I have a column that contains
"*********Task list completion *******
1.test
2.test
3.
4.
5.
How do I create a SQL query to count the completion? i.e. when there is text after the "number ." > 1.Test
The above would come back with count = 2
I have tried:
SELECT id as Task
,table
,table.id
from table
where table.id like '%Tier 1 Please Insure all tasks%'
and table.id LIKE '%3._%'
I solved it like this:
SELECT COUNT(*)
FROM (
SELECT Column FROM table WHERE Column LIKE '[0-9]%._%'
) AS a
In where condition I checked that column:
must start with a number
contain a dot
after dot at least one character
Check test output here on DB FIDDLE
Update
Because you did not provide a full question at start here is my updated answer:
Before running query I created a table with data for testing
CREATE TABLE tbl (field NVARCHAR(200))
INSERT INTO tbl VALUES ('Test DGS ********** Tier 1 Please Insure all tasks are fully completed ********* 1.test 2.test 3. 4. 5. 6. ')
CREATE TABLE #pom (Word NVARCHAR(50))
I wrote main query:
DECLARE #Strings NVARCHAR(200) = (SELECT REVERSE(LEFT(REVERSE(field), charindex('*', REVERSE(field)) - 2)) FROM tbl)
WHILE LEN(#Strings) > 0
BEGIN
INSERT INTO #pom
SELECT LEFT(#Strings, CHARINDEX(' ', #Strings) -1) AS 'Word'
SET #Strings = stuff(#Strings, 1, charindex(' ', #Strings + ' '), '')
END
SELECT COUNT(*)
FROM (
SELECT Word FROM #pom WHERE Word LIKE '[0-9]%._%'
) AS a
And you can see output here:
You can create a function or stored procedure with this code or whatever you need.
You can try this:
SELECT count(*)
FROM table
WHERE table.id LIKE '[1-9]%[a-z]'
If the data is consistently in this format, you can use wildcard expressions as below.
SELECT count(*)
FROM [table]
WHERE [column] LIKE '[1-9]%[a-z]'
Related
I have a column email with multiple delimiters like space ,/ , .
email
/john#thundergroup.com.mi/chris#cup.com.ey
r.Info#bc.com / rudi.an#yy.com
Dal#pema.com/Al#ama.com
/randi#mv.com
zul#sd.com/sat#sd.com/ faze#sd.com
My query:
select email,
CASE WHEN CHARINDEX(' ', email) > 0 THEN SUBSTRING(email, 0, CHARINDEX(' ', email)) ELSE
email END as Emailnew
FROM table
my output:
/john#thundergroup.com.mi/chris#cup.com.ey
r.Info#bc.com
Dal#pema.com/Al#ama.com
/randi#mv.com
zul#sd.com/sat#sd.com/ faze#sd.com
Please suggest changes so that in a single query I'm able to extract email
To get the first email always, you can try this below logic-
DEMO HERE
SELECT
CASE
WHEN CHARINDEX('/',email,2) = 0 THEN REPLACE(email,'/','')
ELSE REPLACE(SUBSTRING(email,0,CHARINDEX('/',email,2)),'/','')
END
FROM your_table
Output will be-
john#thundergroup.com.mi
r.Info#bc.com
Dal#pema.com
randi#mv.com
zul#sd.com
On modern SQL Servers try something like:
-- Setup...
create table dbo.Foo (
FooID int not null identity primary key,
Email nvarchar(100)
);
insert dbo.Foo (Email) values
('/john#thundergroup.com.mi/chris#cup.com.ey'),
('r.Info#bc.com / rudi.an#yy.com'),
('Dal#pema.com/Al#ama.com'),
('/randi#mv.com'),
('zul#sd.com/sat#sd.com/ faze#sd.com');
go
-- Demo...
select FooID, [Email]=value
from dbo.Foo
outer apply (
select top 1 value
from string_split(translate(Email, ' /', ';;'), ';')
where nullif(value, '') is not null
) Splitzville;
Which yields:
FooID Email
1 john#thundergroup.com.mi
2 r.Info#bc.com
3 Dal#pema.com
4 randi#mv.com
5 zul#sd.com
Requirements:
SQL Server 2016 and later for string_split().
