I'm using sigmoid and binary_crossentropy for multi-label classification. A very similar question asked here. And the following custom metric was suggested:
from keras import backend as K
def full_multi_label_metric(y_true, y_pred):
comp = K.equal(y_true, K.round(y_pred))
return K.cast(K.all(comp, axis=-1), K.floatx())
But I do not want to use all() because for one single sample with a true label of [1, 0, 0, 1, 1] and a predicted label of [0, 0, 0, 1, 1] I do not consider the prediction accuracy as zero (due to the the fact that the labels for the last four classes have been predicted correctly).
Here is my model:
# expected input data shape: (batch_size, timesteps, data_dim)
model = Sequential()
model.add(Masking(mask_value=-9999, input_shape=(197, 203)))
model.add(LSTM(512, return_sequences=True))
model.add(Dense(20, activation='sigmoid'))
model.compile(loss='binary_crossentropy',
optimizer=SGD(lr=1e-3, decay=1e-4, momentum=0.9, nesterov=True),
metrics = ['accuracy'])
print(model.summary())
Here is my y_pred for one example:
pred = model.predict(X_test)
y_pred = pred[0,196,:]
y_pred
array([2.6081860e-01, 9.9079555e-01, 1.4816311e-01, 8.6009043e-01,
2.6759505e-04, 3.0792636e-01, 2.6738405e-02, 8.5339689e-01,
5.1105350e-02, 1.5427300e-01, 6.7039116e-05, 1.7909735e-02,
6.4140558e-04, 3.5133284e-01, 5.3054303e-02, 1.2765944e-01,
2.9298663e-04, 6.3041472e-01, 5.8620870e-03, 5.9656668e-01],
dtype=float32)
Here is my y_true for one example:
y_true = Y_test[0,0,:]
y_true
array([1., 0., 0., 0., 0., 0., 0., 0., 0., 1., 0., 0., 0., 1., 1., 0., 0.,
0., 0., 1.])
My question is: How can I set a Keras custom metric function so that each element in y_pred should be compared to the each element in y_true, then an accuracy measure will be given during training? I want to use this metric in metrics = [X])?
Unless I'm mistaken the default binary_crossentropy metric/loss already does what you need. Taking your example
import tensorflow as tf
from tensorflow import keras
y_true = tf.constant([[1, 0, 0, 1, 1]], dtype=tf.int32)
y_pred = tf.constant([[0.6, 0, 0, 1, 1]], dtype=tf.float32)
m = keras.metrics.binary_crossentropy(y_true, y_pred)
m.numpy()
The output is [-log(0.6) / 5].
i.e. The metric/loss for the batch takes into account the losses for each of the 20 outputs of the model. Which I'm assuming represent time steps.
As a metric, it is much more common to use binary_accuracy.
Example:
y_true = tf.constant([[1, 0, 0, 1, 1]], dtype=tf.int32)
y_pred = tf.constant([[0.1, 0, 0, 1, 1]], dtype=tf.float32)
keras.metrics.binary_accuracy(tf.cast(y_true, tf.float32), y_pred)
One can get a better idea of the performance of the model via an ROC metric (https://www.tensorflow.org/api_docs/python/tf/keras/metrics/AUC) which measures the curve at various thresholds see an explanation at https://towardsdatascience.com/understanding-auc-roc-curve-68b2303cc9c5. Personally, I tend to use an accuracy metric while training and look at the precision/recall curve after the model is trained in order to check that it behaves as expected and select the prediction threshold.
Related
ffnn = Sequential([
Flatten(input_shape=X_train.shape[1:]),
Dense(512, activation='relu'),
Dropout(0.2),
Dense(512, activation='relu'),
Dropout(0.2),
Dense(10, activation='softmax')
])
ffnn_history = ffnn.fit(X_train,
y_train,
batch_size=batch_size,
epochs=epochs,
validation_split=0.2,
callbacks=[checkpointer, early_stopping],
verbose=1,
shuffle=True)
ffnn_accuracy = ffnn.evaluate(X_test, y_test, verbose=0)[1]
These codes are from https://github.com/stefan-jansen/machine-learning-for-trading/blob/main/18_convolutional_neural_nets/02_digit_classification_with_lenet5.ipynb.
