AWKing or GREPing brackets [ ]? - awk

Question

I've searched all over and couldn't find a solution.
How would I awk or grep the following:
$ mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration
[/dev/cdc-wdm0] IPv4 configuration available: 'address, gateway, dns'
IP [0]: '11.22.333.44/55'
Gateway: '14.13.198.4'
DNS [0]: '172.17.1.101'
DNS [1]: '172.17.1.102'
DNS [2]: '172.17.1.101'
DNS [3]: '172.17.1.102'
So that I end up with:
11.22.33.44/55
I've tried a bunch of different combinations with both grep and awk and couldn't find a solution.

Answer 1

Using cat file as I don't have mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration:
$ cat file | awk -F"'" '/IP \[/{print $2}'
11.22.333.44/55
$ cat file | awk -F"'" '/Gateway/{print $2}'
14.13.198.4
or maybe this is all you need if the output of that command always looks like the example you posted:
$ cat file | awk -v RS= -F"'" '{print $5}'
11.22.333.44/55
$ cat file | awk -v RS= -F"'" '{print $8}'
14.13.198.4

Answer 2

You can do this in a single awk:
mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration |
awk '$1 == "IP" {gsub(/\047/, "", $NF); print $NF}'
11.22.333.44/55

Answer 3

something like this:
grep '[0-9]' file_with_text | awk '{print $NF}
grep [0-9] only lines with numbers and pipe the output into awk.
The $NF will return the last element.
If you want only the line that has the /, just add it to grep [0-9]/.
Also, for a complete answer, you can pipe the output of the command into grep:
mbimcli -d /dev/cdc-wdm0 -p --query-ip-configuration | grep '[0-9]/' | awk '{print $NF}

Answer 4

I would harness tr for preprocessing and GNU AWK for processing, let file.txt content be
IP [0]: '11.22.333.44/55'
Gateway: '14.13.198.4'
DNS [0]: '172.17.1.101'
DNS [1]: '172.17.1.102'
DNS [2]: '172.17.1.101'
DNS [3]: '172.17.1.102'
then
cat file.txt | tr -d "'" | awk '/IP/{print $NF}'
output
11.22.333.44/55
Explanation: use tr to delete ' then awk to print last column ($NF) if row contain IP.
(tested in tr (GNU coreutils) 8.30 and GNU Awk 5.0.1)