SQL Server 2017 and later for translate().
If you want the first email only, use patindex():
select email,
left(email, patindex('%[^a-zA-Z0-9#.]%', email + ' ') - 1) as Emailnew
from table;
The pattern (a-zA-Z0-9#.) are valid email characters. You may have additional ones that you care about.
Unfortunately, I notice that some of your lists start with delimiter characters. In my opinion, the above works correctly by returning an empty value. That said, your desired results are to get the second value in that case.
So, you have to start the search at the first valid email character:
select t.email,
left(v.email1, patindex('%[^-_a-zA-Z0-9#.]%', v.email1 + ' ') - 1) as Emailnew
from t cross apply
(values (stuff(t.email, 1, patindex('%[-_a-zA-Z0-9#.]%', t.email) - 1, ''))) v(email1);
Here is a db<>fiddle.
I have a table DemoTable in SQL Server. And it has these columns:
Column1, Column2, Column3
I want to query the table
select * from DemoTable
but in query results I want to concatenate Type_ to all the column names available in DemoTable.
So the result of this query should be showing columns
Type_Column1, Type_Column2, Type_Column3
Is there any function or any way to achieve this?
Note: there are N number of columns not only 3 just to rename only these manually.
If the problem is as you say:
After joining all the tables , there are many duplicate column names
then the typical solution is to NOT use *. So instead of this:
SELECT *
FROM A
JOIN B ON ...
JOIN C ON ...
... you should consider using a custom column set, which is the normal and recommended way to do this, as in the following example:
SELECT A.Column1, A.Column2, B.Column3, C.Column4, C.Column5
FROM A
JOIN B ON ...
JOIN C ON ...
Here's one way to automate your task using dynamic SQL:
use MY_DATABASE;
go
--here you specify all your parameters, names should be self-explanatory
declare #sql varchar(1000) = 'select ',
#tableName varchar(100) = 'DemoTable',
#prefix varchar(10) = 'Type_';
select #sql = #sql + name + ' as ' + #prefix + name + ',' from sys.columns
where object_name(object_id) = #tableName;
set #sql = left(#sql, len(#sql) - 1) + ' from ' + #tableName;
exec(#sql);
Some general remarks:
Naming your result set's columns dynamically will demand for dynamic SQL in any case. No way around...
Naming columns to carry extra information is - in most cases - a very bad idea.
the only way I know to deal with the asterisk in a SELECT * FROM ... and still get full control over the columns names and types is XML.
Try this:
SELECT TOP 10 *
FROM sys.objects
FOR XML RAW, ROOT('TableDef'),ELEMENTS, XMLSCHEMA,TYPE
This will return the 10 first rows of sys.objects. The result is an XML, where the rows follow an XML schema definition.
It is possible (but sure not the best in performance) to create a fully inlined query dynamically. The result will be an EAV list carrying everything you need.
