Turn to lowercase using SPARQL replace - sparql

Hi I'm trying to simply write a function that lowercase some of the letter of a string, but without success.
Here is what I wrote:
SELECT *
WHERE {
BIND (REPLACE ("HELLO", "L", LCASE("$0") ) AS ?var)
}
I get back "HELLO".
I followed the spec here https://www.w3.org/TR/xpath-functions/#func-replace for the "$x".
However if I write
SELECT *
WHERE {
BIND (REPLACE ("HELLO", "L", LCASE("$0HI") ) AS ?var)
}
I get back "HELhiLhiO".
Why the LCASE can't be applied to $x?

The LCASE is applied to the string, then the result is passed to the REPLACE function, just like writing "function(1+2)" -- the function get passed 3,not 1+2.
So LCASE is not applied to the value of $0 but to the string "$0".
LCASE("$0HI") is "$0hi".
The REPLACE executes as:
REPLACE ("HELLO", "L", "$0hi")
and each "L" is replaced by "$0hi" with $0 being substituted for "L".

Related

Split by delimiter which is contained in a record

I have a column which I am splitting in Snowflake.
The format is as follows:
I have been using split_to_table(A, ',') inside of my query but as you can probably tell this uncorrectly also splits the Scooter > Sprinting, Jogging and Walking record.
Perhaps having the delimiter only work if there is no spaced on either side of it? As I cannot see a different condition that could work.
I have been researching online but haven't found a suitable work around yet, is there anyone that encountered a similar problem in the past?
Thanks
This is a custom rule for the split to table, so we can use a UDTF to apply a custom rule:
create or replace function split_to_table2(STR string, DELIM string, ROW_MUST_CONTAIN string)
returns table (VALUE string)
language javascript
strict immutable
as
$$
{
initialize: function (argumentInfo, context) {
},
processRow: function (row, rowWriter, context) {
var buffer = "";
var i;
const s = row.STR.split(row.DELIM);
for(i=0; i<s.length-1; i++) {
buffer += s[i];
if(s[i+1].includes(row.ROW_MUST_CONTAIN)) {
rowWriter.writeRow({VALUE: buffer});
buffer = "";
} else {
buffer += row.DELIM
}
}
rowWriter.writeRow({VALUE: s[i]})
},
}
$$;
select VALUE from
table(split_to_table2('Car > Bike,Bike > Scooter,Scooter > Sprinting, Jogging and Walking,Walking > Flying', ',', '>'))
;
Output:
VALUE
Car > Bike
Bike > Scooter
Scooter > Sprinting, Jogging and Walking
Walking > Flying
This UDTF adds one more parameter than the two in the build in table function split_to_table. The third parameter, ROW_MUST_CONTAIN is the string a row must contain. It splits the string on DELIM, but if it does not have the ROW_MUST_CONTAIN string, it concatenates the strings to form a complete string for a row. In this case we just specify , for the delimiter and > for ROW_MUST_CONTAIN.
We can get a little clever with regexp_replace by replacing the actual delimiters with something else before the table split. I am using double pipes '||' but you can change that to something else. The '\|\|\\1' trick is called back-referencing that allows us to include the captured group (\\1) as part of replacement (\|\|)
set str='car>bike,bike>car,truck, and jeep,horse>cat,truck>car,truck, and jeep';
select $str, *
from table(split_to_table(regexp_replace($str,',([^>,]+>)','\|\|\\1'),'||'))
Yes, you are right. The only pattern, which I can see, is the one with the whitespace after the comma.
It's a small workaround but we can make use of this pattern. In below code I am replacing such commas, where we do have whitespaces afterwards. Then I am applying split to table function and I am converting the previous replacement back.
It's not super pretty and would crash if your string contains "my_replacement" or any other new pattern, but its working for me:
select replace(t.value, 'my_replacement', ', ')
from table(
split_to_table(replace('Car > Bike,Bike > Scooter,Scooter > Sprinting, Jogging and Walking,Walking > Flying', ', ', 'my_replacement'),',')) t

