Re-Calculating number of Years, Months, and Days Oracle SQL - sql

Question

I have a query returns this result :
EmpNo
EmpName
Years
Months
Days
111
Ahmed
0
14
39
In this case, I have 14 months, so it should add one year in the years field and remains 2
months in months field, and I have 39 days, so it should add one month in the months field and remains 9 days in days field
how I could re-calculate the years, months, and days to get query result like this :
EmpNo
EmpName
Years
Months
Days
111
Ahmed
1
2
9

Answer 1

Try this, but it is more correct to use the date field:
UPDATE your_table
SET
days = mod(days,30),
months = mod(months,12) + trunc(days/30),
years = years + trunc(months/12);
COMMIT;

Answer 2

It seems strange to say that all months have 30 days. But if you are assuming that you need to recalculate all columns. In this case, revert to days and recalculate everything:
select t.*,
mod(x.total_days, 30) as days,
floor(mod(x.total_days, 360) / 30) as months,
floor(mod(x.total_days / 360)) as years
from t cross join lateral
(select t.days + t.months * 30 + t.years * 360 as total_days
from dual
) x;
Note that this handles the case where you have 0/11/39.
If you want this in an update, you should be able to use a subquery:
update (select t.*, t.days + t.months * 30 + t.years * 360 as total_days
from t
)
set days = total_days, 30),
months = floor(mod(total_days, 360) / 30),
years = floor(mod(x.total_days / 360));
Assuming that a month has 30 days and (hence) that a year has 360 days seems problematic, but that is another issue entirely.

Answer 3

Try this. However, I think it should be 1 year, 3 months and 9 days though, Kindly let me know otherwise.
UPDATE your_table
SET
days = days - 30,
months = months + 1
WHERE
days > 30;
COMMIT;
UPDATE your_table
SET
months = months - 12,
years = years + 1
WHERE
months > 12;
COMMIT;
Output:
Empno Empname Years Months Days
-------------------------------
111 Ahmed 1 3 9