WITH PrepareForXml(QueryAsXml) AS
(
SELECT
(
SELECT TOP 10 *
FROM sys.objects
FOR XML RAW, ROOT('TableDef'),ELEMENTS, XMLSCHEMA,TYPE
)
)
,AllRows AS
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) RowIndex
,rw.query('.') theRowXml
FROM PrepareForXml
CROSS APPLY QueryAsXml.nodes('TableDef/*:row') A(rw)
)
SELECT RowIndex
,B.ColumnName
,B.ColumnValue
,COALESCE(
(SELECT QueryAsXml.value('declare namespace xsd="http://www.w3.org/2001/XMLSchema";
(TableDef
/xsd:schema
/xsd:element
/xsd:complexType
/xsd:sequence
/xsd:element[#name=sql:column("ColumnName")]
/#type )[1]','nvarchar(max)')
FROM PrepareForXml)
,(SELECT QueryAsXml.value('declare namespace xsd="http://www.w3.org/2001/XMLSchema";
(TableDef
/xsd:schema
/xsd:element
/xsd:complexType
/xsd:sequence
/xsd:element[#name=sql:column("ColumnName")]
/xsd:simpleType
/xsd:restriction
/#base)[1]','nvarchar(max)')
FROM PrepareForXml)
) AS ColumnType
FROM AllRows
CROSS APPLY theRowXml.nodes('*:row/*') A(col)
CROSS APPLY (SELECT col.value('local-name(.)','nvarchar(max)') ColumnName
,col.value('(./text())[1]','nvarchar(max)') ColumnValue ) B;
This is the beginning of the result-set:
RowIndex ColumnName ColumnValue ColumnType
1 name sysrscols sqltypes:nvarchar
1 object_id 3 sqltypes:int
1 schema_id 4 sqltypes:int
[...many more...]
I don't know what you need actually, but it might be enough to export the XML as is. It's everything in there...
UPDATE: I did not read carefully enough...
You want to trick out the fact, that a result set's column names must be unique in order to continue with this...
The approach above will not solve this issue. Sorry.
I won't delete this immediately... Might be there are some hints you can get out of this...
You can use the following query to add 'Type' to every column in table:
SELECT Column1 AS Type_Column1, Column2 AS Type_Column2, Column3 AS Type_Column3
FROM DemoTable
I’m fairly used to using MySQL, but not particularly familiar with SQL Server. Tough luck, the database I’m dealing with here is on SQL Server 2014.
I have a table with a column whose values are all integers with leading, separating, and trailing semicolons, like these three fictitious rows:
;905;1493;384;13387;29;933;467;28732;
;905;138;3084;1387;290;9353;4767;2732;
;9085;14493;3864;130387;289;933;4767;28732;
What I am trying to do now is to select all rows where more than one number taken from a list of numbers appears in this column. So for example, given the three rows above, if I have the group 905,467,4767, the statement I’m trying to figure out how to construct should return the first two rows: the first row contains 905 and 467; the second row contains 905 and 4767. The third row contains only 4767, so that row should not be returned.
As far as I can tell, SQL Server does not actually support regex directly (and I don’t even know what managed code is), which doesn’t help. Even with regex, I wouldn’t know where to begin. Oracle seems to have a function that would be very useful, but that’s Oracle.
Most similar questions on here deal with finding multiple instances of the same character (usually singular) and solve the problem by replacing the string to match with nothing and counting the difference in length. I suppose that would technically work here, too, but given a ‘filter’ group of 15 numbers, the SELECT statement would become ridiculously long and convoluted and utterly unreadable. Additionally, I only want to match entire numbers (so if one of the numbers to match is 29, the value 29 would match in the first row, but the value 290 in the second row should not match), which means I’d have to include the semicolons in the REPLACE clause and then discount them when calculating the length. A complete mess.
What I would ideally like to do is something like this:
SELECT * FROM table WHERE REGEXP_COUNT(column, ';(905|467|4767);') > 1
– but that will obviously not work, for all kinds of reasons (the most obvious one being the nonexistence of REGEXP_COUNT outside Oracle).
Is there some sane, manageable way of doing this?
You can do
SELECT *
FROM Mess
CROSS APPLY (SELECT COUNT(*)
FROM (VALUES (905),
(467),
(4767)) V(Num)
WHERE Col LIKE CONCAT('%;', Num, ';%')) ca(count)
WHERE count > 1
SQL Fiddle
Or alternatively
WITH Nums
AS (SELECT Num
FROM (VALUES (905),
(467),
(4767)) V(Num))
SELECT Mess.*
FROM Mess
CROSS APPLY (VALUES(CAST(CONCAT('<x>', REPLACE(Col, ';', '</x><x>'), '</x>') AS XML))) x(x)
CROSS APPLY (SELECT COUNT(*)
FROM (SELECT n.value('.', 'int')
FROM x.x.nodes('/x') n(n)
WHERE n.value('.', 'varchar') <> ''
INTERSECT
SELECT Num
FROM Nums) T(count)
HAVING COUNT(*) > 1) ca2(count)
Could you put your arguments into a table (perhaps using a table-valued function accepting a string (of comma-separated integers) as a parameter) and use something like this?
