Trying to get an overall distinct count of the employees for a range of records which has a group by on it.
I've tried using the "over()" clause but couldn't get that to work. Best to explain using an example so please see my script below and wanted result below.
EDIT:
I should mention I'm hoping for a solution that does not use a sub-query based on my "sales_detail" table below because in my real example, the "sales_detail" table is a very complex sub-query.
Here's the result I want. Column "wanted_result" should be 9:
Sample script:
CREATE TEMPORARY TABLE [sales_detail] (
[employee] varchar(100),[customer] varchar(100),[startdate] varchar(100),[enddate] varchar(100),[saleday] int,[timeframe] varchar(100),[saleqty] numeric(18,4)
);
INSERT INTO [sales_detail]
([employee],[customer],[startdate],[enddate],[saleday],[timeframe],[saleqty])
VALUES
('Wendy','Chris','8/1/2019','8/12/2019','5','Afternoon','1'),
('Wendy','Chris','8/1/2019','8/12/2019','5','Morning','5'),
('Wendy','Chris','8/1/2019','8/12/2019','6','Morning','6'),
('Dexter','Chris','8/1/2019','8/12/2019','2','Mid','2.5'),
('Jennifer','Chris','8/1/2019','8/12/2019','4','Morning','2.75'),
('Lila','Chris','8/1/2019','8/12/2019','2','Morning','3.75'),
('Rita','Chris','8/1/2019','8/12/2019','2','Mid','1'),
('Tony','Chris','8/1/2019','8/12/2019','4','Mid','2'),
('Tony','Chris','8/1/2019','8/12/2019','1','Morning','6'),
('Mike','Chris','8/1/2019','8/12/2019','4','Mid','1.5'),
('Logan','Chris','8/1/2019','8/12/2019','3','Morning','6.25'),
('Blake','Chris','8/1/2019','8/12/2019','4','Afternoon','0.5')
;
SELECT
[timeframe],
SUM([saleqty]) AS [total_qty],
COUNT(DISTINCT [s].[employee]) AS [employee_count1],
SUM(COUNT(DISTINCT [s].[employee])) OVER() AS [employee_count2],
9 AS [wanted_result]
FROM (
SELECT
[employee],[customer],[startdate],[enddate],[saleday],[timeframe],[saleqty]
FROM
[sales_detail]
) AS [s]
GROUP BY
[timeframe]
;
If I understand correctly, you are simply looking for a COUNT(DISTINCT) for all employees in the table? I believe this query will return the results you are looking for:
SELECT
[timeframe],
SUM([saleqty]) AS [total_qty],
COUNT(DISTINCT [s].[employee]) AS [employee_count1],
(SELECT COUNT(DISTINCT [employee]) FROM [sales_detail]) AS [employee_count2],
9 AS [wanted_result]
FROM #sales_detail [s]
GROUP BY
[timeframe]
You can try this below option-
SELECT
[timeframe],
SUM([saleqty]) AS [total_qty],
COUNT(DISTINCT [s].[employee]) AS [employee_count1],
SUM(COUNT(DISTINCT [s].[employee])) OVER() AS [employee_count2],
[wanted_result]
-- select count form sub query
FROM (
SELECT
[employee],[customer],[startdate],[enddate],[saleday],[timeframe],[saleqty],
(select COUNT(DISTINCT [employee]) from [sales_detail]) AS [wanted_result]
--caculate the count with first sub query
FROM [sales_detail]
) AS [s]
GROUP BY
[timeframe],[wanted_result]
Use a trick where you only count each person on the first day they are seen:
select timeframe, sum(saleqty) as total_qty),
count(distinct employee) as employee_count1,
sum( (seqnum = 1)::int ) as employee_count2
9 as wanted_result
from (select sd.*,
row_number() over (partition by employee order by startdate) as seqnum
from sales_detail sd
) sd
group by timeframe;
Note: From the perspective of performance, your complex subquery is only evaluated once.
I want to retrieve different information in one statement from the same table and they have different number of rows.
The first select has five rows in the result and the second select has three rows because some prices have null value. I thought maybe if I can put zero instead of null so they will match the same number of rows but I don't know how to do that, or is there another solution?
select count(ID), Land
from Film_ha2911
group by Land
union
select count(ID)
from Film_ha2911
where Price is not null
group by Land;
The use of UNION implies that the number and type of columns in select must corresponding
so in your case you should use null for not select columns
select count(ID), Land
from Film_ha2911
group by Land
union
select count(ID), null
from Film_ha2911
where Price is not null
group by Land;
But in this case seems you need a left join on the subquery for land
select t1.count1, t1.land , t2.count2
from (
select count(ID) count1, Land
from Film_ha2911
group by Land
) t1
left join (
select count(ID) count2, land
from Film_ha2911
where Price is not null
group by Land;
) t2 on t1.land = t2.land
The desired result can be achieved by single SELECT without UNION.
