How to special character after 3rd character in Oracle SQL query - sql

I want to add special character after 3rd character. Below is the example
Current Phone Number:- 123234567
Expected output :- (123)234-567
How can I do this ?

Concatenation, as you said, along with the substr function:
SQL> with test (col) as
2 (select 123234567 from dual)
3 select '(' || substr(col, 1, 3) || ')' ||substr(col, 4, 3) ||'-'|| substr(col, 7) result
4 from test;
RESULT
------------
(123)234-567
SQL>
Or, using regular expressions:
SQL> with test (col) as
2 (select 123234567 from dual)
3 select regexp_replace(col, '([0-9]{3})([0-9]{3})', '(\1)\2-') result_2
4 from test;
RESULT_2
------------
(123)234-567
SQL>

Related

convert string into rows with SQL

I have a string, like:
'one,two,three'
and I want to convert it in rows and use it into IN clause in an SQL:
one
two
three
I tried something like :
SELECT column_value
FROM XMLTable('"one","two","three"');
and it worked fine but in a join condition it fails.
SELECT 1
FROM dual
WHERE 'one' IN (SELECT column_value
FROM XMLTable('"one","two","three"'));
it gaves me the error:
ORA-00932: inconsistent datatypes: expected - got CHAR
00932. 00000 - "inconsistent datatypes: expected %s got %s"
Can anyone help me on this, please?
NOTE: I would like not use PLSQL
What you need is nothing but just casting a CLOB value to a [VAR]CHAR[2] data type such as
SELECT 1
FROM dual
WHERE 'one' IN (SELECT CAST(column_value AS VARCHAR2(20))
FROM XMLTable('"one","two","three"'))
1
---
1
in order to make it comparable with a literal(such as 'one').
Moreover, CAST might be replaceable with XMLCast as well.
You do not need XML to split the string and can use simple (fast) string functions:
WITH data (value) AS (
SELECT 'one,two,three' FROM DUAL
),
bounds (value, spos, epos) AS (
SELECT value, 1, INSTR(value, ',', 1)
FROM data
UNION ALL
SELECT value, epos + 1, INSTR(value, ',', epos + 1)
FROM bounds
WHERE epos > 0
)
SEARCH DEPTH FIRST BY value SET order_id
SELECT CASE epos
WHEN 0
THEN SUBSTR(value, spos)
ELSE SUBSTR(value, spos, epos-spos)
END as item
FROM bounds;
Which outputs:
ITEM
one
two
three
However
In your case you have an XY-problem and you DO NOT NEED to split the string as you can use LIKE to match the search string against a sub-string of your list:
SELECT 1
FROM dual
WHERE ',' || :your_list || ',' LIKE '%,' || :search_value || ',%';
or with hardcoded strings:
SELECT 1
FROM dual
WHERE ',' || 'one,two,three' || ',' LIKE '%,' || 'one' || ',%';
db<>fiddle here
Query that raised an error - if rewritten to this - works:
SQL> select 1
2 from dual
3 where 'one' in (select regexp_substr('one,two,three', '[^,]+', 1, level)
4 from dual
5 connect by level <= regexp_count('one,two,three', ',') + 1
6 );
1
----------
1
SQL>
Subquery (that uses regexp_substr) splits a comma-separated list of values ('one,two,three') into rows.
Alternatively, if you use Oracle Apex (or have it installed in your database), you can simplify it by utilizing apex_string.split:
SQL> select 1
2 from dual
3 where 'one' in (select * from apex_string.split('one,two,three', ','));
1
----------
1
SQL>
You could use REGEXP_COUNT to find your word in the list.
This would be faster than converting
But read this canonical thread Is storing a delimited list in a database column really that bad?
SELECT
CASE WHEN REGEXP_COUNT('one,two,three', '^([^,]+,)*one(,[^,]+)*$', 1, 'i') > 0
THEN 1 ELSE 0
END as cnt
FROM DUAL;
| CNT |
| --: |
| 1 |
db<>fiddle here

Multiline bind parameter

I'm trying the following query from DBeaver (backend is oracle):
SELECT * FROM mytable where mycolumn in (REPLACE( :req_id_list, CHR(13), ','))
when it prompts for the value of req_id_list I want to paste the values from Excel, which will be one value per line. the query is failing with ORA-00907: missing right parenthesis. is there a way to convert the multiline value to a CSV one ?
I don't use DBeaver so this is a SQL*Plus example. Basically, you'll have to "split" that multi-line input value into separate rows (that's what subquery in lines #8 - 10 does):
Declaring a bind variable:
SQL> var req_id_list varchar2(20)
Storing A + carriage return + C into it:
SQL> exec :req_id_list := 'A' || chr(13) || 'C';
PL/SQL procedure successfully completed.
Query itself (lines #1 - 5 represent sample data; I expect A and C to be returned as that's what I passed to req_id_list):
SQL> with mytable (mycolumn) as
2 (select 'A' from dual union all
3 select 'B' from dual union all
4 select 'C' from dual
5 )
6 select *
7 from mytable
8 where mycolumn in (select regexp_substr(replace(:req_id_list, chr(13), '#'), '[^#]+', 1, level)
9 from dual
10 connect by level <= regexp_count(:req_id_list, chr(13)) + 1
11 );
M
-
A
C
SQL>