How to replace string characters that are not in a reference list in kotlin

I have a reference string on which the allowed characters are listed. Then I also have input strings, from which not allowed characters should be replaced with a fixed character, in this example "0".
I can use filter but it removes the characters altogether, does not offer a replacement. Please note that it is not about being alphanumerical, there are ALLOWED non-alphanumerical characters and there are not allowed alphanumerical characters, referenceStr happens to be arbitrary.
var referenceStr = "abcdefg"
var inputStr = "abcqwyzt"
inputStr = inputStr.filter{it in referenceStr}
This yields:
"abc"
But I need:
"abc00000"
I also considered replace but it looks more like when you have a complete reference list of characters that are NOT allowed. My case is the other way around.
Given:
val referenceStr = "abcd][efg"
val replacementChar = '0'
val inputStr = "abcqwyzt[]"
You can do this with a regex [^<referenceStr>], where <referenceStr> should be replaced with referenceStr:
val result = inputStr.replace("[^${Regex.escape(referenceStr)}]".toRegex(), replacementChar.toString())
println(result)
Note that Regex.escape is used to make sure that the characters in referenceStr are all interpreted literally.
Alternatively, use map:
val result = inputStr.map {
if (it !in referenceStr) replacementChar else it
}.joinToString(separator = "")
In the lambda decide whether the current char "it" should be transformed to replacementChar, or itself. map creates a List<Char>, so you need to use joinToString to make the result a String again.

regex rule for email validation is not working in vuejs

I tried this code as provided in https://v2.vuejs.org/v2/cookbook/form-validation.html.
validEmail: function (email) {
var re = /^(([^<>()\[\]\\.,;:\s#"]+(\.[^<>()\[\]\\.,;:\s#"]+)*)|(".+"))#((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
return re.test(email);
}
Vuejs is saying that - error: Unnecessary escape character: \[ (no-useless-escape) at src/components/form.vue:125:65 which is the line var re = ...
What I am getting wrong here? I called this function like this.validEmail(this.modelname)
The "error" (technically it's just a warning) is saying that you do not need to escape [ in the regex when it is inside a character set ([] syntax) because its meaning is unambiguous (you can't create nested character sets); ], on the other hand, does need to be escaped because it will be interpreted as part of the regex syntax that ends the character set instead of a literal ] character.
Simplified example:
/[\[]/
^ unnecessary escape
should be instead:
/[[]/

whats a good way to parse the incoming url in nifi?

When using HandleHttpRequest, i want to setup a structure to operate on different objects through the same handler:
/api/foo/add/1/2..
how do i easily parse that out into
object = foo
operation = add
arg1 = [1,2,...]
?
Why not to use ExpressionLanguage getDelimitedField ?
From the Expression Language documentation:
getDelimitedField
Description: Parses the Subject as a delimited line of text and returns just a single field from that delimited text.
Subject Type: String
Arguments:
index : The index of the field to return. A value of 1 will return the first field, a value of 2 will return the second field, and so on.
delimiter : Optional argument that provides the character to use as a field separator. If not specified, a comma will be used. This value must be exactly 1 character.
quoteChar : Optional argument that provides the character that can be used to quote values so that the delimiter can be used within a single field. If not specified, a double-quote (") will be used. This value must be exactly 1 character.
escapeChar : Optional argument that provides the character that can be used to escape the Quote Character or the Delimiter within a field. If not specified, a backslash (\) is used. This value must be exactly 1 character.
stripChars : Optional argument that specifies whether or not quote characters and escape characters should be stripped. For example, if we have a field value "1, 2, 3" and this value is true, we will get the value 1, 2, 3, but if this value is false, we will get the value "1, 2, 3" with the quotes. The default value is false. This value must be either true or false.
This code is just an example you can try sticking a executeScript processor on nifi's workbench. You can use this as example.
from urlparse import parse_qs, urlparse
def parse ( uri2parse ) :
o = urlparse( uri2parse )
d = parse_qs( o.query )
return ( o.path[1:], d['year'][0], d['month'][0], d['day'][0] )
# get the flow file from the incoming queue
flowfile = session.get()
if flowfile is not None:
source_URI = flowfile.getAttribute( 'source_URI' )
destination_URI = flowfile.getAttribute( 'destination_URI' )
current_time = flowfile.getAttribute( 'current_time' )
# expand the URI into smaller pieces
src_table, src_year, src_month, src_day = parse( source_URI )
dst_table, dst_year, dst_month, dst_day = parse( destination_URI )
flowfile = session.putAllAttributes( flowfile, { 'src_table' : src_table, 'src_year': src_year, 'src_month' :src_month, 'src_day': src_day })
flowfile = session.putAllAttributes( flowfile, { 'dst_table' : dst_table, 'dst_year': dst_year, 'dst_month' :dst_month, 'dst_day': dst_day })
session.transfer( flowfile, REL_SUCCESS )
else:
flowfile = session.create()
session.transer( flowfile, REL_FAILURE )