DECLARE #T table (String varchar(255))
INSERT INTO #T
VALUES
(';905;1493;384;13387;29;933;467;28732;')
, (';905;138;3084;1387;290;9353;4767;2732;')
, (';9085;14493;3864;130387;289;933;4767;28732;')
DECLARE #Arguments table (Arg int)
INSERT INTO #Arguments
VALUES
(905)
, (467)
, (4767)
SELECT String
FROM
#T
CROSS JOIN #Arguments
GROUP BY String
HAVING SUM(CASE WHEN PATINDEX('%;' + CAST(Arg AS varchar) + ';%', String) > 0 THEN 1 ELSE 0 END) > 1
And example of using this with a function to generate the arguments:
CREATE FUNCTION GenerateArguments (#Integers varchar(255))
RETURNS #Arguments table (Arg int)
AS
BEGIN
WITH cte
AS
(
SELECT
PATINDEX('%,%', #Integers) p
, LEFT(#Integers, PATINDEX('%,%', #Integers) - 1) n
UNION ALL
SELECT
CASE WHEN PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) + p = p THEN 0 ELSE PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) + p END
, CASE WHEN PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) = 0 THEN RIGHT(#Integers, PATINDEX('%,%', REVERSE(#Integers)) - 1) ELSE LEFT(SUBSTRING(#Integers, p + 1, LEN(#Integers)), PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) - 1) END
FROM cte
WHERE p <> 0
)
INSERT INTO #Arguments (Arg)
SELECT n
FROM cte
RETURN
END
GO
DECLARE #T table (String varchar(255))
INSERT INTO #T
VALUES
(';905;1493;384;13387;29;933;467;28732;')
, (';905;138;3084;1387;290;9353;4767;2732;')
, (';9085;14493;3864;130387;289;933;4767;28732;')
;
SELECT String
FROM
#T
CROSS JOIN GenerateArguments('905,467,4767')
GROUP BY String
HAVING SUM(CASE WHEN PATINDEX('%;' + CAST(Arg AS varchar) + ';%', String) > 0 THEN 1 ELSE 0 END) > 1
You can achieve this using the like function for the regex and row_number to determine the number of matches.
Here we declare the column values for testing:
DECLARE #tbl TABLE (
string NVARCHAR(MAX)
)
INSERT #tbl VALUES
(';905;1493;384;13387;29;933;467;28732;'),
(';905;138;3084;1387;290;9353;4767;2732;'),
(';9085;14493;3864;130387;289;933;4767;28732;')
Then we pass your search parameters into a table variable to be joined on:
DECLARE #search_tbl TABLE (
search_value INT
)
INSERT #search_tbl VALUES
(905),
(467),
(4767)
Finally we join the table with the column to search for onto the search table. We apply the row_number function to determine the number of times it matches. We select from this subquery where the row_number = 2 meaning that it joined at least twice.
SELECT
string
FROM (
SELECT
tbl.string,
ROW_NUMBER() OVER (PARTITION BY tbl.string ORDER BY tbl.string) AS rn
FROM #tbl tbl
JOIN #search_tbl search_tbl ON
tbl.string LIKE '%;' + CAST(search_tbl.search_value AS NVARCHAR(MAX)) + ';%'
) tbl
WHERE rn = 2
You could build a where clause like this :
WHERE
case when column like '%;905;%' then 1 else 0 end +
case when column like '%;467;%' then 1 else 0 end +
case when column like '%;4767;%' then 1 else 0 end >= 2
The advantage is that you do not need a helper table. I don't know how you build the query, but the following also works, and is useful if the numbers are in a tsql variable.
case when column like ('%;' + #n + ';%') then 1 else 0 end
I need to add character / number to selected duplicate values.
