Combine multiple rows to single row group by Specific column - sql

I have a table that looks similar to this here:
I would like to able to combine all that data when they have the same Id.
Which would look like this:

Use conditional aggregation:
select id,
max(case when seqnum = 1 then section end) as section1,
max(case when seqnum = 1 then value1 end) as section1_value1,
max(case when seqnum = 1 then value2 end) as section1_value2,
max(case when seqnum = 2 then section end) as section2,
max(case when seqnum = 2 then value1 end) as section2_value1,
max(case when seqnum = 2 then value2 end) as section2_value2
from (select t.*,
row_number() over (partition by id order by section) as seqnum
from t
) t
group by id;

Related

Transpose multiple rows to multiple columns with no aggregate using T-SQL

Users have multiple certificates which might be of 3 different types. They may hold multiple certificates of those types. I would like to put them into a single record anticipating that they will have a max of five certificates of each type.
I've written a query that will find the type and put its information into an appropriately named column but still get one row per certificate.
Data shape is:
Name, cert_Type, Cert Name, cert_State, Cert_Expiration
JOE, Equipment, NULL, Operator, 01/30/2022
JOE Equipment, Rigger, 12/31/2021
JOE License, Maryland, 08/12/2025
I'm doing a group by, but still need some aggregating function to get the desired result which might look like this:
| UserName| userID|Cred_Type_1|Cred_1|Type_1_Cred_1_ Expires|Type_1_Cred_2|Type_1_Cred_2_Expires|Cred_type_2|Type2_State |Type_2_expires|
| ----------- | ----------- |-------------|-------------|------------|------------|-----------|-----------|---|---|
|Joe|123|Equipment|Operator|01/30/2022|Rigger|12/31/2021|License | Maryland|08/12/2025|
Note that there is no aggregate here, not counting or averaging or summing. Is there another aggregate function that will do this?
If I understand correctly, you can use row_number() and conditional aggregation:
select userid, username,
max(case when seqnum = 1 then cert_type end),
max(case when seqnum = 1 then cert_name end),
max(case when seqnum = 1 then cert_state end),
max(case when seqnum = 1 then cert_expiration end),
max(case when seqnum = 2 then cert_type end),
max(case when seqnum = 2 then cert_name end),
max(case when seqnum = 2 then cert_state end),
max(case when seqnum = 2 then cert_expiration end),
max(case when seqnum = 3 then cert_type end),
max(case when seqnum = 3 then cert_name end),
max(case when seqnum = 3 then cert_state end),
max(case when seqnum = 3 then cert_expiration end),
from (select t.*,
row_number() over (partition by userid order by cert_expiration desc) as seqnum
from t
) t
group by userid, username;

How to pivot row data into specific columns db2

I would like to pivot results from a table into a new structure. So that it can map all the children to the parent product.
Current Result
Parent_Prod_Num|Child_Prod_Num|Child_Prod_Code|Child_Prod_Name
1|11|a123|a
1|12|b123|ab
1|13|c123|abc
Expected Result
Parent_Prod_Num|Child_Prod_Num_1| Child_Prod_Code_1|Child_Prod_Name_1| Child_Prod_Num_2| Child_Prod_Code_2|Child_Prod_Name_2| Child_Prod_Num_3| Child_Prod_Code_3|Child_Prod_Name_3
1|11|a123|a|12|b123|ab|13|c123|abc
For a fixed maximum number of children per parent, you can enumerate the rows with row_number(), then pivot with conditional aggregation:
select parent_prod_num,
max(case when rn = 1 then child_prod_num end) as child_prod_num_1,
max(case when rn = 1 then child_prod_code end) as child_prod_code_1,
max(case when rn = 1 then child_prod_name end) as child_prod_name_1,
max(case when rn = 2 then child_prod_num end) as child_prod_num_2,
max(case when rn = 2 then child_prod_code end) as child_prod_code_2,
max(case when rn = 2 then child_prod_name end) as child_prod_name_2,
max(case when rn = 3 then child_prod_num end) as child_prod_num_3,
max(case when rn = 3 then child_prod_code end) as child_prod_code_3,
max(case when rn = 3 then child_prod_name end) as child_prod_name_3
from (
select t.*, row_number() over(partition by parent_prod_num order by child_prod_num) rn
from mytable t
) t
group by parent_prod_num

