I have two tables
id
val
1
a
1
b
1
c
2
d
2
e
3
f
and
id
1
2
What I want is a count of the number of times an ID appears from the first table ONLY IF if it exists in the second table. How can I do this?
Example output:
id
count
1
3
2
2
3
0
Would you like to show ids that do not exist in the first table?
I made it show according to the ids that exist in the first table, if you want it to show up please comment below
select tb7.id, COUNT(tb6.id) as count
from Table_6 tb6 inner join Table_7 tb7 on tb6.id = tb7.id
group by tb7.id
You can use left outer join and count as follows:
Select t1.id, count(t2.id) as cnt
From table1 t1 left join
table2 t2
on t1.id = t2.id
Group by t1.id;
Related
I have Table 1 & 2 with common Column name ID in both.
Table 1 has duplicate entries of rows which I was able to trim using:
SELECT DISTINCT
Table 2 has duplicate numeric entries(dollarspent) for ID's which I needed and was able to sum up:
Table 1 Table 2
------------ ------------------
ID spec ID Dol1 Dol2
54 A 54 1 0
54 A 54 2 1
55 B 55 0 2
56 C 55 3 0
-I need to join these two queries into one so I get a resultant JOIN of Table 1 & Table 2 ON column ID, (a) without duplicates in Table 1 & (b) Summed $ values from Table 2
For eg:
NewTable
----------------------------------------
ID Spec Dol1 Dol2
54 A 3 1
55 B 3 2
Notes : No. of rows in Table 1 and 2 are not the same.
Thanks
Use a derived table to get the distinct values from table1 and simply join to table 2 and use aggregation.
The issue you have is you have a M:M relationship between table1 and table2. You need it to be a 1:M for the summations to be accurate. Thus we derive t1 from table1 by using a select distinct to give us the unique records in the 1:M relationship (assuming specs are same for each ID)
SELECT T1.ID, T1.Spec, Sum(T2.Dol1) as Dol1, sum(T2.Dol2) as Dol2
FROM (SELECT distinct ID, spec
FROM table1) T1
INNER JOIN table2 T2
on t2.ID = T1.ID
GROUP BY T1.ID, T1.Spec
This does assume you only want records that exist in both. Otherwise we may need to use an (LEFT, RIGHT, or FULL) outer join; depending on desired results.
I can't really see your data, but you might want to try:
SELECT DISTINCT ID
FROM TblOne
UNION ALL
SELECT DISTINCT ID, SUM(Dol)
FROM TblTwo
GROUP BY ID
Pre-aggregate table 2 and then join:
select t1.id, t1.spec, t2.dol1, t2.dol2
from (select t2.id, sum(dol1) as dol1, sum(dol2) as dol2
from table2 t2
group by t2.id
) t2 join
(select distinct t1.id, t1.spec
from table1 t1
) t1
on t1.id = t2.id;
For your data examples, you don't need to pre-aggregate table 2. This gives the correct sums -- albeit in multiple rows -- if table1 has multiple specs for a given id.
I'm new to SQL and am having trouble getting results to display that exist in table 1 but not table 2. I need to display how many times each ID from table 1 has been used in table 2 (including 0 if it has not been used) I can get the ID's that exist in Table 1 to display, but not the ID's that don't exist in Table 2.
I am getting:
ID Count
1
1
1
1
1
1
2
but need:
ID Count
1
1
1
0
1
1
0
1
2
I have tried:
SELECT COUNT (PID) AS [ID Count]
FROM SalesOrderProduct
WHERE PID > = 0
GROUP BY PID;
(just for this column that i can't get the 0 values to display in)
Table 1: PID, Description
Table 2: PID, Status
How can I get the results to display showing all the counts for ID in Table 2, including when the count is 0 using UNION?
Thanks everyone
Try this, you can change the attribute name based on your table structure.