This is what I need:
SELECT Name -- Here I need to add for example 1 if It have duplicates
-- If It is hard way to code, how to add 1 to all selected values?
FROM Example
WHERE Id BETWEEN 25 AND 285
If there are 2 equal names Peter It should select Peter and second Peter1
If there is no easy way to make It, how to add 1 to all selected lines? Should select Peter1 instead of Peter
I've tried this:
SELECT Name + ' 1' AS Name -- in this case selecting wrong column
FROM Example
WHERE Id BETWEEN 25 AND 285
EDIT
SELECT #cols += ([Name]) + ','
FROM (SELECT Name --I neeed to integrate It here
FROM FormFields
WHERE ID BETWEEN 50 AND 82
) a
If I use this:
SELECT #cols += ([Name]) + ',' -- here throws error
FROM (SELECT Name + CASE WHEN RowNum = 1 THEN '' ELSE CONVERT(NVARCHAR(100), RowNum-1) END AS [UpdatedName]
FROM (
SELECT Name AS Name,
ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Name) AS "RowNum"
FROM FormFields
WHERE Id Between 50 And 82) x
) a
It throws error: Invalid column name 'Name'.
EDIT 2
It's different tests but some of them have the same criteria. That's why I need It to rename.
You can do this via getting the Row_Number and using a Case. Here's an example for SQL Server:
;With Cte As
(
Select Name, Row_Number() Over (Partition By Name Order By Name) RN
From Example
Where Id Between 25 And 285
)
Select Case When RN = 1 Then Name Else Name + Cast((RN - 1) As Varchar (3)) End As Name
From Cte
You could use the ROW_NUMBER function built into SQL server.
select Name + case when RowNum = 1 then '' else CONVERT(varchar(100), RowNum-1) end as "UpdatedName"
from (
select name as "Name",
ROW_NUMBER() over (partition by name order by name) as "RowNum"
from Example
Where Id Between 25 And 285) x
Please note that this still doesn't guarantee you unique names. Afterall, someone could already have a name of "MyName1", so if you had 2 people with names "MyName" you'd still get 2 "MyName1" with this select statement.
This is very unusual request, it looks like you are trying to "make car run with wheels on the roof" :)
The root problem is almost sure wrong database design... Pivot is usually used for data summaries. If you have in the same column "Peter" and "Peter" with different meanings, it looks that there is something wrong. Or do you need to differentiate both Peters for any other reason?
I do not understand what are you trying to achieve. If Peter is always Peter, and you just want to avoid duplicities, you can simply use "group by Name". But this is what pivot does automatically... If Peter and Peter have two different meanings (like Peter1 and Peter2), you should think about changing database structure, if possible.
Or try to explain more deeply what are you trying to achieve.
EDIT:
OK, now I understand the desired output. And what is the structure of your source data table(s)? From your schema it is clear that you need to make PIVOT columns based on
Testname+groupId
or
Testname+convert(varchar(100),groupId)
if groupId is number. That is your Peter1,Peter2 composition. It will create columns that you need. But I dont't know where testname and groupId are located in your datatables. Do test names correspond to column NAMES or to VALUES stored in DB? Is groupId something like TestId? Again column or value? Provide more info about source data structure, if you need more help, your problem is not so complicated.
Since the columns have group IDs, concatenate the Column name with an Underscore and GroupID as a key value and when you display it, strip the underscore and trailing characters.
Like This:
SELECT #cols += ([Name]) + ','
FROM (SELECT Name + '_' + CAST(GroupId AS varchar)
FROM FormFields
WHERE ID BETWEEN 50 AND 82
) a
I assume you are using this to build a dynamic SQL statement. I'm not sure what the schema of your FormFields Table is, but if it includes something like the test name you could append an AS [Name] + ' - ' +[TestName] to have the column header be something more useful. I would say try a PIVOT, but that could get pretty ungainly if the tests don't have the majority of the fields in common...
