Add values between two fields on the base of month names I have fields in the table from January to December and I want to calculate only the sum between May to September.
code I have tried but it's not working for me
SELECT DATENAME(month,GETDATE()) 'Month Name'
(
select top 1 Column_name='May'
from Information_schema.columns
where Table_name like 'session2021'
)
I have fields in the table from January to December and I want to calculate only the sum between May to September.
I would expect:
select May + June + July + August + September as my_sum
from the_table;
You should fix your data model so you have one row per month, rather than putting the months in separate columns.
Related
I have this query with a SELECT statement and I need to add to my WHERE clause the condition that the date must be prior to the previous month beginning.
SELECT columnA, columnB
FROM TableX
WHERE columnA=20
For example the current date belongs to October so I need to filter the registers where date belongs to September or October from this year.
Let's say we are in December 2022, I would need to filter the registers whose date belongs to November 2022 or December 2022.
I am using an Oracle database.
How can I do it?
It should be something among the lines of:
SELECT columnA, columnB
FROM TableX
WHERE columnA = 20
AND <your_date_column> BETWEEN TRUNC(ADD_MONTHS(SYSDATE,-1),'MM') AND TRUNC(LAST_DAY(SYSDATE),'MM');
I have a table in SQL Server 2012 with a month column stored as nvarchar(255):
"January", "February", "March"
And another column in this table with year stored separately as float
"2012","2013,"2014".
I do not have a day column so I want to create a combined month date column with the day starting as 1.
So for month and year fields January 2012. I want to show '2012-01-01'
How can I do such and add that into my current table?
I want to find the maximum row for a record in my table for each employee.
so for an [employee #], [month],[year]. what is latest record so for example below:
1. 102, Jan, 2019
2. 102, feb, 2019
I want to only see the second record which is the latest.
SQL Server has pretty flexible conversion to date. So, just convert the columns to a date:
select convert(date, month + ' ' + year)
You can get the maximum as:
select empid, max(convert(date, month + ' ' + year))
from t
group by empid;
If you really like, you can change the format for output purposes. I would advise you to stick with a date, though.
Note: This assumes that your internationalization settings are set to English -- which seems reasonable if you are storing month names in English.
Fix your design! The way you store data makes it really inefficient to interpret it. Here, I think the simplest option is datefromparts() and a 12-branches case expression.
Assuming that the (float) year is stored in column col_year and the (string) month is in col_month:
select t.*,
datefromparts(
cast(col_year as int),
case col_month
when 'January' then 1
when 'February' then 2
...
when 'December' then 12
end,
1
) as date_col
from mytable t
I want to filter values from a table, between two weeks, like this:
select * from SalesWeekly
where SalesWeek BETWEEN '50' and '02'
Problem is, i have no idea how to specify week 50 is from year 2019,
and week 02 is from year 2020.
Assuming that you are storing the year in your table, say in table SalesYear, you could concatenate it with the week number and do string comparisons:
select *
from SalesWeekly
where SalesYear || '-' || SalesWeek BETWEEN '2019-50' and '2020-02'
For this to work, SalesWeek must be a 2-characters long string, left padded with 0 (so the 1st week should be '01', not '1').
I have a simple statement that starts:
SELECT a.product, MONTH(a.saledate) AS Month, Count(*) AS Total
Which yields, for example,
Product Month Total
Bike 8 1000
Please can anyone advise if it's possible to add the month's name to this query and also, is it possible to get a monthly total to appear as well?
Thanks!
The query in your example counts all the rows in your table, then presents that count next to a randomly chosen row's product and sale date. That's -- almost certainly -- not what you want. MySQL is quirky that way. Other DBMSs reject your example query.
If you want to display a monthly summary of product sold, here's the basic query:
SELECT a.product,
LAST_DAY(a.saledate) AS month_ending,
COUNT(*) AS Total
FROM table a
GROUP BY a.product, LAST_DAY(a.saledate)
The LAST_DAY() function is a great way to extract month and year from a date.
Finally, if you want to display the text name of the month, you can use the DATE_FORMAT() function to do that. %b as a format specifier gives a three-letter month name, and %M gives the full month name. So this query will do it.
SELECT a.product,
LAST_DAY(a.saledate) AS month_ending,
DATE_FORMAT(LAST_DAY(a.saledate), '%M %Y')) AS month
COUNT(*) AS Total
FROM table a
GROUP BY a.product, LAST_DAY(a.saledate)
In SQL Server 2012+ you can use the EOMONTH() function in place of LAST_DAY().
In SQL Server 2008+ you can use DATENAME(mm, a.saledate) to retrieve the month name from a date.
There are two ways of getting month name
1)
SUBSTRING('JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC ', (MONTH(a.saledate) * 4) - 3, 3)
2)
DATENAME(month, a.saledate)
Some poeple say You might be using MYSQL:
Then getting month name will be:
SELECT MONTHNAME( a.saledate);
I have a table of the fiscal year for 100 years. i.e.
I am wanting to do add a column which shows the fiscal year that each week_ending_date belongs to. So in the table above week number 1, and week_ending_date 2013-10-05 would belong to fiscal year ending 2014.
In short I simply want each value in the added column to be the year part of week_ending_date where the next week_number is 52.
Here would be the pseudo code of what I am trying to achieve.
SELECT
Week_Ending_Date,
(SELECT NEXT VALUE FOR Week_Ending_Date (***but as only year***) FROM Fiscal_Calendar WHERE FC.Week_Number = 52)
FROM Fiscal_Calendar AS FC
JOIN Shipped_Container AS SC
ON SC.Fiscal_Week_Ending = FC.Week_Ending_Date
Bare in mind this has 100 years in the table and so I can't select the last value and makes using WHERE difficult (for me).
One way you can do this is by subtracting 7 * week number, taking the year and adding 1:
select 1 + year(dateadd(day, -7 * week_number, week_ending_date))