Select t1.id, count(t2.id)
From t1 left join t2
on (t1.id = t2.id)
Group By t1.id;
in this case that your ids are not unique use exists with a count plus a union like:
select distinct tbl.id, 0 cnt --for ids not exists in table2
from table1 tbl
where not exists (select t.id from table2 t where t.id=tbl.id)
union
select t1.id, count(t1.id) cnt ----for ids exists in table2
from table1 t1
where exists (select t2.id from table2 t2 where t1.id=t2.id)
group by t1.id
The most related question I looked into was this but sadly I did not get a solution for my problem there.
I have two tables, both have a similar column. The only difference is that one column is missing a few values. I want to join the tables, so that for the missing value in one column, the join will show the missing values.
Ill provide an example since this might be confusing -
table 1 table 2
ID count ID count
1 9 1 2
2 2 2 1
3 1
I want the result to be
table 3
ID count2 count1
1 2 9
2 1 2
3 NULL 1
However, using LEFT OUTER JOIN I could only achieve the table "table 3" without the row for id 3, because it has no representation in table 2.
Can you help me with my problem?
A left join would work for your sample data, I'm guessing you want to know what to do if you move the row with id 3 into table 2 so that your query will show all ids. To show all rows from both tables, use a FULL OUTER JOIN:
SELECT CASE WHEN t1.id IS NULL THEN t2.id ELSE t1.id END AS id,
t2.count as count2, t1.count as count1
FROM t1
FULL OUTER JOIN t2 ON t2.id = t1.id
Hi I have table with the following data
A B bid status
10 20 1 SUCCESS_1
10 20 1 SUCCESS_2
10 30 2 SUCCESS_1
10 30 2 SUCCESS_2
Now I want to print or count above rows based on SUCCESS_1 and SUCCESS_2. I created the following query but it does not work it just returns one row by combining two rows.
select * from tbl t1 join tbl t2 on
on (t1.A=t2.A and t1.B=t2.B and
(t1.Status = 'SUCCESS_1' and t2.Status = 'SUCCESS_2')
where t1.bid= 1
I want output as the following for the above query
A B bid status
10 20 1 SUCCESS_1
10 20 1 SUCCESS_2
I am new to SQL please guide. Thanks in advance.
If you need to do the join for some reason (e.g. your database does not let you select everything if you group by 1 column, because it wants everything projected to either be grouped or be an aggregate), you could do the following:
select t1.*
from tbl t1 join tbl t2
on (t1.A=t2.A and t1.B=t2.B and t1.Status = 'SUCCESS_1' and t2.Status = 'SUCCESS_2')
where t1.bid= 1
union all select t2.*
from tbl t1 join tbl t2
on (t1.A=t2.A and t1.B=t2.B and t1.Status = 'SUCCESS_1' and t2.Status = 'SUCCESS_2')
where t1.bid= 1
order by 1,2,3,4
Your original query is pulling back all the data in one row, but this one pulls back the two rows that make that resulting join row separately.
SELECT * FROM `tbl1` WHERE `bid`=1 GROUP BY `status`
I want to join two tables and get data against an ID from the first table and count a column record from the second table against the same ID. I want a single query which gives me that output.
Following is a use-case/example for your problem and a proposed solution:
You have two tables User and User_Friends which store user-data and contact-information respectively.
And you want to display the name and number of contacts a user has.
Table User:
id Name
0 A
1 B
2 C
3 D
Table User_Friends:
id friend_id
0 1
0 2
0 3
1 2
1 3
Output:
Name Count(*)
A 3
B 2
C 0
D 0
//Display the Name, number of friends
SELECT Name, count(*)
FROM User, User_Friends
WHERE User.id = User_Friends.id
GROUP BY User_Friends.id
I think you're asking about a query like this:
select t1.id, count(t2.id)
from table1 as t1
left outer join table2 as t2
on t2.table1_id = t1.id
group by t1.id;
select
ID,
(select count(*) from table2 where ID=p.ID) as [count]
from table1 p