Calculate difference between time over midnight and condition - sql

When I calculate the difference between two time, I must also pay attention to what happens after midnight.
select *
,datediff(second,
cast([schedule_deptime]as time),
cast([prev_announce_time]as time))
as kpi1_delta
id
date_event
schedule_deptime
prev_announce_time
kpi1_delta
79643204
2021-02-11 19:55:52.000
19:15
2021-02-11 19:39:01.000
1441
79569510
2021-02-11 16:51:05.000
16:50
2021-02-11 16:48:17.000
-103
106160161
2021-01-21 20:43:44.000
20:28
2021-01-21 01:03:41.000
-69859
106216877
2021-01-21 23:50:10.000
23:45
2021-01-21 00:06:52.000
-85088
79703534
2021-02-11 23:58:01.000
00:04
2021-02-11 00:03:01.000
-59
I should get for my third and fourth row:
id
date_event
schedule_deptime
prev_announce_time
kpi1_delta
106160161
2021-01-21 20:43:44.000
20:28
2021-01-21 01:03:41.000
16541
106216877
2021-01-21 23:50:10.000
23:45
2021-01-21 00:06:52.000
1312

Related

Create an event log from an excel file by turning columns into repeated rows

I have an Excel sheet like the following:
ID Arrival Passed Berthing Date UnBerthing Date Departure Passed
1 13/05/2017 15:30 13/05/2017 16:00 31/05/2017 20:44 31/05/2017
2 15/05/2017 16:56 15/05/2017 17:15 16/05/2017 00:00 16/05/2017
3 20/05/2017 09:54 20/05/2017 10:26 20/05/2017 18:07 20/05/2017
4 24/05/2017 16:09 24/05/2017 16:35 25/05/2017 01:03 25/05/2017
5 29/05/2017 10:30 29/05/2017 10:45 29/05/2017 17:33 29/05/2017
I need this in the following format:
ID Event Time
1 Arrival 13/05/2017 15:30
1 Berth 13/05/2017 16:00
1 UnBerth 31/05/2017 20:44
1 Departure 31/05/2017 20:58
2 Arrival 15/05/2017 16:56
2 Berth 15/05/2017 17:15
2 UnBerth 16/05/2017 00:00
2 Departure 16/05/2017 00:04
etc
I've searched the web and this site(youtube...), but with no right answer, i've tried the transpose function and pivot table, but i couldn't make it.
Any help would be appreciated.
Thanks you.

Assuming that your dataset is in range A2:E6.
For getting ID:
=INDEX($A$2:$E$6,CEILING(ROWS($A$1:A1)/4,1),1)
For getting Event:
=CHOOSE(MOD(ROWS($A$1:A1)-1,4)+1,"Arrival","Berth","Unberth","Departure")
For getting Time:
=INDEX($A$2:$E$6,CEILING(ROWS($A$1:A1)/4,1),MOD(ROWS($A$1:A1)-1,4)+2)
and then copy down until you get error.

How to split 24 Hour time by 10 minutes

I am trying to make a graph on BI which needs me to make so the time variable in my database groups for each 10 minutes IE - 11:04:00, 11:08:30, 11:00:28 are grouped as 11-1 then 11-2, ... ,11-6, 12-1 so on. -
06:00:00 06-1
06:03:00
06:06:00
06:09:00
06:12:00 06-2
06:15:00
06:18:00
06:21:00 06-2
06:24:00
06:27:00
06:30:00 06-3
06:33:00
06:36:00
06:39:00
06:42:00 06-4
06:45:00
06:48:00
06:51:00 06-5
06:54:00
06:57:00
07:00:00 07-1
07:03:00
07:06:00
07:09:00
07:12:00 07-2
Is there anyway I can do this on the BI?
Thank you for helping.

This will give you 10-minute block groupings, starting with 0:
=FormatDate([Date];"HH")+"-"+Floor(ToNumber(FormatDate([Date];"mm"))/10)

How to group field by id and find the sum?

