
select memberid,
count(case when status = 'Y' then ticketid end) as y,
count(case when status = 'N' then ticketid end) as n,
case
when count(case when status = 'Y' then ticketid end) > 0
and count(case when status = 'N' then ticketid end) > 0
then 'Y/N'
when count(case when status = 'Y' then ticketid end) > 0
then 'Only Y'
when count(case when status = 'N' then ticketid end) > 0
then 'Only N'
end as yn
from your_table
group by memberid
order by memberid;
Or put the initial query into a CTE or inline view which is clearer and has less repetition, so easier to maintain:
select memberid, y, n,
case
when y > 0 and n > 0 then 'Y/N'
when y > 0 then 'Only Y'
when n > 0 then 'Only N'
end as yn
from (
select memberid,
count(case when status = 'Y' then ticketid end) as y,
count(case when status = 'N' then ticketid end) as n
from your_table
group by memberid
)
order by memberid;
Either way you end up with:
MEMBERID Y N YN
-------- - - ------
A 2 1 Y/N
B 0 2 Only N
C 2 0 Only Y
SQL Fiddle

Related

Adding a dummy identifier to data that varies by position and value

I am working on a project in SQL Server with diagnosis codes and a patient can have up to 4 codes but not necessarily more than 1 and a patient cannot repeat a code more than once. However, codes can occur in any order. My goal is to be able to count how many times a Diagnosis code appears in total, as well as how often it appears in a set position.
My data currently resembles the following:
PtKey
Order #
Order Date
Diagnosis1
Diagnosis2
Diagnosis3
Diagnosis 4
345
1527
7/12/20
J44.9
R26.2
NULL
NULL
367
1679
7/12/20
R26.2
H27.2
G47.34
NULL
325
1700
7/12/20
G47.34
NULL
NULL
NULL
327
1710
7/12/20
I26.2
J44.9
G47.34
NULL
I would think the best approach would be to create a dummy column here that would match up the diagnosis by position. For example, Diagnosis 1 with A, and Diagnosis 2 with B, etc.
My current plan is to rollup the diagnosis using an unpivot:
UNPIVOT ( Diag for ColumnALL IN (Diagnosis1, Diagnosis2, Diagnosis3, Diagnosis4)) as unpvt
However, this still doesn’t provide a way to count the diagnoses by position on a sales order.
I want it to look like this:
Diagnosis
Total Count
Diag1 Count
Diag2 Count
Diag3 Count
Diag4 Count
J44.9
2
1
1
0
0
R26.2
1
1
0
0
0
H27.2
1
0
1
0
0
I26.2
1
1
0
0
0
G47.34
3
1
0
2
0
You can unpivot using apply and aggregate:
select v.diagnosis, count(*) as cnt,
sum(case when pos = 1 then 1 else 0 end) as pos_1,
sum(case when pos = 2 then 1 else 0 end) as pos_2,
sum(case when pos = 3 then 1 else 0 end) as pos_3,
sum(case when pos = 4 then 1 else 0 end) as pos_4
from data d cross apply
(values (diagnosis1, 1),
(diagnosis2, 2),
(diagnosis3, 3),
(diagnosis4, 4)
) v(diagnosis, pos)
where diagnosis is not null;
Another way is to use UNPIVOT to transform the columns into groupable entities:
SELECT Diagnosis, [Total Count] = COUNT(*),
[Diag1 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis1' THEN 1 ELSE 0 END),
[Diag2 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis2' THEN 1 ELSE 0 END),
[Diag3 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis3' THEN 1 ELSE 0 END),
[Diag4 Count] = SUM(CASE WHEN DiagGroup = N'Diagnosis4' THEN 1 ELSE 0 END)
FROM
(
SELECT * FROM #x UNPIVOT (Diagnosis FOR DiagGroup IN
([Diagnosis1],[Diagnosis2],[Diagnosis3],[Diagnosis4])) up
) AS x GROUP BY Diagnosis;
Example db<>fiddle
You can also manually unpivot via UNION before doing the conditional aggregation:
SELECT Diagnosis, COUNT(*) As Total Count
, SUM(CASE WHEN Position = 1 THEN 1 ELSE 0 END) As [Diag1 Count]
, SUM(CASE WHEN Position = 2 THEN 1 ELSE 0 END) As [Diag2 Count]
, SUM(CASE WHEN Position = 3 THEN 1 ELSE 0 END) As [Diag3 Count]
, SUM(CASE WHEN Position = 4 THEN 1 ELSE 0 END) As [Diag4 Count]
FROM
(
SELECT PtKey, Diagnosis1 As Diagnosis, 1 As Position
FROM [MyTable]
UNION ALL
SELECT PtKey, Diagnosis2 As Diagnosis, 2 As Position
FROM [MyTable]
WHERE Diagnosis2 IS NOT NULL
UNION ALL
SELECT PtKey, Diagnosis3 As Diagnosis, 3 As Position
FROM [MyTable]
WHERE Diagnosis3 IS NOT NULL
UNION ALL
SELECT PtKey, Diagnosis4 As Diagnosis, 4 As Position
FROM [MyTable]
WHERE Diagnosis4 IS NOT NULL
) d
GROUP BY Diagnosis
Borrowing Aaron's fiddle, to avoid needing to rebuild the schema from scratch, and we get this:
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=d1f7f525e175f0f066dd1749c49cc46d

