I am trying to make a saved search that shows any inventory numbers with lowercase letter(s) in it. I have tried the following formula but am not having any luck, I have tried using the match parameter but don't want to specify a position for where the lowercase letter may occur, could anyone tell me what I'm doing wrong and what I need to do to correct it?
REGEXP_INSTR({inventorynumber},'%[a-z]%')
I have this in a numeric formula criteria where it is not equal to 0.
In NetSuite Saved Search you do not need to use the wild card (%) with the character class ([]). The following 2 options should work.
REGEXP_INSTR({entityid},'[a-z]')
REGEXP_INSTR({entityid},'[[:lower:]]')
Related
I have made a process that reads PDFs and scrapes their text in UiPath. I am struggling to come up with a regular expression that I can use to search for a PO Number. The text that comes from the scrape is fairly unstructured so my best bet is to search for a set of numbers that starts with a 'PO' with no space. For example, "PO1234567890". I will be setting a variable so the system knows that no PO number was found if the string doesn't come up with anything. Any reference material would be welcome as I am a beginner to VB. Thanks!
I have researched and cannot find a way to do the type of search I would like to do.
I expect to be able to search for a "PO1234567890" and no let something like "PO" save. So I somehow need to be able to search for "PO - two digits" and any numbers following without whitespace.
Just try the following:
Dim Regex As System.Text.RegularExpressions.Regex
Regex = New System.Text.RegularExpressions.Regex("PO[0-9]+")
Regex.Matches(SearchString)
The regex string PO[0-9]+ means:
PO followed by at least one number
if you want more digits for example 3... just use PO[0-9]{3}[0-9]* that means:
PO followed by three numbers and as numbers as it can match.
If you need help using regex matches just ask.
Hope it helps!
I have a test string such as: The Sun and the Moon together, forever
I want to be able to type a few characters or words and be able to match this string if the characters appear in the correct sequence together, even if there are missing words. For example, the following search word(s) should all match against this string:
The Moon
Sun tog
Tsmoon
The get ever
What regex pattern should I be using for this? I should add that the supplied test strings are going to be dynamic within an app, and so I'd like to be able to use a pattern based on the search string.
From your example Tsmoon you show partial words (T), ignoring case (s, m) and allow anything between each entered character. So as a first attempt you can:
Set the ignore case option
Between each chapter input insert the regular expression to match zero or more of anything. You can choose whether to match the shortest or longest run.
Try that, reading the documentation for NSRegularExpression if you're stuck, and see how it goes. If you get stuck ask a new question showing your code and the RE constructed and explain what happens/doesn't work as expected.
HTH
Problem
I need to format an input field visually in order to help the user know what they should type as a phone number. For example, I want to accept a phone number as being a 3 digit area code, 3 digit prefix and 4 digit suffix: (207) 555-1212. I want to:
provide the helper formatting to the input field -- those parentheses and the hyphen
I don't want the 'helper' characters to be included in the actual data I store in my model.
As the user types, I want the parentheses to magically appear, then have the hyphen also appear at the right point.
What's the best way to do it?
Note: This is not for displaying of a number -- I could use a filter for that. This is for formatting data within an input field.
Thanks for your help!
If you are looking for a simple solution, you could give AngularUI a try, http://angular-ui.github.com/
This is the example from the "Mask" section of that page:
<input ng-model="maskDemo" ui-mask="'99-99-9999'">
The "9"'s are numbers, and other stuff is just a mask / placeholders. It should only submit the actual values. You would edit the mask to include parentheses and anything else you may need.
I'm working on a translator that will take English language text (as user input into a UITextView) and (with a button press) replace specific words with alternatives. I have both the English words in scope plus their alternatives in separate Arrays (englishArray and alternativeArray), indexed correspondingly.
My challenge is finding an algorithm that will allow me to identify a word in the input text (a UITextView) ignoring characters like <",.()>, lookup the word in englishArray (case insensitive), locate the corresponding word in alternativeArray and then use that word in place of the original - writing it back to the UITextView.
Any help greatly appreciated.
