How can I convert String to Date type in SQL?
I have a column called timestamp (type varchar) with the following data:
timestamp
06.07.2021 00:00:00
05.07.2021 00:00:00
04.07.2021 00:00:00
I would like to run the following query which is unfortunately not working:
select timestamp from table where
convert(datetime,timestamp,112) = convert(datetime, '20210706')
How should I replace "convert(datetime,timestamp,112)" so that it works?
try use PARSE t-sql function
SELECT PARSE(timestamp AS date USING 'Ru-RU') from table
SQL Server is actually pretty flexible on converting date/times without a format. So, if you want to convert to a date/time, this works:
select convert(datetime, '06.07.2021 00:00:00')
If you are only looking at the date, though, you might want to limit to the first 10 characters. If you are certain that all the strings have valid dates, you can use 104 to convert the value:
select cast(date, left(datetime, 10), 104)
You are comparing against date value, you can convert to date datatype and apply WHERE clause.
declare #TABLE TABLE(timestampvalue varchar(20))
INSERT into #table
values
('06.07.2021 00:00:00'),
('05.07.2021 00:00:00'),
('04.07.2021 00:00:00');
SELECT convert(date,timestampvalue,104) FROM #table where convert(date,timestampvalue,104) = '20210706'
2021-07-06
Note: This type of applying CONVERT function in the WHERE clause, will make the query Non-Sargeable. It is better to change datatype to DATE and then do comparison.
UPDATE TABLE <TABLENAME>
SET TimeStampValue = CONVERT(DATE,TimeStampValue,104)
Now, you can ALTER table.
ALTER TABLE <TABLENAME> ALTER COLUMN TimeStampValue DATE
Now, you can apply the WHERE clause without conversion.
SELECT * FROM tablename where timestampvalue = '20210706'
Related
So I have a couple date fields in a table that are formatted as (DD-MON-YYYY) and I need to convert them to (DD-MM-YYYY) The field itself is already a VARCHAR. In Snowflake, how would I make this change. Here is what I have done so far.
select to_date(end_date, 'dd-mm-yyyy') from
error: Can't parse '31-JAN-2020' as date with format 'dd-mm-yyyy'
An easy way for you to approach this is to convert your string to a date, and then back to a string in the new format, an example follows:
--create an example table to test
CREATE TEMPORARY TABLE xyz (my_dt_string VARCHAR(100));
--insert a couple records
INSERT INTO xyz VALUES ('31-JAN-2020'), ('13-APR-2020');
--test a conversion, from string to date back to string
SELECT my_dt_string,
TO_CHAR(TO_DATE(my_dt_string, 'dd-mon-yyyy'), 'dd-mm-yyyy') converted
FROM xyz;
--looks good? run the following
UPDATE xyz
SET my_dt_string = TO_CHAR(TO_DATE(my_dt_string, 'dd-mon-yyyy'), 'dd-mm-yyyy');
--take a look
select * from xyz;
I hope this helps...Rich
The to_date() function provides you the ability to convert a VARCHAR field to a DATE field, not specify the format of the date. So, you'd want to run this:
SELECT TO_DATE(end_date, 'DD-MON-YYYY');
This will output the date as a date. If you want to specify how you see a date, you have 2 choices:
First, convert it back to a VARCHAR in your preferred format:
SELECT TO_VARCHAR(TO_DATE(end_date, 'DD-MON-YYYY'),'DD-MM-YYYY');
Second, change your session parameter DATE_OUTPUT_FORMAT to be the format you'd like to see dates displayed:
ALTER SESSION SET DATE_OUTPUT_FORMAT = 'DD-MM-YYYY';
This could also be done for a user, rather than a session using:
ALTER USER SET DATE_OUTPUT_FORMAT = 'DD-MM-YYYY';
FORMAT instruction works in a SELECT but has no effect in an UPDATE:
SELECT ##VERSION
DROP TABLE IF EXISTS #t;
CREATE TABLE #t(DateMin datetime);
INSERT INTO #t VALUES ('2019-13-01 00:00:00')
SELECT * FROM #t
UPDATE #t SET DateMin = FORMAT(DateMin, 'dd/MM/yyyy');
SELECT * FROM #t;
SELECT #DateMin AS a, FORMAT(#DateMin, 'dd/MM/yyyy') AS b
A type like DATETIME isn't stored with a format.
So if one updates a DATETIME with a string in a certain format, it doesn't matter for the stored value in the DATETIME field.
The formatted string is implicitly converted to a datetime. At least if it's in a format that's valid.
The function FORMAT, which returns a NVARCHAR is rather used for representation of the datetime field in a query.
Or if one wants to INSERT/UPDATE a string field with a datetime in a certain format. But that should be avoided, because it's much easier to work with a datetime than a string.
