In SQL Server I am attempting to break a date range into hours per day and have the following bit of code which is OK for a short time frame, but rather inefficient for longer periods of time. Could anyone suggest a more efficient approach?
DECLARE #StartDate datetime = '2015-01-27 07:32:35.000',
#EndDate datetime = '2015-04-29 14:39:35.000',
#TempDate datetime = '';
SET #TempDate = #StartDate;
DECLARE #dateTimeTable TABLE (dt datetime, minCol INT);
WHILE #TempDate < #EndDate
BEGIN
INSERT INTO #dateTimeTable VALUES (CONVERT(date,#TempDate), 1)
SET #TempDate = DATEADD(minute,1,#TempDate)
END
Select dt,
FORMAT(SUM(minCol) / 60.0,'F') as Hours
from #dateTimeTable
GROUP BY dt
Thanks,
Carl
The best way would be to use recursive cte :
DECLARE #StartDate datetime = '2015-01-27 07:32:35.000',
#EndDate datetime = '2015-04-29 14:39:35.000';
WITH cte AS (
SELECT CAST(#StartDate AS DATE) startdate,DATEDIFF(minute, #StartDate, DATEADD(DAY, 1, CAST(#StartDate AS DATE) ) ) / 60.0 hours
UNION ALL
SELECT DATEADD(DAY,1, startdate), DATEDIFF(minute, DATEADD(DAY,1, startdate), CASE WHEN DATEADD(DAY,2, startdate) > #EndDate
THEN #enddate ELSE DATEADD(DAY,2, startdate) END) / 60.0
FROM cte
WHERE startdate <> CAST(#EndDate AS DATE)
)
SELECT * FROM cte
db<>fiddle here
Related
I currently have a table with a creation date and a expiry date. I currently have a sql command to get the number of valid items for a given date.
select
count(id) ,CONVERT(date, getdate())
from
table
where
createDate < getdate() and expDate > getdate()
This returns the count and current date.
Is it possible to wrote a sql query that will return the result for a range of dates, say I if wanted to plot the number of valid items over a range of 15 days?
Thanks!
Try this:
create table #datelist (ValidDateCheck date, ValidResults int)
declare #startdate date = '1/1/2015'
declare #enddate date = '2/1/2015'
declare #interval int = 1 --Use 1 if you want every day between your dates, use 2 if you want every other day, etc.
declare #datecounter date = #startdate
declare #count int
while #datecounter <= #enddate
begin
set #count =
(select count(*)
from Table
where CrtDt <= #datecounter and ExpDt > #datecounter)
insert into #datelist values (#datecounter, #count)
set #datecounter = dateadd(dd, #interval, #datecounter)
end
select * from #datelist order by 1
It loops through all the dates in your range, counting valid results for each one.
Check this,
DECLARE #StartDate DATETIME,
#EndDate DATETIME;
SELECT #StartDate = '20110501'
,#EndDate = '20110801';
SELECT
DATEADD(d, x.number, #StartDate) AS MonthName1
,
x.number
FROM master.dbo.spt_values x
WHERE x.type = 'P'
AND x.number <= DATEDIFF(MONTH, #StartDate, #EndDate);
The above query give the list of dates between 2 dates.
As per your table and question, check this also.
declare #table table(id int,frdt datetime, todt datetime)
insert into #table values (1,GETDATE()-20, GETDATE()-19)
,(2,GETDATE()-9, GETDATE()-8)
,(3,GETDATE()+20, GETDATE()+18)
,(4,GETDATE(), GETDATE()-1)
,(5,GETDATE()-20, GETDATE())
,(6,GETDATE()-10, GETDATE()+10 )
select * from #table
declare #frdt datetime = null , #todt datetime = getdate()-10
select #frdt, #todt,* from #table
where
(#frdt is null or #frdt between frdt and todt)
and
(#todt is null or #todt between frdt and todt)
select #frdt = GETDATE()-15 , #todt = GETDATE()
select #frdt, #todt,* from #table
where
(#frdt is null or #frdt between frdt and todt)
and
(#todt is null or #todt between frdt and todt)
I'm writing a report that needs to collect data each day, between 0900hs and 1700hs.