Flag=1/0 based on multiple criteria on same column

I have a temp table that is being created, we will say that column 1 is YearMonth, column2 as user_id, Column 3 is Type.
YearMonth User_id Type
200101 1 x
200101 2 y
200101 2 z
200102 1 x
200103 2 x
200103 2 p
200103 2 q
I want to count userids based on flag based on type. Hence I am trying to set flag to 1 and 0 but it always results in 0.
So for e.g. when the type contains x or y or z AND type contains P or Q then flag=1 by YearMonth.
I am trying something like
SELECT count (distinct t1.user_id) as count,
t1.YearMonth,
case when t1.type in ('x','y','z')
and
t1.type in ('p','q') then 1 else 0 end as flag
FROM table t1
group by 2,3;
I would like to know why it doesn't give output as below:
count YearMonth Flag
0 200001 1
2 200001 0
1 200002 1
1 200002 0
What am I missing here? Thanks
If I follow you correctly, you can use two levels of aggregation:
select yearmonth, flag, count(*) cnt
from (
select yearmonth, id,
case when max(case when t1.type in ('x', 'y', 'z') then 1 else 0 end) = 1
and max(case when t1.type in ('p', 'q') then 1 else 0 end) = 1
then 1
else 0
end as flag
from mytable
group by yearmonth, id
) t
group by yearmonth, flag
This first flags users for each month, using conditional aggregation, then aggregates by flag and month.
If you also want to display 0 for flags that do not appear for a given month, then you can generate the combinations with a cross join first, then brin the above resultset with a left join:
select y.yearmonth, f.flag, count(t.id) cnt
from (select distinct yearmonth from mytable) y
cross join (values (0), (1)) f(flag)
left join (
select yearmonth, id,
case when max(case when t1.type in ('x', 'y', 'z') then 1 else 0 end) = 1
and max(case when t1.type in ('p', 'q') then 1 else 0 end) = 1
then 1
else 0
end as flag
from mytable
group by yearmonth, id
) t on t.yearmonth = y.yearmonth and t.flag = f.flag
group by y.yearmonth, f.flag
I thought a very similar idea as GMB, however, like him, I don't get the expected results. Likely, however, we both are assuming the expected results are wrong:
SELECT COUNT(DISTINCT UserID) AS [Count],
YearMonth,
CASE WHEN COUNT(CASE WHEN [Type] IN ('x','y','z') THEN 1 END) > 0
AND COUNT(CASE WHEN [Type] IN ('p','q') THEN 1 END) > 0 THEN 1 ELSE 0
END AS Flag
FROM (VALUES(200101,1,'x'),
(200101,2,'y'),
(200101,2,'z'),
(200102,1,'x'),
(200103,2,'x'),
(200103,2,'p'),
(200103,2,'q')) V(YearMonth,UserID,[Type])
GROUP BY YearMonth;

Best way to do a Count in TSQL

I am not so good in TSQL and i want to write a report in this manner:
input: Table A
ID Company Product Flag
1 A Car Y
2 A Van N
3 B Van Y
4 A Part N
Output
Company Y N
A 1 2
B 1 0
if one can assist in TSQL...
You could use conditional aggregation:
SELECT Company
,SUM(CASE WHEN Flag = 'Y' THEN 1 ELSE 0 END) AS Y
,SUM(CASE WHEN Flag = 'N' THEN 1 ELSE 0 END) AS N
FROM tab
GROUP BY Company
You are looking for conditional aggregation:
select company,
sum(case when flag = 'Y' then 1 else 0 end) as num_y,
sum(case when flag = 'N' then 1 else 0 end) as num_n
from t
group by company;
You can use CASE expressions (the people call it "conditional aggregation") to count the flagged products per customer like this (which will ignore a record when the Product column is empty):
SELECT Company
, COUNT(CASE Flag WHEN 'Y' THEN Product END) AS Y
, COUNT(CASE Flag WHEN 'N' THEN Product END) AS N
FROM YourTable
GROUP BY Company;
Or you can use this PIVOT query, which is a short form of writing the above:
SELECT Company, Y, N
FROM (SELECT Company, Product, Flag FROM YourTable) AS src
PIVOT (COUNT(Product) FOR Flag IN (Y, N)) AS pvt;
use case when
select company,
sum(case when flag='Y' then 1 else 0 end) as Y,
sum(case when flag='N' then 1 else 0 end) as N from tabe_data
group by company

