T1:
T2:
Expected result
Query 1:
select name,
sum(qty) as total,
count(distinct ids) as head
from t1
group by 1
Query 2:
select
count(distinct ids) as staff
from t2
join t1
on t1.id = t2.id
and files>0
where
t2.type='Mutual'
Query 1 gives name,total,head,files
Query 2 gives staff
But how to combine both into a single query? Redshift doesnt seem to support "staff=(select......)" in select statement.
Example: that doesn't work
select name,
sum(qty) as total,
count(distinct ids) as head,
staff = (select
count(distinct ids)
from t2
join t1
on t1.id = t2.id
and files>0
where
t2.type='Mutual')
from t1
group by 1
Related
I have a table:
My select:
select regexp_split_to_table(t3."Id"::character varying,'') as s
from (select t1."Id" from table1 t1
union all
select t2."Id"from table2 t2) t3
order by s
Or also I can get a string '22173345566179111134546175622323811' with this:
select string_agg(t3."Id"::character varying,'') as s
from (select t1."Id" from table1 t1
union all
select t2."Id"from table2 t2) t3
I need to get a table with number|count data, I mean for any number to get a count of repetitions in the select, for example:
1 | 9
2 | 5
3 | 5
and so on..
PostgreSQL DBMS
Does this do what you want?
select id, count(*)
from (select t1."Id" from table1 t1
union all
select t2."Id" from table2 t2
) t3
group by id
order by id;
If I understand you right, you want a list of all digits, that exist in a set of IDs from two tables and the count of each digit, how often it appears in all these IDs. If so, you just need to GROUP BY a digit and use count().
SELECT s.d,
count(*) count
FROM (SELECT t1."Id"
FROM table1 t1
UNION ALL
SELECT t2."Id"
FROM table2 t2) t3
CROSS JOIN LATERAL regexp_split_to_table(t3."Id"::character varying, '') s(d)
GROUP BY s.d
ORDER BY s.d;
easiest way
select regexp_split_to_table(t3."Id"::character varying,'') s, count(*) count
from (select t1."Id" from table1 t1 union all select t2."Id"from table2 t2) t3
group by s
In the table1 I have 1421144 rows and table2 has 1421134 rows.
I tried this query, but I don't get any rows returned.
select table1.ID
from table1
where ID not in (select ID from table2)
I have also used this query:
select ID from table1
except
select ID from table2
But I don't get any rows. Please help me, if the table1 has duplicates how can I get those duplicates?
Assuming ids are unique, you can use full outer join in either database:
select coalesce(t1.id, t2.id) as id,
(case when t1.id is null then 'T2 only' else 'T1 only' end)
from t1 full outer join
t2
on t1.id = t2.id
where t1.id is null or t2.id is null;
It is quite possible that the two tables have the same sets of ids, but there are duplicates. Try this:
select t1.id, count(*)
from t1
group by t1.id
having count(*) > 1;
and
select t2.id, count(*)
from t2
group by t2.id
having count(*) > 1;
If you have duplicates, try:
WITH Dups AS(
SELECT ID, COUNT(ID) OVER (PARTITION BY ID) AS DupCount
FROM Table1)
SELECT *
FROM Dups
WHERE DupCount > 1;
If you need to delete the dups, you can use the following syntax:
WITH Dups AS(
SELECT ID, ROW_NUMBER() OVER (PARTITION BY ID ORDER BY ID) AS DupCount
FROM Table1)
DELETE FROM Dups
WHERE DupCount > 1;
Obviously, however, check the data before you run a DELETE statement you got from a random on the internet. ;)
I Guess u have data type mismatch between 2 tables, cast them to integers and try your first query
select table1.ID from table1
where cast(ID as int) not in (select cast(ID as int) from table2)
If you have stored in a different format than int, cast them to varchar and
try with this datatype.
Not in takes longer to execute, use left join instead
select t1id from
(
select t1.id t1Id, t2.Id t2Id from table1 left join table2
on cast(t1.id as int) = cast(t2.id as int)
) x where t2Id is null
Table 1:
ID (unqiue), Name, Address
Table 2:
RecordId, ID (key of table 1), Child name
In one query, I want to retrieve all rows of Table 1 with one additional column which will be the count of all record in table 2 from ID (that is number of children for each ID in table 1). Can't figure out how to format a query to retrieve this data.
