I've got the following statement:
select
product_name as ShortestLength = (select top 1 product_name, len(fact_name) Value_Length
from table
order by Value_Length, fact_name ASC)
Which returns this output:
shortestlength
PS
I'd like to add this outcome to another select statement:
select
'Product' as Column_Name,
avg(case when product is null then 1.000 else 0 end) * 100 as PctMissing,
count(product) as TotalCount,
count(distinct product) as UniqueCount
from
table
so the result will be:
column_name
pctmissing
totalcount
uniquecount
shortestlength
Product
5.100
181186
15
PS
What should I add to my initial select statement?
You can use conditional aggregation:
select 'Product' as Column_Name,
avg(case when t.product is null then 1.000 else 0 end)*100 as PctMissing,
count(t.product) as TotalCount,
count(distinct t.product) as UniqueCount,
max(case when seqnum = 1 then product_name end) as shortest_length
from (select t.*,
row_number() over (order by len(fact_name), fact_name) as seqnum
from table t
) t
This assumes that the two table references are really the same table.
You can just use first query as subquery in place of a column in your select statement:
select
'Product' as Column_Name,
avg(case when product is null then 1.000 else 0 end)*100 as PctMissing,
count(product) as TotalCount,
count(distinct product) as UniqueCount,
(select top 1 product_name from table order by Value_Length, fact_name ASC) as ShortestLength
from table
Related
Here is my code
SELECT
(SELECT count(*) WHERE status_id = #TO) as 'TO' ,
(SELECT count(*) WHERE status_id = #RO)as 'RO' ,
(SELECT count(*) WHERE status_id = #AO)as 'AO',
(SELECT count(*) WHERE status_id = #IO)as 'IP',
(SELECT count(*) WHERE status_id = #SO)as 'SO',
created_user
FROM
table1
GROUP BY
created_user
Now i'm getting the following error
Column 'status_id' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
I don't want to group by status_id, how to fix this issue?
I guess you can try to use conditional aggregation
SELECT created_user,
SUM
(
CASE
WHEN status_id = #TO THEN 1 ELSE 0 END
)AS 'TO',
SUM
(
CASE
WHEN status_id = #RO THEN 1 ELSE 0 END
)AS 'RO'
FROM table1
GROUP BY created_user
Select category,
concat(count(category) * 100/ (select count(*) from table3),'%') as category_percentage_males
from table3
where gender in ('m')
group by category
order by category_percentage_males desc
For some reason the order by doesn't return desc once I concat. Without the concat the order by works fine. Any reason as to why this is happening?
This is your query:
Select category, concat(count(category) * 100/ (select count(*) from table3),'%') as category_percentage_males
from table3 where gender in ('m')
group by category
order by category_percentage_males desc;
I would strongly suggest that you require it as:
Select category,
concat(avg(case when gender = 'm' then 100.0 else 0 end), '%') as category_percentage_males
group by category
order by avg(case when gender = 'm' then 100.0 else 0 end) desc;
I have a sql table for student records and I have some duplicate rows for the student dimension cause of the major, so now I have something like this:
ID Major
----------
1 CS
1 Mgt
What I want is to combine this two rows in this form:
ID Major Major2
----------
1 CS Mgt
You need a number for pivoting. Then you can pivot using either pivot or conditional aggregation:
select id,
max(case when seqnum = 1 then major end) as major_1,
max(case when seqnum = 2 then major end) as major_2
from (select t.*,
row_number() over (partition by id order by (select null)) as seqnum
from t
) t
group by id;
Note: you should validate that "2" is large enough to count the majors. You can get the maximum using:
select top 1 id, count(*)
from t
group by id
order by count(*) desc;
If you have at most two different values of major:
select a.id as id,
a.major as major,
b.major as major2
from YOUR_TABLE a
left join YOUR_TABLE b on
a.id = b.id
and (b.major is null or a.major > b.major)
This will help you
Select
ID,
(select top 1 Major from <Your_Table> where id=T.Id order by Major) Major,
(case when count(Id)>1 then (select top 1 Major from #temp where id=T.Id order by Major desc) else null end) Major2
from <Your_Table> T
Group By
ID
You can use pivot function directly
SELECT [ID],[CS] AS Major , [Mgt] AS Major2 from Your_Table_Name
PIVOT
(max(Major)for [Major] IN ([CS] , [Mgt]))as p
I have two different queries that have produced the correct result, but I would like to have them produce the answer out in one table. How do I do that?
