Below is my SQL function script that will help identify the alphanumeric value and dashes (-):
CREATE FUNCTION [dbo].[FN_VALIDATE_ALPHANUMERIC_AND_DASHES](#TX_INPUT VARCHAR(1000))RETURNS BIT AS
BEGIN
DECLARE #bitInputVal AS BIT = 0
DECLARE #InputText VARCHAR(1000)
SET #InputText = LTRIM(RTRIM(ISNULL(#TX_INPUT,'')))
IF #InputText <> ''
BEGIN
SET #bitInputVal = CASE
WHEN #InputText LIKE '%[A-Za-z0-9-]%' THEN 1
ELSE 0
END
END
RETURN #bitInputVal
END
I have problem which I try this query:
SELECT dbo.FN_VALIDATE_CLAIMANT_REF_NO('AbcdefgH-1234*') it gives me a result of 1 though the character * is not included in the regex and should return 0 instead.
What I want to achieve is to explicitly verify if the string consist of alphanumeric (alphabets and numbers) and dashes only.
Please note that there are no limitation in length of the characters, only check if the string consist of alphanumeric and dashes.
You are testing for "whether any alphabet, number or dash is present in the string"
You should instead test whether any character other than alphabet, number or dash is present.
SET #bitInputVal = CASE WHEN #InputText LIKE '%[^A-Za-z0-9-]%' THEN 0 ELSE 1 END
Related
Hi I've taken a function to strip out alphanumeric characters and some punctuation characters from a string.
ALTER FUNCTION [dbo].[Remove_Non_Alphanumeric]
(#String_Parameter VARCHAR(MAX))
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE #Alphanumeric_Characters VARCHAR(289) = '%[^A-Za-z0-9| |?|,|&|\|/|.|'+CHAR(13)+'|'+CHAR(10)+'|(|)|]|[|-]%';
WHILE PATINDEX(#Alphanumeric_Characters, #String_Parameter) > 0
BEGIN
SELECT #String_Parameter = STUFF(#String_Parameter, PATINDEX(#Alphanumeric_Characters, #String_Parameter), 1, '');
END
RETURN #String_Parameter;
END
This mostly seems to work. However there are odd passages which have some characters returned with a ? and odder still some bullet points are changed to ? and others are left. Despite both not being in a my list of acceptable characters.
I would love to have a regex on my LIKE clause with the criteria given:
It should only have 13 length characters
First 8 characters should be number
The 9th character should append a dash (-)
The rest of 4 characters are the rest of the numbers.
Example:
12345678-9123
98765432-1234
Currently have this function:
CREATE FUNCTION [dbo].[FN_VALIDATE_ID](#TX_INPUT VARCHAR(50))RETURNS BIT AS
BEGIN
DECLARE #bitInputVal AS BIT = 1
DECLARE #InputText VARCHAR(50)
SET #InputText = LTRIM(RTRIM(ISNULL(#TX_INPUT,'')))
IF #InputText <> '' AND LEN(#InputText) = 13
BEGIN
SET #bitInputVal = CASE
WHEN #InputText LIKE '%^[0-9]%' THEN 1
ELSE 0
END
END
RETURN #bitInputVal
END
You don't even need a UDF for this, as SQL Server's enhanced LIKE operator can handle this requirement:
SELECT *
FROM yourTable
WHERE col LIKE '[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]-[0-9][0-9][0-9][0-9]';
-- \ 8 digits / - \ 4 digits /
I want to know a flexible way to extract the string between two '-'. The issue is that '-' may or may not exist in the source string. I have the following code which works fine when '-' exists twice in the source string, marking the start and end of the extracted string. But it throws an error "Invalid length parameter passed to the LEFT or SUBSTRING function" when there is only one '-' or none at all or if the string is blank. Can someone please help? Thanks
declare #string varchar(100) = 'BLAH90-ExtractThis-WOW'
SELECT SUBSTRING(#string,CHARINDEX('-',#string)+1, CHARINDEX('-',#string,CHARINDEX('-',#string)+1) -CHARINDEX('-',#string)-1) as My_String
Desired Output: ExtractThis
If there is one dash only e.g. 'BLAH90-ExtractThisWOW' then the output should be everything after the first dash i.e. ExtractThisWOW. If there are no dashes then the string will have a blank space instead e.g. 'BLAH90 ExtractThisWOW' and should return everything after the blank space i.e. ExtractThisWOW.
You can try something like this.
When there is no dash, it starts at the space if there is one or take the whole string if not.
Then I look if there is only one dash or 2
declare #string varchar(100) = 'BLAH90-ExtractThis-WOW'
declare #dash_pos integer = CHARINDEX('-',#string)
SELECT CASE
WHEN #dash_pos = 0 THEN
RIGHT(#string,LEN(#string)-CHARINDEX(' ',#string))
ELSE (
CASE
WHEN #dash_pos = LEN(#string)-CHARINDEX('-',REVERSE(#string))+1
THEN RIGHT(#string,LEN(#string)-#dash_pos)
ELSE SUBSTRING(#string,#dash_pos+1, CHARINDEX('-',#string,#dash_pos+1) -
#dash_pos -1)
END
)
END as My_String
Try this. If there are two dashes, it'll take what is inside. If there is only one or none, it'll keep the original string.
