I am making a table of all product SKUs (fj1_sku column) paired with the product SKU of a second product which is a close substitute to that product (fj2_sku column) based on a range of criteria. To get the main matrix I have done a cross join of the final_join table with itself.
I cannot figure out how to remove the mirror duplicate pairs in the resulting table:
fj1_sku
fj2_sku
10
11
11
10
i.e. I only want one row with the pair 11 & 10.
I have tried a number of solutions found on this platform, but do not want to use a "select distinct" because I need many variables that I cannot use a distinct with.
Here is the code I have so far:
select
fj1.sku as fj1_sku,
fj2.sku as fj2_sku,
fj1.name as fj1_name,
fj2.name as fj2_name,
fj1.brand as fj1_brand,
fj2.brand as fj2_brand
from final_join as fj1
cross join final_join as fj2
where (fj1.sku <> fj2.sku) and (fj1.brand <> fj2.brand)
If you have duplicates for all pairs, then you can use:
select t.*
from t
where fj1_sku < fj2_sku;
If not, you can use be more selective:
select t.*
from t
where t.fj1_sku < t.fj2_sku or
not exists (select 1
from t t2
where t2.fj1_sku = t.fj2_sku and
t2.fj2_sku = t.fj1_sku
);
You can also incorporate similar logic into a delete, if you actually want to change the table.
Related
I have a table named Ticket Numbers, which (for this example) contain the columns:
Ticket_Number
Assigned_Group
Assigned_Group_Sequence_No
Reported_Date
Each ticket number could contain 4 rows, depending on how many times the ticket changed assigned groups. Some of these rows could contain an assigned group of "Desktop Support," but some may not. Here is an example:
Example of raw data
What I am trying to accomplish is to get the an output that contains any ticket numbers that contain 'Desktop Support', but also the assigned group of the max sequence number. Here is what I am trying to accomplish with SQL:
Queried Data
I'm trying to use SQL with the following query but have no clue what I'm doing wrong:
select ih.incident_number,ih.assigned_group, incident_history2.maxseq, incident_history2.assigned_group
from incident_history_public as ih
left join
(
select max(assigned_group_seq_no) maxseq, incident_number, assigned_group
from incident_history_public
group by incident_number, assigned_group
) incident_history2
on ih.incident_number = incident_history2.incident_number
and ih.assigned_group_seq_no = incident_history2.maxseq
where ih.ASSIGNED_GROUP LIKE '%DS%'
Does anyone know what I am doing wrong?
You might want to create a proper alias for incident_history. e.g.
from incident_history as incident_history1
and
on incident_history1.ticket_number = incident_history2.ticket_number
and incident_history1.assigned_group_seq_no = incident_history2.maxseq
In my humble opinion a first error could be that I don't see any column named "incident_history2.assigned_group".
I would try to use common table expression, to get only ticket number that contains "Desktop_support":
WITH desktop as (
SELECT distinct Ticket_Number
FROM incident_history
WHERE Assigned_Group = "Desktop Support"
),
Than an Inner Join of the result with your inner table to get ticket number and maxSeq, so in a second moment you can get also the "MAXGroup":
WITH tmp AS (
SELECT i2.Ticket_Number, i2.maxseq
FROM desktop D inner join
(SELECT Ticket_number, max(assigned_group_seq_no) as maxseq
FROM incident_history
GROUP BY ticket_number) as i2
ON D.Ticket_Number = i2.Ticket_Number
)
SELECT i.Ticket_Number, i.Assigned_Group as MAX_Group, T.maxseq, i.Reported_Date
FROM tmp T inner join incident_history i
ON T.Ticket_Number = i.Ticket_Number and i.assigned_group_seq_no = T.maxseq
I think there are several different method to resolve this question, but I really hope it's helpful for you!
For more information about Common Table Expression: https://www.essentialsql.com/introduction-common-table-expressions-ctes/
The database is Postgres but any SQL logic should help.
I am retrieving the set of sales quotations that contain a given product within the bill of materials. I'm doing that in two steps: step 1, retrieve all DISTINCT quote numbers which contain a given product (by product number).
