I have a table with three columns: start_date, client_id, active.
I need to check the condition: if the user in the last month had active = 1, and at the time start_date active = 0, then assign the value 1, otherwise - 0
The dates in the table are slices for half a year, I only need to check the dates from 06.01.2021
How can I do that?
One option might be this:
select *
from your_table a
where a.active = 0
and a.date_column = :par_certain_date
and a.id in (select b.id
from your_table b
where b.id = a.id
and b.active = 1
and b.date_column= add_months(:par_certain_date, -1)
)
One option is to use window functions:
select t.*
from (select t.*,
max(active) over (partition by id
order by date_column
range between '1' month preceding and '1' month preceding
) as prev_active
from t
) t
where active = 0 and prev_active = 1 and
date = :certain_date;
Related
I want to find records in date range 1/1/19-1/7/19 which increase amount
using table HISTORY:
DATE AMOUNT ID
(Date, number, varchar2(30))
I find IDs inside range correctly
assuming increase/decrease can happens only when having two records with same Id
with suspect as
(select id
from history
where t.createddate < to_date('2019-07-01', 'yyyy-mm-dd')
group by id
having count(1) > 1),
ids as
(select id
from history
join suspect
on history.id = suspect.id
where history.date > to_date('2019-01-01', 'yyyy-mm-dd')
and history.date < to_date('2019-07-01', 'yyyy-mm-dd'))
select count(distinct id)
from history a, history b
where a.id = b.id
and a.date < b.date
and a.amount < b.amount
The problem to find increase I need to find previous record which can be before time range
I can find last previous time before time range, but I failed to use it:
ids_prevtime as (
select history.*, max(t.date) over (partition by t.id) max_date
from history
join ids on history.userid = ids.id
where history.date < to_date('2019-01-01','yyyy-mm-dd' )
), ids_prev as (
select * from ids_prevtime where createdate=max_date
)
I see that you found solution, but maybe you could do it simpler, using lag():
select count(distinct id)
from (select id, date_, amount,
lag(amount) over (partition by id order by date_) prev_amt
from history)
where date_ between date '2019-01-01' and date '2019-07-01'
and amount > prev_amt;
dbfiddle
Add union of last history records before range with records inside range
ids_prev as
(select ID, DATE, AMOUNT
from id_before_rangetime
where createddate = max_date),
ids_in_range as
(select history.*
from history
join ids
on history.ID = ids.ID
where history.date > to_date('2019-01-01', 'yyyy-mm-dd')
and history.date < to_date('2019-07-01', 'yyyy-mm-dd')),
all_relevant as
(select * from ids_in_range union all select * from ids_prev)
and then count increases:
select count(distinct id)
from all_relevant a, all_relevant b
where a.id = b.id
and a.date < b.date
and a.amount < b.amount
Help! We're trying to create a new column (Is Valid?) to reproduce the logic below.
It is a binary result that:
it is 1 if it is the first known value of an ID
it is 1 if it is 3 seconds or later than the previous "1" of that ID
Note 1: this is not the difference in seconds from the previous record
It is 0 if it is less than 3 seconds than the previous "1" of that ID
Note 2: there are many IDs in the data set
Note 3: original dataset has ID and Date
Attached a PoC of the data and the expected result.
You would have to do this using a recursive CTE, which is quite expensive:
with tt as (
select t.*, row_number() over (partition by id order by time) as seqnum
from t
),
recursive cte as (
select t.*, time as grp_start
from tt
where seqnum = 1
union all
select tt.*,
(case when tt.time < cte.grp_start + interval '3 second'
then tt.time
else tt.grp_start
end)
from cte join
tt
on tt.seqnum = cte.seqnum + 1
)
select cte.*,
(case when grp_start = lag(grp_start) over (partition by id order by time)
then 0 else 1
end) as isValid
from cte;
I have a columns as Memnumber, activity type, activity date, activity ID. One member can have activities after few days. I want to write a case statement that if the activity date is most initial then INITIAL and if activity is most recent then MR and if there is any activity in between these 2 dates then BETWEEN. They need to be grouped by Memnumber and treatment type.
I wrote query as :
--MR County Tree
SELECT T0.MEMBERNUMBER,
T0.ACTIVITYTYPE,
T1.MR_CY17,
T1.IN_CY17,
T0.ACTIVITY_DATE,
(T0.ACTIVITYID)
FROM DLA_EXTRACT_FINAL T0
INNER JOIN (
SELECT MEMBERNUMBER,
ACTIVITYTYPE,
MAX(ACTIVITY_DATE) MR_CY17,
MIN(ACTIVITY_DATE) IN_CY17
FROM DLA20_EXTRACT_FINAL
WHERE to_char(ACTIVITY_DATE, 'YYYYMMDD') >= 20170101
AND to_char(ACTIVITY_DATE, 'YYYYMMDD') <= 20171231
GROUP BY MEMBERNUMBER,
ACTIVITYTYPE
) T1 ON T0.MEMBERNUMBER = T1.MEMBERNUMBER
AND T0.ACTIVITYTYPE = T1.ACTIVITYTYPE
AND T0.ACTIVITY_DATE = T1.MR_CY17
--where T0.ACTIVITYTYPE='MT'
WHERE t0.MEMBERNUMBER = 'M500085268'
GROUP BY T0.MEMBERNUMBER,
T0.ACTIVITYTYPE,
T1.MR_CY17,
T1.IN_CY17,
T0.ACTIVITYID,
T0.ACTIVITY_DATE
ORDER BY T0.MEMBERNUMBER,
T0.ACTIVITYTYPE,
T1.MR_CY17,
T1.IN_CY17.
Looking for a solution.
