I have following table,
+------+-------------+----------+---------+
| id | date | amount | amount2 |
+------+-------------+----------+---------+
| | | | 500 |
| 1 | 1/1/2020 | 1000 | |
+------+-------------+----------+---------+
| | | | 100 |
| 1 | 1/3/2020 | 1558 | |
+------+-------------+----------+---------+
| | | | 200 |
| 1 | 1/3/2020 | 126 | |
+------+-------------+----------+---------+
| | | | 500 |
| 2 | 2/5/2020 | 4921 | |
+------+-------------+----------+---------+
| | | | 100 |
| 2 | 2/5/2020 | 15 | |
+------+-------------+----------+---------+
| | | | 140 |
| 2 | 1/1/2020 | 5951 | |
+------+-------------+----------+---------+
| | | | 10 |
| 2 | 1/2/2020 | 1588 | |
+------+-------------+----------+---------+
| | | | 56 |
| 2 | 1/3/2020 | 1568 | |
+------+-------------+----------+---------+
| | | | 45 |
| 2 | 1/4/2020 | 12558 | |
+------+-------------+----------+---------+
I need to get each Id's max date and its amount and amount2 summations, how can I do this. according to above data, I need following output.
+------+-------------+----------+---------+
| | | | 300 |
| 1 | 1/3/2020 | 1684 | |
+------+-------------+----------+---------+
| | | | 600 |
| 2 | 2/5/2020 | 4936 | |
+------+-------------+----------+---------+
How can I do this.
Aggregate and use MAX OVER to get the IDs' maximum dates:
select id, [date], sum_amount, sum_amount2
from
(
select
id, [date], sum(amount) as sum_amount, sum(amount2) as sum_amount2,
max([date]) over (partition by id) as max_date_for_id
from mytable group by id, [date]
) aggregated
where [date] = max_date_for_id
order by id;
first is to use dense_rank() to find the row with latest date
dense_rank () over (partition by id order by [date] desc)
after that, just simply group by with sum() on the amount
select id, [date], sum(amount), sum(amount2)
from
(
select *,
dr = dense_rank () over (partition by id order by [date] desc)
from your_table
) t
where dr = 1
group by id, [date]
Related
I am trying to create an indicator for if a particular transaction was the first time a part was purchased from a particular vendor.
I have a dataset that looks like this:
| transaction_id | vendor_id | part_id | trans_date |
|:--------------:|:---------:|:-------:|:-----------------:|
| 9Bx*2Pc' | a | 873 | 10/12/2018 |
| 1Po.4Ot, | a | 473 | 4/22/2016 |
| 9Sk"7Kv/ | b | 123 | 7/23/2016 |
| 2Lz&7Hu& | a | 873 | 12/20/2017 |
| 8Lz)5Is# | b | 743 | 10/22/2016 |
| 5Sc'6Jl/ | a | 113 | 10/6/2016 |
| 0Ra&8Hb& | a | 653 | 10/4/2017 |
| 4Wc-8Of* | c | 333 | 8/3/2017 |
| 8Vv+9Yo/ | c | 333 | 12/7/2016 |
| 6Qh!1Ha- | c | 333 | 3/28/2017 |
| 2Ol%4Rs# | c | 333 | 5/2/2017 |
| 1Gg#8Cm% | c | 333 | 11/15/2016 |
| 0Lw(6Pv/ | d | 873 | 8/13/2017 |
| 1Gy/7Zw, | a | 443 | 10/12/2018 |
| 2Gz,4Gp. | b | 103 | 1/5/2018 |
| 5Dj)6Wc+ | a | 893 | 12/17/2016 |
| 5Hl-8Ds! | a | 903 | 12/8/2017 |
| 8Ws$3Vy* | b | 873 | 1/13/2018 |
What I am looking to do is determine if the transaction_id was the first time (sorted by trans_date), that the part_id was purchased from a vendor_id. I would imagine the ideal output to look like this:
| transaction_id | vendor_id | part_id | trans_date | first_time |
|:--------------:|:---------:|:-------:|:-----------------:|:----------:|
| 9Bx*2Pc' | a | 873 | 10/12/2018 | N |
| 1Po.4Ot, | a | 473 | 4/22/2016 | Y |
| 9Sk"7Kv/ | b | 123 | 7/23/2016 | Y |
| 2Lz&7Hu& | a | 873 | 12/20/2017 | Y |
| 8Lz)5Is# | b | 743 | 10/22/2016 | Y |
| 5Sc'6Jl/ | a | 113 | 10/6/2016 | Y |
| 0Ra&8Hb& | a | 653 | 10/4/2017 | Y |
| 4Wc-8Of* | c | 333 | 8/3/2017 | N |
| 8Vv+9Yo/ | c | 333 | 12/7/2016 | N |
| 6Qh!1Ha- | c | 333 | 3/28/2017 | N |
| 2Ol%4Rs# | c | 333 | 5/2/2017 | N |
| 1Gg#8Cm% | c | 333 | 11/15/2016 | Y |