conditional aggregation on two different groups in SQL

Here is my data
COUNTYID POLLUTANT TYPE EMISSION
1 A 1
1 A 2
1 B 1
1 B 2
2 A 1
2 A 2
2 B 1
2 B 2
3 A 1
3 A 2
3 B 1
3 B 2
if I do
SELECT sum(EMISSION) from table where POLLUTANT = 'A' group by COUNTYID;
I would get pollution from Polutant 'A'. how can I write a query to get following data:
column 1 with sum of A, column 2 with sum of B, column 3 with sum of A and B?
Thank you
You can use case for filter the value you need
select COUNTYID, sum(case when POLLUTANT='A'then EMISSION else 0 END) tot_a
, sum(case when POLLUTANT='B'then EMISSION else 0 END) tot_b
, sum(EMISSION) tot_a_b
from my_table
group by COUNTYID
You can use conditional aggregation. This moves the filtering conditions from the where clause to the sum()s:
select countyid,
sum(case when emission = 'A' then emission else 0 end) as A,
sum(case when emission = 'B' then emission else 0 end) as B,
sum(emission) as total
from t
group by countyid;
I would like to give some idea. We can use pivot table for answer your question
SELECT * from dbo.[Table_1]
PIVOT
(Sum([type_emmssion]) for [polutant] in ([A], [B]) ) as PivotTable
group by [CountryId] ;
you have to use case statemet:
SELECT
SUM( CASE WHEN POLLUTANT = 'A' THEN EMISSION ELSE 0 END) AS A_EMISSION
SUM( CASE WHEN POLLUTANT = 'B' THEN EMISSION ELSE 0 END) AS B_EMISSION
SUM(EMISSION) AS total_emission
FROM table
GROUP BY COUNTYID;

Oracle query with group

I have a scenario where I need to fetch all the records within an ID for the same source. Given below is my input set of records
ID SOURCE CURR_FLAG TYPE
1 IBM Y P
1 IBM Y OF
1 IBM Y P
2 IBM Y P
2 TCS Y P
3 IBM NULL P
3 IBM NULL P
3 IBM NULL P
4 IBM NULL OF
4 IBM NULL OF
4 IBM Y ON
From the above settings, I need to select all the records with source as IBM within that same ID group.Within the ID group if there is at least one record with a source other than IBM, then I don't want any record from that ID group. Also, we need to fetch only those records where at least one record in that ID group with curr_fl='Y'
In the above scenario even though the ID=3 have a source as IBM, but there is no record with CURR_FL='Y', my query should not fetch the value.In the case of ID=4, it can fetch all the records with ID=4, as one of the records have value='Y'.
Also within the group which has satisfied the above condition, I need one more condition for source_type. if there are records with source_type='P', then I need to fetch only that record.If there are no records with P, then I will search for source_type='OF' else source_type='ON'
I have written a query as given below.But it's running for long and not fetching any results. Is there any better way to modify this query
select
ID,
SOURCE,
CURR_FL,
TYPE
from TABLE a
where
not exists(select 1 from TABLE B where a.ID = B.ID and source <> 'IBM')
and exists(select 1 from TABLE C where a.ID = C.ID and CURR_FL = 'Y') and
(TYPE, ID) IN (
select case type when 1 then 'P' when 2 then 'OF' else 'ON' END TYPE,ID from
(select ID,
max(priority) keep (dense_rank first order by priority asc) as type
from ( select ID,TYPE,
case TYPE
when 'P' then 1
when 'OF' then 2
when 'ON' then 3
end as priority
from TABLE where ID
in(select ID from TABLE where CURR_FL='Y') AND SOURCE='IBM')
group by ID))
I think you can just do a single aggregation over your table by ID and check for the yes flag as well as assert that no non IBM source appears. I do this in a CTE below, and then join back to your original table to return full matching records.
WITH cte AS (
SELECT
ID,
CASE WHEN SUM(CASE WHEN TYPE = 'P' THEN 1 ELSE 0 END) > 0
THEN 1
WHEN SUM(CASE WHEN TYPE = 'OF' THEN 1 ELSE 0 END) > 0
THEN 2
WHEN SUM(CASE WHEN TYPE = 'ON' THEN 1 ELSE 0 END) > 0
THEN 3 ELSE 4 END AS p_type
FROM yourTable
GROUP BY ID
HAVING
SUM(CASE WHEN CURR_FLAG = 'Y' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN SOURCE <> 'IBM' THEN 1 ELSE 0 END) = 0
)
SELECT t1.*
FROM yourTable t1
INNER JOIN cte t2
ON t1.ID = t2.ID
WHERE
t2.p_type = 1 AND t1.TYPE = 'P' OR
t2.p_type = 2 AND t1.TYPE = 'OF' OR
t2.p_type = 3 AND t1.TYPE = 'ON';