SPARQL Inference with SKOS - sparql

Question

We are trying to showcase inference with linked-data.
The simple graph looks like the following in turtle-format:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX ex: <http://schema.example.com/>
PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
ex:Places rdf:type skos:ConceptScheme .
ex:Localities rdf:type skos:Concept .
ex:Localities skos:prefLabel "Localities" .
ex:Localities skos:inScheme ex:Places.
ex:Countries rdf:type skos:Concept .
ex:Countries skos:prefLabel "Countries" .
ex:Countries skos:inScheme ex:Places.
ex:Continents rdf:type skos:Concept .
ex:Continents skos:prefLabel "Continents" .
ex:Continents skos:inScheme ex:Places.
ex:Persons rdf:type skos:Concept .
ex:Persons skos:prefLabel "Persons" .
ex:livesIn a rdf:Property .
ex:isPartOf a rdf:Property .
ex:Localities skos:broader ex:Countries .
ex:Countries skos:broader ex:Continents .
ex:Europe a ex:Continents .
ex:Switzerland a ex:Countries .
ex:Switzerland ex:isPartOf ex:Europe.
ex:France a ex:Countries .
ex:France ex:isPartOf ex:Europe.
ex:Bern a ex:Localities .
ex:Bern skos:prefLabel "Bern".
ex:Bern ex:isPartOf ex:Switzerland.
ex:Thun a ex:Localities .
ex:Thun skos:prefLabel "Thun".
ex:Thun ex:isPartOf ex:Switzerland.
ex:Paris a ex:Localities .
ex:Paris skos:prefLabel "Paris".
ex:Paris ex:isPartOf ex:France.
ex:Hans a ex:Persons.
ex:Hans skos:prefLabel "Hans".
ex:Hans ex:livesIn ex:Bern.
ex:Fritz a ex:Persons.
ex:Frits skos:prefLabel "Fritz".
ex:Fritz ex:livesIn ex:Thun.
ex:Jaques a ex:Persons.
ex:Jaques skos:prefLabel "Jaques".
ex:Jaques ex:livesIn ex:Paris.
The Idea would be to do the following query in SPARQL:
PREFIX ex: <http://schema.example.com/>
ASK where { ex:Hans ex:livesIn ex:Switzerland }
It should return YES, but it returns NO.
Is there a possibility to model the data, that this ASK-Statement can get answered with YES?
In terms of inference it should be True, since ex:Bern is a ex:Localities and this is a skos:broader of ex:Countries, which is ex:Switzerland.
I haven't found any good examples for skos-Modelling and Inference yet.
We would like to work with skos:concepts and rather not with rdfs-subclassing.
Because it should showcase the inference over concepts in situations, where you are not able to subclass everything.
I am using:
GraphDB 9.5.0 EE
OWL2-RL - Ruleset

Answer 1

To complete the question, I'm posting my comment above as an answer...
To make it work, You need to define some meaning to your properties ex:isPartOf and ex:livesIn.
Suggest to make ex:isPartOf transitive and then to define ex:livesIn as a property chain over ex:isPartOf, e.g.:
ex:isPartOf a owl:TransitiveProperty .
ex:livesIn rdf:type owl:ObjectProperty;
owl:propertyChainAxiom( ex:livesIn ex:isPartOf) .