I would like to resample a DataFrame with frequences of 10D but cutting the last decade always at the end of the month.
ES:
print(df)
data
index
2010-01-01 145.08
2010-01-02 143.69
2010-01-03 101.06
2010-01-04 57.63
2010-01-05 65.46
...
2010-02-24 48.06
2010-02-25 87.41
2010-02-26 71.97
2010-02-27 73.1
2010-02-28 41.43
Apply something like df.resample('10DM').mean()
data
index
2010-01-10 97.33
2010-01-20 58.58
2010-01-31 41.43
2010-02-10 35.17
2010-02-20 32.44
2010-02-28 55.44
note that the 1st and 2nd decades are normal 10D resample, but the 3rd can be 8-9-10-11 days based on month and year.
Thanks in advance.
Sample data (easy to check):
# df = pd.DataFrame({"value": np.arange(1, len(dti)+1)}, index=dti)
>>> df
value
2010-01-01 1
2010-01-02 2
2010-01-03 3
2010-01-04 4
2010-01-05 5
...
2010-02-24 55
2010-02-25 56
2010-02-26 57
2010-02-27 58
2010-02-28 59
You need to create groups by (days, month, year):
grp = df.groupby([pd.cut(df.index.day, [0, 10, 20, 31]),
pd.Grouper(freq='M'),
pd.Grouper(freq='Y')])
Now you can compute the mean for each group:
out = grp['value'].apply(lambda x: (x.index.max(), x.mean())).apply(pd.Series) \
.reset_index(drop=True).rename(columns={0:'date', 1:'value'}) \
.set_index('date').sort_index()
Output result:
>>> out
value
date
2010-01-10 5.5
2010-01-20 15.5
2010-01-31 26.0
2010-02-10 36.5
2010-02-20 46.5
2010-02-28 55.5
Related
I have a DataFrame multiData that looks like this:
print(multiData)
Date Open High Low Close Adj Close Volume
Ticker Date
AAPL 0 2010-01-04 7.62 7.66 7.59 7.64 6.51 493729600
1 2010-01-05 7.66 7.70 7.62 7.66 6.52 601904800
2 2010-01-06 7.66 7.69 7.53 7.53 6.41 552160000
3 2010-01-07 7.56 7.57 7.47 7.52 6.40 477131200
4 2010-01-08 7.51 7.57 7.47 7.57 6.44 447610800
... ... ... ... ... ... ... ...
META 2668 2022-12-23 116.03 118.18 115.54 118.04 118.04 17796600
2669 2022-12-27 117.93 118.60 116.05 116.88 116.88 21392300
2670 2022-12-28 116.25 118.15 115.51 115.62 115.62 19612500
2671 2022-12-29 116.40 121.03 115.77 120.26 120.26 22366200
2672 2022-12-30 118.16 120.42 117.74 120.34 120.34 19492100
I need to get rid of "Date 0, 1, 2, ..." column and make the actual "Date" column part of the (multi) index
How do I do this?
Use df.droplevel to delete level 1 and chain df.set_index to add column Date to the index by setting the append parameter to True.
df = df.droplevel(1).set_index('Date', append=True)
df
Open High Low Close Adj Close Volume
Ticker Date
AAPL 2010-01-04 7.62 7.66 7.59 7.64 6.51 493729600
2010-01-05 7.66 7.70 7.62 7.66 6.52 601904800
Given are two series, like this:
#period1
DATE
2020-06-22 310.62
2020-06-26 300.05
2020-09-23 322.64
2020-10-30 326.54
#period2
DATE
2020-06-23 312.05
2020-09-02 357.70
2020-10-12 352.43
2021-01-25 384.39
These two series are correlated to each other, i.e. they each mark either the beginning or the end of a date period. The first series marks the end of a period1 period, the second series marks the end of period2 period. The end of a period2 period is at the same time also the start of a period1 period, and vice versa.
