I have query below, I want sequence result like the value of 'feb' will sum by jan and feb, value of 'mar' will sum by jan, feb and mar,... . Is there any way to get the result like that?
select A.location as location
, count(Case When SUBSTRING(A.base_date,5,2)='01' Then A.customer_no else null end) as "jan"
, count(Case When SUBSTRING(A.base_date,5,2)='02' Then A.customer_no else null end) as "feb"
....
, count(Case When SUBSTRING(A.base_date,5,2)='12' Then A.customer_no else null end) as "dec"
from table_income A group by A.location;
SQL is a much more effective language when you think in rows rather than columns (normalisation).
For example, having one row per month is much simpler...
SELECT
location,
SUBSTRING(base_date,5,2) AS base_month,
SUM(COUNT(customer_no))
OVER (
PARTITION BY location
ORDER BY SUBSTRING(base_date,5,2)
)
AS count_cust
FROM
table_income
GROUP BY
location,
SUBSTRING(base_date,5,2)
Side notes:
If your base_date is a string, it shouldn't be, use data-types relevant to the data
If your base_date is a date or timestamp, you should really use date/timestamp functions, such as EXTRACT(month FROM base_date).
You probably should also account for different years...
SELECT
location,
DATE_TRUNC('month', base_date) AS base_month,
SUM(COUNT(customer_no))
OVER (
PARTITION BY location, DATE_TRUNC('year', base_date)
ORDER BY DATE_TRUNC('month', base_date)
)
AS count_cust
FROM
table_income
GROUP BY
location,
DATE_TRUNC('month', base_date)
Try this :
SELECT A.location as location
, count(Case When SUBSTRING(A.base_date,5,2) in ('01') Then A.customer_no else null end) as "jan"
, count(Case When SUBSTRING(A.base_date,5,2) in ('01','02') Then A.customer_no else null end) as "feb"
....
, count(Case When SUBSTRING(A.base_date,5,2) in ('01','02',...'12') Then A.customer_no else null end) as "dec"
from table_income A group by A.location;
Related
I need to select a max date (DATA_RIF_PATR_KU) for the key PROT, CODICE_COM, but there are also 9999-12-31 values. So when there are others date than 9999-12-31 I need to select the "real max date" else 9999-12-31.
For example:
For the combination:
PROT = '202000060300' AND
CODICE_COM='Z01'
I have 2 dates of DATA_RIF_PATR_KU: 03-11-20, 9999-12-31. I need to select the first one.
I wrote this code:
'''
SELECT
A.GRADO,
A.COMM,
A.PROT,
MAX(A.FLAG_VAL_IND) AS FLAG_VAL_IND,
SUM(A.CONT_VERS) AS CONT_VERS,
SUM(A.IMP_PREN) AS IMP_PREN,
SUM(A.CONT_DIFF) AS CONT_DIFF,
MIN(A.DATA_VER) AS DATA_VER,
MAX(A.PREN_DEB) AS PREN_DEB,
MAX(A.PREN_DEB_VER) AS PREN_DEB_VER,
MAX(A.GRAT_PATR_KU) AS GRAT_PATR_KU,
MAX(CASE WHEN (A.MAX_DATA_RIF_PATR_NON_9999)='SI' THEN A.DATA_RIF_PATR_KU
WHEN (A.MAX_DATA_RIF_PATR_NON_9999_2)='SI2' THEN A.DATA_RIF_PATR_KU END) AS DATA_RIF_PATR_KU,
SUM(A.MAGG_PEC) AS MAGG_PEC,
MAX(A.ASS_PEC) AS ASS_PEC,
MAX(A.ASS_CF) AS ASS_CF,
MAX(A.ASS_VAL) AS ASS_VAL,
MAX(A.FLAG_LAV) AS FLAG_LAV,