I have the following data
id starting_point ending_point Date
A 2525 6565 25/05/2017 13:25:00
B 5656 8989 25/01/2017 10:55:00
A 1234 5656 20/05/2017 03:20:00
A 4562 6245 01/02/2017 19:45:00
B 6496 9999 06/12/2016 21:55:00
B 1122 2211 20/03/2017 18:30:00
How to group the data by their id in the ascending order of date and find the sum of first stating point and last starting point. In this case,
Expected output is :
id starting_point ending_point Date Value
A 4562 6245 01/02/2017 19:45:00
A 1234 5656 20/05/2017 03:20:00
A 2525 6565 25/05/2017 13:25:00 4532 + 6565 = 11127
B 6496 9999 06/12/2016 21:55:00
B 1122 2211 20/03/2017 18:30:00 6496 + 2211 = 8707

IIUC:
In [146]: x.groupby('id').apply(lambda df: df['starting_point'].head(1).values[0]
+ df['ending_point'].tail(1).values[0])
Out[146]:
id
A 8770
B 7867
dtype: int64

SQL Server SUM(Values)

I have the following query that works perfectly well. The query sums the values in a given day.
SELECT
SUM(fldValue) AS 'kWh',
DAY(fldDateTime) AS 'Day',
MONTH(fldDateTime) AS 'Month',
YEAR(fldDateTime) AS 'Year'
FROM
[Data.tblData]
WHERE
tblData_Id IN (SELECT DISTINCT tblData_Id
FROM [Data.tblData])
GROUP BY
YEAR(fldDateTime), MONTH(fldDateTime), DAY(fldDateTime),
tblData_Id,fldDateTime
ORDER BY
YEAR(fldDateTime), MONTH(fldDateTime), DAY(fldDateTime)
The problem I have is that it sums from midnight to midnight, I need it to sum the values after midnight ( >= Midnight) then up to midnight of the next day. The reason for this is the data that comes in for a day, is always after midnight. For example the first logged data will be '2016-01-01 00:01:00', the final logged data will be '2016-01-02 00:00:00'. This is how the hardware works that sends me the data.
I would like to know how to encapsulate >= midnight to midnight in the query.
Dataset:
DateTime Value
20/03/2016 00:30 69.00
20/03/2016 01:00 69.00
20/03/2016 01:30 69.00
20/03/2016 02:00 69.00
20/03/2016 02:30 69.00
20/03/2016 03:00 69.00
20/03/2016 03:30 11.88
20/03/2016 04:00 0.52
20/03/2016 04:30 1.51
20/03/2016 05:00 2.22
20/03/2016 05:30 2.11
20/03/2016 06:00 0.05
20/03/2016 06:30 6.78
20/03/2016 07:00 14.79
20/03/2016 07:30 1.57
20/03/2016 08:00 1.51
20/03/2016 08:30 4.81
20/03/2016 09:00 0.11
20/03/2016 09:30 8.99
20/03/2016 10:00 10.06
20/03/2016 10:30 15.28
20/03/2016 11:00 3.22
20/03/2016 11:30 1.73
20/03/2016 12:00 19.10
20/03/2016 12:30 2.08
20/03/2016 13:00 2.61
20/03/2016 13:30 0.84
20/03/2016 14:00 8.65
20/03/2016 14:30 2.37
20/03/2016 15:00 16.34
20/03/2016 15:30 12.66
20/03/2016 16:00 2.64
20/03/2016 16:30 0.19
20/03/2016 17:00 3.91
20/03/2016 17:30 2.39
20/03/2016 18:00 0.57
20/03/2016 18:30 1.30
20/03/2016 19:00 5.06
20/03/2016 19:30 17.45
20/03/2016 20:00 13.04
20/03/2016 20:30 5.00
20/03/2016 21:00 7.47
20/03/2016 21:30 5.09
20/03/2016 22:00 0.33
20/03/2016 22:30 5.29
20/03/2016 23:00 15.33
20/03/2016 23:30 5.39
21/03/2016 00:00 6.74
Thank you in advance.
The expected sum output value for 20/03/2016 is: 662.98
The output table will look like:
SumValue Day Month Year Meter Id
659.18 20 3 2016 6
251.37 21 3 2016 6
279.03 22 3 2016 6
280.03 23 3 2016 6
284.22 24 3 2016 6
310.12 25 3 2016 6
320.84 26 3 2016 6
269.29 27 3 2016 6
276.11 28 3 2016 6
279.11 29 3 2016 6
The value column is the sum of the values for that day, made up of lots of individual times.