Powershell and SQL parameters. If empty string, pass DBNull

I got this parameter:
$objDbCmd.Parameters.Add("#telephone", [System.Data.SqlDbType]::VarChar, 18) | Out-Null;
$objDbCmd.Parameters["#telephone"].Value = $objUser.Telephone;
Where the string $objUser.Telephone can be empty. If it's empty, how can I convert it to [DBNull]::Value?
I tried:
if ([string]:IsNullOrEmpty($objUser.Telephone)) { $objUser.Telephone = [DBNull]::Value };
But that gives me the error:
Exception calling "ExecuteNonQuery" with "0" argument(s): "Failed to convert parameter value from a ResultPropertyValueCollection to a String."
And if I convert it to a string, it inserts an empty string "", and not DBNull.
How can this be accomplished?
Thanks.
In PowerShell, you can treat null/empty strings as a boolean.
$x = $null
if ($x) { 'this wont print' }
$x = ""
if ($x) { 'this wont print' }
$x = "blah"
if ($x) { 'this will' }
So.... having said that you can do:
$Parameter.Value = $(if ($x) { $x } else { [DBNull]::Value })
But I'd much rather wrap this up in a function like:
function CatchNull([String]$x) {
if ($x) { $x } else { [DBNull]::Value }
}
I don't know about powershell, but in C# I would do something like this:
if ([string]::IsNullOrEmpty($objUser.Telephone))
{
$objDbCmd.Parameters["#telephone"].Value = [DBNull]::Value;
}
else
{
$objDbCmd.Parameters["#telephone"].Value = $objUser.Telephone;
}
Always append +"" at the end of db values...
$command.Parameters["#EmployeeType"].Value= $ADResult.EmployeeType + ""
Many years later, let me clarify:
Josh's answer shows a helpful simplification for testing strings for emptiness (relying on PowerShell's implicit to-Boolean conversion[1]), but it is unrelated to Tommy's (the OP's) problem.
Instead, the error message
"Failed to convert parameter value from a ResultPropertyValueCollection to a String."
implies that it is the non-null case that caused the problem, because $objDbCmd.Parameters["#telephone"].Value expects either a string value or [DBNull]::Value, whereas $objUser.Telephone is of type [ResultPropertyValueCollection], i.e. a collection of values.
Thus, in the non-null case, a string value must be assigned, which must be derived from the collection; one option is to take the first collection element's value, another would be to join all values with a separator to form a single string, using, e.g., [string]::Join(';', $objUser.Telephone) or, if joining the elements with spaces is acceptable (not a good idea with multiple phone numbers), simply with "$($objUser.Telephone)".[2]
Detecting an empty collection via [string]:IsNullOrEmpty() actually worked, despite the type mismatch, due to how PowerShell implicitly stringifies collections when passing a value to a [string] typed method parameter.[2]
Similarly, using implicit to-Boolean conversion works as expected with collections too: an empty collection evaluates to $false, a non-empty one to $true (as long as there are either at least two elements or the only element by itself would be considered $true[1])
Therefore, one solution is to use the first telephone number entry:
$objDbCmd.Parameters["#telephone"].Value = if ($objUser.Telephone) {
$objUser.Telephone[0].ToString() # use first entry
} else {
[DBNull]::Value
}
Note: If $objUser.Telephone[0] directly returns a [string], you can omit the .ToString() call.
In PowerShell v7+ you can alternatively shorten the statement via a ternary conditional:
$objDbCmd.Parameters["#telephone"].Value =
$objUser.Telephone ? $objUser.Telephone[0].ToString() : [DBNull]::Value
[1] For a comprehensive summary of PowerShell's automatic to-Boolean conversions, see the bottom section of this answer.
[2] When implicitly converting a collection to a string, PowerShell joins the stringified elements of a collection with a single space as the separator by default; you can override the separator with the automatic $OFS variable, but that is rarely done in practice; e.g., array 'foo', 'bar' is converted to 'foo bar'; note that this conversion does not apply when you call the collection's .ToString() method explicitly, but it does apply inside expandable (interpolating) strings, e.g., "$array".