If you want to change that format for the user use this:
set dateformat dmy;
By running this statement:
DBCC USEROPTIONS;
you will see your dateformat is ydm so you can alway back it up to that if this is not what you wanted :)
You cannot set the output format of a datetime in the datetime itselfs.
If you need to output the datetime as formatted char/varchar, you need to use the convert-function when you select the data:
SELECT CONVERT(char(10), CURRENT_TIMESTAMP, 101) -- format: MM/dd/yyyy
SELECT CONVERT(char(10), CURRENT_TIMESTAMP, 103) -- format: dd/MM/yyyy
In your case:
SELECT #DateMin AS a, CONVERT(char(10), #DateMin, 103) AS b
That works as expected.
If you want to have a mutable data-type, you need to declare it as sql_variant:
DROP TABLE IF EXISTS #t;
CREATE TABLE #t(DateMin sql_variant);
INSERT INTO #t VALUES ('2019-01-13T00:00:00')
UPDATE #t SET DateMin = FORMAT(CAST(DateMin AS datetime), 'dd''/''MM''/''yyyy');
SELECT * FROM #t;
Also, your format-expression needs to explicitly put the / into quotation marks, aka 'dd''/''MM''/''yyyy', otherwise sql-server replaces it with the date-separator specific to the current culture, which would be . in my case.
Just use convert with option 103 instead, it works on all versions of sql-server and it's probably faster.
Also, your insert-statement fails on some versions of sql-server, because iso-date-format is 2019-01-13T00:00:00 and not 2019-13-01 00:00:00
Correct is:
INSERT INTO #t VALUES ('2019-01-13T00:00:00')
Also
DROP TABLE IF EXISTS #t;
is sql-server 2016+ only, otherwise you need
IF OBJECT_ID('tempdb..#t') IS NOT NULL DROP TABLE #t
And post sql-server 2005, you should use datetime2 instead of datetime.
You shouldn't use datetime anymore, because datetime uses float, and as such is imprecise - if you insert an iso datetime value, it can do funny things because of the float-point-machine-epsilon, e.g. set it to the next day if you have 23:59:59.999, just as a scary example.
I advise you to never use the sql_variant type. If you have a temp-table with defined columns, just create another column where you will write the char/varchar value to.
I have a bunch of values in the form of mm/dd/yyyy stored in a CSV. An example is 06/26/2017. What I found was that I could NOT insert it into a column declared as date or datetime2 type. What I CAN do is to modify that (empty) column to varchar first, then insert.
However at this point, after insertion as varchars, how can I convert this column to "date" or "datatime2"?
Attempting to set system-wide format doesn't work:
sql> SET DATEFORMAT 'mm/dd/yyyy'
[2019-03-31 09:42:04] [S0001][2741] SET DATEFORMAT date order 'mm/dd/yyyy' is invalid.
If the column's data type is date then convert the string to date with:
convert(date, '03/31/2019', 101)
and then insert it.
See the demo.
Read more about convert()
Edit:
Create a varchar column and a date column. Insert the values inside the varchar column and when the process finishes, update the date column by converting each value to a date, like:
UPDATE tablename
SET datecolumn = convert(date, varcharcolumn, 101)
After that you can remove the varchar column.
How can I insert into table with different input using / ,with date datatype?
insert into run(id,name,dob)values(&id,'&name',[what should I write here?]);
I'm using oracle 10g.
Since dob is DATE data type, you need to convert the literal to DATE using TO_DATE and the proper format model. The syntax is:
TO_DATE('<date_literal>', '<format_model>')
For example,
SQL> CREATE TABLE t(dob DATE);
Table created.
SQL> INSERT INTO t(dob) VALUES(TO_DATE('17/12/2015', 'DD/MM/YYYY'));
1 row created.
SQL> COMMIT;
Commit complete.
SQL> SELECT * FROM t;
DOB
----------
17/12/2015
A DATE data type contains both date and time elements. If you are not concerned about the time portion, then you could also use the ANSI Date literal which uses a fixed format 'YYYY-MM-DD' and is NLS independent.
