Setting Qtile Margins Dynamically Through Keyboard Input - config

I'm looking to set up keybindings to increase/decrease gaps and margins in Qtile similar to what the following does in i3-gaps:
bindsym $mod+equal gaps inner current plus 5
bindsym $mod+minus gaps inner current minus 5
bindsym $mod+Shift+equal gaps outer current plus 5
bindsym $mod+Shift+minus gaps outer current minus 5
I can somewhat get the equivalent of outer-gaps to work with the following code:
def increase_gap(qtile):
qtile.screens[0].top.size = screens[0].top.size+5
qtile.screens[0].right.size = screens[0].top.size+5
qtile.screens[0].left.size = screens[0].top.size+5
#margs = screens[0].bottom.margin
screens[0].bottom.margin[0] = screens[0].bottom.margin[0]+5
screens[0].bottom.size=20
qtile.screens[0].cmd_resize()
def decrease_gap(qtile):
qtile.screens[0].top.size = max(screens[0].top.size-5, 0)
qtile.screens[0].right.size = max(screens[0].top.size-5, 0)
qtile.screens[0].left.size = max(screens[0].top.size-5, 0)
#margs = screens[0].bottom.margin
screens[0].bottom.margin[0] = max(screens[0].bottom.margin[0]-5, 0)
screens[0].bottom.size=20
qtile.screens[0].cmd_resize()
Key([mod, "shift"], "equal", lazy.function(increase_gap), desc="Increase gap"),
Key([mod, "shift"], "minus", lazy.function(decrease_gap), desc="Decrease gap"),
I'm not sure this is the right way to do things, though. I'm not sure if this is supposed to be manipulated this way. I'm not really sure that the cmd_resize() function is what I should be using, however from trial and error it's what I've found to work. I'm not sure why the screen[0].bottom.size=20 (20 is the size of my bottom bar. I know I shouldn't hardcode, but I'm trying to produce a proof of concept before I clean the code) is needed, but the bar starts floating if I don't have that there. Finally, increasing and decreasing the gap gets close, but not quite to the original configuration. The gaps look slightly different than the original. So, I'm not sure this is the right way to accomplish this, and I could use the advice.
Secondly, though that gets close to accomplishing what I want on the outer gaps, I have not been able to make any headway to getting the inner gaps to work. I initially tried changing the margin parameter of a layout, and when that didn't work I tried simply initializing a new layout and replacing the old one as posted below, but neither approach worked.
def column_increase_margin(qtile):
current_margin = current_margin + 5
layouts[0] = layout.Columns(border_focus_stack='#d75f5f', margin=current_margin, border_width=0)
screens[0].bottom.size=20
qtile.screens[0].cmd_resize()
I've tried going through the code here, but it's a big project and I'm struggling to make heads or tails from it.
Any advice would be appreciated.

If I understand what you want, you can add the following to the Layout class in libqtile/layout/base.py:
def cmd_increase_margin(self):
self.margin += 10
self.group.layout_all()
def cmd_decrease_margin(self):
new_margin = self.margin - 10
if new_margin < 0:
new_margin = 0
self.margin = new_margin
self.group.layout_all()
You can then add some keys in your config.py to increase and decrease margins. e.g.
KeyChord([mod], "m", [
Key([], "Up", lazy.layout.increase_margin()),
Key([], "Down", lazy.layout.decrease_margin())
],
mode="Margins"
),
I'm new to qtile, so maybe there is something wrong with the above approach, but it seems to work.

Related

A value is trying to be set on a copy of a slice from a DataFrame - don't understand ist

I know this topic has been discussed a lot and I am so sorry, that I stil dont't find the sulution, even the difference between a view and a copy is easy to understand (in other languages)
def hole_aktienkurse_und_berechne_hist_einstandspreis(index, start_date, end_date):
df_history = pdr.get_data_yahoo(symbols=index, start=start_date, end=end_date)
df_history['HistEK'] = df_history['Adj Close']
df_only_trd_index = df_group_trade.loc[index].copy()
for i_hst, r_hst in df_history.iterrows():
df_bis = df_only_trd_index[(df_only_trd_index['DateClose']<=i_hst) & (df_only_trd_index['OpenPos']==0)].copy()
# here comes the part what causes the trouble:
df_history.loc[i_hst]['HistEK'] = df_history.loc[i_hst]['Adj Close'] - df_bis['Total'].sum()/100.0
return df_history
I think I tried nearly everithing, but I don't get it. python is not easy when it comes to this topic.
When you have to specify bow index and column in .loc you have to put all together otherwise the annoying message relative to views appears.
df_history.loc[i_hst, 'HistEK'] = df_history.loc[i_hst, 'Adj Close'] - df_bis['Total'].sum()/100.0
Look the examples here