Simply Join and apply count
select T1.*, COUNT(T2.RECORDID)AS T2COUNT from Table1 T1
INNER JOIN TABLE2 T2 ON T1.ID= T2.ID
--LEFT JOIN TABLE2 T2 ON T1.ID= T2.ID --if you need 0 child records (from commets by #Cha)
GROUP BY T1.ID , T1.Name, T1.Address
The correct way of doing this will be with a OUTER JOIN:
SELECT a.ID, a.Name, a.Address, b.cnt
FROM Table1 a
LEFT OUTER JOIN
(SELECT ID, count(*) cnt from Table2 GROUP BY ID) b
ON a.ID = b.ID
The incorrect way will be with a help of a correlated sub-query:
SELECT a.ID, a.Name, a.Address,
(SELECT count(*) FROM Table2 b WHERE b.ID = a.ID) as cnt
FROM Table1 a
Here is a discussion about correlated subqueries vs OUTER JOINs, if you are interested
Group by table1 fields and count total records in table2:
here T1 alias of table1 and T2 alias of table2.
select T1.ID, T1.Name, T1.Address, count(T2.ID) as total_records
from table1 as T1
left outer join table2 as T2 on T2.ID=T1.ID
group by T1.ID, T1.Name, T1.Address
Some data would be organized thusly:
ID DATE COUNT1 COUNT2
A 20120101 1 2
A 20120201 2 2
B 20120101 3 0
C 20111201 1 0
C 20120301 2 2
Another table has ID NAME
A MYNAME
.... etc
i want to return a table of
ID NAME COUNT COUNT2
for the most recent available piece of data, i.e. the january count for A is not included
i know I need to use HAVING, INNER JOIN, and GROUP BY but every iteration I can come up with has an error.
If you only want rows with the date equal to the global maximum date, just use a subquery:
select ID,DATE,COUNT1,COUNT2
from table
where DATE=(select max(DATE) from table);
If you want the maximum date per ID, then you can use a self join:
select ID,MAX_DATE,COUNT1,COUNT2
from(
select ID,max(DATE) as MAX_DATE
from table
group by ID
)a
join(
select ID,DATE,COUNT1,COUNT2
from table
)b
on (a.ID=b.ID and a.MAX_DATE=b.DATE);
Not necessarily. This should also work:
select t1.id, t2.name, t1,count1, t1.count2
from table_1 t1 join table_2 t2 on (t1.id = t2.id)
where not exists (
select 1
from table_1 t3
where t1.id = t3.id
and t1.date < t3.date)
order by 1;
You'll need a correlated subquery:
SELECT Id, Name, Count1, Count2
FROM CountsTable AS T1 INNER JOIN NamesTable ON T1.Id=NamesTable.Id
WHERE CountsTable.Date = (
SELECT Max(Date) From CountsTable AS T2 WHERE T1.Id=T2.Id
)
I've got the following tables:
Table1 {ArticleNo (int), ArtDescription (string) }
Table2 { ArticleNo (int), Year (date) }
Table1.ArticleNo is a primary key.
Table2.ArticleNo is a foreign key referenced to table1.ArticleNo
It's difficult to explain what I want to query, so here a short example:
Table1
(1,Desk)
(2,Chair)
(3,Ruler)
Table2
(1,2000)
(1,2000)
(2,2001)
The query should return:
1 Desk 2001
2 Chair 2000
3 Ruler 2000
3 Ruler 2001
All articles which are not sold (or whatever) in all years (all years from table2).
I hope you understand my example - the query seems to be very complex. Here my approach to a solution:
SELECT table1.ArticleNo,table1.ArtDescription,table2.Year
FROM table1
JOIN table2
ON table1.ArticleNo=table2.ArticleNo
WHERE NOT table1.ArticleNo IN (SELECT table2.Year FROM table2);
I tried lots of different things.. I hope you can help me!
SELECT t1.*, t2.year
FROM t1
CROSS JOIN
(
SELECT DISTINCT year
FROM t2
) t2
WHERE (t1.id, t2.year) NOT IN
(
SELECT t2.id, t2.year
FROM t2
)
Create an index on t2 (year, id) (in this order) for the query to work fast.
You could use a cross join to create a list of all item+year combinations. Then you could filter the rows without sales with a not exists condition:
select *
from t1 items1
cross join
(
select distinct year
from t2 sales1
) sales2
where not exists
(
select *
from t2 sales3
where sales3.ItemId = items1.ItemId
and sales3.Year = sales2.Year
)
There are a bunch of ways of doing this. Two examples:
select
t1.ArtDescription,
y.Year
from
Table1 t1
join (
select distinct
t2.Year
from
Table2 t2
) y on 1=1
where
not exists (
select
1
from
Table2 tx2
where
tx2.ArticleNo = t1.ArticleNo and tx2.Year = y.Year)
Oracle (SQL Server can do the same thing, use EXCEPT instead of MINUS):
select
t1.ArtDescription,
y.Year
from
Table1 t1
join (
select distinct
t2.Year
from
Table2 t2
) y on 1=1
MINUS
select
t12.ArtDescription
t22.Year
from
Table1 t12
join Table2 t22 on t12.ArticleNo = t22.ArticleNo
SELECT DISTINCT table1.ArticleNo,table1.ArtDescription,table2.Year
FROM table1 CROSS JOIN table2
WHERE table1.ArticleNo != table2.ArticleNo order by table1.ArticleNo;