Oracle SQL - find and replace ASCII

In my database, special characters have got inserted with these ASCII values
ASCII(' ') ASCII('')
49828 32
There is ASCII Value 49828 shown in the column description that is showing as special character ¤
How do I find all the values that have this special character? and how to replace it with a regular space (ASCII 32)
I'd say you'd use REPLACE (as you said).
Sample table:
SQL> create table test (col) as
2 select 'x' || chr(67) || 'y' from dual union all
3 select 'x' || chr(49828) || 'y' from dual;
Table created.
Contents (disregard Ą displayed in my SQL*Plus & my database):
SQL> select * from test;
COL
----
xCy
xĄy
Update only rows that contain that value:
SQL> update test set
2 col = replace(col, chr(49828), chr(32))
3 where instr(col, chr(49828)) > 0;
1 row updated.
Result:
SQL> select * from test;
COL
----
xCy
x y
SQL>

Number formatting in Oracle SQL

I have some problem here. I got to SELECT a column which the result i.e. '01201698765'. How to split this number to becoming like this : '01.2016.98765'.
I've used TO_CHAR, but the '0' (zero) number at the front was gone.
You could use:
SUBSTR
concatenation operator ||
For example,
SQL> WITH sample_data AS(
2 SELECT '01201698765' num FROM dual
3 )
4 --end of sample_data mimicking real table
5 SELECT num,
6 substr(num, 1, 2)||'.'||substr(num, 3, 4)||'.'||substr(num, 7) num_formatted
7 FROM sample_data;
NUM NUM_FORMATTED
----------- -------------
01201698765 01.2016.98765
SQL>
Assuming the column is a string, just use string operations:
select substr(col, 1, 2) || '.' + substr(col, 3, 4) + '.' + substr(col, 5, 5)

Oracle SQL inserting parenthesis into phone number

The original format:
123-456-7890
My goal format:
(123)456-7890
I wanted to go the route of concatenating between substrings but I continually get flagged for errors. I am unsure of a better method to go about implementing a way to format.
My query:
select || '(' || substr(telephone,0, 3)|| ')' ||
substr(telephone,4, 3)|| ' '||
substr(telephone,7, 4)) as telephone,
from book;
My current error:
"missing expression"
You have an extra dangling parenthesis at the end of your SELECT, and you also have a dangling concatenation operator || in the front. Try this:
SELECT '(' || SUBSTR(telephone, 0, 3) || ')' ||
SUBSTR(telephone, 4, 3) || ' ' || SUBSTR(telephone, 7, 4) AS telephone
FROM book
Update:
You should really use this query, because it turns out you also had a problem with forming your desired output as well:
SELECT '(' || SUBSTR(telephone, 1, 3) || ')' || SUBSTR(telephone, 5, 8) AS telephone
FROM book
You can use regular expressions to do.
select regexp_replace
(phoneNo,
'([[:digit:]]{3})\-([[:digit:]]{3})\-([[:digit:]]{4})',
'(\1)\2-\3'
)
from(
select '123-456-7890' as phoneNo from dual)
Output
(123)456-7890
SELECT '123-456-7890','('||SUBSTR('123-456-7890',1,3)||')'||SUBSTR('123-456-7890',5,8) FROM dual;
Using SUBSTR:
SQL> WITH sample_data AS(
2 SELECT '123-456-7890' num FROM dual
3 )
4 -- end of sample_data mimicking real table
5 SELECT num,
6 '('
7 || SUBSTR(num, 1, 3)
8 ||
9 ')'
10 || SUBSTR(num, 5, 8) AS my_num
11 FROM sample_data;
NUM MY_NUM
------------ ---------------
123-456-7890 (123)456-7890
SQL>
Remember, the index for SUBSTR starts from 1. It is bad practice to use 0 as starting index.
You could also do it using REGEXP_REPLACE.
Pattern: (\d{3})(-)(\d{3})(-)(\d{4})
Expression: regexp_replace(num, '(\d{3})(-)(\d{3})(-)(\d{4})', '(\1)\3\4\5')
For example,
SQL> WITH sample_data AS(
2 SELECT '123-456-7890' num FROM dual
3 )
4 -- end of sample_data mimicking real table
5 SELECT num,
6 regexp_replace(num, '(\d{3})(-)(\d{3})(-)(\d{4})', '(\1)\3\4\5') my_num
7 FROM sample_data;
NUM MY_NUM
------------ ---------------
123-456-7890 (123)456-7890
SQL>