i have a table TB_Orders , i save orders in thatl ,ike below :
userid
factorid
productname
economy
vip
count
1
A-123
name1
13000
18000
3
1
A-123
name2
9000
13000
4
2
A-124
name2
2000
5000
2
For example, user 1: has registered two orders with invoice number A-123.
And user 2 has only registered one order
I want to report as follows:
userid
factorid
total economy
total vip
total count
1
A-123
21000
31000
7
2
A-124
2000
5000
2
thanks for your help
This is an aggregation query:
select userid, factorid, sum(economy), sum(vip), sum(count)
from tb_orders
group by userid, factorid;
Aggregation is a very basic part of SQL functionality. If you don't recognize it, I would suggest that you brush up on your SQL skills with a tutorial, book, or something like that.
Related
Consider this table:
id name department email
1 Alex IT blah#gmail.com
1 Alex IT blah#gmail.com
2 Jay HR jay#gmail.com
2 Jay Marketing zou#gmail.com
If I group byid,name and count I get:
id name count(*)
1 Alex 2
2 Jay 2
With this query:
select id,name,count(*) from tb group by id,name;
However I would like to count only records that diverge from department,email, so as to have:
id name count(*)
1 Alex 0
2 Jay 1
This time the count for the first group 1,Alex is 0 because department,email have the same values (duplicated) , on the other hand 2,Jay is one because department,email has one different value.
If you meant "two different values" for "Jay", you can use distinct:
select id,name,count(*) from (SELECT distinct * FROM tb) group by id,name;
You can use count(*) - 1 to get similar results in your question.
this is my table schema, total_hours column is the result of a sum function.
Id name client total_hours
1 John company 1 100
1 John company 2 200
2 Jack company 3 350
2 Jack company 2 150
I want to merge the rows with similar ID into one row, looking like this.
Id name client_a total_hours_a client_b total_hours_b
1 John company 1 100 company 2 200
2 Jack company 3 350 company 2 150
I tried to use pivot but this function does not seem to exist in Dbeaver. Here is my query
SELECT
client
,name
,sum(hours) AS total_hours
FROM pojects
GROUP BY client, name;
Thanks in advance if anyone could be of any help.
I am trying to get a COUNTIFS from excel type of result
Here is the products table:
Name Product
john car
john football
john image
max food
max tv
max laptop
max image
max image
max image
alex tv
alex laptop
alex image
alex cake
alex cake
alex cake
alex cake
alex car
The output should be:
Name Product Number of products per person Number of products of the same type
john car 1 2
john football1 1
john image 1 5
max food 1 1
max tv 1 2
max laptop 1 2
max image 3 5
alex tv 1 2
alex laptop 1 2
alex image 1 5
alex cake 4 4
alex car 1 2
Number of products per person is count of products by name by product
and Number of products of the same type is based on the total count by product
for example image is repeated 3 times for max so in col C the answer is 3 but it there 5 times in the table so answer in col D is 5
I tried but not getting the correct answer:
SELECT
name,
product,
COUNT(*),
COUNT(*) OVER (PARTITION BY product),
from products
GROUP BY 1,2
ORDER BY 1
You are quite close. You need to sum the COUNT(*). You can do this directly in the aggregation query:
SELECT name, product,
COUNT(*),
SUM(COUNT(*)) OVER (PARTITION BY product)
FROM products
GROUP BY 1, 2
ORDER BY 1
#standardSQL
SELECT name, product, product_per_person,
SUM(product_per_person) OVER(PARTITION BY product) product_total
FROM (
SELECT
name,
product,
COUNT(*) product_per_person
FROM `project.dataset.products`
GROUP BY 1,2
)
ORDER BY 1
if to apply to your sample data - result should be
Row name product product_per_person product_total
1 alex cake 4 4
2 alex car 1 2
3 alex image 1 5
4 alex laptop 1 2
5 alex tv 1 2