SUM(A.CONT_DIC) AS CONT_DIC,
SUM(A.CONT_TOT) AS CONT_TOT,
SUM(A.CONT_DIFF_VERIF) AS CONT_DIFF_VERIF,
MAX(A.DATA_AGG) AS DATA_ULTIMA_VALIDAZIONE,
MAX(CASE WHEN (A.DATA_INV)<'9999-12-31'
THEN '1'
ELSE '0' END) AS PRESENZA_INVITO_PAG,
MAX(CASE WHEN (A.DATA_VERS_INV)<'9999-12-31'
THEN '1'
ELSE '0' END) AS PRESENZA_VERS_INVITO
FROM
(
SELECT
distinct BILS05_GRADO AS GRADO,
BILS05_CODICE_COM AS COMM,
BILS05_PROT AS PROT,
CASE WHEN BILS05_FLAG_VAL_IND IN ('0','9')
THEN 'D'
ELSE 'I' END AS FLAG_VAL_IND,
bils05_tipo_doc, bils05_prog_alleg, bils05_pren_deb as pren_deb,
BILS05_PREN_DEB_VERIF AS PREN_DEB_VER,
CASE WHEN BILS05_PREN_DEB='1' AND BILS05_PREN_DEB_VERIF='1'
THEN 0
ELSE BILS05_CONT_VERS_VERIF END AS CONT_VERS,
CASE WHEN BILS05_PREN_DEB='1' AND BILS05_PREN_DEB_VERIF='1'
THEN BILS05_CONT_VERS_VERIF
ELSE 0 END AS IMP_PREN,
BILS05_CONT_DIFF AS CONT_DIFF,
BILS05_DATA_ACQ_KU AS DATA_VER,
BILS05_MAGG_PEC AS MAGG_PEC,
BILS05_ASS_PEC AS ASS_PEC,BILS05_ASS_CF AS ASS_CF,BILS05_ASS_VAL AS ASS_VAL,
BILS05_FLAG_LAV AS FLAG_LAV,
BILS05_CONT_VERS AS CONT_DIC,
BILS05_CONT_TOT AS CONT_TOT,
BILS05_CONT_DIFF_VERIF AS CONT_DIFF_VERIF,
BILS05_DATA_AGG_KU AS DATA_AGG,
BILS05_DATA_INV_PAG AS DATA_INV,
BILS05_DATA_VERS_INV AS DATA_VERS_INV,
BILS05_GRAT_PATR as GRAT_PATR_KU,
BILS05_DATA_RIF_PATR AS DATA_RIF_PATR_KU,
ROW_NUMBER() OVER(PARTITION BY BILS05_PROT, BILS05_CODICE_COM ORDER BY BILS05_DATA_RIF_PATR) AS RN,
LEAD(DATA_RIF_PATR_KU) OVER(PARTITION BY BILS05_PROT, BILS05_CODICE_COM ORDER BY DATA_RIF_PATR_KU) AS FOLLOW_DATA,
LAG(DATA_RIF_PATR_KU) OVER(PARTITION BY BILS05_PROT, BILS05_CODICE_COM ORDER BY DATA_RIF_PATR_KU) AS PREV_DATA,
CASE WHEN (DATA_RIF_PATR_KU < FOLLOW_DATA AND DATA_RIF_PATR_KU NOT = '9999-12-31' AND FOLLOW_DATA='9999-12-31' )THEN 'SI'
ELSE 'NO' END AS MAX_DATA_RIF_PATR_NON_9999,
CASE WHEN (DATA_RIF_PATR_KU NOT = '9999-12-31' AND FOLLOW_DATA IS NULL) OR (DATA_RIF_PATR_KU = '9999-12-31' AND FOLLOW_DATA IS NULL)
THEN 'SI2' ELSE 'NO' END AS MAX_DATA_RIF_PATR_NON_9999_2
FROM ZUCOW.BILS05
WHERE
BILS05_FLAG_LAV='2'
) A
WHERE
A.PROT='202000060300' AND
A.COMM='Z01'
GROUP BY A.GRADO, A.COMM, A.PROT;
'''
but it doesn't work properly. It select 9999-12-31 instead of 03-11-20 in the above example
Your example is rather long and complex, but the general idea would be
(assuming DATA_RIF_PATR_KU is a date field):
select
max(case when DATA_RIF_PATR_KU='9999-12-31' then null else DATA_RIF_PATR_KU end),
PROT, CODICE_COM
FROM FROM ZUCOW.BILS05
GROUP BY 2,3
yes that's the general idea.. Anyway at the end, I solved it in another way:
MAX(CASE WHEN TO_CHAR(A.DATA_RIF_PATR_KU, 'YYYY-MM-DD' ) LIKE ('9999-12-31')THEN '0000-12-31' ELSE TO_CHAR(A.DATA_RIF_PATR_KU, 'YYYY-MM-DD') END) AS DATA_RIF_PATR_KU_STR
So, I converted the 9999-12-31 values in 0000-12-31 (I had to to transform the date value in string), so then I could do the max and then I converted the values back in the ETL software.
