Please consider the following code, which compiles and runs as expected.
import matplotlib.pyplot as plt
import numpy as np
x = np.linspace(0, 2 * np.pi, 400)
y = np.sin(x*13)
fig, ax = plt.subplots()
ax.plot(x, y)
ax.set_title('A single plot')
In Eclipse, when I hover the mouse over the sin function it directs me to the following 'Shared Object' file
_multiarray_umath.cpython-38-darwin.so
However, when I open the file in a separate tab the file is illegible. What would people recommend to be able to see the contents of the file , like *.py core files where there are many useful examples ? Would you want to do that anyway ?
Thanks in advance.
Related
The following is my code, but I can't get the plot to show on my Visual Studio Code even though I am running this on the Python Interactive Window, which should usually show a graph plot after running. The tables are showing just fine. I also do not get a default graph which pops up like it normally should. What am I doing wrong?
import yfinance as yf
import pandas as pd
import matplotlib
matplotlib.use('agg')
import matplotlib.pyplot as plt
import talib
df = pd.read_csv('filename.csv')
df = df.sort_index()
macd, macdsignal, macdhist = talib.MACD(df['Close'], fastperiod=12, slowperiod=26, signalperiod=9)
macd = macd.to_list()
macdsignal = macdsignal.to_list()
macdhist = macdhist.to_list()
df['macd'], df['macdsignal'], df['macdhist'] = macd,macdsignal,macdhist
ax = plt.gca()
print(df.columns)
df.plot(kind='line',x='Date',y='macd', color='blue',ax=ax)
df.plot(kind='line',x='Date',y='macdsignal', color='red', ax=ax)
plt.show()
The csv file has data that looks like this
The issue was with matplotlib.use('agg'), which does not support the show() function. This prevented the graph from being displayed on Visual Studio's Interactive Window. The matplotlib.use('agg') method can, however, be used for saving your graph in a .png format.
According to Matplotlib.org, agg is "the canonical renderer for user interfaces, which uses the Anti-Grain Geometry C++ library to make a raster (pixel) image of the figure". More information can be found at this link here
I'm writing Python code on Databricks to process some data and output graphs. I want to be able to save these graphs as a picture file (.png or something, the format doesn't really matter) to DBFS.
Code:
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame({'fruits':['apple','banana'], 'count': [1,2]})
plt.close()
df.set_index('fruits',inplace = True)
df.plot.bar()
# plt.show()
Things that I tried:
plt.savefig("/FileStore/my-file.png")
[Errno 2] No such file or directory: '/FileStore/my-file.png'
fig = plt.gcf()
dbutils.fs.put("/dbfs/FileStore/my-file.png", fig)
TypeError: has the wrong type - (,) is expected.
After some research, I think the fs.put only works if you want to save text files.
running the above code with plt.show() will get you a bar graph - I want to be able to save the bar graph as an image to DBFS. Any help is appreciated, thanks in advance!
Easier way, just with matplotlib.pyplot. Fix the dbfs path:
Example
import matplotlib.pyplot as plt
plt.scatter(x=[1,2,3], y=[2,4,3])
plt.savefig('/dbfs/FileStore/figure.png')
You can do this by saving the figure to memory and then using the Python local file APIs to write to the DataBricks filesystem (DBFS).
Example:
import matplotlib.pyplot as plt
from io import BytesIO
# Create a plt or fig, then:
buf = BytesIO()
plt.savefig(buf, format='png')
path = '/dbfs/databricks/path/to/file.png'
# Make sure to open the file in bytes mode
with open(path, 'wb') as f:
# You can also use Bytes.IO.seek(0) then BytesIO.read()
f.write(buf.getvalue())
Using 1.5.1 in Python 2.7.
I'm creating a figure, adding an axes object to it, creating a canvas, and putting it into a window. To draw a simple graph, I set the X and Y limits in the axes object, and then call the plot member function with a numpy arange of values and an array of y values of the same length, along with a few formatting options.
What I get is a nice graph of my data, but it is drawn as a closed curve, meaning that there is a diagonal line leading from the end of my graph back to the beginning.
Why would it do this? I can see the occasional utility of an option that does this, when the X values aren't monotonically increasing (say, to draw a polygon), but it hardly seems like a reasonable default. I don't see any axes attribute that would affect this, or any plot parameter. Does anyone know how to make it not wrap around like this?