Here is my code:
SELECT count(distinct ID) as NoOfEmployees
FROM Table_Name
WHERE date<= '2012-05-31';
select count(subA.ID) as EmployeesChanged from (
SELECT A.ID
FROM Table_Name A
WHERE A.date < '2012-06-01'
GROUP BY 1
HAVING COUNT(A.Service_type) > 1 ) subA
Currently I have the following output:
Number of Employees
x
Employees Changed
x
How do I make it
Number of Employees | Employees Changed | (Number of employees - number changed)
x | x | x
I don't know what database do you use. But for some databases you can try:
select q1.Value, q2.Value, q1.Value - q2.Value from
(SELECT count(distinct ID) as Value FROM Table_Name
WHERE date<= '2012-05-31') q1,
(select count(subA.ID) as Value from
( SELECT A.ID FROM Table_Name A
WHERE A.date < '2012-06-01' GROUP BY 1
HAVING COUNT(A.Service_type) > 1 ) subA) q2
If date<= '2012-05-31' is the same as A.date < '2012-06-01' ?
SELECT COUNT(1) AS NoOfEmployees,
SUM(CASE WHEN STCount > 0 then 1 else 0 end) as HasChange,
SUM(CASE WHEN STCount = 0 then 1 else 0 end) as NoChange
FROM
(SELECT ID,
COUNT(A.Service_type) STCount
FROM Table_Name
WHERE date<= '2012-05-31'
GROUP BY ID) AS Data
You can use CROSS JOIN:
SELECT a.*, b.*, a.NoOfEmployees - b.EmployeesChanged
FROM
(
SELECT count(distinct ID) as NoOfEmployees
FROM Table_Name
WHERE date<= '2012-05-31'
) a
CROSS JOIN
(
SELECT count(subA.ID) as EmployeesChanged
FROM
(
SELECT A.ID
FROM Table_Name A
WHERE A.date < '2012-06-01'
GROUP BY 1
HAVING COUNT(A.Service_type) > 1
) subA
) b
Edit:
You might be able to greatly optimize your query by using conditional aggregation instead of executing two separate queries:
SELECT a.NoOfEmployees, a.EmployeesChanged, a.NoOfEmployees - a.EmployeesChanged
FROM
(
SELECT
COUNT(DISTINCT CASE WHEN date <= '2012-05-31' THEN ID END) as NoOfEmployees,
COUNT(DISTINCT CASE WHEN date < '2012-06-01' AND COUNT(Service_type) > 1 THEN ID END) AS EmployeesChanged
FROM Table_Name
GROUP BY ID
) a
I am trying to create SQL Select that returns counts of a certain field based on a field.
So, here is what I am trying to do.
Select count(distinct id) as TotalCount, -- this will be the total of id
count(distinct id where type='A') as TotalA, -- this will be total when type='A'
count(distinct id where type='B') as TotalB -- This will be total when type = 'B'
from MyTable
Basically, TotalCount = TotalA + TotalB.
How can I achieve this in SQL Select Statement?
Thanks.
Select count(distinct id) as TotalCount, -- this will be the total of id
count(distinct case type when 'A' then id else NULL end) as TotalA,
count(distinct case type when 'B' then id else NULL end) as TotalB
from MyTable;
Of course TotalCount may or may not be TotalA + TotalB, depending on the actual data.
You can do it like that:
SELECT
count(distinct id) as TotalCount,
sum(CASE WHEN type = 'A' THEN 1 ELSE 0) as TotalA,
sum(CASE WHEN type = 'B' THEN 1 ELSE 0) as TotalB,
FROM
MyTable
Count per type:
SELECT
type,
count(DISTINCT id)
FROM
MyTable
GROUP BY
type
Why not simply UNION the separate queries.
Select 'all' as which, count(distinct id) as Total from mytable
union
select 'a' as which, count(distinct id) where type='A' as Total from mytable
union
select 'b' as which, count(distinct id) where type='B' as Total from mytable