I thought it would be fine as follows:
cast(convert(char(8),t.trxtime,112)as time)
between CONVERT(VARCHAR(5),getdate(),108) >= '09:00'
and CONVERT(VARCHAR(5),getdate(),108) < '17:00'
....BUT no cigar.
Thank you!!!
Hmmm, you could just use datepart():
where datepart(hour, t.trxtime) between 9 and 16 and
cast(t.trxtime as date) = cast(getdate() as date)
I'm not sure if the date comparison is actually necessary.
You could do something like this (assuming you mean actually for the current date, and not for every date in a range:
declare #startDate datetime
declare #endDate datetime
select #startDate = '2014-11-03 09:00:00',
#endDate = '2014-11-03 17:00:00'
select *
from table
where myDate between #startDate and #endDate
if you did mean between 0900 and 1700 for each day, you could do:
declare #startDate datetime
declare #endDate datetime
select #startDate = '2014-10-03',
#endDate = '2014-11-03' -- note i'm still limiting it to a range of ~1 month
select *
from table
where myDate between #startDate and #endDate
and datepart(hour, myDate) between 9 and 17
I am looking for a query that can returns a series of date range that is one quarter long.
For example, if the input is 2/1/2013 and 3/31/2014, then the output would look like:
start end
2/1/2013 4/30/2013
5/1/2013 7/31/2013
8/1/2013 10/31/2013
11/1/2013 1/31/2014
2/1/2014 3/31/2014
Notice that the last quarter is only 2 months long. Thanks for help in advance.
Just want to add that this is what I did after I did a bit of googling. I was thinking of some more efficient way but I think this is sufficient for my purpose. The first part is to populate a date table, the second part to calculate the quarter range.
DECLARE #StartDate SMALLDATETIME
DECLARE #EndDate SMALLDATETIME
SET #StartDate = '1/1/2011'
SET #EndDate = '12/31/2011'
-- creates a date table, not needed if there is one already
DECLARE #date TABLE ( [date] SMALLDATETIME )
DECLARE #offset INT
SET #offset = 0
WHILE ( #offset < DATEDIFF(dd, #StartDate, DATEADD(dd, 1, #EndDate)) )
BEGIN
INSERT INTO #date ( [date] )
VALUES ( DATEADD(dd, #offset, #StartDate) )
SELECT #offset = #offset + 1
END ;
WITH dateCTE
AS ( SELECT ROW_NUMBER() OVER ( ORDER BY [date] ASC ) AS qID ,
[date] AS qStart ,
CASE WHEN DATEADD(dd, -1, DATEADD(q, 1, [date])) > #EndDate
THEN #EndDate
ELSE DATEADD(dd, -1, DATEADD(q, 1, [date]))
END AS qEnd
FROM #date
WHERE [date] = #StartDate
OR ( DATEDIFF(mm, #StartDate, [date]) % 3 = 0
AND DATEPART(dd, [date]) = DATEPART(dd,
#StartDate)
)
)
I'm need a help to create a Query. My problem is I have a StartDate and EndDate and need separate this in blocs of 60 minutes.
DECLARE #STARTDATE AS SMALLDATETIME
DECLARE #ENDDATE AS SMALLDATETIME
SET #STARTDATE = '2012-11-21 11:03:00'
SET #ENDDATE = '2012-11-21 13:04:00'
I need the return:
Hour, Time
11 , 57
12 , 60
13 , 04
You could use a recursive CTE. For example:
declare #startDate datetime = '2012-11-21 22:05:00'
declare #endDate datetime = '2012-11-22 01:06:00'
; with TimeList as
(
select #startDate as dt
union all
select dateadd(hour, 1, dateadd(hour, datediff(hour, 0, dt), 0))
from TimeList
where dateadd(hour, 1, dt) < #endDate
)
select dt
from TimeList
union all
select #endDate
The snippet dateadd(hour, datediff(hour, 0, dt), 0) removes the hours and minutes from a date. It does so by calculating the number of hours since date 0 and then adding that number of hours to date 0.
Live example at SQL Fiddle.
I unsure if i understood you but this will return the hour and minute after your start date at 60 min intervals.