I also assume you are storing responses to these prompts in a table that looks something like this:
CREATE TABLE [Responses]
(
RespID int IDENTITY NOT NULL,
UserID int NOT NULL,
FieldID int NOT NULL,
RespVal int/varchar/whatever NOT NULL
)
Then perhaps you have a [Test] table with some test metadata that acts as the primary key for your GroupID Foreign key in your FormFields table.
In your example you show responses across all columns, but I'm not sure how that would work since (unless I'm missing something in your explanation and the inferences I've made to your design) one set of responses would only be populated for one of the groups per row, unless you are aggregating responses, but then by what criteria? Perhaps the rows correspond to respondents and all respondents are required to answer across all form types. In that case, your output would work as a PIVOT like this:
DECLARE #sql varchar(4000) = ''
DECLARE #colList varchar(1000)
DECLARE #selList varchar(1000)
;WITH NameBase
AS
(
SELECT t.Name [TestName], f.Name [FieldName], f.GroupId
FROM [FormFields] f
INNER JOIN [Tests] t ON f.GroupID = t.ID
)
SELECT #colList = COALESCE(#colList + ',','') + QUOTENAME([FieldName] + '_' + [GroupId])
, #selList = COALESCE(#selList + ',','') + QUOTENAME([FieldName] + '_' + [GroupId]) + ' AS ' + QUOTENAME([FieldName] + ' - ' + [TestName])
FROM NameBase
SELECT #sql = 'SELECT [UserName],' + #selList + ' FROM (
SELECT u.Name [UserName], f.Name + '_' + f.GroupId [FieldName], r.RespVal [Response]
FROM Responses r
INNER JOIN [TestUsers] u ON r.UserID = u.ID
INNER JOIN [FormFields] f ON r.FieldID = f.ID) t
PIVOT (MAX([Response]) FOR [FieldName] IN (' + #colList + ')) pvt'
EXECUTE(#sql);
I haven't tested that yet, but it should at least point you in the right direction. I'll try to build a SqlFiddle to test it in a little bit.
Customer Table
--------------
ID Name
1 James
2 Peter
Order Table
---------------
OrderId CustId
100 1
101 1
102 2
How can I write a query that returns something like this
ID,Name,ListofOrders
1,James,"100,101"
2,Peter,"102"
In Sybase I had a function called LIST which I could use but I dont find a similar function in SQL SERVER
Please try:
select ID, [Name],
(select OrderID+',' from OrderTable where CustID=ID
group by OrderID for xml path('')) AS ListOfOrders
From CustomerTable
Create a User Defined Function as shown below
CREATE FUNCTION [dbo].[CommaSeperatedOrderIDs](#CustId INT) returns varchar(Max)
AS
BEGIN
DECLARE #CommaSeperatedValues VARCHAR(MAX)
SELECT #CommaSeperatedValues = COALESCE(#CommaSeperatedValues+',' , '') + OrderID
FROM OrderTable WHERE CustId = #CustId
RETURN #CommaSeperatedValues
END
And then,
select ID, [Name], ([dbo].[CommaSeperatedOrderIDs](ID)) AS ListofOrders
From CustomerTable
Adding full details from Sheikh Haris' link.
Given this table:
To get output like:
Use the following SQL:
SELECT field1,
Substring(convert(varchar(100),
(
SELECT (', ' + field2)
FROM #test t2
WHERE t1.field1 = t2.field1
ORDER BY field1, field2
FOR XML PATH( '' )
)), 3, 1000 )
FROM #test t1
GROUP BY field1
I added a convert function to the substring so that the WIDEMEMO field would be displayed (SQL Server)
A very simple and handy solution given on the link below.
http://tejasnshah.wordpress.com/2009/02/28/sql-server-get-column-values-as-comma-seperated-list-using-xml-path-instead-of-udfs-using-sql-coalesce/
The SQL query written on that link is in an image ...so i couldn't copy it here.