I'm not sure where the error is,
(Error at Line 2)
(Help)
select last_name, first_name
from employee group by Employee_ID in
select Employee_ID from service group by Property_ID having count(*)>2;
employee table
create table EMPLOYEE(
Employee_ID int primary key,
Last_name char(30),
First_Name char(30),
CellPhone char(20),
ExperienceLevel char(30),
CONSTRAINT EX_EMPLOYEE_EXPERIENCELEVEL CHECK (ExperienceLevel IN('Master', 'Junior', 'Senior'))
);
service Table
create table SERVICE (
Property_ID int,
Employee_ID int,
Service_Date date,
Hours_worked int,
primary key(Property_ID, Employee_ID),
foreign key(Property_ID) references PROPERTY(Property_ID),
foreign key(Employee_ID) references EMPLOYEE(Employee_ID)
);
property table
create table PROPERTY(
Property_ID int primary key,
Owner_ID int,
Owner_Name char(30),
Owner_email char(30),
Owner_type char(30),
CONSTRAINT EX_PROPERTY_OWNERTYPE CHECK (Owner_type IN('Individual', 'Corporate', 'Partnership'))
);
Your query is not very clear. The in clause before the subquery is not a valid clause at that position. If you want to select the employes whose id are in the subquery, so you have to do something like this:
select last_name, first_name
from employee
WHERE Employee_ID in
(select Employee_ID from service
group by Property_ID having count(*)>2);
Related
CREATE TABLE EMPLOYEE (
EID CHAR(3) NOT NULL PRIMARY KEY,
ENAME VARCHAR2(50) NOT NULL,
JOB_TYPE VARCHAR2(50) NOT NULL,
MANAGER CHAR(3) FOREIGN KEY REFERENCES EMPLOYEE(EID),
HIRE_DATE DATE NOT NULL,
DNO INTEGER FOREIGN KEY REFERENCES DEPARTMENT(DNO),
COMMISSION DECIMAL(10,2),
SALARY DECIMAL(7,2) NOT NULL,
);
CREATE TABLE DEPARTMENT (
DNO INT NOT NULL PRIMARY KEY,
DNAME VARCHAR(50),
LOCATION VARCHAR(50) DEFAULT('NEW DELHI')
);
in creation of the employee table
this is giving me an error of right parenthesis
and the department table is already created
You have an extra comma in the line
SALARY DECIMAL(7,2) NOT NULL,
Delete that comma and the Employee table should be created.
You need to Create the Department Table first to use one of its
Columns as FOREIGN KEY.
Also, check your database. There might already be a Department Table. To avoid getting that error when the table needed is already created, use the keyword IF NOT EXISTS
CREATE TABLE IF NOT EXISTS Department(
DNO INT NOT NULL PRIMARY KEY,
DNAME VARCHAR(50),
LOCATION VARCHAR(50) DEFAULT('NEW DELHI')
);
The error is caused by the trailing comma, but you have other issues:
The FOREIGN KEY is not needed for an inline reference.
You need to define the tables in the right order.
So . . .
CREATE TABLE DEPARTMENT (
DNO INT NOT NULL PRIMARY KEY,
DNAME VARCHAR(50),
LOCATION VARCHAR(50) DEFAULT('NEW DELHI')
);
CREATE TABLE EMPLOYEE (
EID CHAR(3) NOT NULL PRIMARY KEY,
ENAME VARCHAR2(50) NOT NULL,
JOB_TYPE VARCHAR2(50) NOT NULL,
MANAGER CHAR(3) REFERENCES EMPLOYEE(EID),
HIRE_DATE DATE NOT NULL,
DNO INTEGER REFERENCES DEPARTMENT(DNO),
COMMISSION DECIMAL(10,2),
SALARY DECIMAL(7,2) NOT NULL
);
Here is an example of it working.
CREATE TABLE brunch
(
br_id INT NOT NULL PRIMARY KEY,
br_name INT NOT NULL
)
CREATE TABLE employee
(
e_id INT NOT NULL PRIMARY KEY,
bdate DATE,
fname VARCHAR2(30),
lname VARCHAR2(30),
sal NUMBER,
sex VARCHAR2(1),
address VARCHAR2(50),
super_id INT REFERENCES employee(e_id)
)
ALTER TABLE brunch ADD mgr_id int REFERENCES employee(e_Id);
ALTER TABLE employee ADD b_id INT REFERENCES brunch(br_id);
CREATE TABLE client
(
c_id INT NOT NULL PRIMARY KEY,
c_name VARCHAR2(40),
c_oemail VARCHAR2(40),
c_email VARCHAR2(40),
b_id reference brunch(b_id)
)
The problem is with the last table, table client, and it give me an error message that says
ORA-00907: missing right parenthesis
but I don't see any problem with the syntax. Thank you
The last DDL should be
create table client
(
c_id int primary key,
c_name varchar2(40),
c_oemail varchar2(40),
c_email varchar2(40),
b_id references brunch(br_id)
);
where column name b_id should be br_id and
there's no keyword called reference but references
P.S. There's no need to use NOT NULL for a column defined as PRIMARY KEY(already includes NOT NULL).
How do I look at one table and use it to check another table for data integrity?
I have two SQL Tables.
