Exit Do look in nested For loop break all loops - vba

I am new to VBA and getting stuck with a small piece of code which I think I am missing something very easy. I have a column of 0,1 and 2 and trying to calculate the transitions from 0 to 2 and then back to 0 when 0 appears for consecutively atleast A times and 2 appears for consecutive B times. After putting the For and IF loops, I want to exit the Do loop so that it does not get over counted. However putting the Exit Do shows compilation error and shows all the End If and Next statement as an error. I am totally confused why that is happening and any help on it will be greatly appreciated. Thank you
For L = M To lastrow - A
temp = 0
For L1 = L To L + A
temp = temp + Sheets("Sheet1").Range("AH" & L1)
Next L1
If temp = 0 Then
N = L + A: A_start = N: x_start = x_start + 1
For N1 = N To 50 'lastrow - B
If Sheets("Sheet1").Range("AH" & N1) = 2 Then
temp1 = 0
For I1 = N1 To N1 + B
temp1 = temp1 + Sheets("Sheet1").Range("AH" & I1)
Next I1
Do While temp1 = 2 * B
Count = Count + 1: M = I1: B_start = I1: x_Stop = x_Stop + 1
Sheets("Sheet1").Range("AN2") = Count
Exit Do
End If
Next N1
End If
Next L

Related

Exit 2 For loop when condition is met in a 3 For loop nested system in VBA

I am trying to write a code which has multiple For and If loops. I will try to explain the problem first where the dataset I have is like the following in column 'AH':
0,0,0,0,1,1,2,2,2,2,2,2,1,1,1,0,0,0,0,0,2,2,2,2,2,0,0,..... where the number of 0s, 1s and 2s in a stretch is unknown. What I am trying to find the number of cycles, where a cycle is defined when there has to be atleast 3 0s in a stretch and then has to be atleast 4 2s consecutively. So, to do that, I wrote the code in the following format
Dim M As Single: Dim Count As Integer: Dim A As Integer: Dim B As Integer
M = 2: Count = 0: A =3: B=4
Dim temp As Integer: Dim temp1 As Integer: temp = 0
For L = M To 50
Sheets("Sheet1").Range("AJ" & M) = M
temp = 0
For L1 = L To L + A
temp = temp + Sheets("Sheet1").Range("AH" & L1)
Next L1
If temp = 0 Then
N = L + A
For N1 = N To 60
If Sheets("Sheet1").Range("AH" & N1) = 2 Then
temp1 = 0
For I1 = N1 To N1 + B
temp1 = temp1 + Sheets("Sheet1").Range("AH" & I1)
Next I1
If temp1 = 2 * B Then
flg = True
Exit For
End If
End If
Next N1
Count = Count + 1: M = I1
Sheets("Sheet1").Range("AJ2") = Count
If flg = True Then Exit For
End If
M = M + 1
Next L
Basically, what I am trying to do is find the first 0 and count the sum of 3 consecutive values. If it is 0, then I am searching for 2. When the first 2 is found, it will add up the next 4 terms and if the sum is equal to 2*4, then I will update the count and the code should start look for 0. However, using the 'Exit For' puts me out of all the loops. And if I don't put Exit, then it keep counting the 2s for more times. I am new to VBA and struck with this problem for a long time. Any help on this will be greatly appreciated. Thank you in advance.

For Next VBA skips half

I am trying to make a simple VBA in Excel, to copy some data I am trying to regroup. I seems to work good for some part, but it skips a row and column everytime! The problem must be somewhere in the double For..Next.. I am using, but I can't find it:
The result I get:
For i = 1 To AantalPag 'HIERRR
GezSite = BeginCel.Offset(i + 1) 'HIERRR
For iweek = 1 To AantalWeek
GezWeek = BeginCel.Offset(0, iweek)
For i2 = 1 To AantalWeekData
If BeginCelData.Offset(i2 - 1) = GezWeek Then
For i3 = 1 To AantalSitesData
If BeginCelData.Offset(0, i3) = GezSite Then
Sommetje = Sommetje + BeginCelData.Offset(i2 - 1, i3 - 1)
Else
i3 = i3 + 1
End If
Next i3
'BeginCel.Offset(i, iweek) = Sommetje
'Sommetje = 0
Else
i2 = i2 + 1
End If
Next i2
BeginCel.Offset(i, iweek) = Sommetje
Sommetje = 0
iweek = iweek + 1
Next iweek
i = i + 1
Next i
The code below will print the numbers from 1 to 100 in the Immediate window.
For n = 1 to 100
Debug.Print n
Next n
The code below will print every other number in the Immediate window. This is because n is incremented both by n = n + 1 and then again by Next n.
For n = 1 to 100
Debug.Print n
n = n + 1
Next n