declare #string varchar(100) = 'BLAH-90ExtractThisWOW'
declare #dash_index1 int = case when #string like '%-%' then CHARINDEX('-', #string) else -1 end
declare #dash_index2 int = case when #string like '%-%'then len(#string) - CHARINDEX('-', reverse(#string)) + 1 else -1 end
SELECT case
when #dash_index1 <> #dash_index2 then SUBSTRING(#string,CHARINDEX('-',#string)+1, CHARINDEX('-',#string,CHARINDEX('-',#string)+1) -CHARINDEX('-',#string)-1)
else #string end
as My_String
Take your existing code:
declare #string varchar(100) = 'BLAH90-ExtractThis-WOW'
SELECT SUBSTRING(#string,CHARINDEX('-',#string)+1, CHARINDEX('-',#string,CHARINDEX('-',#string)+1) -CHARINDEX('-',#string)-1) as My_String
insert one line, like so:
declare #string varchar(100) = 'BLAH90-ExtractThis-WOW'
SET #string = #string + '--'
SELECT SUBSTRING(#string,CHARINDEX('-',#string)+1, CHARINDEX('-',#string,CHARINDEX('-',#string)+1) -CHARINDEX('-',#string)-1) as My_String
and you're done. (If NULL, you will get NULL returned. Also, this will return all data based on the FIRST dash found in the string, regardless of however many dashes are in the string.)
I am working in SQL Server 2008. I am trying to test whether a string (varchar) has only digit characters (0-9). I know that the IS_NUMERIC function can give spurious results. (My data can possibly have $ signs, which should not pass the test.) So, I'm avoiding that function.
I already have a test to see if a string has any non-digit characters, i.e.,
some_column LIKE '%[^0123456789]%'
I would think that the only-digits test would be something similar, but I'm drawing a blank. Any ideas?
Use Not Like
where some_column NOT LIKE '%[^0-9]%'
Demo
declare #str varchar(50)='50'--'asdarew345'
select 1 where #str NOT LIKE '%[^0-9]%'
There is a system function called ISNUMERIC for SQL 2008 and up. An example:
SELECT myCol
FROM mTable
WHERE ISNUMERIC(myCol)<> 1;
I did a couple of quick tests and also looked further into the docs:
ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0.
Which means it is fairly predictable for example
-9879210433 would pass but 987921-0433 does not.
$9879210433 would pass but 9879210$433 does not.
So using this information you can weed out based on the list of valid currency symbols and + & - characters.
Solution:
where some_column NOT LIKE '%[^0-9]%'
Is correct.
Just one important note: Add validation for when the string column = '' (empty string). This scenario will return that '' is a valid number as well.
Method that will work. The way it is used above will not work.
declare #str varchar(50)='79136'
select
case
when #str LIKE replicate('[0-9]',LEN(#str)) then 1
else 0
end
declare #str2 varchar(50)='79D136'
select
case
when #str2 LIKE replicate('[0-9]',LEN(#str)) then 1
else 0
end
DECLARE #x int=1
declare #exit bit=1
WHILE #x<=len('123c') AND #exit=1
BEGIN
IF ascii(SUBSTRING('123c',#x,1)) BETWEEN 48 AND 57
BEGIN
set #x=#x+1
END
ELSE
BEGIN
SET #exit=0
PRINT 'string is not all numeric -:('
END
END
I was attempting to find strings with numbers ONLY, no punctuation or anything else. I finally found an answer that would work here.
Using PATINDEX('%[^0-9]%', some_column) = 0 allowed me to filter out everything but actual number strings.
The selected answer does not work.
declare #str varchar(50)='79D136'
select 1 where #str NOT LIKE '%[^0-9]%'
I don't have a solution but know of this potential pitfall. The same goes if you substitute the letter 'D' for 'E' which is scientific notation.
I am using SQL Server 2008
I have sql string in column with ; separated values. How i can trim the below value
Current string:
;145615;1676288;178829;
Output:
145615;1676288;178829;
Please help with sql query to trim the first ; from string
Note : The first char may be or may not be ; but if it is ; then only it should trim.
Edit: What i had tried before, although it doesn't make sense after so many good responses.
DECLARE
#VAL VARCHAR(1000)
BEGIN
SET #VAL =';13342762;1334273;'
IF(CHARINDEX(';',#VAL,1)=1)
BEGIN
SELECT SUBSTRING(#VAL,2,LEN(#VAL))
END
ELSE
BEGIN
SELECT #VAL
END
END
SELECT CASE WHEN col LIKE ';%'
THEN STUFF(col,1,1,'') ELSE col END
FROM dbo.table;
Just check the first character, and if it matches, start from the second character:
SELECT CASE WHEN SUBSTRING(col,1,1) = ';'
THEN SUBSTRING(col,2,LEN(col))
ELSE col
END AS col
Here's an example:
DECLARE #v varchar(10)
SET #v = ';1234'
SELECT
CASE
WHEN LEFT(#v,1) = ';' THEN RIGHT(#v, LEN(#v) - 1)
ELSE #v
END
A further development on #Aaron Bertrand's answer:
SELECT
STUFF(col, 1, PATINDEX(';%', col), '')
FROM ...
PATINDEX is similar to LIKE in that it uses a pattern search, but being a function it also returns the position of the first match. In this case, since we a looking for a ; specifically at the beginning of a string, the position returned is going to be either 1 (if found) or 0 (if not found). If it is 1, the STUFF function will delete 1 character at the beginning of the string, and if the position is 0, STUFF will delete 0 characters.