I am dealing with JSONB columns and its quite new to me.
Below is the sample data set
UUID Survey_id Employee_id Employee_Response Status
f212 2 17 [{"q_id": "5", "answer": {"value": "Agree"}, "q_type": "radio-buttons"}, {"q_id": "6", "answer": {"value": "4"}, "q_type": "star-ratings"}, {"q_id": "7", "answer": {"value": "9"}, "q_type": "slider-type"}] active
a3f5 2 46 [{"q_id": "5", "answer": {"value": "Agree"}, "q_type": "radio-buttons"}, {"q_id": "6", "answer": {"value": "4"}, "q_type": "star-ratings"}, {"q_id": "7", "answer": {"value": "8"}, "q_type": "slider-type"}] active
2db8 2 32 [{"q_id": "5", "answer": {"value": "Agree"}, "q_type": "radio-buttons"}, {"q_id": "6", "answer": {"value": "3"}, "q_type": "star-ratings"}, {"q_id": "7", "answer": {"value": "9"}, "q_type": "slider-type"}] active
d2bd 2 40 [{"q_id": "5", "answer": {"value": "Disagree"}, "q_type": "radio-buttons"}, {"q_id": "6", "answer": {"value": "2"}, "q_type": "star-ratings"}, {"q_id": "7", "answer": {"value": "3"}, "q_type": "slider-type"}] active
g632 2 31 [{"q_id": "5", "answer": {"value": "Strongly Agree"}, "q_type": "radio-buttons"}, {"q_id": "6", "answer": {"value": "3"}, "q_type": "star-ratings"}, {"q_id": "7", "answer": {"value": "6"}, "q_type": "slider-type"}] active
Expected output
UUID Survey_id Employee_id Q_5 Q_6 q_7
f212 2 17 Agree 4 9
a3f5 2 46 Agree 4 8
2db8 2 32 Agree 3 9
d2bd 2 40 Disagree 2 3
g632 2 31 Strongly Agree 3 6
Can you please suggest or help to achieve the same,
I have tried below and other various methods but still not luck in achieving it in SQL
SELECT
survey_id,
response::jsonb->'answer'->>'value' as name
FROM survey_resposnes
select survey_id,user_id,
response-> 'q_id' #> '[5]' as q0--,
from survey_resposnes
You can use jsonb_path_query_first() for this:
select r."uuid",
r.survey_id,
r.employee_id,
jsonb_path_query_first(r.employee_response, '$[*] ? (#.q_id == "5").answer.value') #>> '{}' as q_5,
jsonb_path_query_first(r.employee_response, '$[*] ? (#.q_id == "6").answer.value') #>> '{}' as q_6,
jsonb_path_query_first(r.employee_response, '$[*] ? (#.q_id == "7").answer.value') #>> '{}' as q_7
from survey_responses r
jsonb_path_query_first() returns a jsonb value. To convert that into a proper text value, the #>> '{}' is used. If you are fine with a jsonb value as the result you can remove that expression
Online example
Related
Hi I am trying to get sum of quantity group by week of current year.
Here is my query which is working
Sale::selectRaw('sum(qty) as y')
->selectRaw(DB::raw('WEEK(order_date,1) as x'))
->whereYear('order_date',Carbon::now()->format('Y'))
->groupBy('x')
->orderBy('x', 'ASC')
->get();
The response I get is look like this. where x is the week number and y is the sum value.
[
{
"y": "50",
"x": 2
},
{
"y": "4",
"x": 14
}
]
I want to get 0 values for the week that doesn't have any value for y
My desired result should be like this
[
{
"y": "0",
"x": 1
},
{
"y": "50",
"x": 2
},
...
...
...
{
"y": "4",
"x": 14
}
]
kindly need to extract name value, even it's Action or adventure from this column in new column
in pandas
'[{"id": 28, "name": "Action"}, {"id": 12, "name": "Adventure"}, {"id": 14, "name": "Fantasy"}, {"id": 878, "name": "Science Fiction"}]'
You want from_records:
import pandas as pd
data = [{"id": 28, "name": "Action"}, {"id": 12, "name": "Adventure"}, {"id": 14, "name": "Fantasy"}, {"id": 878, "name": "Science Fiction"}]
df = pd.DataFrame.from_records(data)
df
you get
id name
0 28 Action
1 12 Adventure
2 14 Fantasy
3 878 Science Fiction
I need to perform an operation in vega-lite/Kibana 6.5 similar to the next one. I need to divide y axis by "data.values[0].b". How can I perform this operation?
{
"$schema": "https://vega.github.io/schema/vega-lite/v4.json",
"description": "A simple bar chart with embedded data.",
"data": {
"values": [
{"a": "A", "b": 28}, {"a": "B", "b": 55}, {"a": "C", "b": 43},
{"a": "D", "b": 91}, {"a": "E", "b": 81}, {"a": "F", "b": 53},
{"a": "G", "b": 19}, {"a": "H", "b": 87}, {"a": "I", "b": 52}
]
},
"mark": "bar",
"encoding": {
"x": {"field": "a", "type": "ordinal"},
"y": {"field": "b", "type": "quantitative"}
}
Please take a look at Transform Calculate topic in Vega Lite docs.