DECLARE #STARTDATE AS SMALLDATETIME
DECLARE #ENDDATE AS SMALLDATETIME
DECLARE #time AS TABLE(id int identity(1,1), [hour] int, [time] int)
SET #STARTDATE = '2012-11-21 11:03:00'
SET #ENDDATE = '2012-11-21 13:04:00'
WHILE #STARTDATE < #ENDDATE
BEGIN
SELECT #STARTDATE = DATEADD(MINUTE,60,#STARTDATE)
INSERT INTO #time (hour,time)
VALUES(DATEPART(HOUR,#STARTDATE),DATEPART(MINUTE,#STARTDATE))
END
SELECT * FROM #time
You coan do it in three pieces. First piece is for the first hour, 60 minus the minute value, 2nd piece is time=60 for all hours between start+1 and end, third piece is end minutes
and then insert them into a temp table, as abstractChaos has done.
Insert into temp table like AbstractChaos:
DECLARE #STARTDATE AS SMALLDATETIME
DECLARE #ENDDATE AS SMALLDATETIME
DECLARE #TIME AS TABLE(id INT IDENTITY(1,1), [HOUR] INT, [TIME] INT)
SET #STARTDATE = '2012-11-21 11:03:00'
SET #ENDDATE = '2012-11-21 13:04:00'
INSERT INTO #TIME (HOUR,TIME)
VALUES (datepart(HOUR,#startdate) ,60 - datepart(MINUTE,#startdate) )
WHILE #STARTDATE < #ENDDATE
BEGIN
SELECT #STARTDATE = DATEADD(MINUTE,60,#STARTDATE)
INSERT INTO #TIME (HOUR,TIME)
VALUES(datepart(HOUR,#STARTDATE) , 60)
END
INSERT INTO #TIME (HOUR,TIME)
VALUES(datepart(HOUR,#enddate) , datepart(MINUTE,#startdate))
Using SQL Server 2005 I have a field that contains a datetime value.
What I am trying to do is create 2 queries:
Compare to see if stored datetime is of the same month+year as current date
Compare to see if stored datetime is of the same year as current date
There is probably a simple solution but I keep hitting brick walls using various samples I can find, any thoughts?
Thanks in advance.
Compare the parts of the date:
WHERE YEAR( columnName ) = YEAR( getDate() )
While the other answers will work, they all suffer from the same problem: they apply a transformation to the column and therefore will never utilize an index on that column.
To search the date without a transformation, you need a couple built-in functions and some math. Example below:
--create a table to hold our example values
create table #DateSearch
(
TheDate datetime not null
)
insert into #DateSearch (TheDate)
--today
select getdate()
union all
--a month in advance
select dateadd(month, 1, getdate())
union all
--a year in advance
select dateadd(year, 1, getdate())
go
--declare variables to make things a little easier to see
declare #StartDate datetime, #EndDate datetime
--search for "same month+year as current date"
select #StartDate = dateadd(month, datediff(month, 0, getdate()), 0), #EndDate = dateadd(month, datediff(month, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
--search for "same year as current date"
select #StartDate = dateadd(year, datediff(year, 0, getdate()), 0), #EndDate = dateadd(year, datediff(year, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
What the statement does to avoid the transformations, is find all values greater-than or equal-to the beginning of the current time period (month or year) AND all values less-than the beginning of the next (invalid) time period. This solves our index problem and also mitigates any issues related to 3ms rounding in the DATETIME type.
SELECT * FROM atable
WHERE
YEAR( adate ) = YEAR( GETDATE() )
AND
MONTH( adate ) = MONTH( GETDATE() )
It sounds to me like DATEDIFF is exactly what you need:
-- #1 same month and year
SELECT *
FROM your_table
WHERE DATEDIFF(month, your_column, GETDATE()) = 0
-- #2 same year
SELECT *
FROM your_table
WHERE DATEDIFF(year, your_column, GETDATE()) = 0
The datepart function lets you pull the bits you need:
declare #d1 as datetime
declare #d2 as datetime
if datepart(yy, #d1) = datepart(yy, #d2) and datepart(mm, #d1) = datepart(mm, #d2) begin
print 'same'
end
You can use something like this
a)
select *
from table
where MONTH(field) = MONTH(GetDATE())
and YEAR(field) = YEAR(GetDATE())
b)
select *
from table
where YEAR(field) = YEAR(GetDATE())