Is there a way to join two queries in SQL each with an order by? - sql

Question

I have two queries that return data from two tables:
SELECT TOP 3
AE.id, AE.name, COUNT(R.id) 'number of reserves'
FROM
AIRPORT AE
INNER JOIN
FLY V ON V.id_destiny = AE.id
INNER JOIN
RESERVE R ON R.id_fly = V.id
GROUP BY
AE.id, AE.name
ORDER BY
COUNT(R.id) DESC;
Example of returned data:
id
name
number of reserves
6
name1
27
4
name2
18
14
name3
14
and
SELECT TOP 3
AE.id, AE.name, COUNT(R.id) 'number of reserves'
FROM
AEROPUERTO AE
LEFT JOIN
FLY V ON V.id_destiny = AE.id
LEFT JOIN
RESERVE R ON R.id_fly = V.id
GROUP BY
AE.id, AE.name
ORDER BY
COUNT(R.id) ASC;
Example of data returned from this second query:
id
name
number of reserves
7
name4
0
11
name5
0
12
name6
0
I need to combine these into a single output with the first query first (in the same order) and the second query next with the same order like this:
id
name
number of reserves
6
name1
27
4
name2
18
14
name3
14
7
name4
0
11
name5
0
12
name6
0
Is there a way to do it?
Edit: I have already tried the union all option, but I can't use the group by in each query so the table that is returned is different from what I need
(SELECT TOP 3 AE.id, AE.name, COUNT(R.id) 'number of reserves'
FROM AIRPORT AE
INNER JOIN FLY V
ON V.id_destiny = AE.id
INNER JOIN RESERVE R
ON R.id_fly = V.id
GROUP BY AE.id, AE.name)
UNION ALL
(SELECT TOP 3 AE.id, AE.name, COUNT(R.id) 'number of reserves'
FROM AEROPUERTO AE
LEFT JOIN FLY V
ON V.id_destiny= AE.id
LEFT JOIN RESERVE R
ON R.id_fly = V.id
GROUP BY AE.id, AE.name)
ORDER BY COUNT(R.id) ASC;

Answer 1

When you enclosed each query in parenthesis, it is acting like a derived table. You will need a SELECT clause to select from the derived table.
SELECT *
FROM
(
-- Your first query here
) AS Q1
UNION ALL
SELECT *
FROM
(
-- Your second query here
) AS Q2
You may also use CTE to do it
WITH
Q1 AS
(
-- Your first query here
),
Q2 AS
(
-- Your second query here
)
SELECT *
FROM Q1
UNION ALL
SELECT *
FROm Q2
EDIT : if you also wanted the final result in the same order in both query, add another column for final query ORDER BY
WITH
Q1 AS
(
SELECT TOP 3
AE.id, AE.name, COUNT(R.id) 'number of reserves',
Q = 1,
RN = ROW_NUMBER() OVER (ORDER BY COUNT(R.id) DESC)
FROM
AIRPORT AE
INNER JOIN
FLY V ON V.id_destiny = AE.id
INNER JOIN
RESERVE R ON R.id_fly = V.id
GROUP BY
AE.id, AE.name
ORDER BY
COUNT(R.id) DESC
),
Q2 AS
(
SELECT TOP 3
AE.id, AE.name, COUNT(R.id) 'number of reserves',
Q = 2,
RN = ROW_NUMBER() OVER (ORDER BY COUNT(R.id) DESC)
FROM
AEROPUERTO AE
LEFT JOIN
FLY V ON V.id_destiny = AE.id
LEFT JOIN
RESERVE R ON R.id_fly = V.id
GROUP BY
AE.id, AE.name
ORDER BY
COUNT(R.id) ASC
)
SELECT *
FROM Q1
UNION ALL
SELECT *
FROM Q2
ORDER BY Q, RN

Answer 2

I break the query and made two temp tables. You can do this in CTE (Commn Table expression) as well.
SELECT TOP 3 AE.id, AE.name, COUNT(R.id) 'number of reserves'
INTO #Temp_1
FROM AIRPORT AE
INNER JOIN FLY V
ON V.id_destiny = AE.id
INNER JOIN RESERVE R
ON R.id_fly = V.id
GROUP BY AE.id, AE.name
SELECT TOP 3 AE.id, AE.name, COUNT(R.id) 'number of reserves'
into #Temp_2
FROM AEROPUERTO AE
LEFT JOIN FLY V
ON V.id_destiny= AE.id
LEFT JOIN RESERVE R
ON R.id_fly = V.id
GROUP BY AE.id, AE.nam
SELECT *
FROM #Temp_1
UNION ALL
SELECT *
FROM #Temp_2
drop table #Temp_1
drop table #Temp_2