EDIT: here is some sample code. It assumes PyGTK as the GUI environment:
import numpy
import gtk
import matplotlib
from matplotlib.figure import Figure
from matplotlib.backends.backend_gtk import FigureCanvasGTK as FigureCanvas
class junk:
def __init__(self):
self.window = gtk.Window(gtk.WINDOW_TOPLEVEL)
self.window.connect('destroy', self.destroy)
self.window.set_title('junk')
self.window.resize(400, 400)
self.figure = Figure()
self.axes = self.figure.add_axes((0, 0, 1, 1))
self.canvas = FigureCanvas(self.figure)
self.canvas.show()
self.window.add(self.canvas)
self.axes.set_xlim(-10, 12)
self.axes.set_ylim(-1, 122)
x = numpy.arange(-9, 12)
self.axes.plot(x, x * x, linestyle = 'solid')
self.canvas.draw()
self.window.show_all()
def destroy(self, widget, data = None):
gtk.main_quit()
def main(self):
gtk.main()
if __name__ == '__main__':
app = junk()
app.main()
This displays an off-center parabola, and the result looks like this:
Now change the lower Y limit from -1 to 1, so that it clips the bottom a little, and the result looks like this:
This shows that if more than one path is needed to draw the graph, each one has the spurious wraparound.
I'm doing this on Windows, but I had this same problem a couple years ago running on a Gumstix SOM running Linux.
I can not reproduce your issue with the given code
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = np.arange(-9, 12)
ax.plot(x, x*x)
plt.show()
A line is drawn between the points in the order you pass them in. This is the behavior so you can plot things with are not strict functions of x.
BrenBarn identified the solution in the comment to the original post: use the GTKAgg backend instead of the GTK backend. Thanks.
Is it possible to use Python matplotlib code to draw graph in RStudio?
e.g. below Python matplotlib code:
import numpy as np
import matplotlib.pyplot as plt
n = 256
X = np.linspace(-np.pi,np.pi,n,endpoint=True)
Y = np.sin(2*X)
plt.plot (X, Y+1, color='blue', alpha=1.00)
plt.plot (X, Y-1, color='blue', alpha=1.00)
plt.show()
Output graph will be:
Then I need to write a R Markdown to include these code and generate graph automatically after knitting the markdown.
install.packages('devtools') first, get install_github function
install_github("rstudio/reticulate") install the dev version of reticulate
in r markdown doc, use code below to enable the function.
```{r setup, include=FALSE}
library(knitr)
library(reticulate)
knitr::knit_engines$set(python = reticulate::eng_python)
```
Try it , you will get what you want and don't need to save any image.
One possible solution is save the plot as a image, then load the file to markdown.
### Call python code sample
```{r,engine='python'}
import numpy as np
import matplotlib.pyplot as plt
n = 256
X = np.linspace(-np.pi,np.pi,n,endpoint=True)
Y = np.sin(2*X)
fig, ax = plt.subplots( nrows=1, ncols=1 )
ax.plot (X, Y+1, color='blue', alpha=1.00)
ax.plot (X, Y-1, color='blue', alpha=1.00)
#plt.show()
fig.savefig('foo.png', bbox_inches='tight')
print "finished"
```
Output image:
#### The End
Output:
You can do that with reticulate, but most time in trying to follow a tutorial in doing that you may encounter some technicalities that weren't sufficiently explained.
My answer is a little late but I hope it's a thorough walkthrough of doing it the right way - not rendering it and then loading it as a png but have the python code executed more "natively".
Step 1: Configure Python from RStudio
You want to insert an R chunk, and run the following code to configure the path to the version of Python you want to use. The default python that comes shipped with most OS is usually the outdated python 2 and is not where you install your packages. That is the reason why it's important to do this, to make sure Rstudio will use the specified python instance where your matplotlib library (and the other libraries you will be using for that project) can be found:
library(reticulate)
# change the following to point to the desired path on your system
use_python('/Users/Samuel/anaconda3/bin/python')
# prints the python configuration
py_config()
You should expect to see that your session is configured with the settings you specified:
python: /Users/Samuel/anaconda3/bin/python
libpython: /Users/Samuel/anaconda3/lib/libpython3.6m.dylib
pythonhome: /Users/Samuel/anaconda3:/Users/Samuel/anaconda3
version: 3.6.3 |Anaconda custom (64-bit)| (default, Oct 6 2017, 12:04:38) [GCC 4.2.1 Compatible Clang 4.0.1 (tags/RELEASE_401/final)]
numpy: /Users/Samuel/anaconda3/lib/python3.6/site-packages/numpy
numpy_version: 1.15.2
python versions found:
/Users/Samuel/anaconda3/bin/python
/usr/bin/python
/usr/local/bin/python
/usr/local/bin/python3
/Users/Samuel/.virtualenvs/r-tensorflow/bin/python
Step 2: The familiar plt.show
Add a Python chunk (not R!) in your R Markdown document (see attached screenshot) and you can now write native Python code. This means that the familiar plt.show() and plt.imshow() will work without any extra work. It will be rendered and can be compiled into HTML / PDF using knitr.