I've been looking for a way to aggregate these periods as date ranges, but apparently this is not easily possible with Pandas dataframes. Suggestions extremely welcome.
In the easiest case, the output layout should reflect the end dates of periods, which period type it was, and the amount of change between start and stop of the period.
Explicit output:
DATE CHG PERIOD
2020-06-22 NaN 1
2020-06-23 1.43 2
2020-06-26 12.0 1
2020-09-02 57.65 2
2020-09-23 35.06 1
2020-10-12 29.79 2
2020-10-30 25.89 1
2021-01-25 57.85 2
However, if there is any possibility of actually grouping by a date range consisting of start AND stop date, that would be much more favorable
Thank you!
p1 = pd.DataFrame(data={'Date': ['2020-06-22', '2020-06-26', '2020-09-23', '2020-10-30'], 'val':[310.62, 300.05, 322.64, 326.54]})
p2 = pd.DataFrame(data={'Date': ['2020-06-23', '2020-09-02', '2020-10-12', '2021-01-25'], 'val':[312.05, 357.7, 352.43, 384.39]})
p1['period'] = 1
p2['period'] = 2
df = p1.append(p2).sort_values('Date').reset_index(drop=True)
df['CHG'] = abs(df['val'].diff(periods=1))
df.drop('val', axis=1)
Output:
Date period CHG
0 2020-06-22 1 NaN
1 2020-06-23 2 1.43
2 2020-06-26 1 12.00
3 2020-09-02 2 57.65
4 2020-09-23 1 35.06
5 2020-10-12 2 29.79
6 2020-10-30 1 25.89
7 2021-01-25 2 57.85
EDIT: matching the format START - STOP - CHANGE - PERIOD
Starting from the above data frame:
df['Start'] = df.Date.shift(periods=1)
df.rename(columns={'Date': 'Stop'}, inplace=True)
df = df1[['Start', 'Stop', 'CHG', 'period']]
df
Output:
Start Stop CHG period
0 NaN 2020-06-22 NaN 1
1 2020-06-22 2020-06-23 1.43 2
2 2020-06-23 2020-06-26 12.00 1
3 2020-06-26 2020-09-02 57.65 2
4 2020-09-02 2020-09-23 35.06 1
5 2020-09-23 2020-10-12 29.79 2
6 2020-10-12 2020-10-30 25.89 1
7 2020-10-30 2021-01-25 57.85 2
# If needed:
df1.index = pd.to_datetime(df1.index)
df2.index = pd.to_datetime(df2.index)
df = pd.concat([df1, df2], axis=1)
df.columns = ['start','stop']
df['CNG'] = df.bfill(axis=1)['start'].diff().abs()
df['PERIOD'] = 1
df.loc[df.stop.notna(), 'PERIOD'] = 2
df = df[['CNG', 'PERIOD']]
print(df)
Output:
CNG PERIOD
Date
2020-06-22 NaN 1
2020-06-23 1.43 2
2020-06-26 12.00 1
2020-09-02 57.65 2
2020-09-23 35.06 1
2020-10-12 29.79 2
2020-10-30 25.89 1
2021-01-25 57.85 2
2021-01-29 14.32 1
2021-02-12 22.57 2
2021-03-04 15.94 1
2021-05-07 45.42 2
2021-05-12 16.71 1
2021-09-02 47.78 2
2021-10-04 24.55 1
2021-11-18 41.09 2
2021-12-01 19.23 1
2021-12-10 20.24 2
2021-12-20 15.76 1
2022-01-03 22.73 2
2022-01-27 46.47 1
2022-02-09 26.30 2
2022-02-23 35.59 1
2022-03-02 15.94 2
2022-03-08 21.64 1
2022-03-29 45.30 2
2022-04-29 49.55 1
2022-05-04 17.06 2
2022-05-12 36.72 1
2022-05-17 15.98 2
2022-05-19 18.86 1
2022-06-02 27.93 2
2022-06-17 51.53 1
[this is tail of my DataFrame for around 1000 entries][1]
Open Close High Change mx_profitable
Date
2018-06-06 263.00 270.15 271.4 7.15 8.40
2018-06-08 268.95 273.00 273.9 4.05 4.95
2018-06-11 273.30 274.00 278.4 0.70 5.10
2018-06-12 274.00 282.85 284.4 8.85 10.40
I have to sort out the entries of only certain dates, for example, 25th of every month.
