My code:
select distinct entidad, sum(cast(num_importe as float))
from envio_remesa
inner join remesa
on envio_remesa.id = remesa.envio_remesa_id
where remesa.envio_remesa_id = 3 and remesa.tipo_doc='201';
The case is that for example I have two different "entidades"(suppose 18 and 21, but it can be any number), and I want to group in two different records the sum of the "num_importe" for the "entidad" 18, and the sum of the "num_importe" for the "entidad" 21.How could I do it?
What I want to come out:
entidad num_importe
18 92.300,00
21 56.000,20
432 120.000,32
12 12.232,12
you shoud use group by (by the way, distinct is useless here)
select entidad, sum(cast(num_importe as float))
from envio_remesa
inner join remesa
on envio_remesa.id = remesa.envio_remesa_id
where remesa.envio_remesa_id = 3 and remesa.tipo_doc='201'
group by entidad;
You can use aggregation:
select entidad, sum(cast(num_importe as float))
from envio_remesa er inner join
remesa r
on er.id = r.envio_remesa_id
where r.envio_remesa_id = 3 and r.tipo_doc = '201'
group by entidad;
Note: You should qualify entidad and num_importe so it is clear what table they come from.
Also, I added table aliases into the query. They make the query easier to write and to read.
Related
I have 2 queries. One includes a subquery and the other is a pretty basic query. I can't figure out how to combine them to return a table with name, workdate, minutes_inactive, and hoursworked.
I have the code below for what I have tried. The simple query is lines 1,2, and the last 5 lines. I also added a join clause (join punchclock p on p.servrepID = l.repid) to it.
Both these queries ran on their own so this is solely just the problem of combining them.
select
sr.sr_name as liaison, cast(date_created as date) workdate,
(count(date_created) * 4) as minutes_inactive,
(select
sr_name, cast(punchintime as date) as workdate,
round(sum(cast(datediff(minute,punchintime, punchouttime) as real) / 60), 2) as hoursworked,
count(*) as punches
from
(select
sr_name, punchintime = punchdatetime,
punchouttime = isnull((select top 1 pc2.punchdatetime
from punchclock pc2
where pc2.punchdatetime > pc.punchdatetime
and pc.servrepid = pc2.servrepid
and pc2.inout = 0
order by pc2.punchdatetime), getdate())
from
punchclock pc
join
servicereps sr on pc.servrepid = sr.servrepid
where
punchyear >= 2017 and pc.inout = 1
group by
sr_name, cast(punchintime as date)))
from
tbl_liga_popup_log l
join
servicereps sr on sr.servrepID = l.repid
join
punchclock p on p.servrepID = l.repid collate latin1_general_bin
group by
cast(l.date_created as date), sr.sr_name
I get this error:
Msg 102, Level 15, State 1, Line 19
Incorrect syntax near ')'
I keep getting this error but there are more errors if I adjust that part.
I don't know that we'll fix everything here, but there are a few issues with your query.
You have to alias your sub-query (technically a derived table, but whatever)
You have two froms in your outer query.
You have to join to the derived table.
Here's an crude example:
select
<some stuff>
from
(select col1 from table1) t1
inner join t2
on t1.col1 = t2.col2
The large error here is that you are placing queries in the select section (before the from). You can only do this if the query returns a single value. Else, you have to put your query in a parenthesis (you have done this) in the from section, give it an alias, and join it accordingly.
You also seem to be using group bys that are not needed anywhere. I can't see aggregation functions like sum().
My best bet is that you are looking for the following query:
select
sr_name as liaison
,cast(date_created as date) workdate
,count(distinct date_created) * 4 as minutes_inactive
,cast(punchintime as date) as workdate
,round(sum(cast(datediff(minute,punchintime,isnull(pc2_query.punchouttime,getdate())) as real) / 60), 2) as hoursworked
,count(*) as punches
from
punchclock pc
inner join servicereps sr on pc.servrepid = sr.servrepid
cross apply
(
select top 1 pc2.punchdatetime as punchouttime
from punchclock pc2
where pc2.punchdatetime > pc.punchdatetime
and pc.servrepid = pc2.servrepid
and pc2.inout = 0
order by pc2.punchdatetime
)q1
inner join tbl_liga_popup_log l on sr.servrepID = l.repid
where punchyear >= 2017 and pc.inout = 1
I've been trying hopelessly to get the following SQL statement to return the query results and default to 0 if there are no rows matching the query.
This is the intended result:
vol | year
-------+------
0 | 2018
Instead I get:
vol | year
-----+------
(0 rows)
Here is the sql statement:
select coalesce(vol,0) as vol, year
from (select sum(vol) as vol, year
from schema.fact_data
join schema.period_data
on schema.fact_data.period_tag = schema.period_data.tag
join schema.product_data
on schema.fact_data.product_tag =
schema.product_data.tag
join schema.market_data
on schema.fact_data.market_tag = schema.market_data.tag
where "retailer"='MadeUpRetailer'
and "product_tag"='FakeProductTag'
and "year"='2018' group by year
) as DerivedTable;
I know the query works because it returns data when there is data. Just doesn't default to 0 as intended...