Matplotlib - Draw H and V line by specifying X or Y value on a plot

I was wondering today about how finding a specific value on a plot and drawing the right line that goes with. I used to do that on an old chart library, and I was wondering that perhaps this functionnality exist but I don't know how to find it.
The result should look like this: https://miro.medium.com/max/1070/1*Ckhi9soE9Lx2lIf9tPVLMQ.png
To provide some context, I'm doing a PCA over my data, and I would like to point out some thresholds at 97.5, 99 and 99.5% of explained cumuled variance.
Have a great day!
EDIT:
See Answer
As solved by ImportanceOfBeingErnest, here is the code:
whole_pca = PCA().fit(np.array(inputs['Scale'].tolist()))
cumul = np.cumsum(np.round(whole_pca.explained_variance_ratio_, decimals=3)*100)
over_95 = np.argmax(cumul>95)
over_99 = np.argmax(cumul>99)
over_995 = np.argmax(cumul>99.5)
plt.plot(cumul)
plt.plot([0,over_95,over_95], [95,95,0])
plt.plot([0,over_99,over_99], [99,99,0])
plt.plot([0,over_995,over_995], [99.5,99.5,0])
plt.xlim(left=0)
plt.ylim(bottom=80)
plt.ylabel('% Variance Explained')
plt.xlabel('# of Features')
plt.title('PCA Analysis')
Result in:
Thank you!

pseudo randomization in loop PsychoPy

I know other people have asked similar questions in past but I am still stuck on how to solve the problem and was hoping someone could offer some help. Using PsychoPy, I would like to present different images, specifically 16 emotional trials, 16 neutral trials and 16 face trials. I would like to pseudo randomize the loop such that there would not be more than 2 consecutive emotional trials. I created the experiment in Builder but compiled a script after reading through previous posts on pseudo randomization.
I have read the previous posts that suggest creating randomized excel files and using those, but considering how many trials I have, I think that would be too many and was hoping for some help with coding. I have tried to implement and tweak some of the code that has been posted for my experiment, but to no avail.
Does anyone have any advice for my situation?
Thank you,
Rae
Here's an approach that will always converge very quickly, given that you have 16 of each type and only reject runs of more than two emotion trials. #brittUWaterloo's suggestion to generate trials offline is very good--this what I do myself typically. (I like to have a small number of random orders, do them forward for some subjects and backwards for others, and prescreen them to make sure there are no weird or unintended juxtapositions.) But the algorithm below is certainly safe enough to do within an experiment if you prefer.
This first example assumes that you can represent a given trial using a string, such as 'e' for an emotion trial, 'n' neutral, 'f' face. This would work with 'emo', 'neut', 'face' as well, not just single letters, just change eee to emoemoemo in the code:
import random
trials = ['e'] * 16 + ['n'] * 16 + ['f'] * 16
while 'eee' in ''.join(trials):
random.shuffle(trials)
print trials
Here's a more general way of doing it, where the trial codes are not restricted to be strings (although they are strings here for illustration):
import random
def run_of_3(trials, obj):
# detect if there's a run of at least 3 objects 'obj'
for i in range(2, len(trials)):
if trials[i-2: i+1] == [obj] * 3:
return True
return False
tr = ['e'] * 16 + ['n'] * 16 + ['f'] * 16
while run_of_3(tr, 'e'):
random.shuffle(tr)
print tr
Edit: To create a PsychoPy-style conditions file from the trial list, just write the values into a file like this:
with open('emo_neu_face.csv', 'wb') as f:
f.write('stim\n') # this is a 'header' row
f.write('\n'.join(tr)) # these are the values
Then you can use that as a conditions file in a Builder loop in the regular way. You could also open this in Excel, and so on.
This is not quite right, but hopefully will give you some ideas. I think you could occassionally get caught in an infinite cycle in the elif statement if the last three items ended up the same, but you could add some sort of a counter there. In any case this shows a strategy you could adapt. Rather than put this in the experimental code, I would generate the trial sequence separately at the command line, and then save a successful output as a list in the experimental code to show to all participants, and know things wouldn't crash during an actual run.
import random as r
#making some dummy data
abc = ['f']*10 + ['e']*10 + ['d']*10
def f (l1,l2):
#just looking at the output to see how it works; can delete
print "l1 = " + str(l1)
print l2
if not l2:
#checks if second list is empty, if so, we are done
out = list(l1)
elif (l1[-1] == l1[-2] and l1[-1] == l2[0]):
#shuffling changes list in place, have to copy it to use it
r.shuffle(l2)
t = list(l2)
f (l1,t)
else:
print "i am here"
l1.append(l2.pop(0))
f(l1,l2)
return l1
You would then run it with something like newlist = f(abc[0:2],abc[2:-1])