Extra column: PriceNotNull to differentiate is Price value filled or not:
SELECT
Land,
CASE WHEN Price IS NOT NULL THEN 'True' ELSE 'False' END PriceNotNull,
COUNT(ID) AS Count_ID
FROM Film_ha2911
GROUP BY Land, CASE WHEN Price IS NOT NULL THEN 'True' ELSE 'False' END
You can just use count():
select Land, count(*) as total_rows,
count(price) as total_with_price
from Film_ha2911
group by Land;
count() counts the number of non-NULL values, so no special logic is needed to count non-NULL values. By count(id) I assume you want to count all the rows. count(*) is more explicit -- as would count(1) which some people prefer.
If you actually want this on separate rows, I would add an indicator for what the count means:
select Land, 'total rows' as which, count(*) as total_rows
from Film_ha2911
group by Land
union all
select Land, 'with price', count(price)
from Film_ha2911
group by Land;
However, I think the first version with two separate columns is more useful.
I want to count id_r and then return the maxim value of count using
MAX(COUNT(id_r))
but shows me this error
the error
Thanks :)
You can only use one aggregation function at a time.
The ANSI standard way to do what you want is:
select count(*)
from t
group by ?
order by count(*) desc
fetch first 1 row only;
Or alternatively a subquery:
select max(cnt)
from (select count(*) as cnt
from t
group by ?
) x;
Note that you want a group by of something, perhaps id_r.
Try this:
SELECT MAX(e1) as Expr1 FROM (
SELECT COUNT(id_r) as e1
FROM Angajat) as t1
COUNT(id_r) wil return only 1 result since there is no group by clause. Hence, there is no use of max.
You need to add a group by clause in subquery:
SELECT MAX(e1) as Expr1 FROM (
SELECT column1, COUNT(id_r) as e1
FROM Angajat
GROUP BY column1
) as t1
I have a t-sql query where sum function is duplicated.
How to avoid duplicating those statements?
select
Id,
sum(Value)
from
SomeTable
group by
Id
having
sum(Value) > 1000
It look like table aliasing is not supported.
I think with should work:
with tmptable (id,sumv)
as
(select
Id,
sum(Value) as sumv
from
SomeTable
group by
Id
)
select
id,
sumv
from
tmptable
where
sumv>1000
And a fiddle:
http://sqlfiddle.com/#!6/0d3f2/2
You need to remove the sum(Value) from the group by clause.
You can use GROUP BY 1, 2 to group by (in this case) the first and second columns, and thus avoid duplication in the GROUP BY clause.
Among the fields in my table are 2 fields, CTN_NUM and PO_NUM. Each PO_NUM has at least one CTN_NUM, possibly more—distinct or repeated. Any given CTN_NUM cannot have more than 1 PO_NUM. In other words, it's a one to many relationship. I want to create a query which shows the number of unique CTN_NUM's per PO_NUM. I've seen other threads on this forum as well as http://blogs.office.com/b/microsoft-access/archive/2007/09/19/writing-a-count-distinct-query-in-access.aspx and none seem to address this exact issue.
Here's what I tried:
A)
SELECT PO_NUM, Count(CTN_NUM) AS CountOfCTN_NUM
FROM tempSpring_ASN
GROUP BY PO_NUM;
This returns the count of ALL CTN_NUMs per PO_NUM, even if they are not unique.
B)
SELECT PO_NUM, Count(DISTINCT CTN_NUM) AS CountOfCTN_NUM
FROM tempSpring_ASN
GROUP BY PO_NUM;
While this may work in other RDBMS’s, in Access I get a syntax error.
C)
SELECT COUNT(*)
FROM
(SELECT DISTINCT CTN_NUM AS cn
FROM tempSpring_ASN);
This returns the sum of CTN_NUM’s which are distinct to the table, not distinct to the PO_NUM.
D) Same as C, but with a GROUP BY:
SELECT COUNT(*)
FROM
(SELECT DISTINCT CTN_NUM AS cn
FROM tempSpring_ASN)
GROUP BY PO_NUM;
This prompts me for the PO_NUM.
Can you please advise? Thanks.
Try this one:
SELECT PO_NUM, COUNT(*) AS CountOfCTN_NUM
FROM (
SELECT PO_NUM, CTN_NUM
FROM tempSpring_ASN
GROUP BY PO_NUM, CTN_NUM
) a
GROUP BY PO_NUM;
This should also work:
SELECT PO_NUM, COUNT(*) AS CountOfCTN_NUM
FROM (
SELECT DISTINCT PO_NUM, CTN_NUM
FROM tempSpring_ASN
) a
GROUP BY PO_NUM;
Letter D has a syntax error on it. PO_NUM is not present on subquery so you can't use group by on it. It might be that the subquery misses PO_NUM.