I have written a union query but I need to eliminate the lines that are duplicated (line 2 and 3 in the column 'kods') and leave only distinct values of column 'kods'. How can that be done?
You need to decide which of the id values to discard using either min or max and group by the remaining columns. you don't need distinct and can union all since group by will perform the dedupe.
select kods, min(id) id, vards, uzvards from (
select kods, id, vards, uzvards
from dataset
union all
select kods, id, vards, uzvards
from dataset_2
)x
group by kods, vards, uzvards
Related
I'm trying to make an SQL query that returns the greatest number from a column and its respective id.
For more information I have two columns ID and NUMBER. Both of them have 2 entries and I want to get the highest number with the ID next to it. This is what I tried but didn't success.
SELECT ID, MAX(NUMBER) AS MAXNUMB
FROM TABLE1
GROUP BY ID, MAXNUMB;
The problem I'm experiencing is that it just shows ALL the entries and if I add a "where" expression it just shows the same (all entries [ids+numbers]).
Pd.: Yes, I got what I wanted but only with one column (number) if I add another column (ID) to select it "brokes".
Try:
SELECT
ID,
A_NUMBER
FROM TABLE1
WHERE A_NUMBER = (
SELECT MAX(A_NUMBER)
FROM TABLE1);
Presuming you want the IDs* of the row with the highest number (and not, instead, the highest number for each ID -- if IDs were not unique in your table, for example).
* there may be more than one ID returned if there are two or more IDs with equal maximum numbers
you can try this
Select ID,maxNumber
From
(
SELECT
ID,
(Select Max(NUMBER) from Tmp where Id = t.Id) maxNumber
FROM
Tmp t
)T1
Group By ID,maxNumber
The query you posted has an illegal column name (number) and is group by the alias for the max value, which is illegal and also doesn't make sense; and you can't include the unaliased max() within the group-by either. So it's likely you're actually doing something like:
select id, max(numb) as maxnumb
from table1
group by id;
which will give one row per ID, with the maximum numb (which is the new name I've made up for your numeric column) for each ID. Or as you said you get "ALL the entries" you might have group by id, numb, which would show all rows from the table (unless there are duplicate combinations).
To get the maximum numb and the corresponding id you could group by id only, order by descending maxnumb, and then return the first row only:
select id, max(numb) as maxnumb
from table1
group by id
order by maxnumb desc
fetch first 1 row only
If there are two ID with the same maxnumb then you would only get one of them - and which one is indeterminate unless you modify the order by - but in that case you might prefer to use first 1 row with ties to see them all.
You could achieve the same thing with a subquery and analytic function to generating a ranking, and have the outer query return the highest-ranking row(s):
select id, numb as maxnumb
from (
select id, numb, dense_rank() over (order by numb desc) as rnk
from table1
)
where rnk = 1
You could also use keep to get the same result as first 1 row only:
select max(id) keep (dense_rank last order by numb) as id, max(numb) as maxnumb
from table1
fiddle
I have an SQL view, and I want to get unique rows based on only some columns.
If all other columns are the same (excluding A), duplicates must be deleted.
and
If all other columns are the same (excluding B), duplicates must be deleted.
I used the code below, but it still gives me the max of A then the Max of B, and what I want is to get distinct rows excluding these two columns, and I want to keep these columns in the select function.
SELECT Name, Account, MAX(A), MAX(B)
FROM MyTable
GROUP BY Name, Account
Thanks in advance!
Have not tested, but is this what you are searching for?
select sub.Name,sub.Account,MAX(sub.prod)
from
(
select Name,Account,MAX(A) as prod from MyTable group by Name,Account
union all
select Name,Account,MAX(B) as prod from MyTable group by Name,Account
) as sub
group by sub.Name, sub.Account
select d.id, d.registration_number
from DOCUMENTS d
union
select dd.id, dd.registration_number
from DIFFERENT_DOCUMENTS dd
Would it be possible to union those results based solely on the uniqueness of the registration_number, disregarding the id of the documents?
Or, is it possible to achieve the same result in a different way?
Just to add: actually I'm unioning 5 queries, each ~20 lines long, with 4 columns that should be disregarded in determining uniqueness.
you basically need to wrap the unioned data with something else to get only the ones you want.
SELECT min(id), registration_number
FROM (SELECT id, registration_number
FROM documents
UNION ALL
SELECT id, registration_number
FROM different_documents)
GROUP BY registration_number
Union will check the combination of all the columns for uniqueness. You could, however, use union all (that does not remove duplicates) and then apply the logic yourself using the row_number window function:
SELECT id, registration_number
FROM (SELECT id, registration_number,
ROW_NUMBER() OVER (PARTITION BY registration_number ORDER BY id) AS rn
FROM (SELECT id, registration_number
FROM documents
UNION ALL
SELECT id, registration_number
FROM different_documents) u
) r
WHERE rn = 1
Since the other answers are already correct, may I ask why do you need to retrieve other columns in that query since the primary purpose appear to gather unique registration numbers?
Wouldn't it be simpler to first gather unique registration number and then retrieve the other info?
Or in your actual query, first gather the info without the columns that should be disregarded and then gather the info in these column if need be?
Like,for example, making a view with
SELECT d.registration_number
FROM DOCUMENT d
UNION
SELECT dd.registration_number
FROM DIFFERENT_DOCUMENT dd
and then gather information using that view and JOINS?
Assuming registration_number is unique in each table, you can use not exists:
select d.id, d.registration_number
from DOCUMENTS d
union all
select dd.id, dd.registration_number
from DIFFERENT_DOCUMENTS dd
where not exists (select 1
from DOCUMENTS d
where dd.registration_number = d.registration_number
);
I need to get the cumulative sum of column sales and growth starting from second row.
Sample data:
select 1 AS SN,'16000' AS Sales,'0' AS Growth,'16000' AS RequiredTotal
INTO #tempa
union select 2,'','500','16500'
union select 3,'','500','17000'
union select 4,'','500','17500'
union select 5,'','500','18000'
union select 6,'','500','18500'
union select 7,'','500','19000'
SELECT *
FROM #tempa
Here I need to get the requiredtotal column.
First value is the sales itself, And starting from second row, need to get the sum of 1st value of requiredtotal column and the growth column second row.
Use window functions:
select a.*,
(max(sales) over () +
sum(growth) over (order by sn)
) as required
from #tempa a;
Here is a db<>fiddle.
Note that I changed the data types in the fiddle so the numbers are actually numbers. Don't store numbers as strings.
I am trying to work out how much we have taken in for entry fees.
I have two separate queries both returning values but i need them be as one instead of two separate queries.
SELECT SUM(ENTRY) AS TOTAL1 FROM MONEY
SELECT SUM(ENTRY) AS TOTAL1 FROM MONEY2
I needed to use UNION in order to get the statements together. Then used the below to get one number.
SELECT SUM(X.TOTAL1) from
(
SELECT SUM(ENTRY) AS TOTAL1 FROM MONEY
UNION
SELECT SUM(ENTRY) AS TOTAL1 FROM MONEY2
) X;
select sum(entry) as grand_total
from ( select entry from money
union all
select entry from money2
);
The point being, you SHOULD use UNION ALL; and how many columns each table has is irrelevant, because you don't need to UNION ALL the two tables (all columns from each); you only need to UNION ALL the ENTRY column from the first table and the ENTRY column from the second table.