I think need DatetimeIndex.day with boolean indexing:
df[df.index.day == 25]
Sample:
rng = pd.date_range('2017-04-03', periods=1000)
df = pd.DataFrame({'a': range(1000)}, index=rng)
print (df.head())
a
2017-04-03 0
2017-04-04 1
2017-04-05 2
2017-04-06 3
2017-04-07 4
df1 = df[df.index.day == 25]
print (df1.head())
a
2017-04-25 22
2017-05-25 52
2017-06-25 83
2017-07-25 113
2017-08-25 144
I have a time Series. I'd like to group into into blocks of 24-hour blocks, from 8am to 7:59am the next day. I know how to group by date, but I've tried and failed to handle this 8-hour offset using TimeGroupers and DateOffsets.
I think you can use Grouper with parameter base:
print df
date name
0 2015-06-13 00:21:25 1
1 2015-06-14 01:00:25 2
2 2015-06-14 02:54:48 3
3 2015-06-15 14:38:15 2
4 2015-06-15 15:29:28 1
print df.groupby(pd.Grouper(key='date', freq='24h', base=8)).sum()
name
date
2015-06-12 08:00:00 1.0
2015-06-13 08:00:00 5.0
2015-06-14 08:00:00 NaN
2015-06-15 08:00:00 3.0
alternatively to #jezrael's method you can use your custom grouper function:
start_ts = '2016-01-01 07:59:59'
df = pd.DataFrame({'Date': pd.date_range(start_ts, freq='10min', periods=1000)})
def my_grouper(df, idx):
return df.ix[idx, 'Date'].date() if df.ix[idx, 'Date'].hour >= 8 else df.ix[idx, 'Date'].date() - pd.Timedelta('1day')
df.groupby(lambda x: my_grouper(df, x)).size()
Test:
In [468]: df.head()
Out[468]:
Date
0 2016-01-01 07:59:59
1 2016-01-01 08:09:59
2 2016-01-01 08:19:59
3 2016-01-01 08:29:59
4 2016-01-01 08:39:59
In [469]: df.tail()
Out[469]:
Date
995 2016-01-08 05:49:59
996 2016-01-08 05:59:59
997 2016-01-08 06:09:59
998 2016-01-08 06:19:59
999 2016-01-08 06:29:59
In [470]: df.groupby(lambda x: my_grouper(df, x)).size()
Out[470]:
2015-12-31 1
2016-01-01 144
2016-01-02 144
2016-01-03 144
2016-01-04 144
2016-01-05 144
2016-01-06 144
2016-01-07 135
dtype: int64
I need to SUM column something by month:
date something
2010-01-02
2010-01-03
2010-01-04
2010-01-07
2010-01-10
2010-01-12
2010-01-13
2010-01-14
2010-01-15
2010-01-16
2010-01-17
2010-01-18 3
2010-01-19 1
2010-01-21
2010-01-22 11
2010-01-23 1
2010-01-24
2010-01-25
2010-01-26
2010-01-27
2010-01-28
2010-01-29
2010-01-30
2010-01-05 5
2010-01-06 8
2010-01-09
2010-01-08 3
2010-01-11
2010-01-01
2010-01-20 0
2010-01-31 13
Output should be e.g. for JAN 2010 SUM OF SOMETHING 45:
date something
2010-01 45
How to write SQL query for that?
This is a simple aggregation based on the month of the date column:
select to_char("date", 'yyyy-mm'), sum(something)
from the_table
group by to_char("date", 'yyyy-mm')
This assumes the column date has the data type date (or timestamp)