For example,
SQL> INSERT INTO t(dob) VALUES(DATE '2015-12-17');
1 row created.
date must be insert with two apostrophes'
As example if the date is 2018/10/20. It can insert from these query
Query -
insert into run(id,name,dob)values(&id,'&name','2018-10-20')
let suppose we create a table Transactions using SQl server management studio
txn_id int,
txn_type_id varchar(200),
Account_id int,
Amount int,
tDate date
);
with date datatype we can insert values in simple format: 'yyyy-mm-dd'
INSERT INTO transactions (txn_id,txn_type_id,Account_id,Amount,tDate)
VALUES (978, 'DBT', 103, 100, '2004-01-22');
Moreover we can have differet time formats like
DATE - format YYYY-MM-DD
DATETIME - format: YYYY-MM-DD HH:MI:SS
SMALLDATETIME - format: YYYY-MM-DD HH:MI:SS
insert into run(id,name,dob)values(&id,'&name',[what should I write
here?]);
insert into run(id,name,dob)values(&id,'&name',TO_DATE('&dob','YYYY-MM-DD'));
You can also use the "timestamp" data type where it just needs "dd-mm-yyyy"
Like:
insert into emp values('12-12-2012');
considering there is just one column in the table...
You can adjust the insertion values according to your table.
I simply wrote an embedded SQL program to write a new record with date fields.
It was by far best and shortest without any errors I was able to reach my requirement.
w_dob = %char(%date(*date));
exec sql insert into Tablename (ID_Number ,
AmendmentNo ,
OverrideDate ,
Operator ,
Text_ID ,
Policy_Company,
Policy_Number ,
Override ,
CREATE_USER )
values ( '801010',
1,
:w_dob,
'MYUSER',
' ',
'01',
'6535435023150',
'1',
'myuser');
To insert the current date you can just use this GETDATE() function.
insert into run(id,name,dob) values(&id,'&name',GETDATE());
you can also use CURRENT_TIMESTAMP() function to insert current date and time.
I am relatively new to SQL Server so I was wondering how to convert the data type from varchar to date format? I have a few thousands records so I need a query to help to convert the varchar to date in a single query.
I have the date in this format: yyyymmdd, in varchar(8) and I want to convert this into yyyymmdd, in date format.
Is there any queries to help me with this?
For various conversions between VARCHAR and DATETIME have a look at this link.
Actually in your case, since your VARCHAR is in yyyymmdd format, you could just:
convert(datetime, YourVarcharDateField, 112)
Simply Use this Inbuilt CONVERT Function, and Check this Link for formatting Dates
-- Use 101 if you have divider in your date
SELECT convert(datetime, '2014-01-02',101) as [DateTime]
-- Use 112 if you don't have divider in your date
SELECT convert(datetime, '20140131',112) as [DateTime]
Edited:
UPDATE yourTable SET field = convert(datetime, 'yourFieldName',112)
--This will update all of your field regardless of any particular row
--If you want to update any particular set of rows use `WHERE` clause
if you have more various formats goto to the given link.
Data types can be converted either implicitly or explicitly.
Implicit conversions are not visible to the user. SQL Server automatically converts the data from one data type to another. For example, when a smallint is compared to an int, the smallint is implicitly converted to int before the comparison proceeds.
Explicit conversions use the CAST or CONVERT functions.
The CAST and CONVERT functions convert a value (a local variable, a column, or another expression) from one data type to another
convert(datetime, '2013-05-04',101)
CAST ( expression AS data_type )
ALTER TABLE [dbo].[table] ADD ConvertedDate Date
UPDATE [dbo].[SysData] SET ConvertedDate = CAST(VarCharDate as Date)
ALTER TABLE [dbo].[table] DROP COLUMN VarCharDate
Use CAST OR CONVERT function to convert string to date
Try this:
SELECT CAST('20140102' AS DATE) AS convertedDate;
SELECT CAST(colName AS DATE) AS convertedDate FROM tableA; -- Replace column name and table name
OR
SELECT CONVERT(DATE, '20140102', 112) AS convertedDate;
SELECT CONVERT(DATE, colName, 112) AS convertedDate FROM tableA; -- Replace column name and table name
OUTPUT of both queries:
|convertedDate|
|-------------|
|2014-01-02 |
In SQL SERVER, there are two types of built in conversion techniques.
Convert
Cast
Convert having its own defaults so it will be outdated in upgraded version of SQL SERVER
better make use of CAST Conversion technique
In your scenario.Already having the date with datatype of Varchar(8) trying to Convert into Date
Solve in systematic manner.
Adding the one new Column in the existing table.
Alter Table Table_name Add changedDataTypeDate Date
Update the values in varchar datatype to Date Datatype
UpDate Table_name Set ChangedDataTypeDate = CAST(OriginalDataTypeDate as Date)
Again change the new column name into old column name.
Sp_Rename 'Tablename.changedDataTypeDate','OriginalDataTypeDate','COLUMN'
Its done.
Based on u r requirement.
Alter Table customer Add Purchase_Changedtype Date
Update Customer set Purchase_changedtype = CAST(Purchase_date as Date)
(If u need Time also replace Datetime istead of Date)
Alter table Customer Drop column Purchase_date
Sp_Rename 'Customer.Purchase_ChangedType','Purchase_Date','Column'