You want to use window functions. Something like:
SELECT T0.MEMBERNUMBER,
T0.ACTIVITYTYPE,
T0.ACTIVITY_DATE,
T0.ACTIVITYID,
case when row_number() over (partition by T0.MEMBERNUMBER, T0.ACTIVITYTYPE
order by T0.ACTIVITY_DATE) = 1 then 1 else 0 end most_initial,
case when row_number() over (partition by T0.MEMBERNUMBER, T0.ACTIVITYTYPE
order by T0.ACTIVITY_DATE desc) = 1 then 1 else 0 end most_recent
FROM DLA_EXTRACT_FINAL T0
Then you can use case statements to label as INITIAL if most_intial = 1, MR if most_recent = 1, or BETWEEN if both are 0.
I have a table of logged 'status changes'. I need to find the latest status change for a user, and if it was a) a certain 'type' of status change (s.new_status_id), and b) greater than 7 days old (s.change_date), then include it in the results. My current query sometimes returns the second-to-latest status change for a given user, which I don't want -- I only want to evaluate the last one.
How can I modify this query so that it will only include a record if it is the most recent status change for that user?
Query
SELECT DISTINCT ON (s.applicant_id) s.applicant_id, a.full_name, a.email_address, u.first_name, s.new_status_id, s.change_date, a.applied_class
FROM automated_responses_statuschangelogs s
INNER JOIN application_app a on (a.id = s.applicant_id)
INNER JOIN accounts_siuser u on (s.person_who_modified_id = u.id)
WHERE now() - s.change_date > interval '7' day
AND s.new_status_id IN
(SELECT current_status
FROM application_status
WHERE status_phase_id = 'In The Flow'
)
ORDER BY s.applicant_id, s.change_date DESC, s.new_status_id, s.person_who_modified_id;
You can use row_number() to filter one entry per applicant:
select *
from (
select row_number() over (partition by applicant_id
order by change_date desc) rn
, *
from automated_responses_statuschangelogs
) as lc
join application_app a
on a.id = lc.applicant_id
join accounts_siuser u
on lc.person_who_modified_id = u.id
join application_status stat
on lc.new_status_id = stat.current_status
where lc.rn = 1
and stat.status_phase_id = 'In The Flow'
and lc.change_date < now() - interval '7' day
I need to analyze some weblogs and determine if a user has visited once, taken a year break, and visited again. I want to add a flag to every row (Y/N) with a VisitId that meets the above criteria.
How would I go about creating this sql?
Here are the fields I have, that I think need to be used (by analyzing the timestamp of the first page of each visit):
VisitID - each visit has a unique Id (ie. 12356, 12345, 16459)
UserID - each user has one Id (ie. steve = 1, ted = 2, mark = 12345, etc...)
TimeStamp - looks like this: 2010-01-01 00:32:30.000
select VisitID, UserID, TimeStamp from page_view_t where pageNum = 1;
thanks - any help would be greatly appreciated.
You could rank every user's rows, then join the ranked row set to itself to compare adjacent rows:
;
WITH ranked AS (
SELECT
*,
rnk = ROW_NUMBER() OVER (PARTITION BY UserID ORDER BY TimeStamp)
FROM page_view_t
),
flagged AS (
SELECT
*,
IsReturnVisit = CASE
WHEN EXISTS (
SELECT *
FROM ranked
WHERE UserID = r.UserID
AND rnk = r.rnk - 1
AND TimeStamp <= DATEADD(YEAR, -1, r.TimeStamp)
)
THEN 'Y'
ELSE 'N'
END
FROM ranked r
)
SELECT
VisitID,
UserID,
TimeStamp,
IsReturnVisit
FROM flagged
Note: the above flags only return visits.
UPDATE
To flag the first visits same as return visits, the flagged CTE could be modified as follows:
…
SELECT
*,
IsFirstOrReturnVisit = CASE
WHEN p.UserID IS NULL OR r.TimeStamp >= DATEADD(YEAR, 1, p.TimeStamp)
THEN 'Y'
ELSE 'N'
END
FROM ranked r
LEFT JOIN ranked p ON r.UserID = p.UserID AND r.rnk = p.rnk + 1
…
References that might be useful:
WITH common_table_expression (Transact-SQL)
Ranking Functions (Transact-SQL)
ROW_NUMBER (Transact-SQL)
The other guy was faster but since I took time to do it and it's a completely different approach I might as well post It :D.
SELECT pv2.VisitID,
pv2.UserID,
pv2.TimeStamp,
CASE WHEN pv1.VisitID IS NOT NULL
AND pv3.VisitID IS NULL
THEN 'YES' ELSE 'NO' END AS IsReturnVisit
FROM page_view_t pv2
LEFT JOIN page_view_t pv1 ON pv1.UserID = pv2.UserID
AND pv1.VisitID <> pv2.VisitID
AND (pv1.TimeStamp <= DATEADD(YEAR, -1, pv2.TimeStamp)
OR pv2.TimeStamp <= DATEADD(YEAR, -1, pv1.TimeStamp))
AND pv1.pageNum = 1
LEFT JOIN page_view_t pv3 ON pv1.UserID = pv3.UserID
AND (pv3.TimeStamp BETWEEN pv1.TimeStamp AND pv2.TimeStamp
OR pv3.TimeStamp BETWEEN pv2.TimeStamp AND pv1.TimeStamp)
AND pv3.pageNum = 1
WHERE pv2.pageNum = 1
Assuming page_view_t table stores UserID and TimeStamp details of each visit of the user, the following query will return users who have visited taking a break of at least an year (365 days) between two consecutive visits.
select t1.UserID
from page_view_t t1
where (
select datediff(day, max(t2.[TimeStamp]), t1.[TimeStamp])
from page_view_t t2
where t2.UserID = t1.UserID and t2.[TimeStamp] < t1.[TimeStamp]
group by t2.UserID
) >= 365