Objective:
I have a column 'amount' with decimals. I am trying to exclude rows where the amount value ends either with '0's or '5's.
How can I achieve that...
Column type: decimal (7,2)
Ex: numbers to exclude
10.25
11.20
100.00
You probably want this:
WHERE (CAST(your_field * 100 AS INTEGER) % 5) <> 0
But it is hard to tell without more detail on your data type. Also there can be funky rounding issues with floating point values.
An interesting way to do this uses "modular" arithmetic
where col % 0.1 not in (0.00, 0.05)
The % operator works on non-integer bases as well as integer ones.
What I did here is changed the number into a string, trimmed off the trailing blanks, and then reversed the string to take the first character to see if it was no 1 or 5
SELECT * into #test FROM (SELECT CAST(10.25 as decimal(7,2)) as val UNION SELECT 8.21 UNION SELECT 6.00) DQ
select * from #test WHERE LEFT(REVERSE(RTRIM(CAST(val as nvarchar(50)))),1) NOT IN ('5', '0')
drop table #test
I am trying to accommodate for some rogue values in my database, that contain the string 'unknown', I want to set these to 0 and then sum the rest. But for some reason, this isnt happening. Here is what I have -
Values - VARCHAR(30) -
3
0.1
2
16
2
5
2
Unknown
2.4
7
Unknown
And here is my Cast,Sum,Case
Cast(sum(case when stake = 'Unknown' then 0 else stake end) as float) as totalStake
But I get this error - Conversion failed when converting the varchar value '0.1' to data type int.
Help!
Thanks
You must cast stake as a float:
sum(case when stake = 'Unknown' then 0.0 else cast(stake as float) end) as totalStake
You should explicitly convert to some sort of numeric values. Try this:
sum(try_convert(numeric(18, 4), stake)) as totalStake
Your code has at least two issues. First, your case expression returns an integer (because the first then has an integer). So, it tries to convert stake to an integer, which can generate an error.
Second, you should be doing arithmetic operations on data that is explicitly some sort of number type and not rely on implicit conversion.
You can try the following query using isnumeric() to check numeric data.
create table temp (stake VARCHAR(30))
insert into temp values
('3'), ('0.1'), ('2'), ('16'), ('2'), ('5'), ('2'), ('Unknown'), ('2.4'), ('7'), ('Unknown')
--Select * from temp
Select sum(Cast(stake as Float)) from temp where isnumeric(stake) = 1
To handle some exception like null values or . values only you can try this
Select SUM(TRY_CAST(stake as Float)) from temp
You can find the live demo Here.
Initial step would be to replace the 'Unknown' string with 0 using a replace function and then convert the column datatype to the one which allows to perform Aggregate functions and then perform SUM on top of that. The below query will work only for 'unknown' string, if you have different strings other than 'unknown' you might have to choose a different approach like using IsNumeric in Replace function and update the string value to 0.
select sum(cast((REPLACE(stake,'unknown',0)) as float)) from table
This happens because SQL has some problems while converting decimal values to integer values.
In facts, function sum returns integer values
I solved it using round function on the values1 variable ( sorry for using same name for table and column ):
select Cast(sum(case when values1 = 'Unknown' then 0 else round(values1, 2) end) as
float)as totalstrike
from values1
I'm trying to get the max value from a text field. All but two of the values are numbers with a single decimal. However, two of the values have something like 8.2.10. How can I pull back just the integer value? The values can go higher than 9.n, so I need to convert this field into a number so that I can get the largest value returned. So all I want to get back is the 8 from the 8.2.1.
Select cast(VERSION as int) is bombing out because of those two values with a second . in them.
You may derive by using regexp_substr with \d pattern :
with tab as
(
select regexp_substr('8.2.1', '\d', 1, 1) from dual
union all
select regexp_substr('9.0.1', '\d', 1, 1) from dual
)
select * from tab;
For Oracle you must attend the value as string for retire only the part before the dot. Ex:
SELECT NVL( SUBSTR('8.2.1',0, INSTR('8.2.1','.')-1),'8.2.1') AS SR FROM DUAL;
Check than the value is repeated 3 times in the sentence, and if the value is zero or the value didn't have decimal part then it will return the value as was set.
I had to use T-SQL rather PL/SQL, but the idea is the same:
DECLARE #s VARCHAR(10);
SELECT #s='8.2.1';
SELECT CAST(LEFT(#s, CHARINDEX('.', #s) - 1) AS INT);
returns the integer 8 - note that it won't work if there are no dots because it takes the part of the string to the left of the first dot.