Thank You all for helping
I can run this in mysql with no problem
SELECT
DATE_FORMAT(trans_date, '%Y-%m') month,
COUNTRY, COALESCE(COUNT(*), 0) trans_count,
COALESCE(SUM(CASE WHEN state ='approved' THEN 1 END), 0) approved_count,
COALESCE(SUM(amount), 0) trans_total_amount,
COALESCE(SUM(CASE WHEN state ='approved' THEN amount END), 0) approved_total_amount
FROM
Transactions
GROUP BY
month, COUNTRY
ORDER BY
month;
but the same query doesn't run in Orcale, I can't use GROUP BY using aggregation alias, and I can't aggregate without using GROUP BY.
I can call subquery over subquery or use CTE, but it is just so tedious.
What is a good query for type of issue?
As mentioned in another answer, You can not add aliases in GROUP BY but you can add aliases in ORDER BY. Also, DATE_FORMAT is MySql function. It is TO_CHAR in Oracle.
So your final query should be as following:
SELECT
TO_CHAR(TRANS_DATE, 'YYYY-MM') AS MONTH,
COUNTRY,
COUNT(*) AS TRANS_COUNT,
SUM(CASE WHEN STATE = 'approved' THEN 1 ELSE 0 END) AS APPROVED_COUNT,
SUM(AMOUNT) AS TRANS_TOTAL_AMOUNT,
SUM(CASE WHEN STATE = 'approved' THEN AMOUNT ELSE 0 END) AS APPROVED_TOTAL_AMOUNT
FROM TRANSACTIONS
GROUP BY TO_CHAR(TRANS_DATE, 'YYYY-MM'), COUNTRY
ORDER BY MONTH;
Oracle doesn't support aliases for the GROUP BY. Also, the COALESCE() is unnecessary in this case:
SELECT DATE_FORMAT(trans_date, '%Y-%m') as month, COUNTRY,
COUNT(*) as trans_count,
SUM(CASE WHEN state ='approved' THEN 1 ELSE 0 END) as approved_count,
SUM(amount) as trans_total_amount,
SUM(CASE WHEN state = 'approved' THEN amount ELSE 0 END) as approved_total_amount
FROM Transactions
GROUP BY DATE_FORMAT(trans_date, '%Y-%m'), COUNTRY
ORDER BY month;
I have table that contain Id,Date and Status i.e open/close
i just want a result in sql that contain month wise open,close and total count of Id's
e.g In Jan open count 15,close count 5 and total count 20
Use RollUp() and Group By as below:
;WITH T AS
(
SELECT
Id,
DATENAME(MONTH,[Date]) AS [MonthName],
Status
FROM #tblTest
)
SELECT
[MonthName],
[Status],
StatusCount
FROM
(
SELECT
MonthName,
CASE ISNULL(Status,'') WHEN '' THEN 'Total' ELSE Status END AS Status,
Count(Status) AS StatusCount
FROM T
GROUP BY ROLLUP([MonthName],[Status])
)X
WHERE X.MonthName IS NOT NULL
ORDER BY X.[MonthName],X.[Status]
Output:
Note: If required data in single row by month then apply PIVOT
select year(date), month(date),
sum(case when status = 'open' then 1 else 0 end) as open_count,
sum(case when status = 'closed' then 1 else 0 end) as closed_count,
count(*) as total_count
from your_table
group by year(date), month(date)
I have looked at related Qs on Stack.
I am trying to sort my query to display month in ascending order. A similar post on Stack said that I must indicate "ASC", but this doesn't work for me. I have written an Order By. I cannot figure out why it is not working.
SELECT DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date]
FROM Submission
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate)) ORDER BY [Date] ASC;
This is the output:
Month
August
February
September
Note: this is just a part of my query, I didnt think it would necessary to show the rest, which relates to other attributes from my table (Not month related)
Edit: This is my Entire Query: (The Initial One)
SELECT DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date],
SUM( CASE WHEN Submission.Status='Under review' THEN 1 ELSE 0 END) [Under_Review],
SUM( CASE WHEN Submission.Status='Accepted' THEN 1 ELSE 0 END) [Accepted],
SUM( CASE WHEN Submission.Status='Rejected' THEN 1 ELSE 0 END) [Rejected],
SUM( CASE WHEN Submission.Status='In print' THEN 1 ELSE 0 END) [In_print],
SUM( CASE WHEN Submission.Status='Published' THEN 1 ELSE 0 END) [Published]
FROM Submission INNER JOIN ((Faculty INNER JOIN School ON Faculty.FacultyID = School.[FacultyID]) INNER JOIN (Researcher INNER JOIN ResearcherSubmission ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID) ON School.SchoolID = Researcher.SchoolID) ON Submission.SubmissionID = ResearcherSubmission.SubmissionID
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate))
ORDER BY DATENAME( MONTH,(Submission.SubmissionDate));
SELECT DATENAME( MONTH, Submission.SubmissionDate) AS [Date]
FROM Submission
ORDER BY datepart(mm,Submission.SubmissionDate)
You don't need a group by (for the query shown). Also, when you order by month name it would return results in the alphabetical order of month name. You should not use previously defined aliases in the where,order by having and group by clauses.