One that is a person table
CREATE TABLE PERSON
(
ID INT IDENTITY(10000,1) NOT NULL,
Firstname VARCHAR(15),
Lastname VARCHAR(25) NOT NULL,
Birthdate DATE,
Gender VARCHAR(1),
CHECK ( GENDER IN ('M', 'F')),
Street VARCHAR(50),
City VARCHAR(15),
State VARCHAR(2),
CHECK (State IN ('FL','GA','PA')),
Zip INT,
Phone VARCHAR(10),
Employee VARCHAR(1),
CHECK ( Employee IN('Y','N')),
Member VARCHAR(1),
CHECK ( Member IN('Y','N')),
CHECK (Member IN ('Y') or Employee IN ('Y')),
CONSTRAINT PERSON_PK PRIMARY KEY (ID));
And Employee Table
CREATE TABLE EMPLOYEE
(
ID INT NOT NULL,
Datehired DATE DEFAULT GETDATE(),
Status VARCHAR(1),
CHECK ( Status IN ('F','C')),
Position VARCHAR(25),
EmpType VARCHAR(25),
CONSTRAINT EMPLOYEE_PK PRIMARY KEY (ID),
CONSTRAINT EMPLOYEE_PERSON_FK FOREIGN KEY (ID) REFERENCES PERSON);
Let's say someone isn't an employee. I can still insert them into the Employee Table.
INSERT INTO EMPLOYEE
(ID, Status, Position, EmpType)
VALUES
('10000','C','Teaching Classes','Instructor');
How Do I prevent this from happening.
One method is to have a redundant key:
alter table person
contraint unq_person_id_employee
unique (id, employee);
Then add a computed column to employee:
alter table employee add employee as ('Y') persisted;
Finally, add the constraint:
alter table employee
add constraint fk_employee_person
foreign key (id, employee) references person(id, employee);
Now, you are guaranteed that only employees are in the Employee table.
Why is the create tables not allowing me to add the staff tables, the CONSTRAINT seem logical to me.
CREATE TABLE branch
(
Branch_ID VARCHAR(2),
Branch_Name VARCHAR(20),
Branch_Address VARCHAR(40),
Branch_Postcode VARCHAR(15),
Branch_Telephone NUMBER(15),
Branch_email VARCHAR(40),
Branch_Fax NUMBER(15),
PRIMARY KEY ( Branch_ID )
);
CREATE TABLE staff
(
Staff_ID INT NOT NULL PRIMARY KEY,
firstName VARCHAR(20),
lastName VARCHAR(20),
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
salary DECIMAL (19,4),
CONSTRAINT BRANCH_fk FOREIGN KEY(Branch_ID ) REFERENCES branch(Branch_ID )
);
ORA-00904: "BRANCH_ID": invalid identifier
I think you forgot to add the Branch_ID field.
You are referencing this one to be your foreign key at the Staff table, but you didn't define it in your staff table yet.
Change staff table definition to:
CREATE TABLE staff
(
Staff_ID INT NOT NULL PRIMARY KEY,
firstName VARCHAR(20),
lastName VARCHAR(20),
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
salary DECIMAL (19,4),
Branch_ID VARCHAR2(2),
CONSTRAINT BRANCH_fk FOREIGN KEY(Branch_ID) REFERENCES branch(Branch_ID)
);
About Gordon Linoff's comment, check the link below. I modified my answer to match the 'best-practice'.
Difference VARCHAR and VARCHAR2
How are you all?
Basically I've written up this bit of SQL code to create a table but I keep getting the error stated in the title, any idea as to why?
Here's the code:
CREATE TABLE staff(
staffID INT NOT NULL PRIMARY KEY,
firstName VARCHAR2(20),
lastName VARCHAR2(20),
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
salary DECIMAL (19,4),
branchID INT FOREIGN KEY REFERENCES branches(branchID)
);
Also here is the code for my 'branches' table
CREATE TABLE branches
(branchID int NOT NULL PRIMARY KEY,
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
manager VARCHAR2(20));
Any help would be appreciated!
Thank you!
A few suggestions:
First make sure that the branches table has been created.
Second, I would alter the create table code to the following:
CREATE TABLE staff(
staffID INT NOT NULL PRIMARY KEY,
firstName VARCHAR(20),
lastName VARCHAR(20),
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
salary DECIMAL (19,4),
branchID INT,
constraint fk_branchId FOREIGN KEY (branchID) REFERENCES branches(branchID)
);
See SQL Fiddle with Demo. The syntax to create a FOREIGN KEY during table creation is:
CREATE TABLE table_name
(
column1 datatype null/not null,
column2 datatype null/not null,
...
CONSTRAINT fk_column
FOREIGN KEY (column1, column2, ... column_n)
REFERENCES parent_table (column1, column2, ... column_n)
);
Here is the creation of table staff1
CREATE TABLE staff
(
staffID INT NOT NULL PRIMARY KEY,
firstName VARCHAR2(20),
lastName VARCHAR2(20),
addressLine_1 VARCHAR2(30),
city VARCHAR2(15),
postcode VARCHAR2(7),
telephone VARCHAR2(15),
branchID int,
salary DECIMAL (19,4),
CONSTRAINT BRANCH_fk FOREIGN KEY(branchID) REFERENCES branches(branchID)
)
SQL> /
Table created.
Please use constraint name such that finding an error becomes easy.
create table medication (
id int not null primary key,
name varchar(20),
mudslig price number (10),
protect date not null default (getdate()),
finish date not null default (getdate()),
company proect varchre2 (20),
shelf id int,
chemistid int,
constraint shelf_fk foreign key (shelf id) refences shelf (shelf id),
constraint chemist_fk foreign key (chemistid) refences chemist (chemistid)
);
Please use constraint name such that finding an error becomes easy.