| 0Lw(6Pv/ | d | 873 | 8/13/2017 | Y |
| 1Gy/7Zw, | a | 443 | 10/12/2018 | Y |
| 2Gz,4Gp. | b | 103 | 1/5/2018 | Y |
| 5Dj)6Wc+ | a | 893 | 12/17/2016 | Y |
| 5Hl-8Ds! | a | 903 | 12/8/2017 | Y |
| 8Ws$3Vy* | b | 873 | 1/13/2018 | Y |
So far, I have tried (which was influenced by this post):
WITH
first_instance AS (
SELECT
tbl_trans.*,
ROW_NUMBER() OVER (PARTITION BY vendor_id||part_id ORDER BY trans_date) AS row_nums
FROM
tbl_trans
)
SELECT
x.*,
CASE WHEN y.row_nums = 1 THEN 'Y' ELSE 'N' END AS first_time_indicator
FROM
tbl_trans x
LEFT JOIN first_instance y
But I am met with:
ORA-00905: missing keyword
I have created a SQL FIDDLE with this data and the query thus far for testing. How can I determine the if a transaction was a first time purchase for a part/vendor combination?
Use window functions:
select t.*,
(case when row_number() over (partition by vendor_id, part_id order by trans_date) = 1
then 'Y' else 'N'
end) as first_time
from tbl_trans t;
You don't need a join.
Apart from row_number, there are multiple ways of achieving the desired result using analytical function as follows.
You can use first_value analytical function as follows:
Select t.*,
Case
when first_value(trans_date)
over (partition by vendor_id, part_id order by trans_date) = trans_date
then 'Y'
else 'N'
end as first_time
From your_table t;
The same way, you can also use min as follows:
Select t.*,
Case
when min(trans_date)
over (partition by vendor_id, part_id) = trans_date
then 'Y'
else 'N'
end as first_time
From your_table t;
I have a data orders that looks like this:
| Order | Step | Step Complete Date |
|:-----:|:----:|:------------------:|
| A | 1 | 11/1/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/3/2019 |
| | 5 | 11/3/2019 |
| | 6 | 11/5/2019 |
| | 7 | 11/5/2019 |
| B | 1 | 12/1/2019 |
| | 2 | 12/2/2019 |
| | 3 | |
| C | 1 | 10/21/2019 |
| | 2 | 10/23/2019 |
| | 3 | 10/25/2019 |
| | 4 | 10/25/2019 |
| | 5 | 10/25/2019 |
| | 6 | |
| | 7 | 10/27/2019 |
| | 8 | 10/28/2019 |
| | 9 | 10/29/2019 |
| | 10 | 10/30/2019 |
| D | 1 | 10/30/2019 |
| | 2 | 11/1/2019 |
| | 3 | 11/1/2019 |
| | 4 | 11/2/2019 |
| | 5 | 11/2/2019 |
What I need to accomplish is the following:
For each order, assign the 'Order_Completion_Date' field as the most recent 'Step_Complete_Date'. If ANY 'Step_Complete_Date' is NULL, then the value for 'Order_Completion_Date' should be NULL.
I set up a SQL FIDDLE with this data and my attempt, below:
SELECT
OrderNum,
MAX(Step_Complete_Date)
FROM
OrderNums
WHERE
Step_Complete_Date IS NOT NULL
GROUP BY
OrderNum
This is yielding:
ORDERNUM MAX(STEP_COMPLETE_DATE)
D 11/2/2019
A 11/5/2019
B 12/2/2019
C 10/30/2019
How can I achieve:
| OrderNum | Order_Completed_Date |
|:--------:|:--------------------:|
| A | 11/5/2019 |
| B | NULL |
| C | NULL |
| D | 11/2/2019 |
Aggregate function with KEEP can handle this
select ordernum,
max(step_complete_date)
keep (DENSE_RANK FIRST ORDER BY step_complete_date desc nulls first) res
FROM
OrderNums
GROUP BY
OrderNum
You can use a CASE expression to first count if there are any NULL values and if not then find the maximum value:
Query 1:
SELECT OrderNum,
CASE
WHEN COUNT( CASE WHEN Step_Complete_Date IS NULL THEN 1 END ) > 0
THEN NULL
ELSE MAX(Step_Complete_Date)
END AS Order_Completion_Date
FROM OrderNums
GROUP BY OrderNum
Results:
| ORDERNUM | ORDER_COMPLETION_DATE |
|----------|-----------------------|
| D | 11/2/2019 |
| A | 11/5/2019 |
| B | (null) |
| C | (null) |
First, you are representing dates as varchars in mm/dd/yyyy format (at least in fiddle). With max function it can produce incorrect result, try for example order with dates '11/10/2019' and '11/2/2019'.