If my quick look at equivalent functions was correct, then in Oracle that would end up as:
SELECT CAST(SUBSTR(VERSION, 1, INSTR(VERSION, '.') - 1) AS INT)
I have a large amount of card tokens (16 digits) uploaded from xml file to sql-server. The problem is I see them as expression, sample below:
3.3733E+15
3.3737E+15
3.3737E+15
3.3737E+15
3.37391E+15
3.37391E+15
3.37398E+15
3.37453E+15
3.37468E+15
3.37468E+15
3.3747E+15
3.37486E+15
3.37486E+15
3.37567E+15
3.3759E+15
3.3759E+15
Any suggestion to change them to a 16 digit number? I have tried to change the data type, but got error"Conversion failed when converting the varchar value '3.37201E+15' to data type int"
Thanks for help!
Edit:
#X.L.Ant see my code below. I create this table from another one, which is just purely inserted from xml file. Is this may cause an error because some rows are empty in column TOKEN?
CREATE TABLE MULTICURRENCY_CHECK
(
TOKEN varchar(255)
)
/*Merges all card tokens into 1 column, as in xml they are spread across different columns*/
INSERT INTO MULTICURRENCY_CHECK
(
TOKEN
)
SELECT no FROM gpstransactionsnew2
UNION ALL
SELECT no19 FROM gpstransactionsnew2
UNION ALL
SELECT no68 FROM gpstransactionsnew2
UNION ALL
SELECT no93 FROM gpstransactionsnew2
UNION ALL
SELECT no107 FROM gpstransactionsnew2
UNION ALL
SELECT no121 FROM gpstransactionsnew2
SELECT REPLACE(TOKEN, 'OW1', ' ')
FROM MULTICURRENCY_CHECK
/*Converts exponential expression to number*/
SELECT CONVERT(numeric(16,0), CAST(TOKEN AS FLOAT))
FROM MULTICURRENCY_CHECK
Try to cast your string to float before converting it :
SELECT CONVERT(numeric(16,0), CAST(TOKEN AS FLOAT))
FROM MULTICURRENCY_CHECK
See this fiddle.
I don't know what's the format of those numbers in your XML source, but with the data you provide, you'll end up with 33733 for instance followed by a bunch of zeroes. If you have a bigger precision in your XML, maybe you should tweak your importing settings to keep this precision instead of trying to deal with that in the DB.
EDIT:
Try testing your strings with ISNUMERIC to avoid the casting errors you're getting. Adding a raw output of your column will allow you to check which value fails to convert (i.e. converts to 0).
SELECT TOKEN,
CONVERT(NUMERIC(16, 0), CAST(CASE
WHEN ISNUMERIC(TOKEN) = 1
THEN TOKEN
ELSE 0
END AS FLOAT))
FROM MULTICURRENCY_CHECK
For SQL Server 2012+, use TRY_CONVERT().
The use of ISNUMERIC() in xlecoustillier's edited answer does not protect against conversion failures.
Given the following scenario:
CREATE TABLE test(a varchar(100));
insert into test values ('3.3733E+15'),
('3.3737E+15'),
('3.37391E+30'), --fails conversion. included to demonstrate the nature of TRY_CONVERT().
('3.37398E+15'),
('3.37453E+15'),
('3.37468E+15'),
('3.3747E+15'),
('3.37486E+15'),
('3.37567E+15'),
('3.3759E+15');
SELECT TRY_CONVERT(numeric(16,0), CAST(a AS FLOAT))
FROM test
Results in only valid converted values:
---------------------------------------
3373300000000000
NULL
3373910000000000
3373980000000000
3374530000000000
3374680000000000
3374700000000000
3374860000000000
3375670000000000
3375900000000000
However:
SELECT a,
CONVERT(NUMERIC(16, 0), CAST(CASE
WHEN ISNUMERIC(a) = 1
THEN a
ELSE 0
END AS FLOAT))
FROM test
Fails with:
Conversion failed when converting the varchar value '3.3733E+15' to
data type int.
The issue is that all values in the 'a' column return 1 when passed to the ISNUMERIC() function.
SELECT CASE WHEN ISNUMERIC(a) = 1 THEN 'Yes' ELSE 'No' END as IsValueNumeric
FROM test
Try it on SQLFiddle and/or compare with xlecoustillier's sqlfiddle
SELECT colmn_name || '' FROM table_name
This should work.
I'm trying to determine the best way to truncate or drop extra decimal places in SQL without rounding. For example:
declare #value decimal(18,2)
set #value = 123.456
This will automatically round #value to be 123.46, which is good in most cases. However, for this project, I don't need that. Is there a simple way to truncate the decimals I don't need? I know I can use the left() function and convert back to a decimal. Are there any other ways?
ROUND ( 123.456 , 2 , 1 )
When the third parameter != 0 it truncates rather than rounds.