phalcon querybuilder total_items always returns 1

I make a query via createBuilder() and when executing it (getQuery()->execute()->toArray())
I got 10946 elements. I want to paginate it, so I pass it to:
$paginator = new \Phalcon\Paginator\Adapter\QueryBuilder(array(
"builder" => $builder,
"limit" => $limit,
"page" => $current_page
));
$limit is 25 and $current_page is 1, but when doing:
$paginator->getPaginate();
$page->total_items;
returns 1.
Is that a bug or am I missing something?
UPD: it seems like when counting items it uses created sql with limit. There is no difference what limit is, limit divided by items per page always equals 1. I might be mistaken.
UPD2: Colleague helped me to figure this out, the bug was in the query phalcon produces: count() of the group by counts grouped elements. So a workaround looks like:
$dataCount = $builder->getQuery()->execute()->count();
$page->next = $page->current + 1;
$page->before = $page->current - 1 > 0 ? $page->current - 1 : 1;
$page->total_items = $dataCount;
$page->total_pages = ceil($dataCount / 100);
$page->last = $page->total_pages;
I know this isn't much of an answer but this is most likely to be a bug. Great guys at Phalcon took on a massive job that is too big to do it properly in their little free time and things like PHQL, Volt and other big but non-core components do not receive as much attention as we'd like. Also given that most time in the past 6 months was spent on v2 there are nearly 500 bugs about stuff like that and it's counting. I came across considerable issues in ORM, Volt, Validation and Session, which in the end made me stick to other not as cool but more proven solutions. When v2 comes out I'm sure all attention will on the bug list and testing, until then we are mostly on our own. Given that it's all C right now, only a few enthusiast get involved, with v2 this will also change.
If this is the only problem you are hitting, the best approach is to update your query to get the information you need yourself without getPaginate().

MATLAB: Resizing a figure properly

I have a figure that I would like to resize and afterwards print as a PDF.
Using something like
set(hFig, 'PaperUnits', 'centimeters')
set(hFig, 'PaperSize', [x_B x_H]);
works as long as I do not resize the figure too drastically. If I reduce the height then at some points the xlabel moves out of the figure. I have searched a lot but only found an solution to manually resize the underlying axes-object
scalefactor = 0.96;
movefactor = 0.82;
hAx = get(gcf,'CurrentAxes');
g = get(hAx,'Position');
% 1=left, 2=bottom, 3=width, 4=height
g(2) = g(2) + (1-movefactor)/2*g(4);
g(4) = scalefactor*g(4);
set(hAx,'Position',g);
I do not like this approach since I have to manually adjust the two factors.
Before printing I set the 'interpreter' to 'latex' of all text-objects (if that is of concern).
Printing is achieved using
print(hFig, '-dpdf', '-loose', 'test.pdf');
I hoped to loosen the bounding box by using '-loose'. Any help is highly appreciated!
edit:
It seems that really the interpreter (none, tex, latex) plays a role in this. I got inspired by this post here (http://stackoverflow.com/questions/5150802/how-to-save-plot-into-pdf-without-large-margin-around) and came up with this solution:
tightInset = get(gca, 'TightInset');
position(1) = tightInset(1);
position(3) = 1 - tightInset(1) - tightInset(3);
if strcmpi(x_Interpreter,'latex')
position(2) = tightInset(2)+ 1*tightInset(4);
position(4) = 1 - tightInset(2) - 2*tightInset(4);
else
position(2) = tightInset(2)+ 0*tightInset(4);
position(4) = 1 - tightInset(2) - 1*tightInset(4);
end
set(gca, 'Position', position);
This may not solve your problem completely (it may just help clean up your code), but I found the fig code in the file exchange to be helpful: it lets you easily set the exact size of figures without bordering white space.