How to update a value within a column with another value- Oracle - sql

Question

I have a static table that I want to replace a particular value with a string. In other words, in my table, I want to replace the value dog in the type_1 column with 'primate'.
Here is my table:
t_id|type_1|count
1, dog, 22
2, cat, 55
3, bird, 12
Here is my expected output:
t_id|type_1|count
1, primate, 22
2, cat, 55
3, bird, 12
As you can see, I just want to replace the value dog with the value primate.
Here is my code so far:
SELECT REPLACE(t.type_1, 'dog', 'primate')
FROM table_1 t
where t.type_1 = 'dog' and t.t_id='1'
I am new to oracle sql so the syntax is a bit confusing to me. Any ideas or suggestions would help.

Answer 1

If you just want a query, use a case expression:
select t.t_id,
(case when t.type_1 = 'dog' then 'primate' else t.type_1 end) as type_1,
t.count
from table_1 t;
If you want to change the value in the table (i.e. permanently), use update:
update table_1
set type_1 = 'primate'
where type_1 = 'dog';

Answer 2

Looks like update.
This is what you have:
SQL> select * from animal;
T_ID TYPE_1 CNT
---------- ---------- ----------
1 dog 22
2 cat 55
3 bird 12
Change "dog" to "primate":
SQL> update animal set type_1 = 'primate' where type_1 = 'dog';
1 row updated.
Result:
SQL> select * from animal;
T_ID TYPE_1 CNT
---------- ---------- ----------
1 primate 22
2 cat 55
3 bird 12
SQL>
Or, if you just need a select statement, then case might do:
SQL> select t_id,
2 case when type_1 = 'dog' then 'primate'
3 else type_1
4 end as type,
5 cnt
6 from animal;
T_ID TYPE CNT
---------- ---------- ----------
1 primate 22
2 cat 55
3 bird 12
SQL>