vba array element removal

j = LBound(arrayTime)
Do Until j = UBound(arrayTime)
j = j + 1
b = b + 1
cnc = b + r
MsgBox cnc
If cnc > 7 Then
b = 0
r = 0
cnc = b + r
End If
numMins = Sheet5.Cells(cnc + 3, 2) - arrayTime(j)
If numMins < 0 Then
g = g + 1
ReArrangeArray arrayTime, j
'ReDim Preserve arrayTime(numrows - 1 + g)
'arrayTime(numrows - 1 + g) = arrayTime(j)
'MsgBox (arrayTime(numrows - 1 + g))
Else
Sheet5.Cells(cnc + 3, 2) = numMins
End If
Loop
If the if statement is true I want to be able to put the array value at the end of the array and remove that value from its current spot. As the code is, it just adds it to the end and increases the size of the array from 12 to 13. How can I get the array to remain size 12 and still place the value at the end of the array and then remove it from its original position? I do not want to touch the array values in front. Just want to take that value and move it to the end.
For instance
array(1,2,3,4,5)
If statement
j on third loop.
array(j)=3
end array should be
array(1,2,4,5,3)
You could use a helper Sub like this one:
Sub ReArrangeArray(inputArray as Variant, indexToSwap as long)
Dim I As Long
Dim tempVal As Variant
If indexToSwap >= LBound(inputArray) And indexToSwap < UBound(inputArray) Then
tempVal = inputArray(indexToSwap)
For I = indexToSwap To UBound(inputArray) - 1
inputArray(i) = inputArray(i + 1)
Next I
InputArray(UBound(inputArray)) = tempVal
End If
End Sub
To be called by your main Sub as follows:
ReArrangeArray arrayTime, j

Connect Four Horizontal winner

I'm creating a connect four game and I'm having some trouble with the horizontal loop. The loop below works and it's for a vertical win. I have a two labels for each row and two labels for each column one for the color blue and one for the color red. When I add in my other labels I cant seem to find where I take the step-1 in order to change labels and go upwards with the next label. I have also tried adding a whole new loop below that just dedicated to the horizontal winnings.
For i = 5 To 0 Step -1`
If board(i, 0) = 0 Then
board(i, 0) = pturn
If pturn = 1 Then
Labelboard(i, 0).BackColor = Color.Red
CounterB = 0
lblcounterBlue.Text = "Matches = " & CounterB
CounterR = CounterR + 1
lblCounterRed.Text = "Matches = " & CounterR
ElseIf pturn = 2 Then
Labelboard(i, 0).BackColor = Color.Blue
CounterR = 0
lblCounterRed.Text = "Matches = " & CounterR
CounterB = CounterB + 1
lblcounterBlue.Text = "Matches = " & CounterB
End If
pturn = pturn + 1
If pturn = 3 Then pturn = 1
If CounterR = 4 Then
MsgBox("Game Over")
End If
If CounterB = 4 Then
MsgBox("Game Over")
End If
Exit Sub
End If
Next
I don't quite understand your setup, but hopefully this will get you close enough for you to get things working. I'm having to make a few assumptions, but I've tried to declare a constant each time I have to make the code more readable and easier for you to adapt to what you've already written.
What I've written is a function that lets you know if a specific space is part of winning streak. It assumes board() is public. If pturn is also public, you could make this even more efficient as long as you call it every turn, as noted in the comments. If you know which space was the last one played, you can maximize efficiency by only calling the function for that space (assuming you call it at the end of every player turn). If you don't know which space was played last, you can loop through every space in board() and test each one.
Function winner(rowNum As Integer, colNum As Integer) As Integer
'Returns 0 if space does not create a win, or the winning player number if it does
'Change to winner(...) As Boolean <--To only test current player
Dim minRow As Integer = LBound(board, 0)
Dim maxRow As Integer = UBound(board, 0)
Dim minColumn As Integer = LBound(board, 1)
Dim maxColumn As Integer = UBound(board, 1)
'These are the values I assume are in board()
'(I don't actually use them in the code)
Const emptySpace As Integer = 0
Const red As Integer = 1
Const blue As Integer = 2
Dim player As Integer
Dim streak As Integer
Dim r As Integer, c As Integer 'loop placeholders
Dim v As Integer, h As Integer 'control search direction
For v = 0 To 1
For h = -1 To 1
If v = 1 Or h = 1 Then
'These loops and test check each direction (vertical, horizontal and
'both diagonals) for a win exactly once.
player = board(rowNum, colNum)
If player > 0 Then 'If player = pturn <-- to only check current player
streak = 1
'check positive direction
r = rowNum + h
c = colNum + v
Do While r >= minRow And r <= maxRow And c >= minColumn And c <= maxColumn
If board(r, c) = player Then
streak = streak + 1
If streak = 4 Then
Return player 'True <--If testing only current player
Else
r = r + h
c = c + v
End If
Else
Exit Do
End If
Loop
'check negative direction
r = rowNum - h
c = colNum - v
Do While r >= minRow And r <= maxRow And c >= minColumn And c <= maxColumn
If board(r, c) = player Then
streak = streak + 1
If streak = 4 Then
Return player 'True <--If testing only current player
Else
r = r - h
c = c - v
End If
Else
Exit Do
End If
Loop
End If
End If
Next h
Next v
Return 0 'Function has completed and no winner was found
'Return False <-- If only testing current player
End Function