Use the below query for summing up the midnight value with previous day.
SELECT
SUM(fldValue) AS 'kWh',
CASE WHEN CONVERT(VARCHAR(8), fldDateTime, 108)='00:00:00' THEN DAY(fldDateTime)-1 ELSE DAY(fldDateTime) END AS 'Day',
MONTH(fldDateTime) AS 'Month',
YEAR(fldDateTime) AS 'Year'
FROM
Data.[tblData]
GROUP BY
YEAR(fldDateTime), MONTH(fldDateTime),CASE WHEN CONVERT(VARCHAR(8), fldDateTime, 108)='00:00:00' THEN DAY(fldDateTime)-1 ELSE DAY(fldDateTime) END
ORDER BY
YEAR(fldDateTime), MONTH(fldDateTime), CASE WHEN CONVERT(VARCHAR(8), fldDateTime, 108)='00:00:00' THEN DAY(fldDateTime)-1 ELSE DAY(fldDateTime) END
Sample output :

First, I have no idea what the WHERE clause is doing, so I'm going to remove it.
Second, don't use single quotes for column names.
Third, your GROUP BY clause is too complicated. You only need to include the unaggregated columns in the SELECT.
Finally, the key idea is to subtract one hour from the values everywhere they are used. Here is a simple method:
SELECT SUM(fldValue) AS kWh,
DAY(newdt) AS [Day],
MONTH(newdt) AS [Month],
YEAR(newdt) AS [Year]
FROM (SELECT d.*, DATEADD(hour, -1, fldDateTime) as newdt
FROM Data.tblData d
) d
GROUP BY YEAR(newdt), MONTH(newdt), DAY(newdt)
ORDER BY YEAR(newdt), MONTH(newdt), DAY(newdt)

Same answer as #Gordon but you can subtract one minute instead of one hour.
SELECT SUM(fldValue) AS kWh,
DAY(newdt) AS [Day],
MONTH(newdt) AS [Month],
YEAR(newdt) AS [Year]
FROM (SELECT d.*, DATEADD(minute, -1, fldDateTime) as newdt
FROM Data.tblData d
) d
GROUP BY YEAR(newdt), MONTH(newdt), DAY(newdt)
ORDER BY YEAR(newdt), MONTH(newdt), DAY(newdt)

declare #tempTable table ([DateTime] datetime, Value Float)
insert into #tempTable ([DateTime], [Value])
select convert(datetime,'20/03/2016 00:30',103), 69.00 union all
select convert(datetime,'20/03/2016 01:00',103), 69.00 union all
select convert(datetime,'21/03/2016 00:00',103), 6.74
select * from #tempTable
select [sum] = SUM(value), [year] = year(DT), [month] = month(DT), [day] = day(DT)
from (select Value, DT = dateadd(second, -1, [DateTime]) from #tempTable) x
group by year(DT), month(DT), day(DT)

Addition in SQL by month

I need to SUM column something by month:
date something
2010-01-02
2010-01-03
2010-01-04
2010-01-07
2010-01-10
2010-01-12
2010-01-13
2010-01-14
2010-01-15
2010-01-16
2010-01-17
2010-01-18 3
2010-01-19 1
2010-01-21
2010-01-22 11
2010-01-23 1
2010-01-24
2010-01-25
2010-01-26
2010-01-27
2010-01-28
2010-01-29
2010-01-30
2010-01-05 5
2010-01-06 8
2010-01-09
2010-01-08 3
2010-01-11
2010-01-01
2010-01-20 0
2010-01-31 13
Output should be e.g. for JAN 2010 SUM OF SOMETHING 45:
date something
2010-01 45
How to write SQL query for that?

This is a simple aggregation based on the month of the date column:
select to_char("date", 'yyyy-mm'), sum(something)
from the_table
group by to_char("date", 'yyyy-mm')
This assumes the column date has the data type date (or timestamp)