I understand this network and how softmax function works. My question is, the output layer has 10 nodes. The output should be a vector of length 10 (the sum of the vector is 1). How does it matches the label y where y is an integer in the training and evaluating process (shouldn't it transform the output vector to the corresponding integer first)?
Does tensorflow automatically interpret the length-10 output vector to the corresponding integer or what?
In your case the labels are one-hot encoded by the loss function sparse_categorical_crossentropy():
>>> y_true = [1, 2]
>>> y_pred = [[0.05, 0.95, 0], [0.1, 0.8, 0.1]]
>>> tf.keras.losses.sparse_categorical_crossentropy(y_true, y_pred).numpy()
array([0.05129344, 2.3025851 ], dtype=float32)
The output softmax(x) can be interpreted as a probability distribution (Σ softmax(x) = 1.0). So e.g. argmax(softmax(x)) = id_maxprob is going to return you the index of the most probable class.
Hence, your target vector for your neural network is going to be 10-dimensional such that each integer [0, 1, .., 8, 9] corresponds to one node of the softmax-output.
With that being said, the target vector you're trying to predict is simply going to be one-hot encoded:
[1, 0, 0, 0, 0, 0, 0, 0, 0, 0] # == 0
[0, 1, 0, 0, 0, 0, 0, 0, 0, 0] # == 1
..
[0, 0, 0, 0, 0, 0, 0, 0, 0, 1] # == 9
In other words: If you have a batch of images and feed it to your network, the output will be (n, num_classes) (here num_classes is 10) and it is you who is going to do the final interpretation of the output e.g. by using np.argmax in order to get your final predictions.
predictions = model(images)
predicted_ids = np.argmax(predictions, axis=1)
# Print each index == predicted integer
print(predicted_ids)
Also, note the following example:
>>> tf.one_hot([1, 2, 9], depth=10)
<tf.Tensor: shape=(3, 10), dtype=float32, numpy=
array([[0., 1., 0., 0., 0., 0., 0., 0., 0., 0.],
[0., 0., 1., 0., 0., 0., 0., 0., 0., 0.],
[0., 0., 0., 0., 0., 0., 0., 0., 0., 1.]], dtype=float32)>
This is related to an implementation issue in TensorFlow. I have a tensor H of size (batch_size, time_steps, 256) (but batch_size and time_steps are None during build time).
I want to compute a tensor A of the shape (batch_size, time_steps, time_steps, n_dim) which is a Cartesian product across the time dimension. Thus, in simple terms:
A[:,i,j,:] = some_func(H[:,i,:], H[:,j,:])
Since the number of time_steps is None at time of building graph, what would be an elegant way to compute A?
You can use TensorFlow's broadcasting properties to construct cartesian products between tensors by expanding one tensor with an additional dimension and multiplying it with the other tensor.
import tensorflow as tf
A = tf.placeholder(shape=(None, None, 256), dtype=tf.float32)
B = tf.placeholder(shape=(None, None, 256), dtype=tf.float32)
A_ = tf.expand_dims(A, axis=1)
A_*B
Gives
<tf.Tensor 'mul_1:0' shape=(?, ?, ?, 256) dtype=float32>
I have a solution for the case when the size of time_steps axis is specified (i.e. is not None). We can easily use K.repeat_elements and K.tile to form the tensors for cartesian product:
from keras import layers, models
from keras import backend as K
def some_func(a, b):
# define the some_func here
return a + b
def cart_prod(x):
shp = K.int_shape(x)[1]
x_rep = K.repeat_elements(x, shp, axis=1)
x_tile = K.tile(x, [1, shp, 1])
res = some_func(x_rep, x_tile)
return K.reshape(res, [-1, shp, shp, K.shape(res)[-1]])
inp = layers.Input((3, 2))
out = layers.Lambda(cart_prod)(inp)
model = models.Model(inp, out)
model.predict(np.arange(6).reshape(1, 3, 2))
Output:
array([[[[ 0., 2.],
[ 2., 4.],
[ 4., 6.]],
[[ 2., 4.],
[ 4., 6.],
[ 6., 8.]],
[[ 4., 6.],
[ 6., 8.],
[ 8., 10.]]]], dtype=float32)
I'm trying to implement the model described by Professor Andrew Ng for object detection (explanation starts at 10:00).