You can do :
"transform": [
{"calculate": "datum.a / datum.b", "as": "y"}
]
Notice that 'datum' is the keyword used to access data set.
I have a Json like this (it is contained in a clob variable):
{"id": "33", "type": "abc", "val": "2", "cod": "", "sg1": "1", "sg2": "1"}
{"id": "359", "type": "abcef", "val": "52", "cod": "aa", "sg1": "", "sg2": "0"}
…
I need to remove " from values of: id, val, sg1, sg2
Is it possibile?
For example, I need to obtain this:
{"id": 33, "type": "abc", "val": 2, "cod": "", "sg1": 1, "sg2": 1}
{"id": 359, "type": "abcef", "val": 52, "cod": "aa", "sg1": , "sg2": 0}
…
If you are using Oracle 12 (R2?) or later then you can convert your JSON to the appropriate data types and then convert it back to JSON.
Oracle 18 Setup:
CREATE TABLE test_data ( value CLOB );
INSERT INTO test_data ( value )
VALUES ( '{"id": "33", "type": "abc", "val": "2", "cod": "", "sg1": "1", "sg2": "1"}' );
INSERT INTO test_data ( value )
VALUES ( '{"id": "359", "type": "abcef", "val": "52", "cod": "aa", "sg1": "", "sg2": "0"}' );
Query:
SELECT JSON_OBJECT(
'id' IS j.id,
'type' IS j.typ,
'val' IS j.val,
'cod' IS j.cod,
'sg1' IS j.sg1,
'sg2' IS j.sg2
) AS JSON
FROM test_data t
CROSS JOIN
JSON_TABLE(
t.value,
'$'
COLUMNS
id NUMBER(5,0) PATH '$.id',
typ VARCHAR2(10) PATH '$.type',
val NUMBER(5,0) PATH '$.val',
cod VARCHAR2(10) PATH '$.cod',
sg1 NUMBER(5,0) PATH '$.sg1',
sg2 NUMBER(5,0) PATH '$.sg2'
) j
Output:
| JSON |
| :--------------------------------------------------------------- |
| {"id":33,"type":"abc","val":2,"cod":null,"sg1":1,"sg2":1} |
| {"id":359,"type":"abcef","val":52,"cod":"aa","sg1":null,"sg2":0} |
Or, if you want to use regular expressions (you shouldn't if you have the choice and should use a proper JSON parser instead) then:
Query 2:
SELECT REGEXP_REPLACE(
REGEXP_REPLACE(
value,
'"(id|val|sg1|sg2)": ""',
'"\1": "null"'
),
'"(id|val|sg1|sg2)": "(\d+|null)"',
'"\1": \2'
) AS JSON
FROM test_data
Output:
| JSON |
| :-------------------------------------------------------------------------- |
| {"id": 33, "type": "abc", "val": 2, "cod": "", "sg1": 1, "sg2": 1} |
| {"id": 359, "type": "abcef", "val": 52, "cod": "aa", "sg1": null, "sg2": 0} |
db<>fiddle here
I have a gigantic script that I would like to create in an iterative way (while or for loop), so it becomes overviewable and much shorter. It makes so much sense that it should be doable in SQL but so far I have not succeeded. What I did now in order to make it work is a lot of selections that I UNION together to make one table.
I want to iterate through the years, so while year is lower then 2017 execute function with the year in it as variable, starting from 1995.
So actually, an iterative function that fills in all years in the following lines of code and combines all results within one table: I will keep trying myself and update the code if I make progress.
SELECT
regio, 1995 as year, sum("0") as "0", sum("1") as "1", sum("2") as "2", sum("3") as "3", sum("4") as "4", sum("5") as "5", sum("6") as "6", sum("7") as "7", sum("8") as "8", sum("9") as "9", sum("10") as "10"
FROM
source
where
year = 1995 OR "year-1" = 1995 OR "year-2" = 1995 OR "year-3" = 1995 OR "year-4" = 1995
group by
regio
UNION
SELECT
regio, 1996 as year, sum("0") as "0", sum("1") as "1", sum("2") as "2", sum("3") as "3", sum("4") as "4", sum("5") as "5", sum("6") as "6", sum("7") as "7", sum("8") as "8", sum("9") as "9", sum("10") as "10"
FROM
source
where
year = 1996 OR "year-1" = 1996 OR "year-2" = 1996 OR "year-3" = 1996 OR "year-4" = 1996
group by
regio
You would seem to want:
SELECT regio, g.yyyy as year, sum("0") as "0", sum("1") as "1",
sum("2") as "2", sum("3") as "3", sum("4") as "4",
sum("5") as "5", sum("6") as "6", sum("7") as "7",
sum("8") as "8", sum("9") as "9", sum("10") as "10"
FROM source CROSS JOIN
generate_series(1995, 2017) g(yyyy)
WHERE g.yyyy IN (year, "year-1", "year-2", "year-3", "year-4")
GROUP BY regio, g.yyyy;