Removing Duplicates only when criteria's are met - sql

Question

Last question in regards to duplication. I understand how to select duplicate records using COUNT(*) with the HAVING clause > 1, but I'm faced with a challenge of removing duplicates given when a criteria has been met.
I asked one part of this yesterday in removing duplicates when the bill amount cancels out, but now I have to include a criteria to it where when the bill amount has the same positive and negative value that cancels out, the date is the same for both as well as the code.
So for example, record 1 has a bill amount of $250 with code "JUN" and a date of 03/02/2020, record 2 has a bill amount of $250 with code "PII" and a date of 03/07/2020 and record 3 has a bill amount of -$250 with code "PII" and a date of 03/07/2020. The results I would like to see in this example is only record 1 where record 2 and 3 would be consider the duplicates given the criteria that I stated.
Table Creation:
CREATE TABLE Billing (
BillId varchar(10),
SerialNo varchar(10),
BillAmt MONEY,
Code varchar(5),
DispenseDt DATE
);
Data Entry:
INSERT INTO Billing (BillId, SerialNo, BillAmt, Code, DispenseDt)
VALUES ('BL_001','aaa-111',250,'AAP','20200503')
,('BL_002','aab-112',250,'ADD','20200309')
,('BL_003','aab-112',-250,'ADD','20200309')
,('BL_004','aba-120',700,'YED','20200503')
,('BL_005','aba-120',370,'TPP','20200822')
,('BL_006','aba-120',370,'TPP','20201003')
,('BL_007','aba-120',400,'TPP','20200822')
,('BL_008','aba-120',-370,'TPP','20200822')
,('BL_009','aba-120',-700,'YED','20200503')
,('BL_010','baa-201',1000,'TOK','20200927')
,('BL_011','baa-201',-1000,'TOK','20200927')
,('BL_012','bab-210',1000,'TOK','20200927');
Sample Data:
+----------+-----------+---------+------+------------+
| BillId | SerialNo | BillAmt | Code | DispenseDt |
+----------+-----------+---------+------+------------+
| BL_001 | aaa-111 | $250 | AAP | 20200503 |
| BL_002 | aab-112 | $250 | ADD | 20200309 |
| BL_003 | aab-112 |-$250 | ADD | 20200309 |
| BL_004 | aba-120 | $700 | YED | 20200503 |
| BL_005 | aba-120 | $370 | TPP | 20200822 |
| BL_006 | aba-120 | $370 | TPP | 20201003 |
| BL_007 | aba-120 | $400 | TPP | 20200822 |
| BL_008 | aba-120 |-$370 | TPP | 20200822 |
| BL_009 | aba-120 |-$700 | YED | 20200503 |
| BL_010 | baa-201 | $1000 | TOK | 20200927 |
| BL_011 | baa-201 |-$1000 | TOK | 20200927 |
| BL_012 | bab-210 | $1000 | TOK | 20200927 |
+----------+-----------+---------+------+------------+
Desire Results:
+----------+-----------+---------+------+------------+
| BillId | SerialNo | BillAmt | Code | DispenseDt |
+----------+-----------+---------+------+------------+
| BL_001 | aaa-111 | $250 | AAP | 20200503 |
| BL_006 | aba-120 | $370 | TPP | 20201003 |
| BL_007 | aba-120 | $400 | TPP | 20200822 |
| BL_012 | bab-210 | $1000 | TOK | 20200927 |
+----------+-----------+---------+------+------------+
My Code:
select a.SerialNo, a.BillAmt, a.Code, a.DispenseDt
from (
select *,
count(SerialNo) over(partition by SerialNo, DispenseDt) b
from Billing ) a
where b = 1
AND
InvoiceDt >= '20200601' And InvoiceDt <= '20200630'
AND
FacID IN ('IND600','IND605','IND610','IND620','IND630','IND640','IND650','IND660','IND670','IND680','IND690','IND695')
ORDER BY a.Serial;

Answer 1

i tried to solve it but I am kind of stuck myself. The logic here was to get ranks and then filter the rank that is same but somehow my code creates rank [created 2 of them using rank() and row_number()] that will remove some of the cases that you need as output maybe if someone else can edit this code? that would be great
fiddle link:
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=e0c990d3694ad99b628b3e05a5de624f
select
Bill_ID,
Code,
DispenseDt,
new_bill_amt,
rank()
over(partition by new_bill_amt,DispenseDt, code) as rank_,
row_number()
over(partition by new_bill_amt,DispenseDt, code) as rank_2
from (
select
*,
replace(billamt,'-','') as new_bill_amt
from Billing
) as f

Answer 2

I think this might work.
(I used a CTE, but you could convert that into a subquery.)
WITH base_cte AS (
SELECT
B1.SerialNo
, SUM(B1.BillAmt) AS [TotAmt]
, B1.Code
, B1.DispenseDt
FROM #Billing AS B1
GROUP BY
B1.SerialNo
, B1.Code
, B1.DispenseDt
)
SELECT
B.BillId
, B.SerialNo
, B.BillAmt
, B.code
, B.DispenseDt
FROM #Billing AS B
LEFT JOIN base_cte AS X ON X.SerialNo = B.SerialNo
WHERE X.TotAmt = B.BillAmt
AND X.DispenseDt = B.DispenseDt
Output:
BillId SerialNo BillAmt code DispenseDt
BL_001 aaa-111 250.00 AAP 2020-05-03
BL_006 aba-120 370.00 TPP 2020-10-03
BL_007 aba-120 400.00 TPP 2020-08-22
BL_012 bab-210 1000.00 TOK 2020-09-27
EDIT: Here's a different method with OVER().
SELECT
Y.BillId
, Y.SerialNo
, Y.BillAmt
, Y.Code
, Y.DispenseDt
FROM (
SELECT X.*
, [Ct] = COUNT(*) OVER(PARTITION BY X.code, X.TotAmt, X.DispenseDt ORDER BY X.SerialNo, X.code, X.DispenseDt)
FROM (
SELECT
B.BillId
, B.SerialNo
, B.BillAmt
, B.code
, B.DispenseDt
, [TotAmt] = SUM(B.BillAmt) OVER(PARTITION BY B.SerialNo, B.code, B.DispenseDt ORDER BY B.SerialNo, B.code, B.DispenseDt)
FROM #Billing AS B
) AS X
) AS Y
WHERE Y.BillAmt = Y.TotAmt
ORDER BY Y.BillId