Any help in finding why this is the case would be much appreciated!
Using your subquery DerivedTable, you could write:
SELECT coalesce(DerivedTable.vol, 0) AS vol,
y.year
FROM (VALUES ('2018'::text)) AS y(year)
LEFT JOIN (SELECT ...) AS DerivedTable
ON DerivedTable.year = y.year;
Remove the GROUP BY (and the outer query):
select 2018 as year, coalesce(sum(vol), 0) as vol
from schema.fact_data f join
schema.period_data p
on f.period_tag = p.tag join
schema.product_data pr
on f.product_tag = pr.tag join
schema.market_data m
on fd.market_tag = m.tag
where "retailer" = 'MadeUpRetailer' and
"product_tag" = 'FakeProductTag' and
"year" = '2018';
An aggregation query with no GROUP BY always returns exactly one row, so this should do what you want.
EDIT:
The query would look something like this:
select v.yyyy as year, coalesce(sum(vol), 0) as vol
from (values (2018), (2019)) v(yyyy) left join
schema.fact_data f
on f.year = v.yyyy left join -- this is just an example. I have no idea where year is coming from
schema.period_data p
on f.period_tag = p.tag left join
schema.product_data pr
on f.product_tag = pr.tag left join
schema.market_data m
on fd.market_tag = m.tag
group by v.yyyy
However, you have to move the where conditions to the appropriate on clauses. I have no idea where the columns are coming from.
From the code you posted it is not clear in which table you have the year column.
You can use UNION to fetch just 1 row in case there are no rows in that table for the year 2018 like this:
select sum(vol) as vol, year
from schema.fact_data innrt join schema.period_data
on schema.fact_data.period_tag = schema.period_data.tag
inner join schema.product_data
on schema.fact_data.product_tag = schema.product_data.tag
inner join schema.market_data
on schema.fact_data.market_tag = schema.market_data.tag
where
"retailer"='MadeUpRetailer' and
"product_tag"='FakeProductTag' and
"year"='2018'
group by "year"
union
select 0 as vol, '2018' as year
where not exists (
select 1 from tablename where "year" = '2018'
)
In case there are rows for the year 2018, then nothing will be fetched by the 2nd query,
I have a table I called Eventos. I have to select the corresponding outTime from the alarm which has the greater inTime.
And I have to do it quickly/optimized. I have about 1 million entries in the table.
This is my code:
SELECT
CadGrupoEventos.Severidade AS Nível,
CadGrupoEquipamentos.Nome AS Grupo,
CadEquipamentos.TAG AS Equipamento,
CadEventos.MensagemPT AS 'Mensagem de alarme',
MAX(Eventos.InTime) AS 'Hora do evento',
Eventos.OutTime AS 'Hora de saída'
FROM
CadGrupoEventos,
CadEquipamentos,
CadEventos,
Eventos,
CadUsuarios,
CadGrupoEquipamentos
WHERE
Eventos.Acked = 0
AND CadGrupoEventos.Codigo = CadEventos.Grupo
AND CadEquipamentos.Codigo = Eventos.TAG
AND CadEventos.Codigo = Eventos.CodMensagem
AND CadGrupoEquipamentos.Codigo = CadEquipamentos.Grupo
GROUP BY
CadGrupoEventos.Severidade,
CadEquipamentos.TAG,
CadEventos.MensagemPT,
CadGrupoEquipamentos.Nome,
Eventos.OutTime
This code, as it is, returns every single entry from the table.
I have to take Eventos.OutTime out of GROUP BY and still get the value of it.
This is just an educated guess based on your description. Notice I used ANSI-92 style joins which are much more explicit. I also used aliases to make this a lot more legible. Your query might look something like this.
select x.Severidade AS Nível,
x.Nome AS Grupo,
x.TAG AS Equipamento,
x.MensagemPT AS [Mensagem de alarme],
x.[Hora do evento],
x.OutTime AS [Hora de saída]
from
(
SELECT cge.Severidade,
cgequip.Nome,
ce.TAG,
cevt.MensagemPT,
MAX(e.InTime) AS [Hora do evento],
e.OutTime
, RowNum = ROW_NUMBER() over(partition by cge.Severidade, ce.TAG, cevt.MensagemPT, cgequip.Nome order by e.OutTime /*maybe desc???*/)
FROM CadGrupoEventos cge
join CadEventos cevt on cge.Codigo = cevt.Grupo
join Eventos e on AND cevt.Codigo = e.CodMensagem
join CadEquipamentos ce on ce.Codigo = e.TAG
join CadGrupoEquipamentos cgequip on cgequip.Codigo = ce.Grupo
cross join CadUsuarios cu --not sure if this is really what you want but your original code did not have any logic for this table
WHERE e.Acked = 0
GROUP BY cge.Severidade,
ce.TAG,
cevt.MensagemPT,
cgequip.Nome,
e.OutTime
) x
where x.RowNum = 1
scenario : I have Three Tables(Prisoners,AddPaymentTransaction,WithdrawPaymentTransation)
Date in Tables : i have 1 row of prisoner with PrisonerID=5 and two rows in both other table,
i have wrote query to return there data if any prisoner have add some payment in there account or with draw any payment from there payment on same day or on different dates etc.
