How can I retrieve specific year in the format of “2019-05-04 11:20:22.697” in SQL query? I need the date between 2019 and 2020.
select * from date where date between '2019-01-01' and '2020-01-01'
If you want a query to just target the year 2019, then use:
SELECT *
FROM yourTable
WHERE date >= '2019-01-01' AND date < '2020-01-01';
This will include the entire 2019 calendar year, up to, but not including, January 1 of 2020. Note also that the above WHERE clause, as written, is sargable, meaning that the above query could take advantage of an index on the date column for doing the search.
Related
I would like to select from a table where the date falls within a specific time each year f.e:
select * from Customer where date >= August 15th and date <= December 20th
Since this will be for a report that runs every year, I do not want to hardcore the date as I will have to change it every year. I would like to have it dynamic to pick the date from August 15th to December 20th of the current year.
I have the below query where I can retrieve the Month and Date:
SELECT DATENAME(month, date) AS Month,DATENAME(day, date) AS Day from Customer
However, I am struggling to have this selection date range.
TIA
In SQL SERVER 2017
maybe this can help you:
SELECT * FROM Customer WHERE date BETWEEN
CONVERT(DATETIME,CONCAT(YEAR(GETDATE()),'08','15')) AND
CONVERT(DATETIME,CONCAT(YEAR(GETDATE()),'12','20'))
This add the current year to a concatenated date you want, then convert it all into datetime type..
I have a date field in one of my tables and the column name is from_dt. Now I have to compare a month and year combination against this from_dt field and check whether the month has already passed. The current database function uses separate conditions for the month and the year, but this is wrong as it will compare month and year separately. The current code is like this
SELECT bill_rate, currency FROM table_name WHERE
emp_id = employee_id_param
AND EXTRACT(MONTH FROM from_dt) <= month_param
AND EXTRACT(YEAR FROM from_dt) <= year_param
Now the fromt_dt field has value 2021-10-11. If I give month_param as 01 and year_param as 2022, this condition will not work as the month 10 is greater than 1, which I have given. Basically, I need to check whether 01-2022 (Jan 2022) is greater than r equal to 2021-10-01(October 1st, 2021). It would be very much helpful if someone can shed some light here.
If you just want to check whether one date is >= then another:
# select '2022-01-01'::date >= '2021-10-11'::date;
?column?
----------
t
If you want to restrict to year/month then:
select date_trunc('month','2022-01-01'::date) >= date_trunc('month', '2021-10-11'::date);
?column?
----------
t
Where the date_trunc components are:
select date_trunc('month','2022-01-01'::date) ;
date_trunc
------------------------
2022-01-01 00:00:00-08
select date_trunc('month','2021-10-11'::date) ;
date_trunc
------------------------
2021-10-01 00:00:00-07
See Postgres date_trunc for more information.
Assuming the given year_param and month_param are integers you can use the make_date function to create the first of the year_month and date_trunc to get the first on the month from the table. Just compare those values. (See date functions) So:
select bill_rate, currency
from table_name
where emp_id = employee_id_param
and date_trunc('month',from_dt) =
make_date( year_param, month_param, 01);
How to write a SQL/Oracle query to retrieve all those customers whose age in months is more than 200 months?
I have a exam on Monday but I am having some confusion with months and dates calculation.
You can use a Query like this for MySQL:
SELECT *
FROM yourTable
WHERE bithdayField <= NOW() - INTERVAL 200 MONTH;
The logic is the same (the date is older than today minus 200 months), but the actual SQL is usually different, because DBMSes have a large variation of syntax in the date/time area.
Standard SQL & MySQL:
WHERE datecol < current_date - interval '200' month
Oracle:
WHERE datecol < add_months(current_date, -200)
In fact Oracle also supports the Standard SQL version, but it's not recommended, because you might get an invalid date error when you do something like '2018-03-31' - interval '1' month. This is based on a (dumb) Standard SQL rule which MySQL doesn't follow: one month before March 31 was February 31, oops, that date doesn't exists.
In Oracle DB, there are two nice functions : months_between and add_months
been used for these type date calculations. For your case, you may use one of the following :
select id, name, surname
from customers
where months_between(trunc(sysdate),DOB)>200;
or
select id, name, surname
from customers
where add_months(trunc(sysdate),-200)>DOB;
demo
How can i write SQL which will fetch the data for current year -4
e.g. if i run this sql today so it should give me the data from 2014 to till date
if i run this sql in 2019 so it should give me the data from 2015 to till date
please assist.
You can make use of interval
SELECT *
FROM yourtable
WHERE yourcolumn >= trunc(sysdate, 'yyyy') - interval '4' year
AND yourcolumn < trunc(sysdate, 'yyyy');
This will produce results from 2015/Jan/01 to till date; If you need exactly 4 years worth of data then you need to tweak this SQL to include date and month along with the year.
I have a date column in the format YY-MON-DD, e.g. 25-JUN-05. Is it possible to isolate this into 3 separate columns for year, month and day? Where month is converted from text to numerical, e.g. Year: 25, Month: 06, Day: 05?
MS SQL SERVER
As Nebi suggested, you can use DATEPART and extract each part and store it into different columns.
SELECT DATEPART(DAY,'2008-10-22'); -- Returns DAY part i.e 22
SELECT DATEPART(MONTH,'2008-10-22'); -- Returns MONTH part i.e 10
SELECT DATEPART(YEAR,'2008-10-22'); -- Returns YEAR part i.e 2008
Try with the below script,if you are using SQL Server.
SELECT 'Year: '+CAST(LEFT(YourdateColumn,2) as VARCHAR(2))+', Month: ' +CAST(MONTH('01-'+SUBSTRING(YourdateColumn,4,3)+'-15')as VARCHAR(2))+', Day:'+CAST(RIGHT(YourdateColumn,2)as VARCHAR(2))
FROM Yourtable
sample output :
You didn't specify your DBMS.
The following is standard SQL assuming that column really is a DATE column
select extract(year from the_column) as the_year,
extract(month from the_column) as the_month,
extract(day from the_column) as the_day
from the_table;