The second step, retrieve the full quote, with all products listed for each unique quote number.
So far, so good. Now the tough bit. Some rows are duplicates, some are not. Those that are duplicates (quote number & quote version & line number) might or might not have maintenance on them. I want to pick the row that has maintenance greater than 0. The duplicate rows I want to exclude are those that have a 0 maintenance. The problem is that some rows, which have no duplicates, have 0 maintenance, so I can't just filter on maintenance.
To make this exciting, the database holds quotes over 20+ years. And the data scientists guys have just admitted that maybe the ETL process has some bugs...
--- step 0
--- cleanup the workspace
SET CLIENT_ENCODING TO 'UTF8';
DROP TABLE IF EXISTS product_quotes;
--- step 1
--- get list of Product Quotes
CREATE TEMPORARY TABLE product_quotes AS (
SELECT DISTINCT master_quote_number
FROM w_quote_line_d
WHERE item_number IN ( << model numbers >> )
);
--- step 2
--- Now join on that list
SELECT
d.quote_line_number,
d.item_number,
d.item_description,
d.item_quantity,
d.unit_of_measure,
f.ref_list_price_amount,
f.quote_amount_entered,
f.negtd_discount,
--- need to calculate discount rate based on list price and negtd discount (%)
CASE
WHEN ref_list_price_amount > 0
THEN 100 - (ref_list_price_amount + negtd_discount) / ref_list_price_amount *100
ELSE 0
END AS discount_percent,
f.warranty_months,
f.master_quote_number,
f.quote_version_number,
f.maintenance_months,
f.territory_wid,
f.district_wid,
f.sales_rep_wid,
f.sales_organization_wid,
f.install_at_customer_wid,
f.ship_to_customer_wid,
f.bill_to_customer_wid,
f.sold_to_customer_wid,
d.net_value,
d.deal_score,
f.transaction_date,
f.reporting_date
FROM w_quote_line_d d
INNER JOIN product_quotes pq ON (pq.master_quote_number = d.master_quote_number)
INNER JOIN w_quote_f f ON
(f.quote_line_number = d.quote_line_number
AND f.master_quote_number = d.master_quote_number
AND f.quote_version_number = d.quote_version_number)
WHERE d.net_value >= 0 AND item_quantity > 0
ORDER BY f.master_quote_number, f.quote_version_number, d.quote_line_number
The logic to filter the duplicate rows is like this:
For each master_quote_number / version_number pair, check to see if there are duplicate line numbers. If so, pick the one with maintenance > 0.
Even in a CASE statement, I'm not sure how to write that.
Thoughts? The database is Postgres but any SQL logic should help.
I think you will want to use Window Functions. They are, in a word, awesome.
Here is a query that would "dedupe" based on your criteria:
select *
from (
select
* -- simplifying here to show the important parts
,row_number() over (
partition by master_quote_number, version_number
order by maintenance desc) as seqnum
from w_quote_line_d d
inner join product_quotes pq
on (pq.master_quote_number = d.master_quote_number)
inner join w_quote_f f
on (f.quote_line_number = d.quote_line_number
and f.master_quote_number = d.master_quote_number
and f.quote_version_number = d.quote_version_number)
) x
where seqnum = 1
The use of row_number() and the chosen partition by and order by criteria guarantee that only ONE row for each combination of quote_number/version_number will get the value of 1, and it will be the one with the highest value in maintenance (if your colleagues are right, there would only be one with a value > 0 anyway).
Can you do something like...
select
*
from
w_quote_line_d d
inner join
(
select
...
,max(maintenance)
from
w_quote_line_d
group by
...
) d1
on
d1.id = d.id
and d1.maintenance = d.maintenance;
Am I understanding your problem correctly?
Edit: Forgot the group by!
I'm not sure, but maybe you could Group By all other columns and use MAX(Maintenance) to get only the greatest.
What do you think?