VBA - Recognize typos in email domain

I'm working on a VBA script that is to work through an extensive list of email addresses and flag the ones that are suspected of being wrong.
I'd like to refine the routine by adding a function that would spot typos in common domain names such as gmail, hotmail, msn, skynet, etc. I'll have a list of these common display names in an array.
The string function would see if the inputted string looks similar but is not the same as an element in the array, and return true as boolean if it is the case.
Idea is to spot erroneous entries such as: homtail, mns, slynet, hotmal, yahooo, etc.
Not looking for a script per se, looking for inspiration of how to tackle this problem...
a fuzzy comarison is what you need - there is code here that will compare two strings, and give you a score from 0 to 1 depending on how close they are. It will be up to you to decide how close they are to do automatic substitution.
example results:
server text fuzzy score
------- -------- -----------
hotmail hotmale 0.7619048
hotmail hot 0.4285714
hotmail notmail 0.8571429
hotmail NotEvenClose 0.1944444
hotmail hotmail 1
hotmail yellow 0.0952381
hotmail homtail 0.7142857
The the source code has been released under GNU Lesser GPL
in case of link rot, here's the code:
Public Function Fuzzy(ByVal s1 As String, ByVal s2 As String) As Single
Dim i As Integer, j As Integer, k As Integer, d1 As Integer, d2 As Integer, p As Integer
Dim c As String, a1 As String, a2 As String, f As Single, o As Single, w As Single
'
' ******* INPUT STRINGS CLEANSING *******
'
s1 = UCase(s1) 'input strings are converted to uppercase
d1 = Len(s1)
j = 1
For i = 1 To d1
c = Mid(s1, i, 1)
Select Case c
Case "0" To "9", "A" To "Z" 'filter the allowable characters
a1 = a1 & c 'a1 is what remains from s1 after filtering
j = j + 1
End Select
Next
If j = 1 Then Exit Function 'if s1 is empty after filtering
d1 = j - 1
s2 = UCase(s2)
d2 = Len(s2)
j = 1
For i = 1 To d2
c = Mid(s2, i, 1)
Select Case c
Case "0" To "9", "A" To "Z"
a2 = a2 & c
j = j + 1
End Select
Next
If j = 1 Then Exit Function
d2 = j - 1
k = d1
If d2 < d1 Then 'to prevent doubling the code below s1 must be made the shortest string,
'so we swap the variables
k = d2
d2 = d1
d1 = k
s1 = a2
s2 = a1
a1 = s1
a2 = s2
Else
s1 = a1
s2 = a2
End If
If k = 1 Then 'degenerate case, where the shortest string is just one character
If InStr(1, s2, s1, vbBinaryCompare) > 0 Then
Fuzzy = 1 / d2
Else
Fuzzy = 0
End If
Else '******* MAIN LOGIC HERE *******
i = 1
f = 0
o = 0
Do 'count the identical characters in s1 and s2 ("frequency analysis")
p = InStr(1, s2, Mid(s1, i, 1), vbBinaryCompare)
'search the character at position i from s1 in s2
If p > 0 Then 'found a matching character, at position p in s2
f = f + 1 'increment the frequency counter
s2 = Left(s2, p - 1) & "~" & Mid(s2, p + 1)
'replace the found character with one outside the allowable list
'(I used tilde here), to prevent re-finding
Do 'check the order of characters
If i >= k Then Exit Do 'no more characters to search
If Mid(s2, p + 1, 1) = Mid(s1, i + 1, 1) Then
'test if the next character is the same in the two strings
f = f + 1 'increment the frequency counter
o = o + 1 'increment the order counter
i = i + 1
p = p + 1
Else
Exit Do
End If
Loop
End If
If i >= k Then Exit Do
i = i + 1
Loop
If o > 0 Then o = o + 1 'if we got at least one match, adjust the order counter
'because two characters are required to define "order"
finish:
w = 2 'Weight of characters order match against characters frequency match;
'feel free to experiment, to get best matching results with your data.
'If only frequency is important, you can get rid of the second Do...Loop
'to significantly accelerate the code.
'By altering a bit the code above and the equation below you may get rid
'of the frequency parameter, since the order counter increments only for
'identical characters which are in the same order.
'However, I usually keep both parameters, since they offer maximum flexibility
'with a variety of data, and both should be maintained for this project
Fuzzy = (w * o + f) / (w + 1) / d2
End If
End Function
What you want to do is called Hamming codes (or hamming distance) -
try this