Second, the most simple solution is IMHO to use fallback date for nulls and get null back when fallback date wins:
SELECT
OrderNum,
NULLIF(MAX(NVL(Step_Complete_Date,'~')),'~')
FROM
OrderNums
GROUP BY
OrderNum
(Example is still for varchars since tilde is greater than any digit. For dates, you could use 9999-12-31, for instance.)
I want to calculate
(1) total sales amount
(2) number of distinct stores per product
in one query, if possible. Suppose we have data:
+-----------+---------+-------+--------+
| store | product | month | amount |
+-----------+---------+-------+--------+
| Anthill | A | 1 | 1 |
| Anthill | A | 2 | 1 |
| Anthill | A | 3 | 1 |
| Beetle | A | 1 | 1 |
| Beetle | A | 3 | 1 |
| Cockroach | A | 1 | 1 |
| Cockroach | A | 2 | 1 |
| Cockroach | A | 3 | 1 |
| Anthill | B | 1 | 1 |
| Beetle | B | 2 | 1 |
| Cockroach | B | 3 | 1 |
+-----------+---------+-------+--------+
I have tried this with no luck:
select
[product]
,[month]
,[amount]
,cnt_distinct_stores = count(distinct(stores))
from dbo.temp
group by
[product]
,[month]
order by 1,2
Would there be possible any combination of GROUP BY clause with window functions like SUM(amount) OVER(partition by [product],[month] ORDER BY [month] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
Try
SELECT product,
SUM(amount),
COUNT(DISTINCT store)
FROM dbo.temp
GROUP BY product
+--------+--------+-------+-------+
| PartId | ItemId | Price | Staus |
+--------+--------+-------+-------+
| 94669 | 3678 | 88 | 1 |
| 94669 | 3679 | 22 | 1 |
| 94669 | 3680 | 30 | 1 |
| 94669 | 3681 | 50 | 4 |
| 94670 | 3678 | 88 | 1 |
| 94670 | 3679 | 22 | 1 |
| 94670 | 3680 | 30 | 1 |
| 94670 | 3681 | 50 | 1 |
+--------+--------+-------+-------+
The expected output is (without status 4)
+--------+------------+
| PartId | TotalPrice |
+--------+------------+
| 94669 | 140 |
| 94670 | 190 |
+--------+------------+
How can I achieve this in SQL?
Pretty basic aggregation query with a where and group by.
select partid, sum(price) as totalprice
from t
where [status] <> 4
group by partid
If you have to omit status other than 1, it would be correct to use status = 1 instead:
select partid, sum(price) as totalprice
from t
where [status] = 1
group by partid
You can try:
SELECT "Part ID", SUM(Price)
FROM (
SELECT "Part ID", Price
FROM Table
WHERE Status <> 4)
GROUP BY "Part ID";
I have a table Exam_record with the data. I need to know how to pullout the latest 2 record for each EID based on latest exam date.
EID | Exam_name | score | date_of_completion |
-----------------------------------------------
1 | Exam_1 | 60 | 23-Jun-2014 |
1 | Exam_1 | 70 | 10-Jan-2014 |
1 | Exam_1 | 71 | 15-Aug-2014 |
1 | Exam_1 | 65 | 1-Sep-2014 |
2 | Exam_2 | 50 | 2-Jul-2014 |
2 | Exam_2 | 55 | 12-May-2014 |
2 | Exam_2 | 65 | 15-Apr-2014 |
Desired output is
EID | Exam_name | score | date_of_completion |
-----------------------------------------------
1 | Exam_1 | 71 | 15-Aug-2014 |
1 | Exam_1 | 65 | 1-Sep-2014 |
2 | Exam_2 | 55 | 12-May-2014 |
2 | Exam_2 | 50 | 2-Jul-2014 |
Try like this:
select * from
(
select *,row_number()over(partition by EID order by date_of_completion desc) as rn from table
)x
where x<=2
more info