Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
Here is my error message:
This is the text
Oracle requires parentheses for the subqueries:
(select TeamName As Name, points As points
from standing
group by TeamName, points
having Length(TeamName) >= 3 and points > 5
order by points DESC, TeamName ASC
Fetch first 2 rows only
) union
(select TeamName As Name, points As points
from standing
group by TeamName, points
having Length(TeamName) >= 3 and points > 5
order by points ASC
Fetch first 1 rows only
)
The parentheses are needed when the subqueries have either order by or fetch clauses. They are needed to distinguish between applying those clauses to an individual subquery or to the results of the entire union.
Also, you might want union all instead of union -- union incurs overhead for removing duplicates.
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 7 months ago.
Improve this question
SELECT DISTINCT CITY FROM STATION WHERE MOD(ID,2)=0 ORDER BY CITY ASC;
SELECT DISTINCT CITY FROM STATION
Primary command to select data from the database. It is asking to select CITY from the table STATION whose data is unique. Thus, no duplicates are produced in result.
WHERE MOD(ID, 2) = 0
Only select those that have an even number ID.
ORDER BY CITY
Sort the results with respect to CITY names.
ASC
Sort in ascending order; which means that cities with names starting with A will come before those that have Z as first letter.
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
select distinct b.brid,
(select count(1) from account a
where a.brid= b.brid
and a.acctype='current'
) as num_accounts,
b.baddress.street, b.baddress.city, b.baddress.p_code
from branch b;
the table should display the number of current account,but nothing is showing
Query you posted doesn't make sense. What is b.baddress.street? The way you put it,
b is user
baddress is table
street is column
but what is b.brid, then?
You posted screenshot of ... what? Desired result? Can't be as it displays 2 columns, while query returns 5 of them.
Anyway: this is how it might be done. Try to adjust it to your table(s). Mind letter case (is it really 'current'? Maybe 'CURRENT'? Or ...?)
SELECT b.brid,
COUNT (*) num_accounts,
b.street,
b.city,
b.p_code
FROM branch b JOIN account a ON a.brid = b.brid
WHERE a.acctype = 'current'
GROUP BY b.brid,
b.street,
b.city,
b.p_code;
You can use a correlated subquery for this purpose:
select b.*, -- or whatever columns you want
(select count(1)
from account a
where a.brid = b.brid and a.acctype = 'current'
) as num_accounts
from branch b;
In other words, you appear to have an error in how your are referencing columns in b, but the actual part of the query that does the count is correct.
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 1 year ago.
Improve this question
I am try to understant how to make a table that tells me in which specific day were written the most mentions about the persons in my table.
SELECT
person,
COUNT(1) AS count_mentions,
COUNT(DISTINCT current_date) AS mention_per_date,
FROM
`aesthetic-honor-311413.big_data_alon_peled_2021.israel_media_person`
GROUP BY
person
ORDER BY
current_date asc
LIMIT
10;
EXPECTED RESULT:
person mention_per_date
Tomer 24
Shalev 18
Yosef 15
Eran 15
Gal 11
(Fictive names and numbers)
I am try to understant how to make a table that tells me in which specific day were written the most mentions about the persons in my table.
For this question, I would expect a query like this:
SELECT person, date, COUNT(*)
FROM `aesthetic-honor-311413.big_data_alon_peled_2021.israel_media_person`
GROUP BY person, date
QUALIFY ROW_NUMBER() OVER (PARTITION BY person ORDER BY COUNT(*) DESC) = 1;
This returns the date that most frequently occurs for each person. You don't mention the name of the date column, so this just uses date.
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
Improve this question
Sorry, if question unclear, i had misstakes it first tables. I made some updates:
Database: PostgreSQL
I want to group table based on transition (if a=b & b=c then a=c)
Adding a pair (4,c) will merge 2 groups to one "group1".
i assume u want a.b.c to be group1 and the d as group2..
the groupby will work perfectly fine with aliases..
but the number of group op wants is 3 millions groups so a stored proc with a incremental in the end and group by will work fine..
From your comments, it looks like you want to find out transitive relationship.
You can do that with following query. But if the goal here is just to identify the relationship among different groups with their respective id, i guess you can afford to have groups which are not getting incremented with 1.
According to your given example in OP, i think it won't affect you if end result has group1 and group5 instead of group2.
If mention result is fine then you can do that with following updated query. Giving group names in successive manner will impact on query performance which you don't want as you've 3 million of groups.
Please try following query:
select t1.id, concat('group', min(t2.minId)) groups
from t1
join
(select min(id) minId, groups
from t1
group by groups
) t2
on t1.groups = t2.groups
join (select #cnt := 1)y
group by t1.id;
Demo : Click here
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
Improve this question
How can I put 1,2,3,4.... in sequence order in column salary where salary is null?? in oracle
I tried many things but could not find any accurate result
select nvl(column,1) as columnName from yourTable
Use ROWNUM pseudocolumn with nvl function:
select nvl(salary, ROWNUM ) from yourTable
ROWNUM pseudocolumn returns a number indicating the order in which Oracle selects the row from a table or set of joined rows. The first row selected has a ROWNUM of 1, the second has 2, and so on.