Edit: The problem is with the join conditions. You should correct them as per the comments in line.
SELECT DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date],
SUM( CASE WHEN Submission.Status='Under review' THEN 1 ELSE 0 END) [Under_Review],
SUM( CASE WHEN Submission.Status='Accepted' THEN 1 ELSE 0 END) [Accepted],
SUM( CASE WHEN Submission.Status='Rejected' THEN 1 ELSE 0 END) [Rejected],
SUM( CASE WHEN Submission.Status='In print' THEN 1 ELSE 0 END) [In_print],
SUM( CASE WHEN Submission.Status='Published' THEN 1 ELSE 0 END) [Published]
FROM Faculty
INNER JOIN School ON Faculty.FacultyID = School.[FacultyID]
INNER JOIN Researcher ON School.SchoolID = Researcher.SchoolID
INNER JOIN ResearcherSubmission ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID
INNER JOIN SUBMISSION ON Submission.SubmissionID = ResearcherSubmission.SubmissionID
GROUP BY DATENAME( MONTH,(Submission.SubmissionDate))
ORDER BY DATEPART( MONTH,(Submission.SubmissionDate))
A simple option is to add MONTH(Submission.SubmissionDate) to your group by clause, and order by that as well:
SELECT DATENAME( MONTH,(Submission.SubmissionDate)) AS [Date]
FROM Submission
GROUP BY MONTH(Submission.SubmissionDate), DATENAME( MONTH,(Submission.SubmissionDate))
ORDER BY MONTH(Submission.SubmissionDate)
This will work for your real query as well.
You can use MIN() or MAX():
SELECT DATENAME(MONTH,(Submission.SubmissionDate)) AS [Date]
FROM Submission
GROUP BY DATENAME(MONTH,(Submission.SubmissionDate))
ORDER BY MIN([Date]) ASC;
This chooses an arbitrary date from each group and orders by that.
By the way, you probably should care about the year as well as the month. If so:
SELECT YEAR(s.SubmissionDate), DATENAME(MONTH, s.SubmissionDate) AS [Date]
FROM Submission s
GROUP BY YEAR(s.SubmissionDate), DATENAME(MONTH, s.SubmissionDate)
ORDER BY MIN([Date]) ASC;
I want to get the highest value in my query
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
The Output would be TotalMonday ='1' and TotalTuesday ='2'
I need to get the highest value from the outputs which in this case is TotalTuesday=2
select max(daycnt) from
(Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384'
union all
Select SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384')
If you need the max between many columns:
Something interesting in SQLServer 2008 and above
SELECT (SELECT Max(v)
FROM (VALUES ([Total Monday]), ([Total Tuesday]), ...) AS value(v)) as [MaxDate]
From
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
..........
FROM tbl_sched
WHERE teacherID='2014279384'
)a
Another option:
SELECT Case When [Total Monday] > [Total Tuesday] then [Total Monday] else [Total Tuesday] End as maxvalue
FROM
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
)a
I'd say the query below is better in terms of performance and highlights the intention better, because basically we are just GROUPing by days and COUNTing the groups, we don't need CASE's or SUM's (in which case SQL Server will have to go over all the records of the selected teacher).
SELECT TOP 1 Day, COUNT(*) AS Total
FROM tbl_sched
WHERE teacherID='2014279384'
AND Day IN ('Monday','Tuesday')
GROUP BY Day
ORDER BY Total DESC
You can just group by Day, sort by COUNT(*) DESC and get the top count:
SELECT TOP (1)
TotalCount = COUNT(*)
FROM
dbo.tbl_sched
WHERE
teacherID = '2014279384'
GROUP BY
Day
ORDER BY
TotalCount DESC
;
You can also include Day into the output to return the day that had the topmost result.
You can achieve this by using Max Function
Select MAX(SUM(CASE WHEN Day='Monday' THEN 1 END)) AS 'Total Monday',
MAX(SUM(CASE WHEN Day='Tuesday' THEN 1 END)) AS 'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'