NB. I have created a Category extending the NSArray functionality with a indexOfCaseInsensitiveString method that ignores case when doing an indexOfObject type lookup if that helps.
Tony.
I think that using an NSScanner would be best to parse the string into separate words which you could then pass to your indexOfCaseInsensitiveString method. scanCharactersFromSet:intoString: using a set of all the characters you want to ignore, including whitespace and newline characters should get you to the start of a word, and then you could use scanUpToCharactersFromSet:intoString: using the same set to scan to the end of the word. Using scanLocation at the beginning and end of each scan should allow you to get the range of that word, so if you find a match in your array, you will know where in your string to make the replacement.
Thanks for your suggestion. It's working with one exception.
I want to capture all punctuation so I can recreate the original input but with the substituted words. Even though I have a 'space' in my Character Set, the scanner is not putting the spaces into the 'intoString'. Other characters I specify in the Character Set such as '(' and ';' are represented in the 'intoString'.
Net is that when I recreate the input, it's perfect except that I get individual words running into each other.
UPDATE: I fixed that issue by including:
[theScanner setCharactersToBeSkipped:nil];
Thanks again.
I'd like to create a regular expression such that when I compare the a string against an array of strings, matches are returned with the regex ignoring certain characters.
Here's one example. Consider the following array of names:
{
"Andy O'Brien",
"Bob O'Brian",
"Jim OBrien",
"Larry Oberlin"
}
If a user enters "ob", I'd like the app to apply a regex predicate to the array and all of the names in the above array would match (e.g. the ' is ignored).
I know I can run the match twice, first against each name and second against each name with the ignored chars stripped from the string. I'd rather this by done by a single regex so I don't need two passes.
Is this possible? This is for an iOS app and I'm using NSPredicate.
EDIT: clarification on use
From the initial answers I realized I wasn't clear. The example above is a specific one. I need a general solution where the array of names is a large array with diverse names and the string I am matching against is entered by the user. So I can't hard code the regex like [o]'?[b].
Also, I know how to do case-insensitive searches so don't need the answer to focus on that. Just need a solution to ignore the chars I don't want to match against.
Since you have discarded all the answers showing the ways it can be done, you are left with the answer:
NO, this cannot be done. Regex does not have an option to 'ignore' characters. Your only options are to modify the regex to match them, or to do a pass on your source text to get rid of the characters you want to ignore and then match against that. (Of course, then you may have the problem of correlating your 'cleaned' text with the actual source text.)
If I understand correctly, you want a way to match the characters "ob" 1) regardless of capitalization, and 2) regardless of whether there is an apostrophe in between them. That should be easy enough.
1) Use a case-insensitivity modifier, or use a regexp that specifies that the capital and lowercase version of the letter are both acceptable: [Oo][Bb]
2) Use the ? modifier to indicate that a character may be present either one or zero times. o'?b will match both "o'b" and "ob". If you want to include other characters that may or may not be present, you can group them with the apostrophe. For example, o['-~]?b will match "ob", "o'b", "o-b", and "o~b".
So the complete answer would be [Oo]'?[Bb].
Update: The OP asked for a solution that would cause the given character to be ignored in an arbitrary search string. You can do this by inserting '? after every character of the search string. For example, if you were given the search string oleary, you'd transform it into o'?l'?e'?a'?r'?y'?. Foolproof, though probably not optimal for performance. Note that this would match "o'leary" but also "o'lea'r'y'" if that's a concern.
In this particular case, just throw the set of characters into the middle of the regex as optional. This works specifically because you have only two characters in your match string, otherwise the regex might get a bit verbose. For example, match case-insensitive against:
o[']*b
You can add more characters to that character class in the middle to ignore them. Note that the * matches any number of characters (so O'''Brien will match) - for a single instance, change to ?:
o[']?b
You can make particular characters optional with a question mark, which means that it will match whether they're there or not, e.g:
/o\'?b/
Would match all of the above, add .+ to either side to match all other characters, and a space to denote the start of the surname:
/.+? o\'?b.+/
And use the case-insensitivity modifier to make it match regardless of capitalisation.