6 john car 1 2
7 john football 1 1
8 john image 1 5
9 max food 1 1
10 max image 3 5
11 max laptop 1 2
12 max tv 1 2
use group by name and product
SELECT name,
product,
COUNT(*),
COUNT(*) OVER (partition by product)
from products
GROUP BY name,product
ORDER BY 1
I am trying the Sum the 2nd record of one column with the 1st record of another column and store the result in a new column
Here is the example SQL Server table
Emp_Code Emp_Name Month Opening_Balance
G101 Sam 1 1000
G102 James 2 -2500
G103 David 3 3000
G104 Paul 4 1800
G105 Tom 5 -1500
I am trying to get the output as below on the new Reserve column
Emp_Code Emp_Name Month Opening_Balance Reserve
G101 Sam 1 1000 1000
G102 James 2 -2500 -1500
G103 David 3 3000 1500
G104 Paul 4 1800 3300
G105 Tom 5 -1500 1800
Actually the rule for calculating the Reserve column is that
For Month-1 it's the same as Opening Balance
For rest of the months its Reserve for Month-2 = Reserve for Month-1 + Opening Balance for Month-2
You seem to want a cumulative sum. In SQL Server 2012+, you would do:
select t.*,
sum(opening_balance) over (order by [Month]) as Reserve
from t;
In earlier versions, you would do this with a correlated subquery or apply:
select t.*,
(select sum(t2.opening_balance) from t t2 where t2.[Month] <= t.[Month]) as reserve
from t;
You can do a self join.
SELECT t.Emp_Code, t.Emp_Name, t.Month, t.Opening_Balance, t.Opening_Balance + n.Reserve
FROM Table1 t
JOIN Table2 n
ON t.Month = n.Month - 1
I have a table like the one below. It is a record of daily featured products and the customers that purchased them (similar to a daily deal site). A given client can only purchase a product one time per feature, but they may purchase the same product if it is featured multiple times.
FeatureID | ClientID | FeatureDate | ProductID
1 1002 2011-05-01 500
1 2333 2011-05-01 500
1 4458 2011-05-01 500
2 8888 2011-05-10 700
2 2333 2011-05-10 700
2 1111 2011-05-10 700
3 1002 2011-05-20 500
3 4444 2011-05-20 500
4 4444 2011-05-30 500
4 2333 2011-05-30 500
4 1002 2011-05-30 500
I want to count by FeatureID the number of clients that purchased FeatureID X AND who purchased the same productID during a previous feature.
For the table above the expected result would be:
FeatureID | CountofReturningClients
1 0
2 0
3 1
4 3
Ideally I would like to do this with SQL, but am also open to doing some manipulation in Excel/PowerPivot. Thanks!!
If you join your table to itself, you can find the data you're looking for. Be careful, because this query can take a long time if the table has a lot of data and is not indexed well.
SELECT t_current.FEATUREID, COUNT(DISTINCT t_prior.CLIENTID)
FROM table_name t_current
LEFT JOIN table_name t_prior
ON t_current.FEATUREDATE > t_prior.FEATUREDATE
AND t_current.CLIENTID = t_prior.CLIENTID
AND t_current.PRODUCTID = t_prior.PRODUCTID
GROUP BY t_current.FEATUREID
"Per feature, count the clients who match for any earlier Features with the same product"
SELECT
Curr.FeatureID
COUNT(DISTINCT Prev.ClientID) AS CountofReturningClients --edit thanks to feedback
FROM
MyTable Curr
LEFT JOIN
MyTable Prev WHERE Curr.FeatureID > Prev.FeatureID
AND Curr.ClientID = Prev.ClientID
AND Curr.ProductID = Prev.ProductID
GROUP BY
Curr.FeatureID
Assumptions: You have a table called Features that is:
FeatureID, FeatureDate, ProductID
If not then you could always create one on the fly with a temporary table, cte or view.
Then:
SELECT
FeatureID
, (
SELECT COUNT(DISTINCT ClientID) FROM Purchases WHERE Purchases.FeatureDate < Feature.FeatureDate AND Feature.ProductID = Purchases.ProductID
) as CountOfReturningClients
FROM Features
ORDER BY FeatureID
New to this, but wouldn't the following work?
SELECT FeatureID, (CASE WHEN COUNT(clientid) > 1 THEN COUNT(clientid) ELSE 0 END)
FROM table
GROUP BY featureID