here is my query :
select at.PrisonerID ,at.Amount as AAmount,at.Date as ADate,wt.Amount as WAmount,wt.Date as WDate
from Prisoners p, AddPaymentTransaction at,WithdrawPaymentTransation wt
where p.PrisonerID=at.PrisonerID and p.PrisonerID=wt.PrisonerID and at.PrisonerID=wt.PrisonerID and at.PrisonerID=5
but it gives me 4 rows, 9 rows when i have 3 rows of data in each Table etc.
i want rows of data with out duplicate. any suggestions or help will be highly appreciated.
It looks like at.PrisonerID = wt.PrisonerID in your query might be what is causing all of the duplicates. I am guessing AddPaymentTransaction and WithdrawPaymentTransation should not be linked together. So, how about the following:
SELECT at.PrisonerID, at.Amount as AAmount, at.Date as ADate,
wt.Amount as WAmount, wt.Date as WDate
FROM Prisoners p
INNER JOIN AddPaymentTransaction at p.PrisonerID = at.PrisonerID
INNER JOIN WithdrawPaymentTransation wt ON p.PrisonerID = wt.PrisonerID
WHERE at.PrisonerID = 5
but this probably isn't going to give you exactly what you are looking for either. So maybe something like the following:
SELECT * FROM
(
SELECT p.PrisonerID, 'AddPayment' AS Type,
apt.Amount as TransAmount, apt.Date AS TransDate
FROM Prisoners p
INNER JOIN AddPaymentTransaction apt ON p.PrisonerID = apt.PrisonerID
WHERE apt.PrisonerID = 5
UNION
SELECT p.PrisonerID, 'WithdrawPayment' AS Type,
wt.Amount as TransAmount, wt.Date as TransDate
FROM Prisoners p
INNER JOIN WithdrawPaymentTransation wt ON p.PrisonerID = wt.PrisonerID
WHERE wt.PrisonerID = 5
) AS mq
ORDER BY mq.TransDate DESC
i need to group some data but because there are 4 store images , sql query return 4 result for every store. How can i get only one for a store by using sql query ?
select s.name,si.SHOP_IMG_PATH,count(*) amount from stab t
inner join shop s on (s.shop_id = t.shop_id)
inner join SHOP_IMG si on (s.shop_id= si.SHOP_ID)
where t.acct_id = 111 and t.CR_DATE >= sysDate - 1
group by s.name,si.SHOP_IMG_PATH
order by 3 desc,1 asc
As you see below image there a re 4 images so query can give random image
You are grouping by s.name, si.SHOP_IMG_PATH it will consider all possible combination of s.name, si.SHOP_IMG_PATH as separate you need to keep group by only s.name
Try this
SELECT a.NAME, a.PATH, a.AMOUNT
FROM (select
s.name AS 'NAME', si.SHOP_IMG_PATH AS 'PATH', count(*) AS 'AMOUNT',
ROW_NUMBER() OVER(PARTITION BY s.name
ORDER BY type si.SHOP_IMG_PATH) AS rk
from
stab t
inner join shop s on (s.shop_id = t.shop_id)
inner join SHOP_IMG si on (s.shop_id= si.SHOP_ID)
where t.acct_id = 111 and t.CR_DATE >= sysDate - 1
group by s.name
order by 3 desc,1 asc) a
WHERE a.rk = 1;
Alternative
You will get result but this is just a workaround and easy alternative to your problem but not a good one.
select s.name AS 'NAME', min(si.SHOP_IMG_PATH) AS 'PATH', count(*) AS 'AMOUNT',
from
stab t
inner join shop s on (s.shop_id = t.shop_id)
inner join SHOP_IMG si on (s.shop_id= si.SHOP_ID)
where t.acct_id = 111 and t.CR_DATE >= sysDate - 1
group by s.name
order by 3 desc,1 asc
This second query will return result as per your need
group by s.name, si.SHOP_IMG_PATH
You're telling it to differentiate them according to SHOP_IMG_PATH. Hence, it shows 4 results, one for each of those.
You'll have to drop SHOP_IMG_PATH from the select clause, if you won't let it use it.
Edit
Got your comment. What you're looking for is random aggregation. This is achieved diferently on different SQL engines. Google around for the one you're using.
If it's Oracle, as indicated by the question tag, here
I solved my problem by using below query,
select s.name,t.shop_id,(select min(SHOP_IMG_PATH) from SHOP_IMG si where shop_id =t.shop_id),count(*) amount from stab t
inner join shop s on (s.shop_id = t.shop_id)
where t.acct_id = 111 and t.CR_DATE >= sysDate - 1
group by s.name,t.shop_id
order by 4 desc,1 asc