How to return matching column value where only all subqueries are true - sql

Question

I'd like to adjust the below SQL statement so that it only returns the PART_ID where all SELECT PART_ID FROM FABRICATION... conditions are met.
Currently the below statement would return part_id's 1 & 2, when the intent is to only return 1.
Thanks for any advice you can offer.
SELECT *
FROM Part
WHERE Section = 'C6x1_5/8x1/4'
AND Length BETWEEN 41.99 AND 42.01
AND Part.Part_ID IN (SELECT Part_ID FROM Fabrication
WHERE Type LIKE 'HOLE'
AND Face = 1
AND Side = 3
AND Location BETWEEN 2.99 AND 3.01
AND Offset = 2
AND Parameter_1 = 0.5625)
AND Part.Part_ID IN (SELECT Part_ID FROM Fabrication
WHERE Type LIKE 'HOLE'
AND Face = 1
AND Side = 3
AND Location BETWEEN 5.99 AND 6.01
AND Offset = 2
AND Parameter_1 = 0.5625)
Fabrication Table:
PART_ID
TYPE
FACE
SIDE
LOCATION
OFFSET
PARAMETER_1
PARAMETER_2
PARAMETER_3
1
HOLE
1
3
6
2
0.5625
0
0
1
HOLE
1
3
3
2
0.5625
0
0
2
HOLE
1
3
6
2
0.5625
0
0
2
HOLE
1
3
3
2
0.5625
0
0
2
HOLE
1
3
9
2
0.5625
0
0
3
HOLE
1
3
3
2
0.5625
0
0

Answer 1

You can use aggregation and HAVING to validate that there there is exactly one match for each condition and no others:
SELECT *
FROM Part
WHERE Section = 'C6x1_5/8x1/4' AND
Length BETWEEN 41.99 AND 42.01
Part.Part_ID IN (SELECT f.Part_ID
FROM Fabrication f
GROUP BY f.Part_ID
HAVING SUM(CASE WHEN f.Type = 'HOLE' AND f.Face = 1 AND f.Side = 3 AND f.Offset = 2 AND f.Parameter_1 = 0.5625 THEN 1 ELSE 0 END) = COUNT(*) AND
SUM(CASE WHEN Location BETWEEN 2.99 AND 3.01 THEN 1 ELSE 0 END) = 1 AND
SUM(CASE WHEN Location BETWEEN 5.99 AND 6.01 THEN 1 ELSE 0 END) = 1
);

Answer 2

It looks like the only variance in your two queries is Location, for which you want to ensure the number of Fabrication rows meet your criteria and do not have any additional rows outside of your criteria.
One option you can try uses conditional aggregation:
select *
from Part
where Section = 'C6x1_5/8x1/4'
and Length between 41.99 and 42.01
and Part.Part_ID in (
select PART_ID
from Fabrication
where
TYPE = 'HOLE'
and FACE = 1
and SIDE = 3
and offset = 2
and PARAMETER_1 = 0.5625
group by PART_ID
having Count(*)=Sum(case when LOCATION between 2.99 and 3.01 then 1 end) + Sum(case when LOCATION between 5.99 and 6.01 then 1 end)
)