Trying to get specific field from read in Ksh - while-loop

Question

I am trying to write a simple script in Ksh to look at failed attempts and look at the ip addresses. I am dumping a lastb output to a file and want to get just the username tried and the ip address it came from.
the lastb output
user ssh:notty 143.244.175.142 Mon Jun 21 01:04 - 01:04 (00:00)
user ssh:notty 143.244.175.142 Mon Jun 21 00:57 - 00:57 (00:00)
my script looks like this
#!/usr/bin/ksh
FailedLogins="$HOME/sshattempts.txt
if [ -e "$FailedLogins" ]
then
echo "yes file exists"
fi
# while loop
while IFS= read user tty ip
do
printf "$user $ip"
done <"$FailedLogins"

Answer 1

You could use something like this
#!/bin/ksh
if [[ -r $HOME/sshattempts.txt ]]; then
print "yes file $HOME/sshattempts.txt exists"
else
exit
fi
while read line; do
parts=( $line )
print "${parts[0]} ${parts[2]}"
done < $HOME/sshattempts.txt

Answer 2

During processing each line will be parsed into 10 separate (space delimited) fields. When there are not enough variables (3 in this case) the read will stuff the 'rest of the line' into the last variable.
Processing the first line from sshattempts.txt will cause the following variable assignments:
user='user'
tty='ssh:notty'
ip='143.244.175.142 Mon Jun 21 01:04 - 01:04 (00:00)'
While you can edit the code to provide the read with 10 variables, you can make use of the 'stuff rest of line into last variable' rule by adding one more variable to hold all of the fields that come after the ip field, eg:
while IFS= read user tty ip rest_of_line
Now when processing the first line from sshattempts.txt you should see:
user='user'
tty='ssh:notty'
ip='143.244.175.142'
rest_of_line='Mon Jun 21 01:04 - 01:04 (00:00)'

Answer 3

First and third entry of a line:
awk '{print $1, $3}' "$FailedLogins"