SQL count(*) with having - sql

Question

I have this query on oracle.
SELECT CBG.refs, CBG.cuo, CBG.date, CBG.nber, CG.date, CBG.conso,
(SELECT COUNT(*)
FROM MAD.VIN CBV
WHERE CBV.CUO = CBG.CUO AND
CBV.NBER = CBG.NBER AND
CBV.DATE = CBG.DATE AND
CBV.REFS = CBG.REFS
GROUP BY CUO , DATE , NBER , REFS ) AS COUNTS ,
CBG.CONSO_CONCESS AS CONCESS
FROM MAD.GEN CBG, MAD.CAR_GEN CG
WHERE CBG.cuo = CG.cuo AND
CBG.CONSO_DATE IS NOT NULL AND
CBG.date = CG.date AND
CBG.nber = CG.nber
HAVING COUNTS > 0;
when i run this sql query it gives me an error that says: invalid identifier counts.
How do we get results only if count is greater than a given parameter?
Thanks.

Answer 1

Unlike in MySQL, in Oracle we cannot refer to an alias in the HAVING clause (aliases can only be referenced in the ORDER BY clause). One workaround would be to put your current logic into a CTE and then filter it.
WITH cte AS (
SELECT CBG.refs, CBG.cuo, CBG.date AS cbg_date, CBG.nber, CG.date AS cg_date,
CBG.conso,
(SELECT COUNT(*)
FROM MAD.VIN CBV
WHERE CBV.CUO = CBG.CUO AND
CBV.NBER = CBG.NBER AND
CBV.DATE = CBG.DATE AND
CBV.REFS = CBG.REFS
GROUP BY CUO, DATE, NBER, REFS) AS COUNTS,
CBG.CONSO_CONCESS AS CONCESS
FROM MAD.GEN CBG
INNER JOIN MAD.CAR_GEN CG
ON CBG.cuo = CG.cuo AND
CBG.date = CG.date AND
CBG.nber = CG.nber
WHERE CBG.CONSO_DATE IS NOT NULL
)
SELECT refs, cuo, cbg_date, nber, cg_date, conso, COUNTS, CONCESS
FROM cte
WHERE COUNTS > 0;