This will work:
plt.imshow(my_image, cmap='gray')
Or a more elaborated example:
import numpy as np
import matplotlib.pyplot as plt
import os
import cv2
DATADIR = '/Users/Samuel/Datasets/PetImages'
CATEGORIES = ['Dog', 'Cat']
for category in CATEGORIES:
path = os.path.join(DATADIR, category) # path to cat or dog dir
for img in os.listdir(path):
img_array = cv2.imread(os.path.join(path,img), cv2.IMREAD_GRAYSCALE)
plt.imshow(img_array, cmap='gray')
plt.show()
break
break
Output:
Step 3: Knit to HTML / PDF / Word etc
Proceed to knit as usual. The end product is a beautifully formatted document done in Python code using R Markdown. RStudio has come a long way and I'm surprised the level of support it has for Python code isn't more known so hoping anyone that stumbled upon this answer will find it informative and learned something new.
I have been working with reticulate and R Markdown and you should specify your virtual environment. For example my R Markdown starts as follows:
{r setup, include=FALSE}
knitr::opts_chunk$set(echo = TRUE, warning = FALSE, cache.lazy = FALSE)
library(reticulate)
use_condaenv('pytorch') ## yes, you can run pytorch and tensor flow too
Then you can work in either language. So, for plotting with matplotlib, I have found that you need the PyQt5 module to make it all run smoothly. The following makes a nice plot inside R Markdown - it's a separate chunk.
{python plot}
import PyQt5
import numpy as np
import pandas as pd
import os
import matplotlib.pyplot as plt
from matplotlib.pyplot import figure
data = pd.read_csv('Subscriptions.csv',index_col='Date', parse_dates=True)
# make the nice plot
# set the figure size
fig = plt.figure(figsize = (15,10))
# the series
ax1 = fig.add_subplot(211)
ax1.plot(data.index.values, data.Opens, color = 'green', label = 'Opens')
# plot the legend for the first plot
ax1.legend(loc = 'upper right', fontsize = 14)
plt.ylabel('Opens', fontsize=16)
# Hide the top x axis
ax1.axes.get_xaxis().set_visible(False)
####### NOW PLOT THE OTHER SERIES ON A SINGLE PLOT
# plot 212 is the MI series
# plot series
ax2 = fig.add_subplot(212)
ax2.plot(data.index.values, data.Joiners, color = 'orange', label = 'Joiners')
# plot the legend for the second plot
ax2.legend(loc = 'upper right', fontsize = 14)
# set the fontsize for the bottom plot
plt.ylabel('Joiners', fontsize=16)
plt.tight_layout()
plt.show()
You get the following from this:
I don't have the reputation points to add a comment, but Bryan's answer above was the only one to work for me. Adding plt.tight_layout() made the difference. I added that line to the following simple code and the plot displayed.
{python evaluate}
plt.scatter(X_train, y_train, color = 'gray')
plt.plot(X_train, regresssion_model_sklearn.predict(X_train), color = 'red')
plt.ylabel('Salary')
plt.xlabel('Number of Years of Experience')
plt.title('Salary vs. Years of Experience')
plt.tight_layout()
plt.show()
I want the text to appear beside the box instead of inside it:
Here is what I did:
import matplotlib as mpl
import matplotlib.pyplot as plt
from custombox import MyStyle
fig = plt.figure(figsize=(10,10))
legend_ax = plt.subplot(111)
legend_ax.annotate("Text",xy=(0.5,0.5),xycoords='data',xytext=(0.5, 0.5),textcoords= ('data'),ha="center",rotation = 180,bbox=dict(boxstyle="angled, pad=0.5", fc='white', lw=4, ec='Black'))
legend_ax.text(0.6,0.5,"Text", ha="center",size=15)
Here is what it gives me:
Note: custombox is similar to the file that is written in this link:
http://matplotlib.org/1.3.1/users/annotations_guide.html
My ultimate aim is to make it look legend like where the symbol (angled box) appears beside the text that represents it.
EDIT 1: As suggested by Ajean I have annotated text separately but I can't turn of the text within the arrow
One way to do it would be to separate the text and the bbox (which you can reproduce using an arrow). The following gives me something close to what you want, I think.
import matplotlib.pyplot as plt
from matplotlib import patches
fig = plt.figure(figsize=(5,5))
ax = fig.add_subplot(111)
ax.annotate("Text", (0.4,0.5))
bb = patches.FancyArrow(0.5,0.5,0.1,0.0,length_includes_head=True, width=0.05,
head_length=0.03, head_width=0.05, fc='white', ec='black',
lw=4)
ax.add_artist(bb)
plt.show()
You can futz with the exact placement as needed. I'm not an expert on all the kwargs, so this may not be the best solution, but it will work.