I pop into a problem recently, and Im sure its because of how I Join them.
this is my code:
select LP_Pending_Info.Service_Order,
LP_Pending_Info.Pending_Days,
LP_Pending_Info.Service_Type,
LP_Pending_Info.ASC_Code,
LP_Pending_Info.Model,
LP_Pending_Info.IN_OUT_WTY,
LP_Part_Codes.PartCode,
LP_PS_Codes.PS,
LP_Confirmation_Codes.SO_NO,
LP_Pending_Info.Engineer_Code
from LP_Pending_Info
join LP_Part_Codes
on LP_Pending_Info.Service_order = LP_Part_Codes.Service_order
join LP_PS_Codes
on LP_Pending_Info.Service_Order = LP_PS_Codes.Service_Order
join LP_Confirmation_Codes
on LP_Pending_Info.Service_Order = LP_Confirmation_Codes.Service_Order
order by LP_Pending_Info.Service_order, LP_Part_Codes.PartCode;
For every service order I have 5 part code maximum.
If the service order have only one value it show the result correctly but when it have more than one Part code the problem begin.
for example: this service order"4182134076" has only 2 part code, first'GH81-13601A' and second 'GH96-09938A' so it should show the data 2 time but it repeat it for 8 time. what seems to be the problem?
If your records were exactly the same the distinct keyword would have solved it.
However in rows 2 and 3 which have the same Service_Order and Part_Code if you check the SO_NO you see it is different - that is why distinct won't work here - the rows are not identical.
I say you have some problem in one of the conditions in your joins. The different data is in the SO_NO column so check the raw data in the LP_Confirmation_Codes table for that Service_Order:
select * from LP_Confirmation_Codes where Service_Order = 4182134076
I assume you are missing an and with the value from the LP_Part_Codes or LP_PS_Codes (but can't be sure without seeing those tables and data myself).
By this sentence If the service order have only one value it show the result correctly but when it have more than one Part code the problem begin. - probably you are missing and and with the LP_Part_Codes table
Based on your output result, here are the following data that caused multiple output.
Service Order: 4182134076 has :
2 PartCode which are GH81-13601A and GH96-09938A
2 PS which are U and P
2 SO_NO which are 1.00024e+09 and 1.00022e+09
Therefore 2^3 returns 8 rows. I believe that you need to check where you should join your tables.
Use DINTINCT
select distinct LP_Pending_Info.Service_Order,LP_Pending_Info.Pending_Days,
LP_Pending_Info.Service_Type,LP_Pending_Info.ASC_Code,LP_Pending_Info.Model,
LP_Pending_Info.IN_OUT_WTY, LP_Part_Codes.PartCode,LP_PS_Codes.PS,
LP_Confirmation_Codes.SO_NO,LP_Pending_Info.Engineer_Code
from LP_Pending_Info
join LP_Part_Codes on LP_Pending_Info.Service_order = LP_Part_Codes.Service_order
join LP_PS_Codes on LP_Part_Codes.Service_Order = LP_PS_Codes.Service_Order
join LP_Confirmation_Codes on LP_PS_Codes.Service_Order = LP_Confirmation_Codes.Service_Order
order by LP_Pending_Info.Service_order, LP_Part_Codes.PartCode;
distinct will not return duplicates based on your select. So if a row is same, it will only return once.
Hi I have a redshift table of articles that has a field on it that can contain many accounts. So there is a one to many relationship between articles to accounts.
However I want to create a new view where it lists the partner id's in one column and in another column a count of how many times the partner id appears in the articles table.
I've attempted to do this using regex and created a new redshift view, but am getting weird results where it doesn't always build properly. So one day it will say a partner appears 15 times, then the next 17, then the next 15, when the partner id count hasn't actually changed.
Any help would be greatly appreciated.
SELECT partner_id,
COUNT(DISTINCT id)
FROM (SELECT id,
partner_ids,
SPLIT_PART(partner_ids,',',i) partner_id
FROM positron_articles a
LEFT JOIN util.seq_0_to_500 s
ON s.i < regexp_count (partner_ids,',') + 2
OR s.i = 1
WHERE i > 0
AND regexp_count (partner_ids,',') = 0
ORDER BY id)
GROUP BY 1;
Let's start with some of the more obvious things and see if we can start to glean other information.