Syntax
ROUND ( numeric_expression , length [ ,function ] )
Arguments
numeric_expression
Is an expression of the exact numeric or approximate numeric data
type category, except for the bit data type.
length
Is the precision to which numeric_expression is to be rounded. length must be an expression of type tinyint, smallint, or int. When length is a positive number, numeric_expression is rounded to the number of decimal positions specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified by length.
function
Is the type of operation to perform. function must be tinyint, smallint, or int. When function is omitted or has a value of 0 (default), numeric_expression is rounded. When a value other than 0 is specified, numeric_expression is truncated.
select round(123.456, 2, 1)
SELECT Cast(Round(123.456,2,1) as decimal(18,2))
Here's the way I was able to truncate and not round:
select 100.0019-(100.0019%.001)
returns 100.0010
And your example:
select 123.456-(123.456%.001)
returns 123.450
Now if you want to get rid of the ending zero, simply cast it:
select cast((123.456-(123.456%.001)) as decimal (18,2))
returns 123.45
Actually whatever the third parameter is, 0 or 1 or 2, it will not round your value.
CAST(ROUND(10.0055,2,0) AS NUMERIC(10,2))
Do you want the decimal or not?
If not, use
select ceiling(#value),floor(#value)
If you do it with 0 then do a round:
select round(#value,2)
Another truncate with no rounding solution and example.
Convert 71.950005666 to a single decimal place number (71.9)
1) 71.950005666 * 10.0 = 719.50005666
2) Floor(719.50005666) = 719.0
3) 719.0 / 10.0 = 71.9
select Floor(71.950005666 * 10.0) / 10.0
Round has an optional parameter
Select round(123.456, 2, 1) will = 123.45
Select round(123.456, 2, 0) will = 123.46
ROUND(number, decimals, operation)
number => Required. The number to be rounded
decimals => Required. The number of decimal places to round number to
operation => Optional. If 0, it rounds the result to the number of decimal. If another value than 0, it truncates the result to the number of decimals. Default value is 0
SELECT ROUND(235.415, 2, 1)
will give you 235.410
SELECT ROUND(235.415, 0, 1)
will give you 235.000
But now trimming0 you can use cast
SELECT CAST(ROUND(235.415, 0, 1) AS INT)
will give you 235
This will remove the decimal part of any number
SELECT ROUND(#val,0,1)
SELECT CAST(Value as Decimal(10,2)) FROM TABLE_NAME;
Would give you 2 values after the decimal point. (MS SQL SERVER)
Another way is ODBC TRUNCATE function:
DECLARE #value DECIMAL(18,3) =123.456;
SELECT #value AS val, {fn TRUNCATE(#value, 2)} AS result
LiveDemo
Output:
╔═════════╦═════════╗
║ val ║ result ║
╠═════════╬═════════╣
║ 123,456 ║ 123,450 ║
╚═════════╩═════════╝
Remark:
I recommend using built-in ROUND function with 3rd parameter set to 1.
I know this is pretty late but I don't see it as an answer and have been using this trick for years.
Simply subtract .005 from your value and use Round(#num,2).
Your example:
declare #num decimal(9,5) = 123.456
select round(#num-.005,2)
returns 123.45
It will automatically adjust the rounding to the correct value you are looking for.
By the way, are you recreating the program from the movie Office Space?
Try like this:
SELECT cast(round(123.456,2,1) as decimal(18,2))
If you desire to take some number like 89.0904987 and turn it into 89.09 by simply omitting the undesired decimal places, simply use the following:
select cast(yourColumnName as decimal(18,2))
The following screenshot is from W3Schools SQL Data Types section, which describes what decimal(18,2) is doing:
Therefore,
select cast(89.0904987 as decimal(18,2))
gives you: 89.09
Please try to use this code for converting 3 decimal values after a point into 2 decimal places:
declare #val decimal (8, 2)
select #val = 123.456
select #val = #val
select #val
The output is 123.46
I think you want only the decimal value,
in this case you can use the following:
declare #val decimal (8, 3)
SET #val = 123.456
SELECT #val - ROUND(#val,0,1)
I know this question is really old but nobody used sub-strings to round. This as advantage the ability to round really long numbers (limit of your string in SQL server which is usually 8000 characters):
SUBSTRING('123.456', 1, CHARINDEX('.', '123.456') + 2)
I think we can go much easier with simpler example solution found in Hackerrank:
Problem statement: Query the greatest value of the Northern Latitudes
(LAT_N) from STATION that is less than 137.2345. Truncate your answer
to 4 decimal places.
SELECT TRUNCATE(MAX(LAT_N),4)
FROM STATION
WHERE LAT_N < 137.23453;
Solution Above gives you idea how to simply make value limited to 4 decimal points. If you want to lower or upper the numbers after decimal, just change 4 to whatever you want.
Mod(x,1) is the easiest way I think.
select convert(int,#value)