Converting three Rows to one row

I'm trying to convert Rows to Columns from a MS SQL table...
my MS SQL table is like...
I want to SELECT the output as below...
I tried with pivot tables and cross join.. unfortunately could not make it.
any help is highly appreciated
You can use ROW_NUMBER() in a subquery to rank records, and the do conditional aggregation in the outer query:
SELECT
id,
SubId,
MAX(CASE WHEN rn = 1 THEN code END) Code1,
MAX(CASE WHEN rn = 1 THEN TotalAmount END) Code1TotalAmount,
MAX(CASE WHEN rn = 1 THEN TotalDays END) Code1TotalDays,
MAX(CASE WHEN rn = 2 THEN code END) Code2,
MAX(CASE WHEN rn = 2 THEN TotalAmount END) Code2TotalAmount,
MAX(CASE WHEN rn = 2 THEN TotalDays END) Code2TotalDays,
MAX(CASE WHEN rn = 3 THEN code END) Code3,
MAX(CASE WHEN rn = 3 THEN TotalAmount END) Code3TotalAmount,
MAX(CASE WHEN rn = 3 THEN TotalDays END) Code3TotalDays
FROM (
SELECT
t.*,
ROW_NUMBER() OVER(PARTITION BY ID, SubId ORDER BY code) rn
FROM mytable t
) x
GROUP BY ID, SubId

SQL PIVOT table with MIN() and on Multiple columns

Here is the table structure
ID TypeX TypeXDesc XDate TypeCodeY
040001 3669 Unspecified Cat 2005-08-08 1
040001 3669 Unspecified Cat 2006-08-29 2
040001 37515 Tear Film 2005-08-08 1
040001 37999 Disor 2004-07-22 1
Transform above table INTO below USING PIVOT
ID TypeX_1 TypeXDesc_1 XDate_1 TypeCodeY_1 TypeX_2 TypeXDesc_2 XDate_2 TypeCodeY_2 TypeX_3 TypeXDesc_3 XDate_3 TypeCodeY_3
040001 3669 Unspecified Cat 2005-08-08 1 37515 Tear Film 2005-08-08 1 37999 Disor 2004-07-22 1
Look at the same TypeX code but XDate is different and we need to get Min(XDate) so first row is qualified not the second row.
You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().
Then, use conditional aggregation:
select t.id,
max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
from (select t.*,
row_number() over (partition by id, typex order by xdate as seqnum,
dense_rank() over (partition by id order by typex) as grpnum
from t
) t
group by id;

need to convert data in multiple rows with same ID into 1 row with multiple columns

I reviewed versions of my question already addressed, but some of the good tips I found (using rank() over (partition...) for example, do not seem to work in the Sybase version I am on.
I am hoping to run a procedure that pulls data organized as follows:
Email | Preference
email1 | PreferenceXYZ
email1 | PreferenceABC
And render it in a table like the following:
Email | Preference1 | Preference2
email1 | PreferenceXYZ | PreferenceABC
In essence, I have multiple records for the same person (best identified via email record as a unique identifier) and I want to capture these multiple preferences for a given user and create 1 individual record per user (per email).
If you only have two preferences, then you can use min() and max():
select email, min(preference) as preference1,
(case when min(preference) <> max(preference) then max(preference) end) as preference2
from t
group by email;
EDIT:
If you have up to seven values, then pivot using row_number():
select email,
max(case when seqnum = 1 then preference end) as preference1,
max(case when seqnum = 2 then preference end) as preference2,
max(case when seqnum = 3 then preference end) as preference3,
max(case when seqnum = 4 then preference end) as preference4,
max(case when seqnum = 5 then preference end) as preference5,
max(case when seqnum = 6 then preference end) as preference6,
max(case when seqnum = 7 then preference end) as preference7
from (select t.*, row_number() over (partition by email order by preference) as seqnum
from t
) t
group by email;
EDIT II:
You can actually do this with a correlated subquery instead of row_number():
select email,
max(case when seqnum = 1 then preference end) as preference1,
max(case when seqnum = 2 then preference end) as preference2,
max(case when seqnum = 3 then preference end) as preference3,
max(case when seqnum = 4 then preference end) as preference4,
max(case when seqnum = 5 then preference end) as preference5,
max(case when seqnum = 6 then preference end) as preference6,
max(case when seqnum = 7 then preference end) as preference7
from (select t.*,
(select count(*)
from t t2
where t2.email = t.email and
t2.preference <= t.preference
) as seqnum
from t
) t
group by email;