eg 18.45 should be 00000000001845000
datatype suppose number(x,5) so last five digits are for precision
Another option is to use the V format model element; from the documentation:
Element
Example
Description
V
999V99
Returns a value multiplied by 10n (and if necessary, round it up), where n is the number of 9's after the V.
So you can do:
select to_char(18.45, '000000000000V00000') from dual;
TO_CHAR(18.45,'000000000000V00000')
-----------------------------------
00000000001845000
or without the leading space (which is a placehold for a minus sign in case there are negative values):
select to_char(18.45, 'FM000000000000V00000') from dual;
TO_CHAR(18.45,'FM000000000000V00000')
-------------------------------------
00000000001845000
db<>fiddle
Also you can multiply for 100000 the given number:
SELECT TO_CHAR(18.45 * 100000, '00000000000000000') FROM DUAL;
This should do it:
SELECT REPLACE(TO_CHAR(18.45, 'FM000000000000D00000', 'NLS_NUMERIC_CHARACTERS=''.,'''), '.', '') FROM DUAL;
The NLS_NUMERIC_CHARACTERSmakes sure the decimal separator is a . regardless what the session is configured. This way we're safe to remove it from the resulting string with the replace function.
The FM is used to suppress the leading space character.
Related
The query below outputs 1642575.0. But I only want 1642575 (just the number without the decimal and the zero following it). The number of delimited values in the field varies. The only constant is that there's always only one number with a decimal. I was trying to write a regexp function to extract the number between " and ..
How would I revise my regexp_extract function to get the desired output? Thank you!
select regexp_extract('{"1244644": "1642575.0", "1338410": "1650435"}','([1-9][0-9]*[.][0-9]+)&*');
You can cast the result to bigint.
select cast(regexp_extract('{"1244644": "1642575.9", "1338410": "1650435"}','([1-9][0-9]*[.][0-9]+)&*') as bigint) col;
output - 1642575
You can use round if you want to round it off.
select round(regexp_extract('{"1244644": "1642575.9", "1338410": "1650435"}','([1-9][0-9]*[.][0-9]+)&*')) col;
output - 1642576
Use this regexp: '"(\\d+)\\.' - means double-quote, capturing group with one or more digits, dot.
select regexp_extract('{"1244644": "1642575.9", "1338410": "1650435"}','"(\\d+)\\.',1)
Result:
1642575
To skip any number of leading zeroes, use this regexp: '"0*(\\d+)\\.'
I need help with a Oracle Query
I have a query:
scenario 1: select to_char('1737388250',what format???) from dual;
expected output: 173,7388250
scenario 2: select to_char('173738825034',what format??) from dual;
expected output: 173,738825034
scenario 3: select to_char('17373882',what format??) from dual;
expected output: 173,73882
I need a query to satify all above scenarios?
Can some one help please?
It is possible to get the desired result with a customized format model given to to_char; I show one example below. However, any solution along these lines is just a hack (a solution that should work correctly in all cases, but using features of the language in ways they weren't intended to be used).
Here is one example - this will work if your "inputs" are positive integers greater than 999 (that is: at least four digits).
with
sample_data (num) as (
select 1737388250 from dual union all
select 12338 from dual
)
select num, to_char(num, rpad('fm999G', length(num) + 3, '9')) as formatted
from sample_data
;
NUM FORMATTED
---------- ------------
1737388250 173,7388250
12338 123,38
This assumes comma is the "group separator" in nls_numeric_characters; if it isn't, that can be controlled with the third argument to to_char. Note that the format modifier fm is needed so that no space is prepended to the resulting string; and the +3 in the second argument to rpad accounts for the extra characters in the format model (f, m and G).
You can try
select TO_CHAR(1737388250, '999,99999999999') from dual;
Take a look here
Your requirement is different so you can use substr and concatanation as follows:
select substr(your_number,1,3)
|| case when your_number >= 1000 then ',' end
|| substr(1737388250,4)
from dual;
Db<>fiddle
Your "number" is enclosed in single-quotes. This makes it a character string, albeit a string of only numeric characters. But a character string, nonetheless. So it makes no sense to pass a character string to TO_CHAR.
Everyone's suggestions are eliding over this and useing and using an actual number .. notice the lack of single-quotes in their code.
You say you always want a comma after the first three "numbers" (characters), which makes no sense from a numerical/mathematical sense. So just use INSTR and insert the comma:
select substr('123456789',1,3)||','||substr('123456789',4) from dual:
If the source data is actually a number, then pass it to to_char, and wrap that in substr:
select substr(to_char(123456789),1,3)||','||substr(to_char(123456789,4) from dual:
I am using Oracle SQL Developer and I have a query in which one of the columns has a number value that I want to divide by 1,000,000 then display to show commas and up to 10 decimal places if the calculate value has any decimal places. I am currently using this query:
to_char(value/1000000, 'FM999,999,990.9999999999') as Millions_Value
The above format gives me commas and retains the number of decimal places I want, but it unfortunately adds a decimal point at the end of whole numbers as well.
Example:
value/1000000 = 33993
formatted value = 33,993.
what I want = 33,993
For a decimal value, I get what I want and need to keep the format
Example:
value/1000000 = 0.158739
formatted value = 0.158739
value/1000000 = 10.82
formatted value = 10.82
And ideas on how to get rid of the decimal for integers?
The easiest way is to use RTRIM, e.g.