He describes the first element of the output vector as the probability that an object was detected, followed by the coordinates of the bounding box of the object matched (when one is matched). The last part of the output vector is a softmax of all the classes your model knows.
As he explains it, using a simple squared error for the case when there is a detection is fine, and just the squares difference of y^[0] - y[0]. I get that this is a naive approach. I'm just wanting to implement this for the learning experience.
My questions
How do I implement this conditional loss in tensorflow?
How do I handle this conditional about y^[0] when dealing with a batch.
How do I implement this conditional loss in tensorflow?
You can convert the loss function to:
Error = mask[0]*(y^[0]-y[0])**2 + mask[1]*(y^[1]-y[1])**2 ... mask[n]*(y^[n]-y[n])**2),
where mask = [1, 1,...1] for y[0] = 1 and [1, 0, ...0] for y[0] = 0
How do I handle this conditional about y^[0] when dealing with a
batch.
For a batch, you can construct the mask on the fly like:
mask = tf.concat([tf.ones((tf.shape(y)[0],1)),y[:,0][...,None]*y[:,1:]], axis=1)
Code:
y_hat_n = np.array([[3, 3, 3, 3], [3,3,3,3]])
y_1 = np.array([[1, 1, 1, 1], [1,1,1,1]])
y_0 = np.array([[0, 1, 1, 1], [0,1,1,1]])
y = tf.placeholder(tf.float32,[None, 4])
y_hat = tf.placeholder(tf.float32,[None, 4])
mask = tf.concat([tf.ones((tf.shape(y)[0],1)),y[:,0][...,None]*y[:,1:]], axis=1)
error = tf.losses.mean_squared_error(mask*y, mask*y_hat)
with tf.Session() as sess:
print(sess.run([mask,error], {y:y_0, y_hat:y_hat_n}))
print(sess.run([mask,error], {y:y_1, y_hat:y_hat_n}))
# Mask and error
#[array([[1., 0., 0., 0.],
# [1., 0., 0., 0.]], dtype=float32), 2.25]
#[array([[1., 1., 1., 1.],
# [1., 1., 1., 1.]], dtype=float32), 4.0]
input: length(placeholder), index(1D tensor)
output: 0-1 1D tensor
example: length 5, index [0,1,3], output tensor should be [1,1,0,1,0]
I have tried scatter_add, which requires Variable which requires known shape, and embedding_lookup from matrix with [length, length], which is not effective when length is large.
Any ideas?
Try tf.sparse_to_dense:
output_size = tf.placeholder(tf.int32, [1])
index = tf.constant([0, 1, 3])
ones = tf.ones([tf.size(index)])
result = tf.sparse_to_dense(index, output_size, ones)
with tf.Session() as sess:
sess.run(result, feed_dict={output_size: [5]})
Outputs: array([ 1., 1., 0., 1., 0.], dtype=float32)
Suppose I have a tensor in Tensorflow that its values are like:
A = [[0.7, 0.2, 0.1],[0.1, 0.4, 0.5]]
How can I change this tensor into the following:
B = [[1, 0, 0],[0, 0, 1]]
In other words I want to just keep the maximum and replace it with 1.
Any help would be appreciated.
I think that you can solve it with a one-liner:
import tensorflow as tf
import numpy as np
x_data = [[0.7, 0.2, 0.1],[0.1, 0.4, 0.5]]
# I am using hard-coded dimensions for simplicity
x = tf.placeholder(dtype=tf.float32, name="x", shape=(2,3))
session = tf.InteractiveSession()
session.run(tf.one_hot(tf.argmax(x, 1), 3), {x: x_data})
The result is the one that you expect:
Out[6]:
array([[ 1., 0., 0.],
[ 0., 0., 1.]], dtype=float32)