Next GROUP BY 1 on your outer query needs to be GROUP BY partner_id.
Next you don't need an order by in your INNER query and the database engine will probably do a better job optimizing performance without it so remove ORDER BY id.
If you want your final results to be ordered then add an ORDER BY partner_id or similar clause after your group by of your OUTER query.
It looks like there are also problems with how you are splitting a partnerid from partnerids but I am not positive about that because I need to understand your view and the data it provides to know how that affects your record count for partnerid.
Next your LEFT JOIN statement on the util.seq_0_to_500 I am pretty sure you can drop off the s.i = 1 as the first condition will satisfy that as well because 2 is greater than 1. However your left join really acts more like an inner join because you then exclude any non matches from positron_articles that don't have a s.i > 0.
Oddly then your entire join and inner query gets kind of discarded because you only want articles that have no commas in their partnerids: regexp_count (partner_ids,',') = 0
I would suggest posting the code for your util.seq_0_to_500 and if you have a partner table let use know about that as well because you can probably get your answer a lot easier with that additional table depending on how regexp_count works. I suspect regex_count(partnerids,partnerid) exampleregex_count('12345,678',1234) will return greater than 0 at which point you have no choice but to split the delimited strings into another table before counting or building a new matching function.
If regex_count only matches exact between commas and you have a partner table your query could be as easy as this:
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
positron_articles a
LEFT JOIN PARTNERTABLE p
ON regexp_count(a.partnerids,p.partnerid) > 0
GROUP BY
p.partner_id
I will actually correct myself as I just thought of a way to join a partner table without regexp_count. So if you have a partner table this might work for you. If not you will need to split strings. It basically tests to see if the partnerid is the entire partnerids, at the beginning, in the middle, or at the end of partnerids. If one of those is met then the records is returned.
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
PARTNERTABLE p
INNER JOIN positron_articles a
ON
(
CASE
WHEN a.partnerids = CAST(p.partnerid AS VARCHAR(100)) THEN 1
WHEN a.partnerids LIKE p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid THEN 1
ELSE 0
END
) = 1
GROUP BY
p.partner_id
Need help on a query using sql server 2005
I am having two tables
code
chargecode
chargeid
orgid
entry
chargeid
itemNo
rate
I need to list all the chargeids in entry table if it contains multiple entries having different chargeids
which got listed in code table having the same charge code.
data :
code
100,1,100
100,2,100
100,3,100
101,11,100
101,12,100
entry
1,x1,1
1,x2,2
2,x3,2
11,x4,1
11,x5,1
using the above data , it query should list chargeids 1 and 2 and not 11.
I got the way to know how many rows in entry satisfies the criteria, but m failing to get the chargeids
select count (distinct chargeId)
from entry where chargeid in (select chargeid from code where chargecode = (SELECT A.chargecode
from code as A join code as B
ON A.chargecode = B.chargeCode and A.chargetype = B.chargetype and A.orgId = B.orgId AND A.CHARGEID = b.CHARGEid
group by A.chargecode,A.orgid
having count(A.chargecode) > 1)
)
First off: I apologise for my completely inaccurate original answer.
The solution to your problem is a self-join. Self-joins are used when you want to select more than one row from the same table. In our case we want to select two charge IDs that have the same charge code:
SELECT DISTINCT c1.chargeid, c2.chargeid FROM code c1
JOIN code c2 ON c1.chargeid != c2.chargeid AND c1.chargecode = c2.chargecode
JOIN entry e1 ON e1.chargeid = c1.chargeid
JOIN entry e2 ON e2.chargeid = c2.chargeid
WHERE c1.chargeid < c2.chargeid
Explanation of this:
First we pick any two charge IDs from 'code'. The DISTINCT avoids duplicates. We make sure they're two different IDs and that they map to the same chargecode.
Then we join on 'entry' (twice) to make sure they both appear in the entry table.
This approach gives (for your example) the pairs (1,2) and (2,1). So we also insist on an ordering; this cuts to result set down to just (1,2), as you described.