RTRIM(to_char(value/1000000, 'FM999,999,990.9999999999'), '.') as Millions_Value
will remove any trailing periods.
EDIT
If you want to get fancy and internationalize it you need to query NLS_SESSION_PARAMETERS to get the decimal separator, use the G (group) and D (decimal) specifiers in the format string, and then trim off any trailing decimal separator characters. Or in other words:
WITH cteData AS (SELECT 123456789.123456789 AS N FROM DUAL UNION ALL
SELECT 123 FROM DUAL),
cteDecimalSeparator AS (SELECT SUBSTR(VALUE, 1, 1) AS DECIMAL_SEPARATOR
FROM NLS_SESSION_PARAMETERS
WHERE PARAMETER = 'NLS_NUMERIC_CHARACTERS')
SELECT TO_CHAR(N, 'FM999G999G990D9999999999') AS OLD_FORMAT,
RTRIM(TO_CHAR(N, 'FM999G999G990D9999999999'), s.DECIMAL_SEPARATOR) AS NEW_FORMAT
FROM cteData d
CROSS JOIN cteDecimalSeparator s
which returns
OLD_FORMAT NEW_FORMAT
123,456,789.123456789 123,456,789.123456789
123. 123
Remember: there's no kill like overkill :-)
Personally, I think it looks good with one trailing 0, so converting your format string to have a 0 after the decimal. But to answer you question, I think you just need to trim it after you convert the number like this:
SELECT TRIM(TRAILING '.' FROM TO_CHAR('345676', 'FM999G999G990D9999999999'))
FROM DUAL;
How do we convert and add trailing and leading zeros to a number? For example 123.45. I need to make this ten digits long and have padding numbers in front and back. I would like to convert it to 0001234500. Two trailing numbers after the last digit of the decimal. Remove the decimal. Fill in the remaining space with zeroes for the leading end.
I have this so far and it adds trailing zeroes and removes the decimal.
REPLACE(RIGHT('0'+CAST(rtrim(convert(char(10),convert(decimal(10,4),Field))) AS VARCHAR(10)),10),'.','') as New_Field
In MySQL you would have RPAD and LPAD to get stuff like this done, in SQL Server (2012+) you can get something similar by working with FORMAT.
Easiest way is to FORMAT your numbers with a dot so that they take the right place in the format string, then remove that dot. You need to specify a locale, since in different regions you will get a different decimal sign (even if you use . within the format pattern, you would get , in various locales) - using en-US makes sure you get a dot.
REPLACE(FORMAT(somenumber, '000000.0000', 'en-US'), '.', '')
A few examples:
WITH TempTable(somenumber) AS (
SELECT 3
UNION SELECT 3.4
UNION SELECT 3.45
UNION SELECT 23.45
UNION SELECT 123.45
)
SELECT
somenumber,
REPLACE(FORMAT(somenumber, '000000.0000', 'en-US'), '.', '')
FROM
TempTable;
Gives
3.00 0000030000
3.40 0000034000
3.45 0000034500
23.45 0000234500
123.45 0001234500
You seem to really be overthinking what you need to do here. If we take it in steps, perhaps you'll see that this can be achieved much more easily. This solution runs under the idea that the value 123.45 becomes 0001234500 and 6.5 becomes 0000065000.
Firstly, let's pad out the right hand side of the number 123.45 so that we have 1234500 That's easy enough : 123. 45 * 100 = 12345 So, to get 1234500 we simply need to multiple it by a couple of extra factors of 10:
SELECT 123.45 * 10000; --1234500.00
Ok, now, let's get rid of those decimal places. Easiest way, convert it to an int:
SELECT CONVERT(int, 123.45 * 10000); --1234500
Nice! Now, the finalstep, the leading 0's. A numerical value, in SQL Server, won't display leading zeros. SELECT 01, 001.00; Will return 1 and 1.00 respectively. A varchar however, will though (as it's not a number). We can, therefore, make use of that with a further conversion, and then then use of RIGHT:
SELECT RIGHT('0000000000' + CONVERT(varchar(10),CONVERT(int,123.45 * 10000)),10);
Now you have the value you want '0001234500'.
If you're only after padding, (so 6.5 becomes 0006500) then you should be able to work out how to achieve this with the help above (hint you don't need RIGHT).
Any questions, please do ask.
I'm currently battling with something
that must be trivial for you.
I have 2 number 191 and 97, and I need to put them in a SQL request, as chars and 97 must be printed as 097.
At first I tried 999, but it added 2 space to my numbers.
then 099, it does print 097 but it adds a space to it.
to_char(:center, '099') = " 197" and " 097"
Where is this space coming from?
Thanks.
What you're looking for is the Format Modifier element:
to_char(:center, 'fm099')
The leading space is for the potential minus sign. To remove it you can use FM in the format:
to_char(v_num,'FM099')
9 9999 Returns value with the specified number of digits with a leading space if positive or with a leading minus if negative.Leading zeros are blank, except for a zero value, which returns a zero for the integer part of the fixed-point number.
From http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm#i34510
Use #DavidAldridge solution, or trim your value.
If you are looking for the all column values in same number of digits even the actual value having less digits. Try this
a) SELECT TO_CHAR(COLUMN_NAME, 'FM099') FROM TABLE_NAME;
b) SELECT TO_CHAR(COLUMN_NAME, 'FM000') FROM TABLE_NAME;
Both is working fine. but don't know which one would be the best choice.