getdownloadurl from Firebase storage expo cli - react-native

Question

I am trying to display the image from firebase storage. Below is the file location copied from firebase storage. It is a jpeg file
profile/2186uPKjgo4pMOQNm0Cm/profilepic
My following code returned error.
useEffect(() => {
function geturl(){
const filename = "profile/"+userid+"/profilepic.jpeg";
var ref = firebase.storage().ref(filename);
console.log(filename);
// This returns the exact file name
ref.getDownloadURL().then((url)=> {
console.log(url);
});
}
geturl();
}, []);
I got this error [object Object]. After that, I tried the following code async await
useEffect(() => {
async function geturl(){
const filename = "profile/"+userid+"/profilepic.jpeg";
var ref = firebase.storage().ref(filename);
console.log("inside geturl");
const downloadurl = await ref.getDownloadURL();
console.log(downloadurl);
}
geturl();
}, []);
Now Im getting the following error.
Possible Unhandled Promise Rejection (id: 29):
"code_": "storage/object-not-found",
"message_": "Firebase Storage: Object 'profile/2186uPKjgo4pMOQNm0Cm/profilepic.jpeg' does not exist.",
"name_": "FirebaseError",
"serverResponse_": "{
\"error\": {
\"code\": 404,
\"message\": \"Not Found. Could not get object\",
\"status\": \"GET_OBJECT\"
}
}",
}
Please let me know how I can get the url?

Answer 1

here you go you can use this function it uploads image to firebase storage and get the image uri at the same time
const uploadImage = async () => {
const response = await fetch(image);
const blob = await response.blob();
let filename = image.substring(image.lastIndexOf('/')+1);
const ext = filename.split('.').pop();
const name = filename.split('.').slice(0, -1).join('.');
filename = name + Date.now() + '.' + ext;
try {
var ref = firebase.storage().ref().child('post-images/'+filename);
await ref.put(blob)
.then(snapshot => {
return snapshot.ref.getDownloadURL();
})
.then(downloadURL => {
console.log(`Successfully uploaded file and got download link');
return downloadURL;
});
return null;
} catch (error) {
return null;
}
}